I am working on language identifier where i need to pass the text to server and identify the language where I'm trying to pass the Hindi characters through URL to server.How can i pass the Hindi characters as URL parameter in java.please somebody help me with this.
You need to encode your URL using URLEncoder. Just use URLEncoder.encode method, something like this:
String yourEncodedURL = URLEncoder.encode(yourURLWithHindiCharacters, "UTF-8");
Related
In my Android application I get JSON response string from a PHP url. from the response I get some hotel names with apostrophe, I get ' character instead of apostrophe. How can I parse the hotel with special characters in android? I can see the apostrophe in the browser but could not see in android logcat.
I have tried jresponse = URLEncoder.encode(jresponse,"UTF-8"); but I could not get apostrophe for hotel name.
This is the one of the hotel name in the response.
I see the following in browser.
{"id":12747,
"name":"Oscar's",
....
}
But in the logcat:
id 12747
name Oscar's
Use the decoder instead of encoder. URLDecoder.decode(jresponse,"UTF-8")
Use ISO-8859-2 when you create the URLEncodedEntity that you send off. You can set this as a parameter in the constructor.
Without a specified charset, you are probably sending the data in UTF-8/UTF-16 (most common) which the server is interpreting in a different way.
EDIT: It looks like ISO-8859-2 doesn't support ñ. You may have to change something server-side. http://en.wikipedia.org/wiki/ISO/IEC_8859-2
You can try Html class. eg :-
jresponse = Html.fromHtml(jresponse);
I used URLEncoder but this seems URLEncoder does not cover everything of url query parameter encoding (escaped). I searched and someone used URLEncoder to encode whole url. For my case I iust want to encode (escape) url query parameter values.
Here are some code I am used
String url = "http://myserver.com?x=" + URLEncoder.encode(x_value, "UTF-8");
Anyone has any ideas? Thanks.
I'm trying to get an url parameter in jee.
So I have this kind of url :
http://MySite/MySite.jsp?page=recherche&msg=toto
First i tried with : request.getParameter("msg").toString();
it works well but if I try to search "c++" , the method "getParameter()" returns "c" and not "c++" and i understand.
So I tried another thing. I get the current URL and parse it to get the value of the message :
String msg[]= request.getQueryString().split("msg=");
message=msg[1].toString();
It works now for the research "c++" but now I can't search accent. What can I do ?
EDIT 1
I encode the message in the url
String urlString=Utils.encodeUrl(request.getParameter("msg"));
so for the URL : http://MySite/MySite.jsp?page=recherche&msg=c++
i have this encoded URL : http://MySite/MySite.jsp?page=recherche&msg=c%2B%2B
And when i need it, i decode the message of the URL
String decodedUrl = URLDecoder.decode(url, "ISO-8859-1");
Thanks everybody
Anything you send via "get" method goes as part of the url, which needs to be urlencoded to be valid in case it contains at least one of the reserved characters. So, any character will need to be encoded before sending.
In order to send c++, you would have to send c%2B%2B. That would be interpreted properly at the server side.
Here some reference you can check:
http://www.blooberry.com/indexdot/html/topics/urlencoding.htm
Now the question is, how and where do you generate your URL? According to the language, you will need to use the proper method to encode your strings.
if I try to search "c++" , the method "getParameter()" returns "c" and not "c++"
Query parameters are treated as application/x-www-form-urlencoded, so a + character in the URL means a space character in the parameter value. If you want to send a + character then it needs to be encoded in the URL as %2B:
http://MySite/MySite.jsp?page=recherche&msg=c%2B%2B
The same applies to accented characters, they need to be escaped as the bytes of their UTF-8 representation, so été would need to be:
msg=%C3%A9t%C3%A9
(é being Unicode character U+00E9, which is C3 A9 in UTF-8).
In short, it's not the fault of this code, it's the fault of whatever component is responsible for constructing the URL on the client side.
Call your URL with
msg=c%2B%2B
+ in a URL mean 'space'. It needs to be escaped.
You need to escape special characters when passing them as URL parameters. Since + means space and & means and another parameter, these cannot be used as parameter values.
See this other S.O. question.
You may want to use the Apache HTTP client library to help you with the URL encoding/decoding. The URIUtil class has what you need.
Something like this should work:
String rawParam = request.getParameter("msg");
String msgParam = URIUtil.decode(rawParam);
Your example indicates that the data is not being properly encoded on the client side. See this JavaScript question.
How do you encode a path parameter (not form-url-encoded) but just a single URL that's appended in the format:
public String method(#PathParam("url") String url) {
}
There are lots of references to form URL encoding, but I want to simply encode a string as in the above.
Like mentioned in the previous answer URLEncoder can only be used for query paramaters, not path parameters. This matters e.g. for spaces which are a + in the query parameter but a %20 in the path.
org.springframework.web.util.UriUtils.encodePath()
can be used. Also using an org.apache.http.client.utils.URIBuilder would work. setPath is escaping the path part here. Also pure Java by using a constructor of java.net.Uri works.
Why would you want to *en*code it there, if anything wouldn't you want to *de*code it? In any case, you would call the standard URLEncoder.
I am using jsps and in my url I have a value for a variable like say "L & T". Now when I try to retrieve the value for it by using request.getParameter I get only "L". It recognizes "&" as a separator and thus it is not getting considered as a whole string.
How do I solve this problem?
java.net.URLEncoder.encode("L & T", "utf8")
this outputs the URL-encoded, which is fine as a GET parameter:
L+%26+T
A literal ampersand in a URL should be encoded as: %26
// Your URL
http://www.example.com?a=l&t
// Encoded
http://www.example.com?a=l%26t
You need to "URL encode" the parameters to avoid this problem. The format of the URL query string is:
...?<name>=<value>&<name>=<value>&<etc>
All <name>s and <value>s need to be URL encoded, which basically means transforming all the characters that could be interpreted wrongly (like the &) into %-escaped values. See this page for more information:
http://www.w3schools.com/TAGS/ref_urlencode.asp
If you're generating the problem URL with Java, you use this method:
String str = URLEncoder.encode(input, "UTF-8");
Generating the URL elsewhere (some templates or JS or raw markup), you need to fix the problem at the source.
You can use UriUtils#encode(String source, String encoding) from Spring Web. This utility class also provides means for encoding only some parts of the URL, like UriUtils#encodePath.