Develop Reference

Change name of property while deserializing response in Java

JSON Response from API :
{
"result":[
{
"ResultType":"SUCCESS"
}
]
}
After Converting to ResultClass.class :
{
"result":[
{
"resultType":null
}
]
}
Expected Output After Converting to ResultClass.class :
{
"result":[
{
"resultType":"SUCCESS"
}
]
}
I am integrating with third party API.I want to change property name while deserializing .I have tried #JsonProperty on filed getter and setter.But the value is not reflected in field resultType.
ResultClass.java
#JsonProperty("result")
List<TestClass> result = new ArrayList<>();
public List<TestClass> getResult() {
return result;
}
public void setResult(List<TestClass> result) {
this.result = result;
}
TestClass.java
#JsonProperty("ResultType")
private String resultType;
public String getResultType() {
return resultType;
}
public void setResultType(String resultType) {
this.resultType = resultType;
}
Note : I have tried JsonObject and it is working fine.I am using HttpClient and HttpResponse for making request.Jackson Version : 2.5.0

2 Solutions are available:
1. Make case-insensitive deserializing
Add this feature on your object mapper:
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(MapperFeature.ACCEPT_CASE_INSENSITIVE_PROPERTIES, true);
2. Serialize and deserialize with different property names
To change the name of the property ResultType to resultType, you should rather use both #JsonGetter and #JsonSetter:
import com.fasterxml.jackson.annotation.JsonGetter;
import com.fasterxml.jackson.annotation.JsonSetter;
public class TestClass {
private String resultType;
#JsonGetter("resultType")
public String getResultType() {
return resultType;
}
#JsonSetter("ResultType")
public void setResultType(String resultType) {
this.resultType = resultType;
}
}

Deserialize a JSON containing a list of objects using Gson

I'm trying to deserialize a JSON which containes a String and a list of objects in my Spring web application.
JSON
[
{
"jsonrpc":"2.0",
"result":[
{
"event":{
"id":"27809810",
"name":"Spezia v Trapani",
"countryCode":"IT",
"timezone":"Europe/London",
"openDate":"2016-05-28T16:30:00.000Z"
},
"marketCount":13
},
{
"event":{
"id":"27811083",
"name":"Torino U19 v Atalanta U19",
"countryCode":"IT",
"timezone":"Europe/London",
"openDate":"2016-05-29T16:15:00.000Z"
},
"marketCount":18
},
...
]
My classes are:
ListEventsResponse class
public class ListEventsResponse {
private String jsonrpc;
private List<ListEventsResult> result;
public ListEventsResponse() { }
public String getJsonrpc() {
return jsonrpc;
}
public void setJsonrpc(String jsonrpc) {
this.jsonrpc = jsonrpc;
}
public List<ListEventsResult> getResult() {
return result;
}
public void setResult(List<ListEventsResult> result) {
this.result = result;
}
}
ListEventsResult class
public class ListEventsResult {
private Event event;
private int marketCount;
public ListEventsResult() { }
public Event getEvent() {
return event;
}
public void setEvent(Event event) {
this.event = event;
}
public int getMarketCount() {
return marketCount;
}
public void setMarketCount(int marketCount) {
this.marketCount = marketCount;
}
}
I have also Event class, composed by 5 String (id, name, etc.).
Controller
[...]
ListEventsResponse listEvents = new Gson().fromJson(response.toString(), ListEventsResponse.class);
List<ListEventsResult> eventsList = listEvents.getResult();
return new ModelAndView("page", "eventsList", eventsList);
My .jsp page
[...]
<c:forEach items="${eventsList}" var="listEventsResult">
Match: <c:out value="${listEventsResult.name}"/>
</c:forEach>
[...]
My code runs and doesn't give any error, but no match is shown on my page, in fact listEvents doesn't contains any object.
I can't understand how to deserialize properly the list of objects, so my question is: which logic is behind the deserialization of a json which contains a list of objects?
I post my code just to explain better my problem.

As you have a Json Array as response , you need to deserialize like below
Gson gson = new Gson();
Type type = new TypeToken<List<ListEventsResponse>>(){}.getType();
List<ListEventsResponse> events = (List<ListEventsResponse>) gson.fromJson(response.toString(), type);

JAX-WS For Json request and response [duplicate]

Is it possible that a jax-ws soap-webservice can output json format instead of xml?
#Component
#WebService
public class HRSService {
#WebMethod
public String test(String value) {
return value; //returned as XML. JSON possible?
}
}

Apparently it's possible by following the instructions indicated at https://jax-ws-commons.java.net/json/ (Archive version)
Summing up:
#BindingType(JSONBindingID.JSON_BINDING)
public class MyService {
public Book get(#WebParam(name="id") int id) {
Book b = new Book();
b.id = id;
return b;
}
public static final class Book {
public int id = 1;
public String title = "Java";
}
}
You just need jaxws-json.jar in your WEB-INF/lib for this to work.
I hope it helps!

This is late. I recently returned to programming in Java, but for those who will be visiting this page in the future. The example in the JAXWS metro documents works only in javascript. I used the following together with JSONObject:
#WebServiceProvider
#ServiceMode(value = Service.Mode.MESSAGE)
#BindingType(value=HTTPBinding.HTTP_BINDING)
then implement Provider(DataSource), as in example:
public class clazz implements Provider<DataSource>
{ ...
#Override
public DataSource invoke(DataSource arg)
{
...
String emsg = "Request Parameter Error.";
String sret = create_error_response(emsg);
return getDataSource(sret);
}
}
private DataSource getDataSource(String sret)
{
ByteArrayDataSource ds = new ByteArrayDataSource(sret.getBytes(), "application/json");
return ds;
}
public String create_error_response(String msg)
{
JSONObject json = new JSONObject();
json.put("success", new Boolean(false));
json.put("message", msg);
return json.toString();
}

How do I deserialize this JSON type

I have a JSON that looks like this:
{
"results": {
"exchange": [
"site.com",
{
"currency": "usd",
"last_traded": "2015.24"
}
]
}
}
How do I get the last_traded value?
I wrote some POJO for this, but I can't seem to find a way to get the key-value inside exchange array.
public class ExchangeContainer {
#Expose
private Results results;
public Results getResults() {
return results;
}
public void setResults(Results results) {
this.results = results;
}
#Override
public String toString() {
return ToStringBuilder.reflectionToString(this);
}
}
public class Results {
#Expose
private List<String> exchange = new ArrayList<String>();
public List<String> getExchange() {
return exchange;
}
public void setExchange(List<String> exchange) {
this.exchange = exchange;
}
#Override
public String toString() {
return ToStringBuilder.reflectionToString(this);
}
}
I'm using GSON to deserialize this JSON.
So in order for me to traverse through the model is:
ExchangeContainer response;
String rate = response.getResults().getExchange().get(1); // how to continue?
and I'm stuck.

Implement interface using implements JsonDeserializer in your class
and override deserialize method.
Example link - http://www.javacreed.com/gson-deserialiser-example/

As you have created list of Strings by
private List<String> exchange = new ArrayList<String>();
& setting another list in created list i.e., in exchange
public void setExchange(List<String> exchange)
When you get value by invoking line
String rate = response.getResults().getExchange().get(1);
it contains "last_traded": "2015.24" is it right ?
Now to get 2015.24, you have following choices :-
String[] split(":")
String substring(int beginIndex)
I hope this will solve your problem.

Converting Java objects to JSON with Jackson

I want my JSON to look like this:
{
"information": [{
"timestamp": "xxxx",
"feature": "xxxx",
"ean": 1234,
"data": "xxxx"
}, {
"timestamp": "yyy",
"feature": "yyy",
"ean": 12345,
"data": "yyy"
}]
}
Code so far:
import java.util.List;
public class ValueData {
private List<ValueItems> information;
public ValueData(){
}
public List<ValueItems> getInformation() {
return information;
}
public void setInformation(List<ValueItems> information) {
this.information = information;
}
#Override
public String toString() {
return String.format("{information:%s}", information);
}
}
and
public class ValueItems {
private String timestamp;
private String feature;
private int ean;
private String data;
public ValueItems(){
}
public ValueItems(String timestamp, String feature, int ean, String data){
this.timestamp = timestamp;
this.feature = feature;
this.ean = ean;
this.data = data;
}
public String getTimestamp() {
return timestamp;
}
public void setTimestamp(String timestamp) {
this.timestamp = timestamp;
}
public String getFeature() {
return feature;
}
public void setFeature(String feature) {
this.feature = feature;
}
public int getEan() {
return ean;
}
public void setEan(int ean) {
this.ean = ean;
}
public String getData() {
return data;
}
public void setData(String data) {
this.data = data;
}
#Override
public String toString() {
return String.format("{timestamp:%s,feature:%s,ean:%s,data:%s}", timestamp, feature, ean, data);
}
}
I just missing the part how I can convert the Java object to JSON with Jackson:
public static void main(String[] args) {
// CONVERT THE JAVA OBJECT TO JSON HERE
System.out.println(json);
}
My Question is: Are my classes correct? Which instance do I have to call and how that I can achieve this JSON output?

To convert your object in JSON with Jackson:
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.ObjectWriter;
ObjectWriter ow = new ObjectMapper().writer().withDefaultPrettyPrinter();
String json = ow.writeValueAsString(object);

I know this is old (and I am new to java), but I ran into the same problem. And the answers were not as clear to me as a newbie... so I thought I would add what I learned.
I used a third-party library to aid in the endeavor: org.codehaus.jackson
All of the downloads for this can be found here.
For base JSON functionality, you need to add the following jars to your project's libraries:
jackson-mapper-asl
and
jackson-core-asl
Choose the version your project needs. (Typically you can go with the latest stable build).
Once they are imported in to your project's libraries, add the following import lines to your code:
import org.codehaus.jackson.JsonGenerationException;
import org.codehaus.jackson.map.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
With the java object defined and assigned values that you wish to convert to JSON and return as part of a RESTful web service
User u = new User();
u.firstName = "Sample";
u.lastName = "User";
u.email = "sampleU#example.com";
ObjectMapper mapper = new ObjectMapper();
try {
// convert user object to json string and return it
return mapper.writeValueAsString(u);
}
catch (JsonGenerationException | JsonMappingException e) {
// catch various errors
e.printStackTrace();
}
The result should looks like this:
{"firstName":"Sample","lastName":"User","email":"sampleU#example.com"}

Just follow any of these:
For jackson it should work:
ObjectMapper mapper = new ObjectMapper();
return mapper.writeValueAsString(object);
//will return json in string
For gson it should work:
Gson gson = new Gson();
return Response.ok(gson.toJson(yourClass)).build();

You could do this:
String json = new ObjectMapper().writeValueAsString(yourObjectHere);

This might be useful:
objectMapper.writeValue(new File("c:\\employee.json"), employee);
// display to console
Object json = objectMapper.readValue(
objectMapper.writeValueAsString(employee), Object.class);
System.out.println(objectMapper.writerWithDefaultPrettyPrinter()
.writeValueAsString(json));

You can use Google Gson like this
UserEntity user = new UserEntity();
user.setUserName("UserName");
user.setUserAge(18);
Gson gson = new Gson();
String jsonStr = gson.toJson(user);

Well, even the accepted answer does not exactly output what op has asked for. It outputs the JSON string but with " characters escaped. So, although might be a little late, I am answering hopeing it will help people! Here is how I do it:
StringWriter writer = new StringWriter();
JsonGenerator jgen = new JsonFactory().createGenerator(writer);
jgen.setCodec(new ObjectMapper());
jgen.writeObject(object);
jgen.close();
System.out.println(writer.toString());

Note: To make the most voted solution work, attributes in the POJO have to be public or have a public getter/setter:
By default, Jackson 2 will only work with fields that are either
public, or have a public getter method – serializing an entity that
has all fields private or package private will fail.
Not tested yet, but I believe that this rule also applies for other JSON libs like google Gson.

public class JSONConvector {
public static String toJSON(Object object) throws JSONException, IllegalAccessException {
String str = "";
Class c = object.getClass();
JSONObject jsonObject = new JSONObject();
for (Field field : c.getDeclaredFields()) {
field.setAccessible(true);
String name = field.getName();
String value = String.valueOf(field.get(object));
jsonObject.put(name, value);
}
System.out.println(jsonObject.toString());
return jsonObject.toString();
}
public static String toJSON(List list ) throws JSONException, IllegalAccessException {
JSONArray jsonArray = new JSONArray();
for (Object i : list) {
String jstr = toJSON(i);
JSONObject jsonObject = new JSONObject(jstr);
jsonArray.put(jsonArray);
}
return jsonArray.toString();
}
}