This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 7 years ago.
I have been trying to connect to a mysql database and it was succesfull. In the onPostExecute method, I get a result which seems to me exactly the same as the real input. In this example the emailadress jb#jb.jb. Logcat shows both the real input as the result. Yet my code doesn't agree that it is the same. Any advice?
EDIT: This link apparently gave the answer: answer on the question
You have to use String.equals() instead of == to compare Strings. check this link
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This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 4 years ago.
So, I'm trying to do something really simple, and that's check if a password equals something in my SWT application. So, my code was this:
if (passwordBox.getText() == "test") {
passwordBox.setVisible(false);
}
However, in my application, which uses text fields marked as passwords (with that variable), it will not fire that when I click a button. I already have button handling working, since I have an else statement that fires, but this will not fire when the password box obviously equals "test". What's wrong here?
Strings are always compared by equals().
if(("test").equals(passwordBox.getText())) {
passwordBox.setVisible(false);
}
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 4 years ago.
I am reasonably experienced with programming, but not specifically in Java. I am coming across the following error when working in eclipse. My code is the following:
I have used the debug function, and it reports that carbonPrefix is pent, but that carbon stays at 0 throughout. Like I said, I am a novice to Java and Eclipse, so I may not be using the debug function to it's full extent.
For anybody that's interested, this the start of code where you input the name of an alkane and it tells you the formula. It worked in Javascript and I'm just trying to translate it into Java.
Thank you all so much!
you have to use
carbonPrefix.equals("pent");
in java == operator used to compare two object references and the method equals() is used to compare two strings to determine whether they are equal or not.
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 6 years ago.
i'm taking user input from
String riddle=b.readLine();
riddle1=Integer.parseInt(riddle);
and obviously, i'm trying to get the user to answer a riddle.
I tried using the following
if(riddle1=="answer")
but that doesn't work
Try this
riddle.equals("answer");
As == doesn't checks whether both strings are equal or not, it compares string's location.
You can click here for more information about it.
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 6 years ago.
I already tried with string.equal function which will compare two strings, but what will be optimize way of doing same.
Suggestions are welcome.
Hi all got it may help others What's the quickest way to compare strings in Java?
Thanks Saurabh for sharing link.
According to me, You should use the equals() method of the String class to compare Strings.
if (xyz.equals("something")) {
//Do what you want if string is equal...
}
see this also..
This question already has answers here:
How do I compare strings in Java?
(23 answers)
Closed 9 years ago.
My program is using the following code
String mobile="";
if(mobile!="")
System.out.println("++++++");
System.out.println("------");
But if statement always set true. how it is possible? how to correct the code to get false for if condition?
try this way
if(!(mobile.equals("")))
there are difference between == and .equals()
As whoAmI has suggested its better to
if(!("".equals(mobile)))
because it can handle mobile as null
you can't use "!=" on strings. This only compares the references of the strings. If you want to compare the content of the strings you need to use equals
if(!("".equals(mobile)))