class Call {
int count;
public void increment() {
for (int i = 0; i < 1000; i++)
count++;
}
}
class Caller implements Runnable {
Call c;
public Caller(Call c) {
this.c = c;
}
#Override
public void run() {
// TODO Auto-generated method stub
c.increment();
}
}
class Calling implements Runnable {
Call c;
public Calling(Call c) {
this.c = c;
}
#Override
public void run() {
// TODO Auto-generated method stub
synchronized (c) {
c.increment();
}
}
}
public class SynchronizedBlock {
public static void main(String[] args) throws InterruptedException {
Call call = new Call();
Calling calling = new Calling(call);
Caller caller = new Caller(call);
Thread t1 = new Thread(caller);
Thread t2 = new Thread(calling);
t1.start();
t2.start();
t1.join();
t2.join();
System.out.println("caller:" + caller.c.count);
}
}
Here have made increment method synchronized in 1 class and in other class i havent made it as synchronized. When i run the above code , it sometimes gives value of count less than 2000 .
As per my understanding, Since Calling class's object has already locked the object, so there is no need to synchronize in Caller class increment method.
Could you please help me in understanding the logic here.
Since Calling class's object has already locked the object, so there
is no need to synchronize in Caller class increment method.
Your understanding is incorrect. In order for parallel actions on a variable to be deterministic, you must have some sort of synchronization in place on every access/modification to that variable**.
You need to synchronize in Caller as well.
**: This is a necessary but insufficient condition to guarantee determinism.
synchronized keyword in java means that lock will be acquired before entering the block and released after exit.
Since t2 acquires/releases the lock and t1 doesn't, there is effectively no synchronization going on. t1 just goes in the block whenever the CPU time is assigned to it.
t2 also always goes in the block without waiting because the lock is never acquired by t1.
--
If you synchronize the increment method your program will work correctly:
class Call {
int count;
public synchronized void increment() {
for (int i = 0; i < 1000; i++)
count++;
}
}
After this change you can remove the synchronized block from t2.
What's probably happening when you get the correct value of 2000, happens between the lines:
t1.start();
t2.start();
This is because the execution of public void increment(); is finishing in a single quantum, before the t2.start() line is even executed. A Thread Quantum is the time that the thread runs before a different thread can run on the processors core.
The first thread doesn't lock the object, and occasionally a single quantum will not encompass the entire execution of increment(), which leaves time for thread 2 to begin executing and working on the same object data. This will result in 2 copies of the variable count existing at the same time, competing for the same memory.
Try increasing the amount of increments for (int i = 0; i < 1000; i++) to some number like for (int i = 0; i < 10000000; i++). You will most likely see the application begin to fail more often.
Related
Let's say I have the following code in Java
public class SynchronizedCounter {
private int c = 0;
public synchronized void increment() {
c++;
}
}
And I create two threads T1 and T2
Thread T1 = new Thread(c1);
Thread T2 = new Thread(c2);
Where c1 and c2 are two different instances of the class SynchronizedCounter.
It is really needed to synchronize the method increment? Because I know that when we use a synchronized method, the thread hold a lock on the object, in this way other threads cannot acquire the lock on the same object, but threads "associated" with other objects can execute that method without problems. Now, because I have only one thread associated with the object c1, it is anyway needed to use the synchronized method? Also if no other threads associated with the same object exist?
In your specific example, synchronized is not needed because each thread has its own instance of the class, so there is no data "sharing" between them.
If you change your example to:
Thread T1 = new Thread(c);
Thread T2 = new Thread(c);
Then you need to synchronize the method because the ++ operation is not atomic and the instance is shared between threads.
The bottom line is that your class is not thread safe without synchronized. If you never use a single instance across threads it doesn't matter. There are plenty of legitimate use cases for classes which are not thread safe. But as soon as you start sharing them between threads all bets are off (i.e. vicious bugs may appear randomly).
Given code/example does not need synchronization since it is using two distinct instances (and so, variables). But if you have one instance shared between two or more threads, synchronization is needed, despite comments stating otherwise.
Actually it is very simple to create a program to show that behavior:
removed synchronized
added code to call the method from two threads
public class SynchronizedCounter {
private int c = 0;
public void increment() {
c++;
}
public static void main(String... args) throws Exception {
var counter = new SynchronizedCounter();
var t1 = create(100_000, counter);
var t2 = create(100_000, counter);
t1.start();
t2.start();
// wait termination of both threads
t1.join();
t2.join();
System.out.println(counter.c);
}
private static Thread create(int count, SynchronizedCounter counter) {
return new Thread(() -> {
for (var i = 0; i < count; i++) {
counter.increment();
}
System.out.println(counter.c);
});
}
}
Eventually (often?) this will result in weird numbers like:
C:\TMP>java SynchronizedCounter.java
122948
136644
136644
add synchronized and output should always end with 200000:
C:\TMP>java SynchronizedCounter.java
170134
200000
200000
Apparently posted code is not complete: the incremented variable is private and there is no method to retrieve the incremented value. impossible to really know if the method must be synchronized or not.
I'm reading java multithreading tutorial which says thread only gives up key until it completes synchronised method, however when I run the following code (about 20 times):
public class SyncDemo implements Runnable{
#Override
public void run() {
for (int i = 0; i < 10; i++) {
sync();
}
}
private synchronized void sync() {
System.out.println(Thread.currentThread().getName());
}
public static void main(String[] args) {
SyncDemo s = new SyncDemo();
Thread a = new Thread(s, "a");
Thread b = new Thread(s, "b");
a.start();
b.start();
}
}
it only prints a then b, which I expect a mixed sequence of them because current thread will unlock every time after sync() is executed inside the loop? Thus giving the other thread a chance to print its name?
There is nothing in your program that would demand a certain execution order. So the run time will schedule the threads in a way that makes most sense in the current situation. Factors that may influence the order are number of processors, load situation, ...
I am trying to understand Synchornized in Java.
I understood if I have access a synchronized method on same object from 2 different Threads, only one will be able to access at a time.
But I think if the same method is being called on 2 different instances, Both Objects should be able to access the method parallel. Which would cause race condition if accessing/modifying a static member variable from the method. But I am not able to see the race condition happening in below code.
Could someone please explain whats wrong with the code or my understanding.
For reference code is accessible at : http://ideone.com/wo6h4R
class MyClass
{
public static int count=0;
public int getCount()
{
System.out.println("Inside getcount()");
return count;
}
public synchronized void incrementCount()
{
count=count+1;
}
}
class Ideone
{
public static void main(String[] args) throws InterruptedException {
final MyClass test1 = new MyClass();
final MyClass test2 = new MyClass();
Thread t1 = new Thread() {
public void run()
{
int k=0;
while (k++<50000000)
{
test1.incrementCount();
}
}
};
Thread t2 = new Thread() {
public void run()
{
int l=0;
while (l++<50000000)
{
test2.incrementCount();
}
}
};
t1.start();
t2.start();
t1.join();
t2.join();
//System.out.println(t2.getState());
int x=500000000+500000000;
System.out.println(x);
System.out.println("count = " + MyClass.count);
}
}
You're right that the race condition exists. But the racy operations are so quick that they're unlikely to happen -- and the synchronized keywords are likely providing synchronization "help" that, while not required by the JLS, hide the races.
If you want to make it a bit more obvious, you can "spell out" the count = count + 1 code and put in a sleep:
public synchronized void incrementCount()
{
int tmp = count + 1;
try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
count=tmp;
}
That should show the races more easily. (My handling of the interrupted exception is not good for production code, btw; but it's good enough for small test apps like this.)
The lesson learned here is: race conditions can be really hard to catch through testing, so it's best to really understand the code and prove to yourself that it's right.
Since syncrhonized methods actually synchronize on this different instance methods will lock on different objects and therefore you will get race conditions since they don't block each other.
You probably have to make your own lock object and lock on that.
class MyClass
{
public static int count=0;
//this is what you lock on
private static Object lock = new Object();
public int getCount()
{
synchronized(lock){
System.out.println("Inside getcount()");
return count;
}
}
public void incrementCount()
{
synchronized(lock){
count = count+1;
}
}
//etc
Now when you run your main, this gets printed out:
1000000000
count = 100000000
Here's the relevant section of the Java specification:
"A synchronized method acquires a monitor (ยง17.1) before it executes. For a class (static) method, the monitor associated with the Class object for the method's class is used. For an instance method, the monitor associated with this (the object for which the method was invoked) is used."
However I fail to see where the MyClass' instances are actually incrementing "count" so what exactly are you expecting to show as a race condition?
(Taken originally from this answer)
I can't Seem to get a final counter value Of 20000. What is wrong with this code?
public class Synchronize2 {
public static void main(String[] args) {
Threading t1 = new Threading();
Threading t2 = new Threading();
t1.start();
t2.start();
try {
t1.join();
t2.join();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(Threading.counter);
}
}
class Threading extends Thread {
static int counter;
public synchronized void incrementer() {
counter++;
}
public void run() {
for (int i=0; i<10000; i++) {
incrementer();
}
}
}
Your synchronized incrementer method will lock on the object itself. But you have 2 different objects, each locking on themselves, so the method isn't thread safe; both threads can still access incrementer at the same time.
Additionally, the post-increment operation isn't thread safe because it's not atomic; there is a read operation and an increment operation, and a thread can be interrupted in the middle of the two operations. This non-thread-safe code presents a race condition, where thread one reads the value, thread two reads the value, then thread one increments and thread two increments, yet only the last increment "wins" and one increment is lost. This shows up when the ending value is less than 20000.
Make the method static too, so that because it's synchronized, it will lock on the class object of the class, which is proper synchronization here.
public static synchronized void incrementer() {
You synchronize on two different Objects. Your incrementer is a short form of this:
public void incrementer() {
synchronized (this) {
counter++;
}
}
But the two instances of "this" are not the same Object. Thus, you do not synchronize at all. Try it this way:
private static Object sync = new Object();
public void incrementer() {
synchronized (sync) {
counter++;
}
}
You should also make the variable counter volatile. It is not strictly neccessary here, because you use it only in synchronized blocks. But in real code you might read it outside such a block, and then you will get problems. Non volatile variables can be read from a local thread cache, instead from the memory.
I have always thought that synchronizing the run method in a java class which implements Runnable is redundant. I am trying to figure out why people do this:
public class ThreadedClass implements Runnable{
//other stuff
public synchronized void run(){
while(true)
//do some stuff in a thread
}
}
}
It seems redundant and unnecessary since they are obtaining the object's lock for another thread. Or rather, they are making explicit that only one thread has access to the run() method. But since its the run method, isn't it itself its own thread? Therefore, only it can access itself and it doesn't need a separate locking mechanism?
I found a suggestion online that by synchronizing the run method you could potentially create a de-facto thread queue for instance by doing this:
public void createThreadQueue(){
ThreadedClass a = new ThreadedClass();
new Thread(a, "First one").start();
new Thread(a, "Second one, waiting on the first one").start();
new Thread(a, "Third one, waiting on the other two...").start();
}
I would never do that personally, but it lends to the question of why anyone would synchronize the run method. Any ideas why or why not one should synchronize the run method?
Synchronizing the run() method of a Runnable is completely pointless unless you want to share the Runnable among multiple threads and you want to sequentialize the execution of those threads. Which is basically a contradiction in terms.
There is in theory another much more complicated scenario in which you might want to synchronize the run() method, which again involves sharing the Runnable among multiple threads but also makes use of wait() and notify(). I've never encountered it in 21+ years of Java.
There is 1 advantage to using synchronized void blah() over void blah() { synchronized(this) { and that is your resulting bytecode will be 1 byte shorter, since the synchronization will be part of the method signature instead of an operation by itself. This may influence the chance to inline the method by the JIT compiler. Other than that there is no difference.
The best option is to use an internal private final Object lock = new Object() to prevent someone from potentially locking your monitor. It achieves the same result without the downside of the evil outside locking. You do have that extra byte, but it rarely makes a difference.
So I would say no, don't use the synchronized keyword in the signature. Instead, use something like
public class ThreadedClass implements Runnable{
private final Object lock = new Object();
public void run(){
synchronized(lock) {
while(true)
//do some stuff in a thread
}
}
}
}
Edit in response to comment:
Consider what synchronization does: it prevents other threads from entering the same code block. So imagine you have a class like the one below. Let's say the current size is 10. Someone tries to perform an add and it forces a resize of the backing array. While they're in the middle of resizing the array, someone calls a makeExactSize(5) on a different thread. Now all of a sudden you're trying to access data[6] and it bombs out on you. Synchronization is supposed to prevent that from happening. In multithreaded programs you simply NEED synchronization.
class Stack {
int[] data = new int[10];
int pos = 0;
void add(int inc) {
if(pos == data.length) {
int[] tmp = new int[pos*2];
for(int i = 0; i < pos; i++) tmp[i] = data[i];
data = tmp;
}
data[pos++] = inc;
}
int remove() {
return data[pos--];
}
void makeExactSize(int size) {
int[] tmp = new int[size];
for(int i = 0; i < size; i++) tmp[i] = data[i];
data = tmp;
}
}
Why? Minimal extra safety and I don't see any plausible scenario where it would make a difference.
Why not? It's not standard. If you are coding as part of a team, when some other member sees your synchronized run he'll probably waste 30 minutes trying to figure out what is so special either with your run or with the framework you are using to run the Runnable's.
From my experience, it's not useful to add "synchronized" keyword to run() method. If we need synchronize multiple threads, or we need a thread-safe queue, we can use more appropriate components, such as ConcurrentLinkedQueue.
Well you could theoretically call the run method itself without problem (after all it is public). But that doesn't mean one should do it. So basically there's no reason to do this, apart from adding negligible overhead to the thread calling run(). Well except if you use the instance multiple times calling new Thread - although I'm a) not sure that's legal with the threading API and b) seems completely useless.
Also your createThreadQueue doesn't work. synchronized on a non-static method synchronizes on the instance object (ie this), so all three threads will run in parallel.
Go through the code comments and uncomment and run the different blocks to clearly see the difference, note synchronization will have a difference only if the same runnable instance is used, if each thread started gets a new runnable it won't make any difference.
class Kat{
public static void main(String... args){
Thread t1;
// MyUsualRunnable is usual stuff, only this will allow concurrency
MyUsualRunnable m0 = new MyUsualRunnable();
for(int i = 0; i < 5; i++){
t1 = new Thread(m0);//*imp* here all threads created are passed the same runnable instance
t1.start();
}
// run() method is synchronized , concurrency killed
// uncomment below block and run to see the difference
MySynchRunnable1 m1 = new MySynchRunnable1();
for(int i = 0; i < 5; i++){
t1 = new Thread(m1);//*imp* here all threads created are passed the same runnable instance, m1
// if new insances of runnable above were created for each loop then synchronizing will have no effect
t1.start();
}
// run() method has synchronized block which lock on runnable instance , concurrency killed
// uncomment below block and run to see the difference
/*
MySynchRunnable2 m2 = new MySynchRunnable2();
for(int i = 0; i < 5; i++){
// if new insances of runnable above were created for each loop then synchronizing will have no effect
t1 = new Thread(m2);//*imp* here all threads created are passed the same runnable instance, m2
t1.start();
}*/
}
}
class MyUsualRunnable implements Runnable{
#Override
public void run(){
try {Thread.sleep(1000);} catch (InterruptedException e) {}
}
}
class MySynchRunnable1 implements Runnable{
// this is implicit synchronization
//on the runnable instance as the run()
// method is synchronized
#Override
public synchronized void run(){
try {Thread.sleep(1000);} catch (InterruptedException e) {}
}
}
class MySynchRunnable2 implements Runnable{
// this is explicit synchronization
//on the runnable instance
//inside the synchronized block
// MySynchRunnable2 is totally equivalent to MySynchRunnable1
// usually we never synchronize on this or synchronize the run() method
#Override
public void run(){
synchronized(this){
try {Thread.sleep(1000);} catch (InterruptedException e) {}
}
}
}