I have an object which can be serialized to JSON using Jackson. I want to add this object to a JSONObject and have the content serialized
JSONObject msg = new JSONObject();
put("something", "value");
put("myThing", myThing);
mapper.writeValueAsString(msg);
String s = msg.toString();
but the result is
{"something":"value","myThing":"com.example.things"}
I have tried
put("myThing", mapper.valueToTree(myThing))
// and
put("myThing", mapper.writeValueAsString(myThing))
however both of these result in the child object beening escaped
{"something":"value","myThing":"{\"foo\":\"bar\"}"}
How do I get what I really want ...
{"something":"value","myThing":{"foo":"bar"}}
Create an JSONObject for the myThing object.
Like this:
JSONObject obj = new JSONObject();
obj.put("foo", myThing.getFoo());
and add this to the main JSONObject:
JSONObject msg = new JSONObject();
msg.put("something", "value");
msg.put("myThing", obj);
Another method is to use Annotations to mark the fields in a class which should be serialized and then generate the JSON Object via reflection.
I have some classes on Github which you can use.
Example for usage:
public class MyClass {
#JSONElement(name = "foo")
private String field1;
MyClass(String f) {
this.field1 = f;
}
[...]
}
MyClass object = new MyClass("bar");
JSONObject json = JSONMarshaller.marshall(object);
The resulting JSON for this object is:
{"foo":"bar"}
I had managed to mix up org.json and com.fasterxml.jackson.
ObjectNode msg = mapper.createObjectNode();
msg.put("something", "value");
msg.put("myThing", mapper.valueToTree(myThing));
String s = msg.toString();
This now gives the output I was expecting
Related
I am kinda new to Rest assured testing, I have been dealing with diff. json and Api's.
I know how to pass a json object as body for POST request but my code gives error when I try to pass a JSON Array as body for POST request can someone suggest me how to do it.
The code I have been using for json object is
obj = parser.parse(new FileReader("path of json"));
jsonObject = (JSONObject) obj;
String jsonString = jsonObject.toJSONString();
Map<String, String> body = new ObjectMapper().readValue(jsonString, HashMap.class);
response = RestAssuredExtension.PostOpsWithBody(url, body);
This code gives class cast exception at
jsonObject = (JSONObject) obj; when I pass a json array.
Kindly help me with the same
This is the JSON Array
[
{
"findingId": "20177044",
"unsupressAfterDuration": 1669968369043,
"developer": "manan.girdhar#armorcode.io",
"kbIds": [],
"ticketConfigurationId": "3350",
"customFields": []
}
]
Your parser parses the part of JSON and probably returns a JSONArray, but you are casting it to JSONObject. Maybe you want to use something like
obj = parser.parse(new FileReader("path of json"));
if (obj instanceof JSONObject) {
jsonObject = (JSONObject) obj;
String jsonString = jsonObject.toJSONString();
Map<String, String> body = new ObjectMapper().readValue(jsonString, HashMap.class);
response = RestAssuredExtension.PostOpsWithBody(url, body);
} else {
throw new Exception("We do not know how to handle non-objects like " + obj.getClass().getName());
// replace this with list-handling code
}
If you want only one code fragment to handle both objects and lists, cast to JsonStructure.
answering my own question as I found a solution
JSONArray array1 = new JSONArray();
data1.put("findingId", findingIdFinal);
data1.put("unsupressAfterDuration", "1669968369043");
data1.put("developer","manan.girdhar#armorcode.io");
data1.put("kbIds",array1);
data1.put("ticketConfigurationId", jiraId);
data1.put("customFields",array1);
array.put(data1);
String jsonString = array.toString();
List<Map<String, String>> body = new ObjectMapper().readValue(jsonString, List.class);
response = RestAssuredExtension.PostOpsWithBodyWithArray(url, body);
I'm trying to create a JSON Object from a String. The String looks like this: {"case":"getAllProducts"}.
Why is jobj always empty?
String received = textMessage.getText();
System.out.println(received); //{"case":"getAllProducts"} - perfect
JsonObject jobj = new Gson().fromJson(received, JsonObject.class);
System.out.println(jobj); //{} - why empty???
String reqCase = jobj.get("case").getAsString();
I already checked out other articles here where its done exactly like I did. I can't find my problem here..
Instead of
new Gson().fromJson(received, JsonObject.class);
it should be
new Gson().fromJson(received, YourClass.class);
where YourClass is a user defined class having attributes same as the attributes in your JSON.
This is the JSON file I am working with
{"sentiment":
{"document":
{
"label": "positive",
"score": 0.53777
}
}
}
I need to access the value in label and score. using java. How can I do that?
Find below the code I am using right now:
JSONParser parser = new JSONParser();
try
{
Object object = parser
.parse(new FileReader("output_nlu_sentiment.json"));
//convert Object to JSONObject
JSONObject jsonObject = new JSONObject();
JSONObject sentimentobject= new JSONObject();
JSONObject documentobject = new JSONObject();
sentimentobject= (JSONObject) jsonObject.get("sentiment");
documentobject= (JSONObject) sentimentobject.get("document");
String label = (String) documentobject.get("label");
//float score = (float) jsonObject.get("score");
System.out.println(label);
String test = (String) sentimentobject.get("label");
System.out.println(test);
} catch(FileNotFoundException fe)
{
fe.printStackTrace();
}
catch(Exception e)
{
e.printStackTrace();
}
Why is it printing the value as null.
You might want to have a look at JacksonXml for json parsing.
Right now the problem is that you're not using the JsonObject returned by parser.parse(...).
Instead you use the get method on objects you just created. This of course means that you don't getthe valie you want to.
Try to use following code (JSONObject jsonObject = (JSONObject) object instead of JSONObject jsonObject = new JSONObject();), because you didn't use object at all, just create new empty JSONObject.
JSONParser parser = new JSONParser();
try
{
Object object = parser
.parse(new FileReader("output_nlu_sentiment.json"));
//convert Object to JSONObject
JSONObject jsonObject = (JSONObject) object;
JSONObject sentimentobject = (JSONObject) jsonObject.get("sentiment");
JSONObject documentobject= (JSONObject) sentimentobject.get("document");
String label = (String) documentobject.get("label");
System.out.println(label);
float score = (float) documentobject.get("score");
System.out.println(score );
}catch(FileNotFoundException fe)
{
fe.printStackTrace();
}
catch(Exception e)
{
e.printStackTrace();
}
You have to make use of object created in Object object = parser.parse(new FileReader("output_nlu_sentiment.json")); while creating the jsonObject
For that you can look at the code below:
Object object = parser
.parse(new FileReader("file2.json"));
//convert Object to JSONObject
JSONObject jsonObject = (JSONObject) object;
JSONObject sentimentobject= new JSONObject();
JSONObject documentobject = new JSONObject();
sentimentobject= (JSONObject) jsonObject.get("sentiment");
documentobject= (JSONObject) sentimentobject.get("document");
String label = (String) documentobject.get("label");
//float score = (float) jsonObject.get("score");
System.out.println(label);
String test = (String) sentimentobject.get("label");
You will get the positive printed on console.
you should see the content in para 'sentimentobject',force convert into class JSONObject can not get the value you want.
I prefer the FasterXML Jackson support to parse JSON into plain old Java objects (POJOs). These POJOs are often called Data Transfer Objects (DTOs) and give you a way to turn your JSON fields into properly typed members of the corresponding DTO.
Here is an example method to do that. The ObjectMapper(s) are generally maintained as statics somewhere else because FasterXML's implementation caches information to improve efficiency of object mapping operations.
static final ObjectMapper mapper = new ObjectMapper();
This is the JSON deserialization method:
public static <T> T deserializeJSON(
final ObjectMapper mapper, final InputStream json,
final Class<T> clazz)
throws JsonParseException, UnrecognizedPropertyException,
JsonMappingException, IOException
{
final String sourceMethod = "deserializeJSON";
logger.entering(sourceClass, sourceMethod);
/*
* Use Jackson support to map the JSON into a POJO for us to process.
*/
T pojoClazz;
pojoClazz = mapper.readValue(json, clazz);
logger.exiting(sourceClass, sourceMethod);
return pojoClazz;
}
Assuming I have a class called FooDTO, which has the appropriate Jackson annotations/getters/setters (note you must always provide a default empty public constructor), you can do this:
FooDTO foo = deserializeJSON(mapper, inputstream, FooDTO.class);
The deserialization throws a few different exceptions (all of which have IOException as their parent class) that you will need to handle or throw back to the caller.
Here besides of the correction alreay addressed in comments and other answers, I include some other changes you can benefit of:
It is not necessary to initialize the JSONObjects with a new instance that is going to be ovewritten in the next line.
You can use getJSONObject(), getString(), getFloat() instead of get(), in this way you don't need to cast the result.
public void parseJson() {
JSONParser parser = new JSONParser();
try
{
JSONObject jsonObject = new JSONParser().parse(new FileReader("output_nlu_sentiment.json"));
JSONObject sentimentobject= null;
JSONObject documentobject = null;
sentimentobject= jsonObject.getJSONObject("sentiment");
documentobject= sentimentobject.getJSONObject("document");
String label = documentobject.getString("label");
float score = documentobject.getFloat("score");
String output = String.format("Label: %s Score: %f", label, score);
System.out.println(output);
}catch(FileNotFoundException fe){
fe.printStackTrace();
}catch(Exception e){
e.printStackTrace();
}
}
Also for this kind of objects, where the attribute names could act as object properties, I suggest you take a look at Gson library. After modeling the json as a composition of POJOs, the parsing takes 1 line of code.
I have weird problem with gson (my gson version is 2.3.1)
I have JsonObject instance called jsonObject (JsonObject jsonObject)
jsonObject has value, not empty
And I create another one, JsonObject tempOject = jsonObject;
So, when I try to remove element inside tempObject, lets say,
tempObject.remove("children");
Then that code affected the jsonObject instance.
Here is the code snippet :
jsonObject = element.getAsJsonObject();
JsonElement tempElement = element;
JsonObject tempObject = jsonObject;
String tempJson;
if(tempObject.has("children")){
tempObject.remove("children");
tempJson = tempObject.toString();
tempElement = new JsonParser().parse(tempJson);
}
if(nodes.isEmpty()){
elements = new ArrayList<>();
nodes.put(iterator, elements);
}
if(!nodes.containsKey(iterator)){
elements = new ArrayList<>();
nodes.put(iterator, elements);
}
nodes.get(iterator).add(tempElement);
if (jsonObject.has("children")){
tempNextJson = jsonObject.get("children").toString();
tempCurrJson = jsonObject.toString();
tempIterator++;
metaDataProcessor(tempNextJson, tempCurrJson, tempNextJson, tempIterator, maxLevel);
}
I have read the gson JsonObject class, it use deep copy method. That was not supposed to affected the reference since JsonObject using deep value copy, so the returned JsonObject object is the new one.
But why this is happened?
Anyway...there is deepCopy method inside JsonObject class
JsonObject deepCopy() {
JsonObject result = new JsonObject();
Iterator i$ = this.members.entrySet().iterator();
while(i$.hasNext()) {
Entry entry = (Entry)i$.next();
result.add((String)entry.getKey(), ((JsonElement)entry.getValue()).deepCopy());
}
return result;
}
But thats an abstract method from JsonElement class which implemented on JsonObject, and the attribute not set as public, so I cannot call that method. But I guess that method supposedly called directly when I do instance copy.
How about that?
Thanks in advance
This can be used to copy any object of any type!
just have to use Gson.
public <T> T deepCopy(T object, Class<T> type) {
try {
Gson gson = new Gson();
return gson.fromJson(gson.toJson(object, type), type);
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
in your case you can call it like:
JsonObject jsonObject = deepCopy(oldJsonObject, JsonObject.class);
Starting from version 2.8.2, deepCopy() in Gson JsonElement is public, so you can now use it to make a deep copy of your JSON object.
Setting tempObject = jsonObject will not create a second object for you. All that does is create another reference to your original jsonObject.
What you want to do is something like:
JSONObject tempObject = new JSONObject(jsonObject.toString());
tempObject.remove("children");
This will create a new JsonObject which is a copy of the original json you had.
If you can only use the GSON libraries, there is the JsonObject.deepyCopy() method. Which was added in r855: https://code.google.com/p/google-gson/source/detail?r=855
Using the deepCopy() method it would be
JsonObject tempObject = jsonObject.deepCopy();
tempObject.remove("children");
Looks like Gson developers decided not to expose deepCopy(). You could serialize your JsonElement this into a string and back, however, I think it's far more efficient to implement deep cloning outside of JsonObject instead. Here's my solution to this:
#Nonnull
public static JsonObject deepCopy(#Nonnull JsonObject jsonObject) {
JsonObject result = new JsonObject();
for (Map.Entry<String, JsonElement> entry : jsonObject.entrySet()) {
result.add(entry.getKey(), deepCopy(entry.getValue()));
}
return result;
}
#Nonnull
public static JsonArray deepCopy(#Nonnull JsonArray jsonArray) {
JsonArray result = new JsonArray();
for (JsonElement e : jsonArray) {
result.add(deepCopy(e));
}
return result;
}
#Nonnull
public static JsonElement deepCopy(#Nonnull JsonElement jsonElement) {
if (jsonElement.isJsonPrimitive() || jsonElement.isJsonNull()) {
return jsonElement; // these are immutables anyway
} else if (jsonElement.isJsonObject()) {
return deepCopy(jsonElement.getAsJsonObject());
} else if (jsonElement.isJsonArray()) {
return deepCopy(jsonElement.getAsJsonArray());
} else {
throw new UnsupportedOperationException("Unsupported element: " + jsonElement);
}
}
I have found the simplest solution for this. Since the deepCopy() method from JsonObject seems didn't work, then I just to make some transformation from JsonObject value to string and then transform to JsonElement with JsonParser().
Then make some new JsonObject from our new JsonObject. It seems more simple instead of create some helper method which is needs to reimplement the deepCopy. If we reimplement the iteration must considered how deep the JsonObject is. Since JsonObject is hashmap (LinkedTreeMap), and the value is JsonElement, so it need to parse recursively through JsonElement.
Here is my json Object.
{"id":"mrbbt6f3fa99gld0m6n52osge0",
"name_value_list":
{"user_default_dateformat":{"name":"user_default_dateformat","value":"m/d/Y"}},
"module_name":"Users"}
I got id,and module_name through following code.How can i get user_default_dateformat?.
I know it may so simple but I am a newbie in json.
String jsonResponse;
while ((jsonResponse = br.readLine()) != null) {
jsonOutput = jsonResponse;
}
JSONObject job = new JSONObject(jsonOutput);
System.out.println(job);// i can see the same json object
that i showen above.
sessionID = job.get("id").toString();
Exception generating coge
JSONObject job2=new JSONObject(job);
dateFormat = job2.get("user_default_dateformat").toString();
The Eexception is
org.json.JSONException: JSONObject["user_default_dateformat"] not found.
Thanks,
name_value_list is also an Object.
JSONObject job2 = new JSONObject(job.get("name_value_list"));
So there you get
job2.get("user_default_dateformat");
Every {} in your JSON is an object. So for every String you get which is something like {"xy":"za","ab":"cd"} you have to cast it to the JSONObject
Edit for your error:
As you can see in your code the line:
JSONObject job2=new JSONObject(job);
will try to generate a JSONObject out of your JSONObject.
You have to get the JSONObject in your JSONObject.
You want to get the user_default_dateformat which is in your JSONObject:
String name_value_list_string = job.get("name_value_list").toString();
//this string is another json-string which contains the user_default_dateformat
JSONObject name_value_list_object = new JSONObject(name_value_list_string);
//This JSONObject contains the user_default_dateformat but this is also a JSONObject
String user_default_dateformat_string = name_value_list_object.get("user_default_dateformat").toString();
//this String contains the user_default_dateformat JSONString
JSONObject user_default_dateformat_object = new JSONObject(user_default_dateformat_string);
//This JSONObject contains the String values of your user_default_dateformat
if you are using JSONSimple library you can use this:
jsonObject = (JSONObject) new JSONParser().parse(jsonstr);
System.out.println((JSONObject)jsonObject.get("name_value_list"))).get("user_default_dateformat"));
This should give you the required result.