I am facing an issue when I convert my string to date format.
This is what I have tried -
First try:
String completionDate1 = request.getParameter("completion_date");
System.out.println(completionDate1); // O/P --> 21/10/2016 (Correct)
DateFormat df = new SimpleDateFormat("yyyy/MM/dd");
Date date = new Date();
date = df.parse(completionDate1);
System.out.println(date); // O/P --> Tue Apr 08 00:00:00 IST 27 (Inorrect)
Second try:
String completionDate1 = request.getParameter("completion_date");
System.out.println(completionDate1); // O/P --> 21/10/2016 (Correct)
Date completionDate = new SimpleDateFormat("yyyy/MM/dd").parse(completionDate1);
System.out.println(completionDate); // O/P --> Tue Apr 08 00:00:00 IST 27 (Inorrect)
The output I'm expecting is that, the completionDate should be Date format not String. I'm just printing the completionDate just to make sure the date format is getting getting converted.
The main intention of getting it in date format is I need this for an Update query so it has to be Date and not String.
Kindly let me know where I'm going wrong. I need this date format as I need to store this date in a database.
Thanks
You have to format the date after parsing it but your parsing format is also incorrect so its giving wrong output. Try
String completionDate1 = "21/10/2016";
System.out.println(completionDate1);
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
Date date = new Date();
date = df.parse(completionDate1);
DateFormat df1 = new SimpleDateFormat("yyyy/MM/dd");
System.out.println(df1.format(date));
DEMO
Wrong pattern
First problem is that your defined parsing pattern does not match your input string. For 21/10/2016 pattern should be dd/MM/yyyy.
java.sql.Date versus java.util.Date
Second problem is that for database access you should be using the java.sql.Date class for a date-only value without time-of-day and without time zone. Not to be confused with java.util.Date which is a date and time-of-day value. You should specify the fully-qualified class name in such discussions as this Question.
Neither of these classes have a “format”. They have their own internal representation, a count from epoch.
java.time
Third problem is that you are using old outdated classes. In Java 8 and later, use java.time framework now built-in. In Java 6 & 7, use its back-port, the ThreeTen-Backport project. For Android, use the adaptation of that back-port, ThreeTenABP.
In the java.time classes we now have the LocalDate class for date-only values.
String input = "21/10/2016"
DateTimeFormatter formatter = DateTimeFormatter.ofPattern( "dd/MM/yyyy" );
LocalDate localDate = LocalDate.parse( input , formatter );
Hopefully some day JDBC drivers will be updated to directly use the java.time types. Until then, use the new methods added to the old java.sql types to convert.
java.sql.Date sqlDate = java.sql.Date.valueOf( localDate );
Now pass that java.sql.Date object to the setDate method on a PreparedStatement object for transmission to a database.
Note that at no time did we make use of any more strings. We went from original input String to java.time.Date to java.sql.Date.
At no point did we use java.util.Date. Check your import statements to eliminate java.util.Date.
By the way, to go the other direction from java.sql.Date to LocalDate:
LocalDate localDate = mySqlDate.toLocalDate();
Use below code
String completionDate1 = request.getParameter("completion_date");
System.out.println(completionDate1); // O/P --> 21/10/2016 (Correct)
Date completionDate = new SimpleDateFormat("dd/MM/yyyy").parse(completionDate1);
String date = new SimpleDateFormat("yyyy/MM/dd").format(completionDate);
System.out.println(date);
You can try this
DateFormat df = new SimpleDateFormat("yyyy/mm/dd");
String completionDate = df.format(request.getParameter("completion_date"));
System.out.println(completionDate);
I'm new in OFBiz, and Java. I used bellow block of code for checking date time input and use that for searching in table.
Timestamp strtDate = UtilDateTime.getTimestamp((String)request.getParameter("strt_date"));
if(strtDate != null)
{
// then here i used the date for taking data.
}
When i fill the date time field of form to search or when no date is selected for searching error occure that show numberFormatException, so how i can solve that? thanks for any help and guide.
Based on the Apache ofbiz API it looks like UtilDateTime#getTimestamp(String) expects milliseconds value. You are passing in "2014-01-12 05-44-56". You need to parse your date first. With pure pre 1.8 java (keep in mind that formatters aren't thread safe):
String dateString = "2014-01-12 05-44-56";
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH-mm-ss");
Date date = formatter.parse(dateString);
UtilDateTime.getTimestamp(date.getTime());
Since java 1.8 (highly recommended to switch if you can!):
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH-mm-ss");
ZonedDateTime date = ZonedDateTime.parse(text, formatter);
long millis = date.toInstant().toEpochMilli();
you have to pass time in milliseconds not as you are passing.
you can check code also :
public static Timestamp getTimestamp(String milliSecs) throws NumberFormatException {
return new Timestamp(Long.parseLong(milliSecs));
}
it will parse the data in long which you are passing and that should be valid long value.
request.getParameter("strt_date") will anyways return String, so no need to cast it explicitly to String. Moreover, there will be a contract between Client & Server on the required Date Format. So you have to parse the String-Date in the same format using SimpleDateFormat. Code outlook will look like bellow:
SimpleDateFormat formatter = new SimpleDateFormat("contract-date-format");
Date date = formatter.parse(request.getParameter("strt_date"));
UtilDateTime.getTimestamp(date.getTime());
I want to remove time from Date object.
DateFormat df;
String date;
df = new SimpleDateFormat("dd/MM/yyyy");
d = eventList.get(0).getStartDate(); // I'm getting the date using this method
date = df.format(d); // Converting date in "dd/MM/yyyy" format
But when I'm converting this date (which is in String format) it is appending time also.
I don't want time at all. What I want is simply "21/03/2012".
You can remove the time part from java.util.Date by setting the hour, minute, second and millisecond values to zero.
import java.util.Calendar;
import java.util.Date;
public class DateUtil {
public static Date removeTime(Date date) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
cal.set(Calendar.HOUR_OF_DAY, 0);
cal.set(Calendar.MINUTE, 0);
cal.set(Calendar.SECOND, 0);
cal.set(Calendar.MILLISECOND, 0);
return cal.getTime();
}
}
The quick answer is :
No, you are not allowed to do that. Because that is what Date use for.
From javadoc of Date :
The class Date represents a specific instant in time, with millisecond precision.
However, since this class is simply a data object. It dose not care about how we describe it.
When we see a date 2012/01/01 12:05:10.321, we can say it is 2012/01/01, this is what you need.
There are many ways to do this.
Example 1 : by manipulating string
Input string : 2012/01/20 12:05:10.321
Desired output string : 2012/01/20
Since the yyyy/MM/dd are exactly what we need, we can simply manipulate the string to get the result.
String input = "2012/01/20 12:05:10.321";
String output = input.substring(0, 10); // Output : 2012/01/20
Example 2 : by SimpleDateFormat
Input string : 2012/01/20 12:05:10.321
Desired output string : 01/20/2012
In this case we want a different format.
String input = "2012/01/20 12:05:10.321";
DateFormat inputFormatter = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss.SSS");
Date date = inputFormatter.parse(input);
DateFormat outputFormatter = new SimpleDateFormat("MM/dd/yyyy");
String output = outputFormatter.format(date); // Output : 01/20/2012
For usage of SimpleDateFormat, check SimpleDateFormat JavaDoc.
Apache Commons DateUtils has a "truncate" method that I just used to do this and I think it will meet your needs. It's really easy to use:
DateUtils.truncate(dateYouWantToTruncate, Calendar.DAY_OF_MONTH);
DateUtils also has a host of other cool utilities like "isSameDay()" and the like. Check it out it! It might make things easier for you.
What about this:
Date today = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
today = sdf.parse(sdf.format(today));
What you want is impossible.
A Date object represents an "absolute" moment in time. You cannot "remove the time part" from it. When you print a Date object directly with System.out.println(date), it will always be formatted in a default format that includes the time. There is nothing you can do to change that.
Instead of somehow trying to use class Date for something that it was not designed for, you should look for another solution. For example, use SimpleDateFormat to format the date in whatever format you want.
The Java date and calendar APIs are unfortunately not the most well-designed classes of the standard Java API. There's a library called Joda-Time which has a much better and more powerful API.
Joda-Time has a number of special classes to support dates, times, periods, durations, etc. If you want to work with just a date without a time, then Joda-Time's LocalDate class would be what you'd use.
edit - note that my answer above is now more than 10 years old. If you are using a current version of Java (Java 8 or newer), then prefer to use the new standard date and time classes in package java.time. There are many classes available that represent just a date (day, month, year); a date and time; just a time; etc.
Date dateWithoutTime =
new Date(myDate.getYear(),myDate.getMonth(),myDate.getDate())
This is deprecated, but the fastest way to do it.
May be the below code may help people who are looking for zeroHour of the day :
Date todayDate = new Date();
GregorianCalendar todayDate_G = new GregorianCalendar();
gcd.setTime(currentDate);
int _Day = todayDate_GC.get(GregorianCalendar.DAY_OF_MONTH);
int _Month = todayDate_GC.get(GregorianCalendar.MONTH);
int _Year = todayDate_GC.get(GregorianCalendar.YEAR);
GregorianCalendar newDate = new GregorianCalendar(_Year,_Month,_Day,0,0,0);
zeroHourDate = newDate.getTime();
long zeroHourDateTime = newDate.getTimeInMillis();
Hope this will be helpful.
you could try something like this:
import java.text.*;
import java.util.*;
public class DtTime {
public static void main(String args[]) {
String s;
Format formatter;
Date date = new Date();
formatter = new SimpleDateFormat("dd/MM/yyyy");
s = formatter.format(date);
System.out.println(s);
}
}
This will give you output as21/03/2012
Or you could try this if you want the output as 21 Mar, 2012
import java.text.*;
import java.util.*;
public class DtTime {
public static void main(String args[]) {
Date date=new Date();
String df=DateFormat.getDateInstance().format(date);
System.out.println(df);
}
}
You can write that for example:
private Date TruncarFecha(Date fechaParametro) throws ParseException {
String fecha="";
DateFormat outputFormatter = new SimpleDateFormat("MM/dd/yyyy");
fecha =outputFormatter.format(fechaParametro);
return outputFormatter.parse(fecha);
}
The correct class to use for a date without time of day is LocalDate. LocalDate is a part of java.time, the modern Java date and time API.
So the best thing you can do is if you can modify the getStartDate method you are using to return a LocalDate:
DateTimeFormatter dateFormatter = DateTimeFormatter
.ofLocalizedDate(FormatStyle.SHORT)
.withLocale(Locale.forLanguageTag("en-IE"));
LocalDate d = eventList.get(0).getStartDate(); // We’re now getting a LocalDate using this method
String dateString = d.format(dateFormatter);
System.out.println(dateString);
Example output:
21/03/2012
If you cannot change the getStartDate, you may still be able to add a new method returning the type that we want. However, if you cannot afford to do that just now, convert the old-fashioned Date that you get (I assume java.util.Date):
d = eventList.get(0).getStartDate(); // I'm getting the old-fashioned Date using this method
LocalDate dateWithoutTime = d.toInstant()
.atZone(ZoneId.of("Asia/Kolkata"))
.toLocalDate();
Please insert the time zone that was assumed for the Date. You may use ZoneId.systemDefault() for the JVM’s time zone setting, only this setting can be changed at any time from other parts of your program or other programs running in the same JVM.
The java.util.Date class was what we were all using when this question was asked 6 years ago (no, not all; I was, and we were many). java.time came out a couple of years later and has replaced the old Date, Calendar, SimpleDateFormat and DateFormat. Recognizing that they were poorly designed. Furthermore, a Date despite its name cannot represent a date. It’s a point in time. What the other answers do is they round down the time to the start of the day (“midnight”) in the JVM’s default time zone. It doesn’t remove the time of day, only sets it, typically to 00:00. Change your default time zone — as I said, even another program running in the same JVM may do that at any time without notice — and everything will break (often).
Link: Oracle tutorial: Date Time explaining how to use java.time.
A bit of a fudge but you could use java.sql.Date. This only stored the date part and zero based time (midnight)
Calendar c = Calendar.getInstance();
c.set(Calendar.YEAR, 2011);
c.set(Calendar.MONTH, 11);
c.set(Calendar.DATE, 5);
java.sql.Date d = new java.sql.Date(c.getTimeInMillis());
System.out.println("date is " + d);
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
System.out.println("formatted date is " + df.format(d));
gives
date is 2011-12-05
formatted date is 05/12/2011
Or it might be worth creating your own date object which just contains dates and not times. This could wrap java.util.Date and ignore the time parts of it.
java.util.Date represents a date/time down to milliseconds. You don't have an option but to include a time with it. You could try zeroing out the time, but then timezones and daylight savings will come into play--and that can screw things up down the line (e.g. 21/03/2012 0:00 GMT is 20/03/2012 PDT).
What you might want is a java.sql.Date to represent only the date portion (though internally it still uses ms).
String substring(int startIndex, int endIndex)
In other words you know your string will be 10 characers long so you would do:
FinalDate = date.substring(0,9);
Another way to work out here is to use java.sql.Date as sql Date doesn't have time associated with it, whereas java.util.Date always have a timestamp.
Whats catching point here is java.sql.Date extends java.util.Date, therefore java.util.Date variable can be a reference to java.sql.Date(without time) and to java.util.Date of course(with timestamp).
In addtition to what #jseals has already said. I think the org.apache.commons.lang.time.DateUtils class is probably what you should be looking at.
It's method : truncate(Date date,int field) worked very well for me.
JavaDocs : https://commons.apache.org/proper/commons-lang/javadocs/api-2.6/org/apache/commons/lang/time/DateUtils.html#truncate(java.util.Date, int)
Since you needed to truncate all the time fields you can use :
DateUtils.truncate(new Date(),Calendar.DAY_OF_MONTH)
If you are using Java 8+, use java.time.LocalDate type instead.
LocalDate now = LocalDate.now();
System.out.println(now.toString());
The output:
2019-05-30
https://docs.oracle.com/javase/8/docs/api/java/time/LocalDate.html
You can also manually change the time part of date and format in "dd/mm/yyyy" pattern according to your requirement.
public static Date getZeroTimeDate(Date changeDate){
Date returnDate=new Date(changeDate.getTime()-(24*60*60*1000));
return returnDate;
}
If the return value is not working then check for the context parameter in web.xml.
eg.
<context-param>
<param-name>javax.faces.DATETIMECONVERTER_DEFAULT_TIMEZONE_IS_SYSTEM_TIMEZONE</param-name>
<param-value>true</param-value>
</context-param>
Don't try to make it hard just follow a simple way
date is a string where your date is saved
String s2=date.substring(0,date.length()-11);
now print the value of s2.
it will reduce your string length and you will get only date part.
Can't believe no one offered this shitty answer with all the rest of them. It's been deprecated for decades.
#SuppressWarnings("deprecation")
...
Date hitDate = new Date();
hitDate.setHours(0);
hitDate.setMinutes(0);
hitDate.setSeconds(0);
I want to convert the timestamp 2011-03-10T11:54:30.207Z to 10/03/2011 11:54:30.207. How can I do this? I want to convert ISO8601 format to UTC and then that UTC should be location aware. Please help
String str_date="2011-03-10T11:54:30.207Z";
DateFormat formatter ;
Date date ;
formatter = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss.SSS");
date = (Date)formatter.parse(str_date);
System.out.println("output: " +date );
Exception :java.text.ParseException: Unparseable date: "2011-03-10T11:54:30.207Z"
Firstly, you need to be aware that UTC isn't a format, it's a time zone, effectively. So "converting from ISO8601 to UTC" doesn't really make sense as a concept.
However, here's a sample program using Joda Time which parses the text into a DateTime and then formats it. I've guessed at a format you may want to use - you haven't really provided enough information about what you're trying to do to say more than that. You may also want to consider time zones... do you want to display the local time at the specified instant? If so, you'll need to work out the user's time zone and convert appropriately.
import org.joda.time.*;
import org.joda.time.format.*;
public class Test {
public static void main(String[] args) {
String text = "2011-03-10T11:54:30.207Z";
DateTimeFormatter parser = ISODateTimeFormat.dateTime();
DateTime dt = parser.parseDateTime(text);
DateTimeFormatter formatter = DateTimeFormat.mediumDateTime();
System.out.println(formatter.print(dt));
}
}
Yes. you can use SimpleDateFormat like this.
SimpleDateFormat formatter, FORMATTER;
formatter = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
String oldDate = "2011-03-10T11:54:30.207Z";
Date date = formatter.parse(oldDate.substring(0, 24));
FORMATTER = new SimpleDateFormat("dd-MMM-yyyy HH:mm:ss.SSS");
System.out.println("OldDate-->"+oldDate);
System.out.println("NewDate-->"+FORMATTER.format(date));
Output
OldDate-->2011-03-10T11:54:30.207Z
NewDate-->10-Mar-2011 11:54:30.207
Enter the original date into a Date object and then print out the result with a DateFormat. You may have to split up the string into smaller pieces to create the initial Date object, if the automatic parse method does not accept your format.
Pseudocode:
Date inputDate = convertYourInputIntoADateInWhateverWayYouPrefer(inputString);
DateFormat outputFormat = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss.SSS");
String outputString = outputFormat.format(inputDate);
You might want to have a look at joda time, which is a little easier to use than the java native date tools, and provides many common date patterns pre-built.
In response to comments, more detail:
To do this using Joda time, you need two DateTimeFormatters - one for your input format to parse your input and one for your output format to print your output. Your input format is an ISO standard format, so Joda time's ISODateTimeFormat class has a static method with a parser for it already: dateHourMinuteSecondMillis. Your output format isn't one they have a pre-built formatter for, so you'll have to make one yourself using DateTimeFormat. I think DateTimeFormat.forPattern("mm/dd/yyyy kk:mm:ss.SSS"); should do the trick. Once you have your two formatters, call the parseDateTime() method on the input format and the print method on the output format to get your result, as a string.
Putting it together should look something like this (warning, untested):
DateTimeFormatter input = ISODateTimeFormat.dateHourMinuteSecondMillis();
DateTimeFormatter output = DateTimeFormat.forPattern("mm/dd/yyyy kk:mm:ss.SSS");
String outputFormat = output.print( input.parseDate(inputFormat) );
Hope this Helps:
public String getSystemTimeInBelowFormat() {
String timestamp = new SimpleDateFormat("yyyy-mm-dd 'T' HH:MM:SS.mmm-HH:SS").format(new Date());
return timestamp;
}
Use DateFormat. (Sorry, but the brevity of the question does not warrant a longer or more detailed answer.)
How can I format the "2010-07-14 09:00:02" date string to depict just "9:00"?
Use DateTimeFormatter to convert between a date string and a real LocalDateTime object. with a LocalDateTime as starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the DateTimeFormatter.
String originalString = "2010-07-14 09:00:02";
LocalDateTime dateTime = LocalDateTime.parse(originalString, DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss"));
String newString = DateTimeFormatter.ofPattern("H:mm").format(dateTime); // 9:00
In case you're not on Java 8 or newer yet, use SimpleDateFormat to convert between a date string and a real Date object. with a Date as starting point, you can easily apply formatting based on various patterns as definied in the javadoc of the SimpleDateFormat.
String originalString = "2010-07-14 09:00:02";
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(originalString);
String newString = new SimpleDateFormat("H:mm").format(date); // 9:00
Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse("2010-07-14 09:00:02");
String time = new SimpleDateFormat("H:mm").format(date);
http://download.oracle.com/javase/1.4.2/docs/api/java/text/SimpleDateFormat.html
A very simple way is to use Formatter (see date time conversions) or more directly String.format as in
String.format("%tR", new Date())
The other answers were good answers when the question was asked. Time moves on, Date and SimpleDateFormat get replaced by newer and better classes and go out of use. In 2017, use the classes in the java.time package:
String timeString = LocalDateTime.parse(dateString, DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss"))
.format(DateTimeFormatter.ofPattern("H:mm"));
The result is the desired, 9:00.
I'm assuming your first string is an actual Date object, please correct me if I'm wrong. If so, use the SimpleDateFormat object: http://download.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html. The format string "h:mm" should take care of it.
If you have date in integers, you could use like here:
Date date = new Date();
date.setYear(2010);
date.setMonth(07);
date.setDate(14)
date.setHours(9);
date.setMinutes(0);
date.setSeconds(0);
String time = new SimpleDateFormat("HH:mm:ss").format(date);
let datestring = "2017-02-14 02:16:28"
let formatter = DateFormatter()
formatter.dateStyle = DateFormatter.Style.full
formatter.timeStyle = DateFormatter.Style.full
formatter.dateFormat = "yyyy-MM-dd hh:mm:ss"
let date = formatter.date(from: datestring)
let date2 = formatter.String(from: date)