I'm trying to use google guava cache in my spring app, but result is never caching.
This are my steps:
in conf file:
#EnableCaching
#Configuration
public class myConfiguration {
#Bean(name = "CacheManager")
public CacheManager cacheManager() {
return new GuavaCacheManager("MyCache");
}
}
In class I want to use caching:
public class MyClass extends MyBaseClass {
#Cacheable(value = "MyCache")
public Integer get(String key) {
System.out.println("cache not working");
return 1;
}
}
Then when I'm calling:
MyClass m = new MyClass();
m.get("testKey");
m.get("testKey");
m.get("testKey");
It's entering function each time and not using cache:
console:
cache not working
cache not working
cache not working
Does someone have an idea what am I missing or how can I debug that?
You should not manage a spring bean by yourself. Let spring to manage it.
#EnableCaching
#Configuration
public class myConfiguration {
#Bean(name = "CacheManager")
public CacheManager cacheManager() {
return new GuavaCacheManager("MyCache");
}
#Bean
public MyClass myClass(){
return new MyClass();
}
}
After that you should use MyClass in a managed manner.
public static void main(String[] args) throws Exception {
final ApplicationContext applicationContext = new AnnotationConfigApplicationContext(myConfiguration.class);
final MyClass myclass = applicationContext.getBean("myClass");
myclass.get("testKey");
myclass.get("testKey");
myclass.get("testKey");
}
Related
Assuming you have the following spring configuration:
#Configuration
public class Config {
#Bean
public SomeBean someBean() {
SomeBean someBean = new SomeBean();
someBean.setVar("foobar");
return someBean;
}
}
Then I can use this configuration in some other class for example by importing it with #Import(Config.class). Now, say you don't want to hardcode the string "foobar" but pass it as a parameter to that configuration. How would I do that? It would be nice to create a custom annotation like #FooBarConfiguration(var = "foobar"). Is that possible?
The #Ben answer is the classic and better approach. But if you don't want to use a property file, you can use a #Bean for that. Each #Bean holds a value that you would like to inject.
Full code example:
#SpringBootApplication
public class So49053082Application implements CommandLineRunner {
#Bean
String beanValueFooBar() {
return "fooBar";
}
#Bean
String beanValueBarFoo() {
return "barFoo";
}
private class SomeBean {
private String var;
public void setVar(final String var) {
this.var = var;
}
}
#Configuration
public class Config {
#Bean
public SomeBean someBean(String beanValueBarFoo) {
SomeBean someBean = new SomeBean();
System.out.println(beanValueBarFoo);
someBean.setVar(beanValueBarFoo);
return someBean;
}
}
#Override
public void run(String... args) {
}
public static void main(String[] args) {
ConfigurableApplicationContext context = SpringApplication.run(So49053082Application.class, args);
context.close();
}
}
Consider using the #Value annotation:
#Configuration
public class Config {
#Value("${myParamValue}")
public String myParam;
#Bean
public SomeBean someBean() {
SomeBean someBean = new SomeBean();
someBean.setVar(myParam);
return someBean;
}
}
you'll need to put the parameters into the environment somehow: there are various techniques using the OS environment, runtime parameters or configuration files, as suits your purposes.
I would like to read some properties, like DB access configs, when initializing bean or service in spring boot.
Anyone knows good ways ?
This is my current code snippet.
public class SampleApplication implements ApplicationRunner
{
#Autowired
private YAMLConfig myConfig;
#Override
public void run(ApplicationArguments args) throws Exception
{
System.out.println(myConfig != null); //YAMLConfig has been intialized here
}
public SampleApplication()
{
System.out.println(myConfig == null); //myConfig is null
}
#Configuration
public static class Config
{
#Bean
#ConditionalOnProperty(value = {"batch.execute"}, havingValue = "SampleApplication")
public SampleApplication sampleApplication()
{
return new SampleApplication();
}
}
}
#Configuration
#EnableConfigurationProperties
#ConfigurationProperties
public class YAMLConfig
{
private String environment;
public String getEnvironment()
{
return environment;
}
public void setEnvironment(String environment)
{
this.environment = environment;
}
}
Thanks for taking a look at this!
create this method inside your SampleApplication class
#PostConstruct
public void init() {
// at this point, all the dependency injection has happened already
myConfig.doStuff()
}
it will be called by spring automatically after all bean initialization has been done.
I'm using the latest version of spring and using the caching concept. My (rest) service class seems to not be injected with the caching annotation. If I remove them it works perfectly however I don't use cache which is not what I want.
Application:
#SpringBootApplication
#EnableCaching
public class MyApplication{
public static void main(String[] args) {
SpringApplication.run(MyApplication.class, args);
}
#Bean
public CacheManager cacheManager() {
SimpleCacheManager cacheManager = new SimpleCacheManager();
cacheManager.setCaches(Arrays.asList(new ConcurrentMapCache("MyCache")));
return cacheManager;
}
The service:
#CacheConfig(cacheNames = "MyCache")
#Service
public class MyServiceImpl implements MyService {
private final Logger logger = LoggerFactory.getLogger(this.getClass());
private final String errormessage = "Error getting books";
#Autowired
private UserRepositoryCrud userRepository;
public MyServiceImpl () {
}
#Override
#Cacheable(value = "MyCache", key = "#description", unless = "#result?.size() > 0")
public final List<Books> getBooks(String description) {
logger.debug("Starting getBooksService");
//service implementation ...
(I also have a Restcontroler that only call this service)
When calling this method getBooks, I got a nullpointer on the logger, but when debugging I realize that everything is null, even the errormessage string...
If I remove the #Cacheable annotation, it then works but I do not have the cache working which is not what I want.
Do you know what can be wrong ?
Thanks a lot,
Guys I found the issue... because the method was final!!! I spent a lot of time to find this!
I use #EntityListeners to make operations before I save in my Db and after I load.
Inside my Listener class I make a call to an Ecryptor (which needs to fetch info from configuration file), so the encryptor can't be called statically and need to be injected in my Listener. Right?
Well, injections in EntityListeners can't be done straight away, but you have some methods to do that, like using SpringBeanAutowiringSupport.processInjectionBasedOnCurrentContext(this); or even the method showed here. https://guylabs.ch/2014/02/22/autowiring-pring-beans-in-hibernate-jpa-entity-listeners/
Cool, the problem is: None of the solutions support unit testing! When running tests that encryptor I had injected in my model Listener is always null.
Here SpringBeanAutowiringSupport does not inject beans in jUnit tests There is a solution to create this context and pass to a instantiated object, but it does not solve my problem since I have the "Injection" to add to it.
Any way to create a context in my tests and somehow pass it to my listeners?
If not, any way I can create a static method to my Encryptor and still have access to the Environment API to read my properties?
Package Listener:
public class PackageListener{
#Autowired
Encryptor encryptor;
#PrePersist
public void preSave(final Package pack){
pack.setBic(encryptor.encrypt(pack.getBic()));
}
...
My test
#Test
#WithuserElectronics
public void testIfCanGetPackageById() throws PackageNotFoundException{
Package pack = packagesServiceFactory.getPackageService().getPackage(4000000002L);
}
Package service
public Package getPackage(Long id) throws PackageNotFoundException{
Package pack = packageDao.find(id);
if (pack == null) {
throw new PackageNotFoundException(id);
}
return pack;
}
Encryptor:
public class Encryptor{
private String salt;
public Encryptor(String salt){
this.salt = salt;
}
public String encrypt(String string){
String key = this.md5(salt);
String iv = this.md5(this.md5(salt));
if (string != null) {
return encryptWithAesCBC(string, key, iv);
}
return string;
}
...
You can create a DemoApplicationContextInitializer class to store the appliationContext reference in a static property in your main class.
public class DemoApplicationContextInitializer implements
ApplicationContextInitializer<ConfigurableApplicationContext> {
#Override
public void initialize(ConfigurableApplicationContext ac) {
Application.context = ac;
}
}
#SpringBootApplication
public class Application {
public static ApplicationContext context;
public static void main(String[] args) throws Exception {
new SpringApplicationBuilder(Application.class)
.initializers(new DemoApplicationContextInitializer())
.run(args);
}
}
Then you can access the context in your entity listener
public class PackageListener{
//#Autowired
Encryptor encryptor;
#PrePersist
public void preSave(final Package pack){
encryptor = Application.context.getBean(Encryptor.class);
pack.setBic(encryptor.encrypt(pack.getBic()));
}
}
And to make this work in your junit test, just add the initializer in your test like this ...
#RunWith(SpringRunner.class)
#SpringBootTest(webEnvironment=WebEnvironment.RANDOM_PORT, classes = Application.class)
#ContextConfiguration(classes = Application.class, initializers = DemoApplicationContextInitializer.class)
public class MyTest {
...
}
It works without any issue in my environment. Hope it will be helpful to you too.
To answer what you need, you have to create 2 classes that will do all the configuration needed.
You have to create a testConfig with the next annotations:
#Configuration
#ComponentScan(basePackages = { "yourPath.services.*",
"yourPath.dao.*" })
#EnableAspectJAutoProxy
#EnableTransactionManagement
#EnableJpaRepositories(basePackages = "yourPath.dao.entities",
entityManagerFactoryRef = "entityManagerFactory",
transactionManagerRef = "transactionManager",
repositoryBaseClass = Dao.class)
#Import({ DataSourceConfig.class }) //Explained below
public class TestConfig {
#Autowired
private DataSource dataSource;
#Bean
public List<String> modelJPA() {
return Collections.singletonList("es.carm.sms.ortopedia.entities");
}
#Bean(name = "transactionManager")
public PlatformTransactionManager transactionManager(EntityManagerFactory entityManagerFactory) {
JpaTransactionManager transactionManager = new JpaTransactionManager();
transactionManager.setEntityManagerFactory(entityManagerFactory);
return transactionManager;
}
#Bean(name = "entityManagerFactory")
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
LocalContainerEntityManagerFactoryBean entityManagerFactory = new LocalContainerEntityManagerFactoryBean();
entityManagerFactory.setPackagesToScan(modelJPA().toArray(new String[modelJPA().size()]));
entityManagerFactory.setDataSource(this.dataSource);
JpaVendorAdapter jpaVendorAdapter = new HibernateJpaVendorAdapter();
entityManagerFactory.setJpaVendorAdapter(jpaVendorAdapter);
return entityManagerFactory;
}
}
Then if you want to connect with your database:
#Configuration
public class DataSourceConfig {
#Bean
public DataSource dataSource() {
DriverManagerDataSource dataSource = new DriverManagerDataSource();
dataSource.setDriverClassName("oracle.jdbc.OracleDriver");
dataSource.setUrl("jdbc:oracle:thin:#ip:port:sid");
dataSource.setUsername("name");
dataSource.setPassword("pass");
return dataSource;
}
}
Now you have it all set up, you just need to create your test importing your configurations:
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(classes = TestConfig.class)
public class TestCase {...}
You will get your spring context initialized with access to all your resources (MVC) Services, DAO and Model.
I am practising on spring-social and it seems that the userConnectionRepository is not properly autowired in the following code when I do a "Run as Junit Test" in Eclipse. I get a Null pointer exception on the usersConnectionRepository when creating a new FacebookOffLine although breakpoints put in the #Bean java creation code shows that they seem to be properly created. Thanks in advance,
public class FacebookOffline {
private Facebook fb;
#Autowired
private UsersConnectionRepository usersConnectionRepository;
public FacebookOffline(User user) {
super();
ConnectionRepository cr = usersConnectionRepository.createConnectionRepository(user.getId());
fb = cr.getPrimaryConnection(Facebook.class).getApi();
}
}
Here is the test code :
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(classes = {
org.springframework.social.quickstart.config.MainConfig.class,
org.springframework.social.quickstart.config.SocialConfig.class })
public class FacebookOfflineTest {
#Test
public void test1() {
FacebookOffline essai = new FacebookOffline(new User("yves"));
And the Spring configuration classes adapted from Keith Donald Quick Start Sample :
#Configuration
#ComponentScan(basePackages = "org.springframework.social.quickstart", excludeFilters = { #Filter(Configuration.class) })
#PropertySource("classpath:org/springframework/social/quickstart/config/application.properties")
public class MainConfig {
#Bean
public DataSource datasource() {
DriverManagerDataSource toReturn = new DriverManagerDataSource("jdbc:mysql://localhost:3306/spring_social");
toReturn.setDriverClassName("com.mysql.jdbc.Driver");
toReturn.setUsername("spring");
toReturn.setPassword("spring");
return toReturn;
}
}
#Configuration
public class SocialConfig {
#Inject
private Environment environment;
#Inject
private DataSource dataSource;
#Bean
public ConnectionFactoryLocator connectionFactoryLocator() {
ConnectionFactoryRegistry registry = new ConnectionFactoryRegistry();
registry.addConnectionFactory(new FacebookConnectionFactory(environment
.getProperty("facebook.clientId"), environment
.getProperty("facebook.clientSecret")));
return registry;
}
#Bean
public UsersConnectionRepository usersConnectionRepository() {
JdbcUsersConnectionRepository repository = new JdbcUsersConnectionRepository(
dataSource, connectionFactoryLocator(), Encryptors.noOpText());
return repository;
}
}
Actually there are 2 problems here.
Spring cannot autowire beans it doesn't control (i.e. created with new)
Dependencies aren't available in the constructor (an object instance is needed before it can be injected)
The first one can be mitigated by letting spring manage an instance of FacebookOffline (or if you need multiple instances make the bean request or session scoped).
The second is a bit harder but can probaly solved by using a method annotated with #PostConstruct (or by implementing InitializingBean from spring).
You did
FacebookOffline essai = new FacebookOffline(new User("yves"));
That means, Spring isn't managing this essai instance and thus spring can't autowire any variables in the essai.
You'll have to create bean of FacebookOffline in SocialConfig.
Then you can have
/* ... */
public class FacebookOfflineTest {
#Autowired
ApplicationContext context;
#Test
public void test1() {
FacebookOffline essai = context.getBean(FacebookOffline.class);
OR
/* ... */
public class FacebookOfflineTest {
#Autowired
FacebookOffline essai;
#Test
public void test1() {
// You can use essai now
Also, you'll need to update FacebookOffline as Dependencies ain't available in constructor.
public class FacebookOffline {
private Facebook fb;
#Autowired
private UsersConnectionRepository usersConnectionRepository;
public FacebookOffline(User user) {
super();
}
#PostConstruct
void loadFacebook() {
ConnectionRepository cr = usersConnectionRepository.createConnectionRepository(user.getId());
fb = cr.getPrimaryConnection(Facebook.class).getApi();
}
}
Spring can't autowire fields on an instance you create via new since it doesn't know about it. Declare a bean of type FacebookOffline instead.