Using UTF-8 query not working in hibernate - java

I have this user_model.java below:
public class User_Model implements Serializable {
#Id #GeneratedValue
private Long id;
#ColumnTransformer(
read="AES_DECRYPT(username, 'Hf7p4u6e') USING utf8))",
write="AES_ENCRYPT(?, 'Hf7p4u6e')")
The above code is working when I remove USING utf8) but when I put it again I get this error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.USING user_mo0_.UTF-8).
I don't want to remove the utf8 because I used it for korean language.
I also put a utf8 setting in my hibernate.xml
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/mydb?UseUnicode=true&characterEncoding=utf8</property>
<property name="hibernate.connection.CharSet">utf8</property>
<property name="hibernate.connection.characterEncoding">utf8</property>
<property name="hibernate.connection.useUnicode">true</property>
But still, it's not work at all.How can I make my query work? any help

Two things:
Maybe you ned to use 'USING utf8' with CONVERT function (https://dev.mysql.com/doc/refman/5.0/en/charset-convert.html)
CONVERT(_latin1 AES_DECRYPT(username, 'Hf7p4u6e') USING utf8)
utf8 has nothing to do with your already created tables if they are not in UTF-8. This only forces newly created tables to use UTF-8. Existing tables remain as they are.

Related

Hibernate Identity differences when moving from Oracle To Postgres

I am switching a Java application using Hibernate from Oracle to Postgres and encountering a issue with Id GeneratedValues.
The Domain objects have Ids configured like this:
#Id #GeneratedValue(strategy = GenerationType.AUTO) #Column(name = "id")
private Long id;
Under Oracle there was a sequence called "HIBERNATE_SEQUENCE" that provided this. I have created this sequence in Postgres like this:
CREATE SEQUENCE HIBERNATE_SEQUENCE MINVALUE 1 MAXVALUE 9223372036854775807 INCREMENT BY 1 START WITH 50000 CACHE 20 NO CYCLE ;
However, when persisting an object I'm getting an error of:
org.postgresql.util.PSQLException: ERROR: missing FROM-clause entry for table "hibernate_sequence"
I have tried:
switching the "GenerationType" to "SEQUENCE"
creating the sequence in lower case (hibernate_sequence)
But I get the same error in both cases.
You have to configure Hibernate to speak the PostgreSQL dialect of SQL.
In Oracle you get the next value of a sequence with a pseudo-column (hibernate_sequence.nextval), while in PostgreSQL you use a function (nextval(hibernate_sequence)). Using the Oracle syntax with PostgreSQL will cause the error you quote.
The main problem I had was not setting the hibernate.dialect property correctly.
It was
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
and changing it to
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL95Dialect"/>
fixed it and started using the correct sequence function as Laurenze Able pointed out

HSQL database user lacks privilege or object not found error

I am trying to use hsqldb-2.3.4 to connect from Spring applicastion.
I created data base using the following details
Type : HSQL Database Engine Standalone
Driver: org.hsqldb.jdbcDriver
URL: jdbc:hsqldb:file:mydb
UserName: SA
Password: SA
I created a table named ALBUM under "MYDB" schema
In spring configuration file:
<bean id="jdbcTemplate"
class="org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate">
<constructor-arg ref="dbcpDataSource" />
</bean>
<bean id="dbcpDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="org.hsqldb.jdbcDriver" />
<property name="url" value="jdbc:hsqldb:file:mydb" />
<property name="username" value="SA" />
<property name="password" value="SA" />
</bean>
And in my spring controller I am doing jdbcTemplate.query("SELECT * FROM MYDB.ALBUM", new AlbumRowMapper());
And It gives me exception:
org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.jdbc.BadSqlGrammarException: PreparedStatementCallback; bad SQL grammar [SELECT * FROM MYDB.ALBUM]; nested exception is java.sql.SQLSyntaxErrorException: user lacks privilege or object not found: ALBUM
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:982)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:861)
javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:846)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
If I execute same query through SQL editor of hsqldb it executes fine. Can you please help me with this.
As said by a previous response there is many possible causes. One of them is that the table isn't created because of syntax incompatibility. If specific DB vendor syntax or specific capability is used, HSQLDB will not recognize it. Then while the creation code is executed you could see that the table is not created for this syntax reason. For exemple if the entity is annoted with #Column(columnDefinition = "TEXT") the creation of the table will fail.
There is a work around which tell to HSQLDB to be in a compatible mode
for pgsl you should append your connection url with that
"spring.datasource.url=jdbc:hsqldb:mem:testdb;sql.syntax_pgs=true"
and for mysql with
"spring.datasource.url=jdbc:hsqldb:mem:testdb;sql.syntax_mys=true"
oracle
"spring.datasource.url=jdbc:hsqldb:mem:testdb;sql.syntax_ora=true"
note there is variant depending on your configuration
it could be hibernate.connection.url= or spring.datasource.url=
for those who don't use the hibernate schema creation but a SQL script you should use this kind of syntax in your script
SET DATABASE SQL SYNTAX ORA TRUE;
It will also fix issues due to vendor specific syntax in SQL request such as array_agg for posgresql
Nota bene : The the problem occurs very early when the code parse the model to create the schema and then is hidden in many lines of logs, then the unitTested code crash with a confusing and obscure exception "user lacks privilege or object not found error" which does not point the real problem at all. So make sure to read all the trace from the beginning and fix all possible issues
If you've tried all the other answers on this question, then it is most likely that you are facing a case-sensitivity issue.
HSQLDB is case-sensitive by default. If you don't specify the double quotes around the name of a schema or column or table, then it will by default convert that to uppercase. If your object has been created in uppercase, then you are in luck. If it is in lowercase, then you will have to surround your object name with double quotes.
For example:
CREATE MEMORY TABLE "t1"("product_id" INTEGER NOT NULL)
To select from this table you will have to use the following query
select "product_id" from "t1"
user lacks privilege or object not found can have multiple causes, the most obvious being you're accessing a table that does not exist. A less evident reason is that, when you run your code, the connection to a file database URL actually can create a DB. The scenario you're experiencing might be you've set up a DB using HSQL Database Manager, added tables and rows, but it's not this specific instance your Java code is using. You may want to check that you don't have multiple copies of these files: mydb.log, mydb.lck, mydb.properties, etc in your workspace. In the case your Java code did create those files, the location depends on how you run your program. In a Maven project run inside Netbeans for example, the files are stored alongside the pom.xml.
I had the error user lacks privilege or object not found while trying to create a table in an empty in-memory database.
I used spring.datasource.schema and the problem was that I missed a semicolon in my SQL file after the "CREATE TABLE"-Statement (which was followed by "CREATE INDEX").
I had similar issue with the error 'org.hsqldb.HsqlException: user lacks privilege or object not found: DAYS_BETWEEN' turned out DAYS_BETWEEN is not recognized by hsqldb as a function. use DATEDIFF instead.
DATEDIFF ( <datetime value expr 1>, <datetime value expr 2> )
When running a HSWLDB server. for example your java config file has:
hsql.jdbc.url = jdbc:hsqldb:hsql://localhost:9005/YOURDB;sql.enforce_strict_size=true;hsqldb.tx=mvcc
check to make sure that your set a server.dbname.#. for example my server.properties file:
server.database.0=eventsdb
server.dbname.0=eventsdb
server.port=9005
I was inserting the data in hsql db using following script
INSERT INTO Greeting (text) VALUES ("Hello World");
I was getting issue related to the Hello World object not found and HSQL database user lacks privilege or object not found error
which I changed into the below script
INSERT INTO Greeting (text) VALUES ('Hello World');
And now it is working fine.
Add these two extra properties:
spring.jpa.hibernate.naming.implicit-strategy=
org.hibernate.boot.model.naming.ImplicitNamingStrategyLegacyJpaImpl
spring.jpa.hibernate.naming.physical-strategy=
org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl
I bumped into kind of the same problem recently. We are running a grails application and someone inserted a SQL script into the BootStrap file (that's the entry point for grails). That script was supposed to be run only in the production environment, however because of bad logic it was running in test as well. So the error I got was:
User lacks privilege or object not found:
without any more clarification...
I just had to make sure the script was not run in the test environment and it fixed the problem for me, though it took me 3 hours to figure it out. I know it is very, very specific issue but still if I can save someone a couple of hours of code digging that would be great.
I was having the same mistake. In my case I was forgetting to put the apas in the strings.
I was doing String test = "inputTest";
The correct one is String test = "'inputTest'";
The error was occurring when I was trying to put something in the database
connection.createStatement.execute("INSERT INTO tableTest values(" + test +")";
In my case, just put the quotation marks ' to correct the error.
In my case the error occured because i did NOT put the TABLE_NAME into double quotes "TABLE_NAME" and had the oracle schema prefix.
Not working:
SELECT * FROM FOOSCHEMA.BAR_TABLE
Working:
SELECT * FROM "BAR_TABLE"
had this issue with concatenating variables in insert statement. this worked
// var1, var3, var4 are String variables
// var2 and var5 are Integer variables
result = statement.executeUpdate("INSERT INTO newTable VALUES ('"+var1+"',"+var2+",'"+var3+"','"+var4+"',"+var5 +")");
In my case the issue was caused by the absence (I'd commented it out by mistake) of the following line in persistence.xml:
<property name="hibernate.hbm2ddl.auto" value="update"/>
which prevented Hibernate from emitting the DDL to create the required schema elements...
(different Hibernate wrappers will have different mechanisms to specify properties; I'm using JPA here)
I had this error while trying to run my application without specifying the "Path" field in Intellij IDEA data source (database) properties. Everything else was configured correctly.
I was able to run scripts in IDEA database console and they executed correctly, but without giving a path to the IDEA, it was unable to identify where to connect, which caused errors.
You have to run the Database in server mode and connect.Otherwise it wont connect from external application and give error similar to user lacks privilege.
Also change the url of database in spring configuration file accordingly when running DB in server mode.
Sample command to run DB in server mode
$java -cp lib/hsqldb.jar org.hsqldb.server.Server --database.0 file:data/mydb --dbname.0 Test
Format of URL in configuration file
jdbc:hsqldb:hsql://localhost/Test
In my case, one of the columns had the name 'key' with the missing #Column(name = "key") annotation so that in the logs you could see the query that created the table but in fact it was not there. So be careful with column names
For what it's worth - I had this same problem. I had a column named 'TYPE', which I renamed to 'XTYPE' and a column named ORDER which I renamed to 'XORDER' and the problem went away.
Yet another reason could be a misspelt field name. If your actual table has an id column named albumid and you'd used album_id, then too this could occur.
As another anwer remarked, case differences in field names too need to be taken care of.
I faced the same issue and found there was more than one PersistenceUnit (ReadOnly and ReadWrite) , So the tables in HSQLDDB created using a schema from one persistence unit resulted in exception(HSQL database user lacks privilege or object not found error) being thrown when accessed from other persistence unit .It happens when tables are created from one session in JPA and accessed from another session
In my case the table MY_TABLE was in the schema SOME_SCHEMA. So calling select/insert etc. directly didn't work. To fix:
add file schema.sql to the resources folder
in this file add the line CREATE SCHEMA YOUR_SCHEMA_NAME;

Hibernate putting backticks around columnDefinition

I have a column in the database which has been defined as follows in the entity class:
#Column(name="lastlogindate", columnDefinition ="TIMESTAMP DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP")
private Timestamp lastlogindate;
The create table command that is being generated is as follows:
create table usermaster (
lastlogindate `TIMESTAMP DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP`)
while what works is
create table usermaster (
lastlogindate TIMESTAMP DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP)
Hibernate reports the following error while creating tables:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TIMESTAMP DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
Unable to understand why extra ticks are being added and how to avoid it.
The version details are as follows:
HIBERNATE VERSION: 4.3.8.Final
MySQL version:5.6.26
MySQL Dialect information:
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="transaction.factory_class">
org.hibernate.transaction.JDBCTransactionFactory</property>
<property name="current_session_context_class">thread</property>
<property name="show_sql">true</property>
<property name="hibernate.connection.autocommit ">false</property>
<property name="hibernate.globally_quoted_identifiers">true</property>
Please remove the following config line:
<property name="hibernate.globally_quoted_identifiers">true</property>
This is likely not needed and almost surely causing the problem you experience.
UPDATE:
The issue was finally solved by changing the dialect to MySQL5 from generic MySQL:
org.hibernate.dialect.MySQL5Dialect

select length of oracle long raw with sql statement

storing filedata via a hibernate (using postgresql or oracle 10g/11g) property mapped as
<property name="fileData" type="binary">
<column name="fileData" length="104857600" />
</property>
from a java application i need to access the length of the field from the db (i do not want to load whole the object, for performance reasons). i did not find any hibernate (hql) solution to query that information, so i decided to search for features of the different databases that were used. for postgresql i found:
select BIT_LENGTH(filedata) from table
which works perfectly (and astonishing fast). now i need something similar for the use with oracle. i already tried
select utl_raw.length(filedata) from table
and
select DBMS_LOB.GETLENGTH(filedata) from table
which both results in the error msg:
"Error: ORA-00997: illegal use of LONG datatype"
is there any possibilty to query the length of that hibernate property on an oracle db without selecting the object itself?
(hibernate creates a "long raw" field on oracle, and a "bytea" field on postgresql)
thx in advance
(addition: statement will be used in a migration-context, newly created filedata entities will get a filesize property programatically)
Well, looks like i found an answer here:
https://community.oracle.com/thread/2137593
create table temp_deleteme as select to_lob(<long raw field>) obj from <tablename>;
select dbms_lob.getlength(obj) from temp_deleteme;
after creating the tempTable i can select the filedatalength from it, write it to my entities, and delete the table again. still not really good performance, but that let the db do the work and i will not have to transfer entities to my server for only calculating the needed information.

Getting org.hibernate.MappingException: No Dialect mapping for JDBC type: -4 exception?

I am getting following exception at query.list() line:
org.hibernate.MappingException: No Dialect mapping for JDBC type: -4
at org.hibernate.dialect.TypeNames.get(TypeNames.java:56)
at org.hibernate.dialect.TypeNames.get(TypeNames.java:81)
at org.hibernate.dialect.Dialect.getHibernateTypeName(Dialect.java:369)
at org.hibernate.loader.custom.CustomLoader$Metadata.getHibernateType(CustomLoader.java:559)
at org.hibernate.loader.custom.CustomLoader$ScalarResultColumnProcessor.performDiscovery(CustomLoader.java:485)
at org.hibernate.loader.custom.CustomLoader.autoDiscoverTypes(CustomLoader.java:501)
at org.hibernate.loader.Loader.getResultSet(Loader.java:1787)
at org.hibernate.loader.Loader.doQuery(Loader.java:662)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:224)
at org.hibernate.loader.Loader.doList(Loader.java:2211)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2095)
at org.hibernate.loader.Loader.list(Loader.java:2090)
at org.hibernate.loader.custom.CustomLoader.list(CustomLoader.java:289)
at org.hibernate.impl.SessionImpl.listCustomQuery(SessionImpl.java:1695)
at org.hibernate.impl.AbstractSessionImpl.list(AbstractSessionImpl.java:142)
at org.hibernate.impl.SQLQueryImpl.list(SQLQueryImpl.java:152)
following is my configuration file:
<property name="hibernate.connection.driver_resource">com.mysql.jdbc.Driver</property>
<property name="hibernate.connection.password">mysql</property>
<property name="hibernate.connection.url">jdbc:mysql://localhost:3306/mydatabase</property>
<property name="hibernate.connection.username">root</property>
<property name="hibernate.default_schema">mydatabase</property>
<property name="hibernate.dialect">org.hibernate.dialect.MySQL5InnoDBDialect</property>
When I am trying to run application into Eclipse IDE then this exception is not coming but when I create jar of application and run then only I am getting it.
thanks in advance...
Sometimes database returns results of custom SQL queries in strange types that cannot be mapped to Hibernate types (especially when you use expressions under select).
You need to find an offending query and add an explicit cast to it.
For example
Object o = session.createSQLQuery("select 2*2").uniqueResult();
may cause such a problem. You may fix it as follows:
Object o = session.createSQLQuery("select cast(2*2 as int)").uniqueResult();
Got the solution:
Just change the Query, I am fetching whole record instead of select specific.
e.g. from table and then get respective field (here script) value from table Object instead of using select script from table, It is working fine now.

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