I have to integrate Avaya IVRS with Service now through java rest web-service. If user calls through Avaya IVRS, he should have option to choose from menu via their phone keypad and do the following functions :- 1. Add a ticket 2. Update a ticket 3. Close a ticket
I have written code to create and update ticket but i don't know how to integrate with service now.
/////////////////////////////////////////////////
// POST OPERATION -- Create a new Incident ticket
/////////////////////////////////////////////////
String endpointPOST = baseURI + "/in";
PostMethod post = new PostMethod(endpointPOST);
post.addRequestHeader("X-AccessKey", accessKey);
post.addRequestHeader("Accept" , "application/xml");
post.addRequestHeader("Content-Type", "application/xml; charset=UTF-8");
post.setRequestBody("<in>" + "<customer COMMON_NAME=\"System_SD_User\"/>" +
"<description>Created from REST API Java Samples code</description>" + "</in>");
try {
System.out.println("Execute POST request for " + endpointPOST);
// Execute POST request
int result = client.executeMethod(post);
System.out.println("Response status code: " + result);
System.out.println("Response body: ");
System.out.println(post.getResponseBodyAsString());
System.out.println();
} catch (HttpException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
post.releaseConnection();
}
//////////////////////////////////////////////////////
// PUT OPERATION -- Update an existing Incident ticket
//////////////////////////////////////////////////////
String endpointPUT = baseURI + "/in/400001";
PutMethod put = new PutMethod(endpointPUT);
put.addRequestHeader("X-AccessKey", accessKey);
put.addRequestHeader("Accept" , "application/xml");
put.addRequestHeader("Content-Type", "application/xml; charset=UTF-8");
put.setRequestBody(
"<in>" + "<summary>Updated from REST API Java Samples code</summary>" + "</in>");
try {
System.out.println("Execute PUT request for " + endpointPUT);
// Execute PUT request
int result = client.executeMethod(put);
System.out.println("Response status code: " + result);
System.out.println("Response body: ");
System.out.println(put.getResponseBodyAsString());
System.out.println();
} catch (HttpException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
put.releaseConnection();
}
you can integrate REST API default option given in OD or you can write customize java code or create a jar of your application call that in OD
try the below code it's tested in Avaya lab
String webServiceURl="https://XXXXXXXXXX/services/OceanaDataoceana/data/context/schema";
try{
URL url = new URL(webServiceURl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
String input ="{""}";//pass paramenter for request
OutputStream os = conn.getOutputStream();
os.write(input.getBytes());
os.flush();
System.out.println("conn.getResponseCode() ::::"+conn.getResponseCode());
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
JSONObject object;
try {
object = new JSONObject(output);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("json response::: "+output);
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
If you are talking about Experience Portal then you have two choices. You can use the Orchestration Designer's built-in REST client (File/New/Web Service Operation File (REST)) or you implement it in a separate project and attach the rest client to your OD project.
Related
I am trying to convert this request written java to c#(Xamarin android) , java one seems to be working , but c# one is failing with bad request(400) .
Could you please point out if i am translating rightly ?
Java code
String url = "https://someUrl";
try {
URL url1 = new URL(url);
URLConnection uc = url1.openConnection();
String basicAuth = Base64.encodeToString((APIKEY).getBytes("UTF-8"), Base64.NO_WRAP);
uc.setRequestProperty("Authorization", basicAuth);
InputStream in = uc.getInputStream();
// Log.e(TAG, "response: " + response);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
C# code
String url = "https://someUrl";
// Add custom implementation here as needed.
var uri = new Uri(url);
var authHeaderValue = Convert.ToBase64String(Encoding.UTF8.GetBytes (API_KEY), Base64FormattingOptions.None);
try
{
using(var client = new HttpClient())
{
client.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("Authorization", authHeaderValue);
var response = await client.GetAsync(uri);
}
}
catch (Exception e)
{
Log.Debug ("TokenSending", "failed to send token" + e);
}
I am using restheart to provide a restful interface to mongodb. The interface is set up and running and provides the correct answer if a GET request is sent through Chrome. However if I use the following java code using a HttpURLConnection I get a 201 response with no content.
try {
videos = new URL("http://www.example.com:8080/myflix/videos");
} catch (Exception et) {
System.out.println("Videos URL is broken");
return null;
}
HttpURLConnection hc = null;
try {
hc = (HttpURLConnection) videos.openConnection();
String login="admin:admin";
final byte[] authBytes = login.getBytes(StandardCharsets.UTF_8);
final String encoded = Base64.getEncoder().encodeToString(authBytes);
hc.addRequestProperty("Authorization", "Basic "+encoded);
hc.setDoInput(true);
hc.setDoOutput(true);
hc.setUseCaches(false);
hc.setRequestMethod("GET");
hc.setRequestProperty("Accept-Encoding", "gzip, deflate, sdch");
hc.setRequestProperty("Content-Type", "application/json");
hc.setRequestProperty("Accept", "application/json,text/html,application/hal+json,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*");
} catch (Exception et) {
System.out.println("Can't prepare http URL con");
return (null);
}
BufferedReader br = null;
try {
OutputStreamWriter writer = new OutputStreamWriter(
hc.getOutputStream());
} catch (Exception et) {
System.out.println("Can't get reader to videos stream");
}
String inputLine;
String sJSON = null;
try {
int rc = hc.getResponseCode();
What is the correct way to authenticate using Java to the resthert interface? (Details on the restheart authentication is here Restheart authentication
I made few changes (look for inline comments starting with <==) and it works:
The way you generate the authentication request header is correct. When I run your code I actually got 415 Unsupported Media Type, that went away commenting out hc.setDoOutput(true). A GET is a input operation, in fact you were also trying to get an OutStream from the connection: you need to get an InputStream actually.
URL url;
try {
url = new URL("http://127.0.0.1:8080/test/huge");
} catch (Exception et) {
System.out.println("Videos URL is broken");
Assert.fail(et.getMessage());
return;
}
HttpURLConnection hc = null;
try {
hc = (HttpURLConnection) url.openConnection();
String login = "admin:admin";
final byte[] authBytes = login.getBytes(StandardCharsets.UTF_8);
final String encoded = Base64.getEncoder().encodeToString(authBytes);
hc.addRequestProperty("Authorization", "Basic " + encoded);
System.out.println("Authorization: " + hc.getRequestProperty("Authorization"));
hc.setDoInput(true);
//hc.setDoOutput(true); <== removed, otherwise 415 unsupported media type
hc.setUseCaches(false);
hc.setRequestMethod("GET");
hc.setRequestProperty("Accept-Encoding", "gzip, deflate, sdch");
hc.setRequestProperty("Accept", "application/json,text/html,application/hal+json,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*");
} catch (Exception et) {
System.out.println("Can't prepare http URL con");
}
System.out.println(hc.toString());
BufferedReader br = null;
try {
InputStreamReader reader = new InputStreamReader(hc.getInputStream()); // <== the request is a GET, data is in input
} catch (Exception et) {
System.out.println("Can't get reader to videos stream");
}
int rc = hc.getResponseCode();
System.out.println("response code: " + rc);
System.out.println("response message: " + hc.getResponseMessage());
Assert.assertEquals(200, rc);
I have the following code in my program, used for inserting record -
private Void downloadUrl() throws IOException {
String postParameters;
HttpURLConnection urlConnection = null;
postParameters = "name="+ URLEncoder.encode(user.name,"UTF-8")
+"&age="+URLEncoder.encode(user.age+"","UTF-8")
+"&username="+URLEncoder.encode(user.username,"UTF-8")
+"&password="+URLEncoder.encode(user.password,"UTF-8");
if (postParameters != null) {
Log.i("Post", "POST parameters: " + postParameters);
try {
URL urlToRequest = new URL(SERVER_ADDRESS);
urlConnection = (HttpURLConnection) urlToRequest.openConnection();
urlConnection.setReadTimeout(30000 /* milliseconds */);
urlConnection.setConnectTimeout(30000 /* milliseconds */);
urlConnection.setDoOutput(true);
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
urlConnection.setFixedLengthStreamingMode(
postParameters.getBytes().length);
PrintWriter out = new PrintWriter(urlConnection.getOutputStream());
out.print(postParameters.getBytes());
out.close();
// handle issues
int statusCode = urlConnection.getResponseCode();
Log.e("Response", "The response is: " + statusCode);
} catch (MalformedURLException e) {
// handle invalid URL
Log.e("Response", "invalid URL");
} catch (SocketTimeoutException e) {
// hadle timeout
Log.e("Response", "handle timeout");
} catch (IOException e) {
// handle I/0
Log.e("Response", "handle IO problem");
} finally {
if (urlConnection != null) {
urlConnection.disconnect();
}
}
}
return null;
}
The code is showing no errors and the logged entries are
09-27 12:24:17.944 5006-5039/? E/Response﹕ The response is: 200
09-27 12:24:33.729 5006-5118/? I/Post﹕ POST parameters: name=vibha&age=25&username=vib&password=1234
But when I check the database, the new record is not created.
But if I use PHP code in a file and post the same parameters,the records are getting inserted.
My requirement for help and guidance is how to pass the post parameter in the HttpURLConnection class
I have a string that I am trying to send to a Parse.com cloud function. According to the REST API documentation (https://www.parse.com/docs/rest#general-requests), it must be in json format, so I made it into a json object and converted it to a string to append to the end of the http request url.
JSONObject jsonParam = new JSONObject();
jsonParam.put("emailId", emailId);
String urlParameters = jsonParam.toString();
Then I send the request as so, in my attempt to match their cURL code example as Java code:
con.setDoOutput(true);
DataOutputStream wr = null;
wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
Nonetheless, I receive a returned error code of 400 with error message "Bad Request", which I believe to be caused by unrecognizable parameters being sent to the cloud function. None of the other errors in my code trigger. Yet I verified through console logs that emailId is a normal string and the resulting JSON object, as well as its .toString() equivalent comes out as a proper string reading of a JSON object. Also this worked for another function I have in which I am creating an object in my Parse database. So why would it not work here?
Here is the full function for reference and context:
private void sendEmailWithParse(String emailId) throws IOException {
String url = "https://api.parse.com/1/functions/sendEmailNow";
URL obj = new URL(url);
HttpsURLConnection con = null;
try {
con = (HttpsURLConnection) obj.openConnection();
} catch (IOException e) {
System.out.println("Failed to connect to http link");
e.printStackTrace();
}
//add request header
try {
con.setRequestMethod("POST");
} catch (ProtocolException e) {
System.out.println("Failed to set to POST");
e.printStackTrace();
}
con.setRequestProperty("X-Parse-Application-Id", "**************************************");
con.setRequestProperty("X-Parse-REST-API-Key", "************************************************");
con.setRequestProperty("Content-Type", "application/json");
JSONObject jsonParam = new JSONObject();
jsonParam.put("emailId", emailId);
System.out.println("parameter being sent to cloud function: " + jsonParam);
System.out.println("parameter being sent to cloud function as string: " + jsonParam.toString());
String urlParameters = jsonParam.toString();
// Send post request
con.setDoOutput(true);
DataOutputStream wr = null;
try {
wr = new DataOutputStream(con.getOutputStream());
} catch (IOException e1) {
System.out.println("Failed to get output stream");
e1.printStackTrace();
}
try {
wr.writeBytes(urlParameters);
} catch (IOException e) {
System.out.println("Failed to connect to send over Parse object as parameter");
e.printStackTrace();
}
try {
wr.flush();
} catch (IOException e) {
e.printStackTrace();
}
try {
wr.close();
} catch (IOException e) {
System.out.println("Failed to connect to close datastream connection");
e.printStackTrace();
}
int responseCode = 0;
try {
responseCode = con.getResponseCode();
} catch (IOException e) {
System.out.println("Failed to connect to get response code");
e.printStackTrace();
}
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post parameters : " + urlParameters);
System.out.println("Response Code : " + responseCode);
System.out.println("Response message: " + con.getResponseMessage());
}
I solved the problem by using the HttpRequest external library. It gave me better control of the request and made for easier debugging of the problem. The server was receiving the request just fine, the problem was with the JSON encoding. Rather than putting the JSON object as a parameter in the request, I inserted it into the body of the http request and encoded it in UTF-8.
In the end, this is the code that worked:
String url = "https://api.parse.com/1/functions/sendEmailNow";
URL obj = new URL(url);
//Attempt to use HttpRequest to send post request to parse cloud
HttpRequest request = HttpRequest.post(obj).contentType("application/json");
request.header("X-Parse-Application-Id", "**************************");
request.header("X-Parse-REST-API-Key", "********************");
JSONObject jsonParam = new JSONObject();
jsonParam.put("emailId", emailId);
request.send(jsonParam.toString().getBytes("UTF8"));
if (request.ok())
System.out.println("HttpRequest WORKED");
else
System.out.println("HttpRequest FAILED " + request.code() + request.body());
I am trying to write a JSON Client which uses HTTP GET method,and I am getting an response of 500.The code I have tried is below,Is there any wrong with the same?The request parameter I am trying to set is entityName=Nila and parentEntity=500000001 as parameters.
URL url = new URL("http://192.168.210.74:9763/services/testEntityService?entityName=Nila&parentEntity=500000001");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/json");
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
Its an internal server error yes the problem is on server side.