How to test something in Multi-Threaded Environment using Java [duplicate] - java

This question already has answers here:
How should I unit test multithreaded code?
(29 answers)
Closed 5 years ago.
How do I test something like this in multithreaded environment. I know it's gonna fail, cause this code is not thread-safe. I just wanna know how can i prove it? Creating bunch of threads and trying to add with those different threads? This code is intentionally not written properly cause of testing purposes !!!
public class Response_Unit_Manager {
private static HashMap<String, Response_Unit> Response_Unit_DB =
new HashMap<> ();
/**
*
* This subprogram adds a new Response_Unit to the data store. The
* new response unit must be valid Response_Unit object and it's ID must be
* unique (i.e., must not already exist in the data store.
*
* Exceptions Thrown: Null_Object_Exception
*/
public static void Add_Response_Unit (Response_Unit New_Unit)
throws Null_Object_Exception, Duplicate_Item_Exception {
String Unit_ID = New_Unit.Unit_ID ();
if (New_Unit == null)
throw new Null_Object_Exception ();
else if (Response_Unit_Exists (Unit_ID))
throw new Duplicate_Item_Exception (Unit_ID);
else
Response_Unit_DB.put (Unit_ID, New_Unit);
} //end Add_Response_Unit

You may get lucky and see a failure when running a test, but non-failing code doesn't mean that it's thread-safe code. The only automated ways to check thread-safety is with some static analysis tools that let you put annotations on methods/classes and scan for potential issues. For example, I know FindBugs support some annotations and does concurrency checking based on them. You should be able to apply this to your single Tester class. There is still a lot of room for improvement in the industry on this topic, but here are some current examples:
http://robertfeldt.net/publications/grahn_2010_comparing_static_analysis_tools_for_concurrency_bugs.pdf
http://homepages.inf.ed.ac.uk/dts/students/spathoulas/spathoulas.pdf

As others have noted, you can't write a test that will guarantee failure as the thread schedule might "just work out", but you can write tests that have a very low probability of passing if there are thread safety issues. For example, you're code attempts to disallow duplicate items in your DB but due to thread safety issues it can't do that. So spawn a ton of threads, have them all wait on a CountdownLatch or something to maximize your chances of triggering the race, then have them all try to insert the same item. Finally you can check that (a) all but one thread saw a Duplicate_Item_Exception and (b) Response_Unit_DB contains only a single item. For these kinds of tests you can also run it several times (in the same test) to maximize your chances of triggering the issue.
Here's an example:
#Test
public void testIsThreadSafe() {
final int NUM_ITERATIONS = 100;
for(int i = 0; i < NUM_ITERATIONS; ++i) {
oneIsThreaSafeTest();
}
}
public void oneIsThreadSafeTest() {
final int NUM_THREADS = 1000;
final int UNIT_ID = 1;
final Response_Unit_Manager manager = new Response_Unit_Manager();
ExecutorService exec = Executors.newFixedThreadPool(NUM_THREADS);
CountdownLatch allThreadsWaitOnThis = new CountdownLatch(1);
AtomicInteger numThreadsSawException = new AtomicInteger(0);
for (int i = 0; i < NUM_THREADS; ++i) {
// this is a Java 8 Lambda, if using Java 7 or less you'd use a
// class that implements Runnable
exec.submit(() -> {
allThreadsWaitOnThis.await();
// making some assumptions here about how you construct
// a Response_Unit
Response_Unit unit = new Response_Unit(UNIT_ID);
try {
manager.Add_Response_Unit(unit);
} catch (Duplicate_Item_Exception e) {
numThreadsSawException.incrementAndGet();
}
});
// release all the threads
allThreadsWaitOnThis.countdown();
// wait for them all to finish
exec.shutdown();
exec.awaitTermination(10, TimeUnits.MINUTES);
assertThat(numThreadsSawException.get()).isEqualTo(NUM_THREADS - 1);
}
You can construct similar tests for the other potential thread safety issues.

The easiest way to find errors with testing, like the one which is contained in your class, is to use a Testrunner like for example the following:
package com.anarsoft.mit;
import java.util.concurrent.atomic.AtomicInteger;
public class Test_Response_Unit_Manager implements Runnable {
private final AtomicInteger threadCount = new AtomicInteger();
public void test() throws Exception
{
for(int i = 0; i < 2 ;i++)
{
Thread thread = new Thread(this, "Thread " + i);
this.threadCount.incrementAndGet();
thread.start();
}
while( this.threadCount.get() > 0 )
{
Thread.sleep(1000);
}
Thread.sleep(10 * 1000);
}
public void run()
{
exec();
threadCount.decrementAndGet();
}
protected void exec()
{
Response_Unit_Manager.Add_Response_Unit(new Response_Unit(Thread.currentThread().getId()));
}
public static void main(String[] args) throws Exception
{
(new Test_Response_Unit_Manager()).test();
}
}
And to use a dynamic race condition detection tool like http://vmlens.com, a lightweight race condition detector. This will show you the following race conditions:
And the stacktraces leading to the bug. On the left the write and one the right the read.
http://vmlens.com works with eclipse, so it depens on the ide you are using, if its useful for you

Related

How to test that Java class is thread safe?

Let's take this simple class:
public class CounterService {
private volatile Counter counter;
public CounterService(Counter counter) {
this.counter = counter;
}
public long getCounterValue() {
System.out.println("GET: " + this.counter.counter + " in thread " +
Thread.currentThread().getName());
return this.counter.counter;
}
public long setCounterValue(long newValue) {
this.counter = this.counter.updateCounter(newValue);
System.out.println("--set: " + newValue + " in thread " +
Thread.currentThread().getName());
return this.counter.counter;
}
}
public class Counter {
public final long counter;
public Counter(long counter) {
this.counter = counter;
}
public Counter updateCounter(long i) {
return new Counter(i);
}
}
Now I want to write the unit test, that will always pass, if the CounterService is thread safe (eg. when I set get and set methods synchronized). I belive that writing a test, which will always fail if this class isn't thread safe, may be impossible.
I tried with something like this:
#Test
public void multipleThreadSetAndGetShouldCorrectValue() throws ExecutionException, InterruptedException {
int threads = 10;
final Counter counter = new Counter(0);
final CounterService counterService = new CounterService(counter);
CountDownLatch latch = new CountDownLatch(1);
ExecutorService executorService = Executors.newFixedThreadPool(threads);
Collection<Future<Long>> results = new ArrayList<>();
AtomicLong sequence = new AtomicLong(0);
for (int i = 0; i < threads; i++) {
results.add(executorService.submit(() -> {
latch.await(1, TimeUnit.SECONDS);
latch.countDown();
counterService.setCounterValue(sequence.getAndIncrement());
return counterService.getCounterValue();
}));
}
final Set<Long> uniqueResult = new HashSet<>();
for (Future<Long> result : results) {
uniqueResult.add(result.get());
}
assertEquals(threads, uniqueResult.size());
}
But this test will occasionally fail even if the CounterService is thread safe.
How to write unit test that will always pass when the class is thread safe? How to write test to check, that get method returns the last set value, even if it was modified by another thread?
First, your Counter class is pointless. The updateCounter method doesn't update, it returns a new object. So just delete the Counter class and use long in your CounterService.
There then remains the question as to what CounterService is for. It just wraps a long.
But disregarding that. No - you can't really write a test to prove that something is not thread-safe as multi-threading problems are not deterministic. You could insert delays into places where you know race conditions might occur, but that only works if you already know it isn't thread-safe in a particular place and you want to prove it. But if you don't know where the problem is you might not be able to insert the delays in the right place to prove the possible problem does exist.
By the same token, you can't really prove that it is correct either, although again you can increase your chances by inserting sleeps between operations to force problems. But it may not work and you are not testing the real-world scenario.
Your test is failing because you don't understand what synchronized does and what thread-safely implies.
In your test, you are setting a counter value and then getting it in the next line. If you synchronize the set and the get, all that means is that the individual get and set operations are thread-safe. It doesn't mean that you can call get and set separately and that get will return the same value that the previous set used.
If you want to set something and then get the same value back again safely you have to wrap the get and the set calls in a synchronized block.
synchonized(this) { // get must return same thing that was set
set
get
}
I strongly recommend that you focus on understanding what your program needs to achieve and what thread-safety and sychronization means in that context. Otherwise, you won't be able to develop a correct test anyway.

Unit test the thread safety of a singleton class in Java?

Let's imagine I have the following java class :
static class Singleton {
static Singleton i;
static Singleton getInstance() {
if (i == null) {
i = new Singleton();
}
return i;
}
}
Now, we all know this will work, but - it apparently is not thread safe - I am not actually trying to fix the thread safety - this is more of a demo, my other class is identical, but uses a mutex and synchronization - the unit test will be ran against each to show that one is thread safe, and the other, is not. What might the unit test which would fail if getInstance is not thread safe look like?
Well, race conditions are by nature probabilistic so there's no deterministic way to truly generate a race condition. Any possible way against your current code would need to be run many times until the desired outcome is achieved. You can enforce a loose ordering of access on i by making a mock singleton to test against to simulate what a certain condition might look like, though. Rule of thumb with synchronization is preventative measures beat trying to test and figure out what's wrong after bad code is mangled in a code base.
static class Singleton {
static Singleton i;
static Singleton getInstance(int tid) {
if (i == null) {
if (tid % 2 == 0) i = new Singleton()
}
return i;
}
}
So certain threads will write to i and other threads will read i as if they reached "return i" before "the even thread id's were able to check and initialize i" (sort of, not exactly, but it simulates the behavior). Still, there's a race between the even threads in this case because the even threads may still write to i after another reads null. To improve, you'd need to implement thread safety to force the condition where one thread reads i, gets null, while the other thread sets i to new Singleton() a thread-unsafe condition. But at that point you're better off just solving the underlying issue (just make getInstance thread safe!)
TLDR: there are infinitely many race conditions that can occur in a unsafe function call. You can mock the code to generate a mock of a specific race condition (say, between just two threads) but it's not feasible to just blanket test for "race conditions"
This code worked for me.
The trick is that it is probabilistic like said by other users.
So, the approach that should be taken is to run for a number of times.
public class SingletonThreadSafety {
public static final int CONCURRENT_THREADS = 4;
private void single() {
// Allocate an array for the singletons
final Singleton[] singleton = new Singleton[CONCURRENT_THREADS];
// Number of threads remaining
final AtomicInteger count = new AtomicInteger(CONCURRENT_THREADS);
// Create the threads
for(int i=0;i<CONCURRENT_THREADS;i++) {
final int l = i; // Capture this value to enter the inner thread class
new Thread() {
public void run() {
singleton[l] = Singleton.getInstance();
count.decrementAndGet();
}
}.start();
}
// Ensure all threads are done
// The sleep(10) is to be somewhat performant, (if just loop,
// this will be a lot slow. We could use some other threading
// classes better, like CountdownLatch or something.)
try { Thread.sleep(10); } catch(InterruptedException ex) { }
while(count.get() >= 1) {
try { Thread.sleep(10); } catch(InterruptedException ex) { }
}
for( int i=0;i<CONCURRENT_THREADS - 1;i++) {
assertTrue(singleton[i] == singleton[i + 1]);
}
}
#Test
public void test() {
for(int i=0;i<1000;i++) {
Singleton.i = null;
single();
System.out.println(i);
}
}
}
This have to make some change in the Singleton design pattern. That the instance variable is now accessible in the Test class. So that we could reset the Singleton instance available to null again every time the test is repeated, then we repeat the test 1000 times (if you have more time, you could make it more, sometimes finding an odd threading problem require that).
In some cases this solution works. Unfortunately its hard to test singleton to provoke thread unsafe.
#Test
public void checkThreadUnSafeSingleton() throws InterruptedException {
int threadsAmount = 500;
Set<Singleton> singletonSet = Collections.newSetFromMap(new ConcurrentHashMap<>());
ExecutorService executorService = Executors.newFixedThreadPool(threadsAmount);
for (int i = 0; i < threadsAmount; i++) {
executorService.execute(() -> {
Singleton singleton = Singleton.getInstance();
singletonSet.add(singleton);
});
}
executorService.shutdown();
executorService.awaitTermination(1, TimeUnit.MINUTES);
Assert.assertEquals(2, singletonSet.size());
}

Exact same code (with multithreading) doesn't work on 2 different computers

I'm working at the moment on a simple Chess A.I. (calculate possible future turns, rate them, chosse the best one, + some tricks so you don't have to calculate every single turn). The code is written in Java and I'm using Netbeans. To make the calculations faster, I use multithreading. The code works roughly like this:
Main function makes first some calculations and then starts 8 threads.
the threads execute the main-calculations
when they finish, they set a boolean value in a boolean array (finished[]) true. This array is in the "main Class" (if you call it like this), where also the main function is.
during all this time the main function is waiting and checking constantly if every value of the finished[] - array is true. If that is the case, it continues it's work.
Now I have a strange problem. The code works perfectly on my PC, but when I run the EXACT same code on my laptop, the main function won't continue its work, after all values of the finished[]-array are true. I already made some changes in the code, so I can try it with different numbers of threads, but the result is always the same.
I have totally no idea what's going on here and would really appreciate it, if someone of you had any answers and/or suggestions!
If you need any more Information just ask, I'll try my best. :)
(Sorry for possible grammar mistakes, english isn't my native language, but I'm trying my best. ;))
So I was asked to show some Code I used in the program:
(Perhaps first a warning, yes I am still a big Noob in Java and this is my first time I work with threads so don't be shocked if you see terrible mistakes I possibly made. xD)
The main Class looks something like this:
public class Chess_ai_20 {
static boolean finished[] = new boolean[8];
Distributor[] Distributors = new Distributor[8];
...
public static void main(String[] args) {
boolean testing=false;
...
//some calculations and other stuff
...
Distributors[0] = new Distributor(...., "0"); //the String "0" will be the thread name.
Distributors[1] = new ...
...
Distributors[7] = new Distributor(...., "7");
for (int i = 0; i < 8; i++) {
Distributoren[i].start();
}
testing=false;
while(testing==false){
if(finished[0]==true && finished[1]==true && ... && finished[7]==true){
testing=true; //That's the point where I get stuck I suppose
}
}
System.out.println("I made it!");
}
public static void setFinished(int i) {
finished[i] = true;
System.out.println("finished [" + i + "] = " + finished[i]);
System.out.println(Arrays.toString(finished)); //To check how many values already are true
}
}
Then we got of course the class "Distributor"
public class Distributor extends Thread {
Thread t;
String threadname;
boolean running=false;
...
Distributor(......, String s) {
threadname=s;
...
...
}
#Override
public void start() {
running=true;
if (t == null) {
t = new Thread(this,threadname);
t.start();
}
}
#Override
public void run() {
if(running){
...
//Do the main calculations etc.
...
//All the Calculations habe been done at this point
Chess_ai_20.setFinished(Character.getNumericValue(threadname.charAt(0))); //Set the value of finished[] true in the main class
running=false;
}
}
}
As others have mentioned, using a Future would be much simpler and easy to understand. Below is a snippet demonstrating how you could rewrite your code. Check out the code in action.
First, you write a Callable to define the task that you want to do.
public class MyCallable implements Callable<Boolean> {
#Override
public Boolean call() {
// Do some job and return the result.
return Boolean.TRUE;
}
}
And then, you submit this task to an Executor. There are a lot of Executors in JDK. You want to go through the Concurrency Tutorial first.
ExecutorService executor = Executors.newFixedThreadPool(Runtime
.getRuntime().availableProcessors());
List<Callable<Boolean>> callables = new ArrayList<>();
for (int counter = 0; counter < 8; counter++) {
callables.add(new MyCallable());
}
List<Future<Boolean>> futures = executor.invokeAll(callables);
for (Future<Boolean> future : futures) {
System.out.println(future.get()); // You'd want to store this into an array or wherever you see fit.
}
executor.shutdown();
Remember that the futures returned by the executor are in the same order as the Callables you submitted (or added) to the Collection (in this case, an ArrayList). So you don't need to worry about returning the index, an ID or even the name of the Thread (if you assigned one) to map the corresponding result.

Java concurrency counter not properly clean up

This is a java concurrency question. 10 jobs need to be done, each of them will have 32 worker threads. Worker thread will increase a counter . Once the counter is 32, it means this job is done and then clean up counter map. From the console output, I expect that 10 "done" will be output, pool size is 0 and counterThread size is 0.
The issues are :
most of time, "pool size: 0 and countThreadMap size:3" will be
printed out. even those all threads are gone, but 3 jobs are not
finished yet.
some time, I can see nullpointerexception in line 27. I have used ConcurrentHashMap and AtomicLong, why still have concurrency
exception.
Thanks
import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.ThreadPoolExecutor;
import java.util.concurrent.atomic.AtomicLong;
public class Test {
final ConcurrentHashMap<Long, AtomicLong[]> countThreadMap = new ConcurrentHashMap<Long, AtomicLong[]>();
final ExecutorService cachedThreadPool = Executors.newCachedThreadPool();
final ThreadPoolExecutor tPoolExecutor = ((ThreadPoolExecutor) cachedThreadPool);
public void doJob(final Long batchIterationTime) {
for (int i = 0; i < 32; i++) {
Thread workerThread = new Thread(new Runnable() {
#Override
public void run() {
if (countThreadMap.get(batchIterationTime) == null) {
AtomicLong[] atomicThreadCountArr = new AtomicLong[2];
atomicThreadCountArr[0] = new AtomicLong(1);
atomicThreadCountArr[1] = new AtomicLong(System.currentTimeMillis()); //start up time
countThreadMap.put(batchIterationTime, atomicThreadCountArr);
} else {
AtomicLong[] atomicThreadCountArr = countThreadMap.get(batchIterationTime);
atomicThreadCountArr[0].getAndAdd(1);
countThreadMap.put(batchIterationTime, atomicThreadCountArr);
}
if (countThreadMap.get(batchIterationTime)[0].get() == 32) {
System.out.println("done");
countThreadMap.remove(batchIterationTime);
}
}
});
tPoolExecutor.execute(workerThread);
}
}
public void report(){
while(tPoolExecutor.getActiveCount() != 0){
//
}
System.out.println("pool size: "+ tPoolExecutor.getActiveCount() + " and countThreadMap size:"+countThreadMap.size());
}
public static void main(String[] args) throws Exception {
Test test = new Test();
for (int i = 0; i < 10; i++) {
Long batchIterationTime = System.currentTimeMillis();
test.doJob(batchIterationTime);
}
test.report();
System.out.println("All Jobs are done");
}
}
Let’s dig through all the mistakes of thread related programming, one man can make:
Thread workerThread = new Thread(new Runnable() {
…
tPoolExecutor.execute(workerThread);
You create a Thread but don’t start it but submit it to an executor. It’s a historical mistake of the Java API to let Thread implement Runnable for no good reason. Now, every developer should be aware, that there is no reason to treat a Thread as a Runnable. If you don’t want to start a thread manually, don’t create a Thread. Just create the Runnable and pass it to execute or submit.
I want to emphasize the latter as it returns a Future which gives you for free what you are attempting to implement: the information when a task has been finished. It’s even easier when using invokeAll which will submit a bunch of Callables and return when all are done. Since you didn’t tell us anything about your actual task, it’s not clear whether you can let your tasks simply implement Callable (may return null) instead of Runnable.
If you can’t use Callables or don’t want to wait immediately on submission, you have to remember the returned Futures and query them at a later time:
static final ExecutorService cachedThreadPool = Executors.newCachedThreadPool();
public static List<Future<?>> doJob(final Long batchIterationTime) {
final Random r=new Random();
List<Future<?>> list=new ArrayList<>(32);
for (int i = 0; i < 32; i++) {
Runnable job=new Runnable() {
public void run() {
// pretend to do something
LockSupport.parkNanos(TimeUnit.SECONDS.toNanos(r.nextInt(10)));
}
};
list.add(cachedThreadPool.submit(job));
}
return list;
}
public static void main(String[] args) throws Exception {
Test test = new Test();
Map<Long,List<Future<?>>> map=new HashMap<>();
for (int i = 0; i < 10; i++) {
Long batchIterationTime = System.currentTimeMillis();
while(map.containsKey(batchIterationTime))
batchIterationTime++;
map.put(batchIterationTime,doJob(batchIterationTime));
}
// print some statistics, if you really need
int overAllDone=0, overallPending=0;
for(Map.Entry<Long,List<Future<?>>> e: map.entrySet()) {
int done=0, pending=0;
for(Future<?> f: e.getValue()) {
if(f.isDone()) done++;
else pending++;
}
System.out.println(e.getKey()+"\t"+done+" done, "+pending+" pending");
overAllDone+=done;
overallPending+=pending;
}
System.out.println("Total\t"+overAllDone+" done, "+overallPending+" pending");
// wait for the completion of all jobs
for(List<Future<?>> l: map.values())
for(Future<?> f: l)
f.get();
System.out.println("All Jobs are done");
}
But note that if you don’t need the ExecutorService for subsequent tasks, it’s much easier to wait for all jobs to complete:
cachedThreadPool.shutdown();
cachedThreadPool.awaitTermination(Long.MAX_VALUE, TimeUnit.DAYS);
System.out.println("All Jobs are done");
But regardless of how unnecessary the manual tracking of the job status is, let’s delve into your attempt, so you may avoid the mistakes in the future:
if (countThreadMap.get(batchIterationTime) == null) {
The ConcurrentMap is thread safe, but this does not turn your concurrent code into sequential one (that would render multi-threading useless). The above line might be processed by up to all 32 threads at the same time, all finding that the key does not exist yet so possibly more than one thread will then be going to put the initial value into the map.
AtomicLong[] atomicThreadCountArr = new AtomicLong[2];
atomicThreadCountArr[0] = new AtomicLong(1);
atomicThreadCountArr[1] = new AtomicLong(System.currentTimeMillis());
countThreadMap.put(batchIterationTime, atomicThreadCountArr);
That’s why this is called the “check-then-act” anti-pattern. If more than one thread is going to process that code, they all will put their new value, being confident that this was the right thing as they have checked the initial condition before acting but for all but one thread the condition has changed when acting and they are overwriting the value of a previous put operation.
} else {
AtomicLong[] atomicThreadCountArr = countThreadMap.get(batchIterationTime);
atomicThreadCountArr[0].getAndAdd(1);
countThreadMap.put(batchIterationTime, atomicThreadCountArr);
Since you are modifying the AtomicInteger which is already stored into the map, the put operation is useless, it will put the very array that it retrieved before. If there wasn’t the mistake that there can be multiple initial values as described above, the put operation had no effect.
}
if (countThreadMap.get(batchIterationTime)[0].get() == 32) {
Again, the use of a ConcurrentMap doesn’t turn the multi-threaded code into sequential code. While it is clear that the only last thread will update the atomic integer to 32 (when the initial race condition doesn’t materialize), it is not guaranteed that all other threads have already passed this if statement. Therefore more than one, up to all threads can still be at this point of execution and see the value of 32. Or…
System.out.println("done");
countThreadMap.remove(batchIterationTime);
One of the threads which have seen the 32 value might execute this remove operation. At this point, there might be still threads not having executed the above if statement, now not seeing the value 32 but producing a NullPointerException as the array supposed to contain the AtomicInteger is not in the map anymore. This is what happens, occasionally…
After creating your 10 jobs, your main thread is still running - it doesn't wait for your jobs to complete before it calls report on the test. You try to overcome this with the while loop, but tPoolExecutor.getActiveCount() is potentially coming out as 0 before the workerThread is executed, and then the countThreadMap.size() is happening after the threads were added to your HashMap.
There are a number of ways to fix this - but I will let another answer-er do that because I have to leave at the moment.

Concurrent Thread-safe AtomicInteger

I've read through the API documentation of the java.util.concurrent package, but have obviously misunderstood something. The overview says
A small toolkit of classes that support lock-free thread-safe
programming on single variables.
However, a small test application shows that the AtomicInteger class does not provide thread-safety, at least when it is shared across threads (I accept that the getAndSet / increment methods themselves are at least atomic)
Test:
import java.util.Random;
import java.util.concurrent.atomic.AtomicInteger;
public class AtomicIntTest
{
public static void main(String[] args) throws InterruptedException
{
AtomicInteger atomicInt = new AtomicInteger(0);
WorkerThread w1 = new WorkerThread(atomicInt);
WorkerThread w2 = new WorkerThread(atomicInt);
w1.start();
w2.start();
w2.join(); // <-- As pointed out by StuartLC and BarrySW19, this should be w1.join(). This typo allows the program to produce variable results because it does not correctly wait for *both* threads to finish before outputting a result.
w2.join();
System.out.println("Final value: " + atomicInt.get());
}
public static class WorkerThread extends Thread
{
private AtomicInteger atomicInt = null;
private Random random = new Random();
public WorkerThread(AtomicInteger atomicInt)
{
this.atomicInt = atomicInt;
}
#Override
public void run()
{
for (int i = 0; i < 500; i++)
{
this.atomicInt.incrementAndGet();
try
{
Thread.sleep(this.random.nextInt(50));
}
catch(InterruptedException e)
{
e.printStackTrace();
}
}
}
}
}
When I run this class, I consistently get results ranging from around 950 to 1000, when I would expect to always see exactly 1000.
Can you explain why do I not get consistent results when two threads access this shared AtomicInteger variable? Have I misunderstood the thread-safety guarantee?
Looks like a simple cut&paste error - you are joining to thread "w2" twice and never to "w1". At present, you would expect the thread "w1" to still be running half the time when you print the 'final' value.

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