My structure looks like :
public class ReadCSV {
volatile List<FlightDetails> detail;
main() {
ReadCSV obj=new ReadCSV();
obj.detail=Collections.synchronizedList(new ArrayList<FlightDetails>());
new Thread(new Runnable(){
#Override
public void run() {
try {
...
//pass the object along
readAndParseFile("someFile.csv",obj);
} catch (IOException e) {
...
}
// prints Alright
System.out.println(obj.detail.get(0).getDep_loc());
}
}).start();
// Throws AIOB Exception
System.out.println(obj.detail.get(0).getArr_loc());
}
static void readAndParseFile(String csvFileName, ReadCSV obj) {
...
..
//make changes to the object
obj.detail.add()
// works fine
}
While passing the object without the thread, the changes are made.But the changes are not reflected even after making the field Volatile.
1) what is wrong in the above code?
2) Is it alright to follow this approach?
3) what is the general way to do such jobs?
I am very new to multi threading .
If you have a Thread object that does some task and you want to see the results, wait for its termination.
Thread p = new Thread(new Runnable(){
//...
}); // no start here
p.start(); // let it run
p.join(); // wait for its end
There is not much gain in executing another thread while the starting thread has nothing better to do than to wait for the started thread's end.
you need to wait till your reader thread has finished.
you can use futures or Thread.join()
Related
I've an object that's created when the class is instantiated. I create a lock i-e; wait() on that object inside a background thread, however the app still gets unresponsive. My understanding of synchronization/locking is that if object.wait() is called in the main thread than it's equivalent to blocking the main thread however if it's called inside a background thread (even though the object upon which wait() is called in the main thread, shouldn't cause problems).
Can someone please help me out understanding this?
Example code:
class MyClass {
private final Object myLockObject = new Object();
public void connect() {
new Thread(new Runnable{
mSocket.connect();
myLockObject.wait(); // causing ANR
}).start();
}
private void socketConnectCallback() {
//upon callback
myLockObject.notifyAll();
}
}
class MyAndroidService extends Service {
public void onStartCommand() {
MyClass myClassObject = new MyClass();
myClassObject.connect();
//it immediately returns here even with the code written above.
}
}
First of all, this code will throw an IllegalMonitorStateException. This is because before calling object.wait(), you need to make sure that you are holding the object's monitor. One way to do this is to use:
synchronised(object) {
// this thread now owns the object's monitor
object.wait();
}
Further, the thread that calls for object.wait() relinquishes its ownership on that object's monitor and waits for some other thread to notify it. Once it gets the notification, it will wait until it reacquires the object's monitor (since some other thread might be having the ownership of that monitor even if the waiting thread got the notify signal). Then it continues normal execution.
In your case, the background thread should block, and the main thread should continue executing normally. Isn't this what you have mentioned is happening?
I don't know if this will help so much, but I can't comment so I want to get your attention to this code:
newThread(new Runnable {
mSocket.connect();
myLockObject.wait();
}).start();
This must be like:
(new Thread( new Runnable() {
public void run() {
try {
mSocket.connect(); // connect takes argument(s)
} catch (IOException e) {
// Catch the excpetion
}
try {
myLockObject.wait();
} catch (InterruptedException e) {
// Catch the excpetion
}
}
})).start();
and since Runnable is a functional interface you can use lambda expression instead of creating a new object.
Edit:
I think I figured out what do you want to do, if you want to make a thread that connects the socket and then wait to be notified and want it to acquire the intrinsic lock of the object myLockObject to prevent interleaving then you have to put the code you want to be executed by the thread in a guarded block:
private final void connectSocket() {
synchronized(myLockObject) {
try {
mSocket.connect(null);
} catch (IOException e) {
}
try {
myLockObject.wait();
} catch (InterruptedException e) {
}
}
}
and in the connect method just call connectSocket
public void connect() {
new Thread(new Runnable() {
public void run() {
connectSocket();
}
}).start();
}
This is a general Java question and not an Android one first off!
I'd like to know how to run code on the main thread, from the context of a secondary thread. For example:
new Thread(new Runnable() {
public void run() {
//work out pi to 1,000 DP (takes a while!)
//print the result on the main thread
}
}).start();
That sort of thing - I realise my example is a little poor since in Java you don't need to be in the main thread to print something out, and that Swing has an event queue also - but the generic situation where you might need to run say a Runnable on the main thread while in the context of a background thread.
EDIT: For comparison - here's how I'd do it in Objective-C:
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0UL), ^{
//do background thread stuff
dispatch_async(dispatch_get_main_queue(), ^{
//update UI
});
});
Thanks in advance!
There is no universal way to just send some code to another running thread and say "Hey, you, do this." You would need to put the main thread into a state where it has a mechanism for receiving work and is waiting for work to do.
Here's a simple example of setting up the main thread to wait to receive work from other threads and run it as it arrives. Obviously you would want to add a way to actually end the program and so forth...!
public static final BlockingQueue<Runnable> queue = new LinkedBlockingQueue<Runnable>();
public static void main(String[] args) throws Exception {
new Thread(new Runnable(){
#Override
public void run() {
final int result;
result = 2+3;
queue.add(new Runnable(){
#Override
public void run() {
System.out.println(result);
}
});
}
}).start();
while(true) {
queue.take().run();
}
}
In case you are on Android, using a Handler should do the job?
new Handler(Looper.getMainLooper()).post(new Runnable () {
#Override
public void run () {
...
}
});
An old discussion, but if it is a matter of sending request to the main thread (an not the opposite direction) you can also do it with futures. The basic aim is to execute something in background and, when it is finished, to get the result:
public static void main(String[] args) throws InterruptedException, ExecutionException {
// create the task to execute
System.out.println("Main: Run thread");
FutureTask<Integer> task = new FutureTask<Integer>(
new Callable<Integer>() {
#Override
public Integer call() throws Exception {
// indicate the beginning of the thread
System.out.println("Thread: Start");
// decide a timeout between 1 and 5s
int timeout = 1000 + new Random().nextInt(4000);
// wait the timeout
Thread.sleep(timeout);
// indicate the end of the thread
System.out.println("Thread: Stop after " + timeout + "ms");
// return the result of the background execution
return timeout;
}
});
new Thread(task).start();
// here the thread is running in background
// during this time we do something else
System.out.println("Main: Start to work on other things...");
Thread.sleep(2000);
System.out.println("Main: I have done plenty of stuff, but now I need the result of my function!");
// wait for the thread to finish if necessary and retrieve the result.
Integer result = task.get();
// now we can go ahead and use the result
System.out.println("Main: Thread has returned " + result);
// you can also check task.isDone() before to call task.get() to know
// if it is finished and do somethings else if it is not the case.
}
If your intention is to do several stuff in background and retrieve the results, you can set some queues as said above or you can split the process in several futures (starting all at once or starting a new one when needed, even from another future). If you store each task in a map or a list, initialized in the main thread, you can check the futures that you want at anytime and get their results when they are done.
You may want to use the 'even dispatching thread' where most event driven things happen. If you are using swing then:
SwingUtilities.invokeLater(new Runnable() {
public void run() {
Your code here.
}
});
Or create a class that implements Runnable and pass it into invokeLater().
If you're using JavaFX, which I highly recommend, then you can use
Platform.runLater(new Runnable() {
#Override
public void run() {
alert(text);
}
});
from within your non-UI thread, and the runnable will executed from the UI thread on return from your thread.
A little late to the party but I think that my approach is a little bit different.
Modifying Affe's solution a little bit
public static final BlockingQueue<Runnable> queue = new LinkedBlockingQueue<>();
public static void main(String[] args) {
Thread myThread = new Thread(
() -> {
String name = Thread.currentThread().getName();
System.out.println("initial current thread " + name);
queue.add(() -> System.out.println(Thread.currentThread().getName()));
});
myThread.setName("background thread");
myThread.start();
try {
myThread.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
while (!queue.isEmpty()) {
try {
queue.take().run();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
output
initial current thread background thread
main
Supposed I have a class MyThread, which implements Runnable with a method dosomething():
class MyThread implements Runnable{
Object dosomething(Parameter p){ ... }
run(){...};
}
If I do:
main(){
MyThread my = new MyThread().run();
Object o = my.dosomething(p);
}
will dosomething be executed on myThread or in the main Thread?
How can I start the execution of dosomething on myThread from the main Thread and retrieve the returned Object?
main(){
MyThread my = new MyThread().run();
Object o = my.dosomething(p);
}
If you do that it won't compile: you're trying to assign the result of a void method, void run(), to an object of type MyThread.
Implementing runnable and calling run() will not cause the code to be executed in a separate thread unless you pass it to another thread (i.e. Tread t = new Thread(my);)
How can I start the execution of dosomething on myThread from the main Thread and retrieve the returned Object?
You do that by storing the result of doSomething() in a location where you can access it later.
class MyClass
{
public Object doSomething()
{
// return the object
return new Object();
}
}
class MyRunnable implements Runnable
{
private final MyClass _mc;
private final object _lock;
private final List<object> _results;
public MyRunnable(MyClass mc, List<object> results, object lock)
{
_mc = mc;
_lock = lock;
_results = results;
}
public void run()
{
synchronized(_lock)
{
_results.add(_mc.doSomething());
}
}
}
So now in main:
void main(){
MyClass mc = new MyClass();
List<object> results = new List<object>();
object lock = new object();
// Execute your thread and wait for it to complete
Thread t = new Thread(new MyRunnable(mc, results, lock ));
t.start();
t.join();
// Get the results
for(object result:results)
{
// do something with the result
}
}
This should give you an idea of what you're doing "wrong." A more realistic example would be if you spawn multiple threads, run them concurrently and then join on all of them until they all complete.
Sounds like you may want to consider Callables and Futures.
There's a decent explanation at http://www.vogella.de/articles/JavaConcurrency/article.html#futures
You can use delegate, for example.
new MyThread(callWhenFinishObject)
It'll be executed on the main thread, since it's that thread that calls the method. If you want dosomething to run in the separate thread, have it called within run() and store the result in a myThread field for later retrieval.
You might want to check class Future or other stuff in java.util.concurrent for some convenient way of waiting for the result to become available.
EDIT: if dosomething should only run until some condition is satisfied that must be flagged in the main thread, have run() block until the main thread somehow signals the other thread that it's okay to go on.
EDIT 2: here, someone confirm this is what's being asked:
package threadtest;
public class Main {
public static void main(final String[] args) {
final MyThread otherThread = new MyThread();
System.out.println("Main thread: I'm gonna start the other thread now...");
otherThread.start();
System.out.println("Main thread: there, hope it does well.");
try {
Thread.sleep(1000); //Lets main thread take a snooze...
} catch(InterruptedException ex) {
//whatever
}
System.out.println("Main thread: I'm gonna do some stuff in the meantime...");
try {
Thread.sleep(200); //Lets main thread take a snooze...
} catch(InterruptedException ex) {
//whatever
}
System.out.println("Main thread: maybe clean up the kitchen.");
try {
Thread.sleep(1000); //Lets main thread take a snooze...
} catch(InterruptedException ex) {
//whatever
}
System.out.println("Main thread: does other thread have something for me yet?");
if(otherThread.getResult() == null)
System.out.println("Main thread: nope, not yet.");
try {
Thread.sleep(500); //Lets main thread take a snooze...
} catch(InterruptedException ex) {
//whatever
}
System.out.println("Main thread: oh crap! I forgot to tell it that it may execute its method!");
otherThread.allowToExecute();
System.out.println("Main thread: phew... better keep checking now before it gets angry.");
while(otherThread.getResult() == null) {
try {
Thread.sleep(100); //Lets main thread take a snooze...
} catch(InterruptedException ex) {
//whatever
}
}
System.out.println("Main thread: there we go, it gave me a result. Rest in peace, other thread...");
}
private static class MyThread extends Thread {
private boolean mayExecuteDoSomething = false;
private Object result = null;
#Override
public void run() {
System.out.println("Other thread: whoa, someone started me!");
while(!mayExecuteDoSomething) {
try {
Thread.sleep(100); //I'm gonna sleep for a bit...
} catch(InterruptedException ex) {
//whatever
}
}
System.out.println("Other thread: alright, I'm allowed to execute my method!");
result = doSomething();
System.out.println("Other thread: there, did it. I'll just call it quits now.");
}
public void allowToExecute() {
mayExecuteDoSomething = true;
}
private Object doSomething() {
return new Object();
}
public Object getResult() {
return result;
}
}
}
This is a very crude approach to the issue. The basic concepts are there, though. In reality, you'd want to use stuff like Callable and Future for proper asynchronous computation.
That is not possible.
When you create a thread, it runs the code in run() and exits.
There is no way to inject code into a different thread; that would break the core execution model. (Within a thread, your code runs sequentially, with nothing in between)
If you want to, you can create a thread that listens for callback (Runnable instances) in a queue and executes them (like a message loop).
This is how the UI thread works.
Also, you aren't actually startign a thread; you need to write new Thread(someRunnable).start()
I have an event handling mechanism in my Android code to dump the sensor values in a file. Right now, I'm doing it in the main UI thread and hence the UI button responsiveness is very sluggish and I would like to speed it up.
How can I use multithreading on event handling functions? I'm trying to do it like this:
Create a global variable writeNow.
When the sensor value changes, set WriteNow = true
Create a thread in the class which looks like this:
Thread thread1 = new Thread()
{
public void run()
{
if(writeNow == true)
{
try
{
fos.write(s.getBytes());
}
catch (IOException e)
{
e.printStackTrace();
}
writeNow = false;
}
}
};
Thus, whenever writeNow is true, it will write to a File and then set WriteNow to false. However, I realize this is not the right approach, because the thread will execute once and then stop executing. When I tried a simple example with a while(true) and wait(), I found that the thread is interrupted millions of times.
So how do I enclose this event handling mechanism in a single thread, for speeding up a process?
Thanks!
You can try one of the following approaches:
It looks like you're trying to keep your writer thread running all the time; what you can do is spawn the thread only when you need it. Take a look at the example in the Android documentation for handling expensive operation in the UI thread.
Here is the example from that page:
public class MyActivity extends Activity {
[ . . . ]
// Need handler for callbacks to the UI thread
final Handler mHandler = new Handler();
// Create runnable for posting
final Runnable mUpdateResults = new Runnable() {
public void run() {
updateResultsInUi();
}
};
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
[ . . . ]
}
protected void startLongRunningOperation() {
// Fire off a thread to do some work that we shouldn't do directly in the UI thread
Thread t = new Thread() {
public void run() {
mResults = doSomethingExpensive();
mHandler.post(mUpdateResults);
}
};
t.start();
}
private void updateResultsInUi() {
// Back in the UI thread -- update our UI elements based on the data in mResults
[ . . . ]
}
}
Since it doesn't look like you're doing anything in the UI thread once you finish writing you don't really need to bother with a Handler. But you might want to use it to display a Toast once the file has been written to.
On the other hand, if you still want to have a thread running, you might have it sleep() and periodically wake up and check the status of writeNow.
Thread thread1 = new Thread()
{
public void run()
{
while(true)
{
if(writeNow == true)
{
try
{
fos.write(s.getBytes());
}
catch (IOException e)
{
e.printStackTrace();
}
writeNow = false;
}
try
{
Thread.sleep(100); //sleep for 100 ms
}
catch (InterruptedException e)
{
Log.d('', e.getMessage());
}
}
}
};
Note that this will quickly get complicated and you might lose the bytes you want to write if your thread is sleeping when new data comes in and when it wakes up, even newer data has been received and has overwritten the previous bytes. You'd need some sort of a queue to manage that.
I'm not sure what you were doing with the wait() but that should've also worked and is in fact, the approach for problems involving a consumer and producer. The idea is to have your thread synchronize and wait() on a shared object (like perhaps your queue of bytes); a second thread will call notify() on the shared object when there is data available to write and the writer thread will be woken up. The writer thread should then write and reloop. Take a look at this tutorial.
As for the interruption of your thread, your thread may be interrupted for a number of reasons which is why it is good practice (especially when using wait()) to ensure that the condition you checked before you called wait() is still valid because you could've been woken because of either a call to notify()/notifyAll() or because of an interruption.
Handler handler = null;
handler = new Handler();
//create another class for and make consrtuctor as u want. so that u can use that effectively.
//for example.
popupIndex = new IndexThread(handler,head, target,ltp,price,IndexNifty.this,columsView,call);
popupIndex.setColumnViewexit(columsView);
handler.postDelayed(popupIndex, 300);
//another class
public IntraThread(Handler handler,String script,int target,int ltp,int price,Intraday intraday,TextView columsView,String call){
super();
this.target = target;
this.ltp = ltp;
this.price = price;
this.intraday = intraday;
this.columsView = columsView;
this.script= script;
this.handler= handler;
this.call= call;
}
public void run(){
// write ur code here....
}
I have a method and a thread which I'd like to run in the following order: First the method should do something with an object, and then the thread should do something with the object. They share the same object. I have to synchronize them, but I am just meeting with Threads. How can I do that?
private synchronized method()
{
//do something with an object (a field)
}
Runnable ObjectUpdater = new Runnable()
{
//do something with the object after the method has finished
}
My code, that somehow manages to freeze my Main thread (where the method is)
My thread code:
private Runnable something = new Runnable(){
synchronized (this){
while (flag == false)
{ try {wait();)
catch (IntExc ie) {e.printStackTrace...}
}
//here it does its thing
}
setFlag(false);
}
My method code (part of the main thread)
private void Method()
{
//do its thing
setFlag(true);
notifyAll();
}
To me that is simple questions
" you said that I do not know which is
going to access the object first - the
separate ObjectUpdater thread, or the
main thread (with the method). If the
separate thread accesses it before the
main thread, that is bad and I don't
want this to happen"
if you want the main thread method to call first then the objectUpdater thread , have a flag to know whether the method is visited first by main thread ,if it is updater then call wait to this thread , once main finishes it call notify which will run separator thread,
to know which thread is main thread or updater thread , set a name to the thread while creating it. and get the name as Thread.currentThread().getName().
Use the Semaphore class to allow access to the object.
public class Main
{
public static void main (String[] args) {
final Obj obj = new Obj();
final Semaphore semaphore = new Semaphore(0);
Thread t = new Thread(new Runnable() {
#Override
public void run() {
try {
semaphore.acquire();
} catch (InterruptedException ex) {
Thread.currentThread().interrupt();
return;
}
obj.doSomething();
}
});
t.setName("test");
t.start();
try {
Thread.sleep(1000);
} catch (InterruptedException ignored) {
}
obj.doSomething();
semaphore.release();
}
}
class Obj {
public void doSomething() {
System.out.println("something done by " + Thread.currentThread());
}
}
Apart from synchronizing on the object, you could call the method as first statement in the new thread, or you could start the new thread at the end of the method.
It is hard to say what is the best approach in your case, maybe you can give us some more details on the how and what?
Update
In answer to your code (for some reason I cannot add another comment...)
Is the method called from a synchronized(this) block? If not the notifyAll() should be in a synchronized block. Also, can you update the code to show where/how your main thread interacts with the method and the object?
I think better approach would be to call the method using which you want to perform something with an object, and then declare the thread which would do something with an object.