I am new to Spring Data Mongo so I must be doing something wrong because I can't manage to execute such a simple query. This is my model:
#Document(collection="brands")
public class Brand{
#Id
private int id;
private String name;
...
//getters-setters
}
#Document(collection="models")
public class Model{
#Id
private int id;
private String name;
#DBRef
private Brand brand;
...
//getters-setters
}
I would like to get all models from a brand, so I implement the DAO as follows:
#Repository
public interface IModelDAO extends MongoRepository<Model, Integer>{
#Query(value="{ 'brand.$id' : ?0 }")
public List<Model> findByBrandId(Integer id);
}
If I execute this mongodb query in the shell it works: db.modelss.find({ 'brand.$id' : 1 })
But, the Java application throws the following exception:
Caused by: java.lang.IllegalAccessError
at org.springframework.data.mapping.PropertyReferenceException.detectPotentialMatches(PropertyReferenceException.java:134)
Apparently it is looking for a field $id in Brand class, and since it doesn't exist it fails. So I change the query to the following, so that it navigates to the id field:
#Query(value="{ 'brand.id' : ?0 }")
Now, it doesn't throw an exception but it doesn't find anything in the DB.
Debugging the MongoTemplate.executeFindMultiInternal() method in can see that in
DBCursor cursor = null;
try {
cursor = collectionCallback.doInCollection(getAndPrepareCollection(getDb(), collectionName));
cursor's query is query={ "brand" : 134}. So it makes sense it doesn't find anything. Changing the query value during debugging to query={ "brand.$id" : 134} it works.
So, why isn't the query correctly translated?
The problem was caused by the #Id int type. Changing it to Integer solved it:
#Document(collection="brands")
public class Brand{
#Id
private Integer id;
private String name;
...
//getters-setters
}
#Document(collection="models")
public class Model{
#Id
private Integer id;
private String name;
#DBRef
private Brand brand;
...
//getters-setters
}
try this;
Query que = new Query();
que.addCriteria(Criteria.where("user.$id").is(new ObjectId("123456789012345678901234")));
Related
I have two models, Owner and Contract. A contract has an instance of an owner, owner does not have a list of contracts. I'm trying to query my list of contracts, to return a list filtered by owner, ie, a list of contracts by owner.
I had tried to follow previous examples and use Criteria to write a custom query, but, following suggestions I've checked the docks and tried to use named queries instead, however, I'm still really struggling.
There was an unexpected error (type=Internal Server Error, status=500).
Named parameter not bound : ownerId; nested exception is org.hibernate.QueryException: Named parameter not bound : ownerId
My models look like this:
#Entity
#Table(name="Contracts")
#NamedQueries({
#NamedQuery(
name = "Contract.allContractsByOwner",
query = "SELECT c FROM Contract c WHERE c.owner.id LIKE :ownerId"
)
})
public class Contract {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column
private Long id;
#ManyToOne
private Owner owner;
#Column
private double price;
#Column
private String deliverDate;
public Contract(Owner owner, double price, String deliverDate) {
this.id = id;
this.owner = owner;
this.price = price;
this.deliverDate = deliverDate;
}
and
#Entity
#Table(name="Owners")
public class Owner {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column
private Long id;
#Column
private String name;
public Owner(String name){
this.name = name;
}
my contractRepoImpl
#Service
public class ContractRepositoryImpl implements ContractRepositoryCustom {
ContractRepository contractRepository;
#Autowired
EntityManager entityManager;
public List allContractsByOwner(Long ownerId) {
List contracts = entityManager.createQuery(
"SELECT c FROM Contract c WHERE c.owner.id LIKE :ownerId", Contract.class)
.getResultList();
return contracts;
}
}
which I name in my ContractRepo and ContractRepoCustom files, and then in my controller I map to it like so. But, when I query it in my browser I get the error in my terminal.
#GetMapping(value="/owners/{ownerId}/contracts")
public List allContractsByOwner(#PathVariable("ownerId") Long ownerId){
return contractRepository.allContractsByOwner(ownerId);
}
I appreciate this is probably beginners mistakes, I am trying to follow docs but get a bit stuck with syntax & where annotations need to go.
Thanks JB Nizet, got there in the end
I added parameters to my contractRepoImpl
#Service
public class ContractRepositoryImpl implements ContractRepositoryCustom {
ContractRepository contractRepository;
#Autowired
EntityManager entityManager;
public List allContractsByOwner(Long id) {
List contracts = entityManager.createQuery(
"SELECT c FROM Contract c WHERE c.owner.id = :ownerId", Contract.class)
.setParameter("ownerId", id)
.getResultList();
return contracts;
}
}
that then produced a SQL error, which I fixed by changing my #NamedQuery from 'LIKE' to '=' in my Contract class...
#NamedQueries({
#NamedQuery(
name = "Contract.allContractsByOwner",
query = "SELECT c FROM Contract c WHERE c.owner.id = :ownerId"
)
})
I'm using a JPA query that uses a specification to retrieve entities. When I execute the query, I'm getting the error:
org.springframework.data.mapping.PropertyReferenceException: No property name found for type Task!
I've looked at the answers to similar questions that have been asked on this site previously & tried to model my code to follow the patterns that were recommended but the code is still failing.
When I step through the code with a debugger, the expanded path in the criteria builder is returning the embedded ID class, but when the specification is actually used in the query it looks like the attribute is being applied to the base entity class.
Am I missing something obvious?
Here is the entity class:
#Entity
#Table(name = "TASKS")
public class Task implements Serializable {
#EmbeddedId
private TaskId id;
...more attributes, getters and setters
}
Here is the embedded ID entity class:
#Embeddable
public class TaskId implements Serializable {
#Column(name = "NAME", length = 100)
private String name;
...more attributes, getters and setters
}
Here is the specification builder that matches on the embedded id 'name' attribute:
public class HasTaskNameSpec {
private HasTaskNameSpec() {
}
public static Specification<Task> equals(String name) {
return (root, query, criteriaBuilder) -> {
return criteriaBuilder.equal(root.get("id").get("name"), taskName);
};
}
}
The query is executed on the repository as follows:
List<Task> results = taskRepository.findAll(HasTaskNameSpec.equals("foo"));
The repository itself is very simple:
public interface TaskRepository extends JpaRepository<Task, TaskId>, JpaSpecificationExecutor<Task> {
List<Task> findByIdName(String name);
Page<Task> findByIdName(String name, Pageable page);
}
** EDIT added methods to repository as was suggested below **
Ahh, the root cause was totally in our codebase. There was a sort order being specified on the page that didn't include the embedded "id" attribute. The above code works.
'root.get({embeddedIdName}).get({subPropertyName})' is used to query on embeddedId using specification.
#Embeddable
public class ProjectId implements Serializable{
private static final long serialVersionUID = 1L;
#Column(name = "PROJECT_NAME")
private String projectName;
#Column(name = "ORGANIZATION")
private String organization;
......
......
}
#Entity
#Table(name = "projects")
public class Project {
#EmbeddedId
private ProjectId projectId;
#Column(name = "STARTED_TIME")
private Timestamp startedTime;
#Column(name = "ACTIVE")
private String active;
#Column(name = "DESCRIPTION")
private String description;
......
......
}
In the above snippet, ProjectId is an embedded id. To query on projectName, we should use below snippet.
expression = root.get("projectId").get("projectName");
Demo application link.
Take a look at this link which has a similar query.
EmbbededId Lookup
The final answer suggests that you can add a method to your TaskRepository thus.
public interface TaskRepository extends JpaRepository<Task, TaskId>, JpaSpecificationExecutor<Task> {
public List<Task> findByIdName(String name);
}
I am attempting to retrieve a list of results from my database, by following an example in this answer. Howeverm, I keep getting the following error:
java.lang.AbstractMethodError: org.hibernate.ejb.EntityManagerImpl.createQuery(Ljava/lang/String;Ljava/lang/Class;)Ljavax/persistence/TypedQuery;
Here is my code, to denote how I am calling this:
#Entity
#Table(name = "MY_TABLE")
public class CoolsEntity implements Serializable {
#Id
#Column(name = "ID", columnDefinition = "Decimal(10,0)")
#GeneratedValue(strategy = GenerationType.IDENTITY)
private String id;
#Column(name = "COOL_GUY_NAME")
private String name;
public String getId() {
return id;
}
public void setId(final String id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(final String name) {
this.name= name;
}
}
This code below generates the error:
final String sql = "select c from CoolsEntity c";
final TypedQuery<CoolsEntity> query = em.createQuery(sql, CoolsEntity.class);
final List<CoolsEntity> results = query.getResultList();
return results;
However, if I do something like this, I can see the results:
final String sql = "select c from CoolsEntity c";
final Query query = em.createQuery(sql);
#SuppressWarnings("unchecked")
final List<CoolsEntity> results = query.getResultList();
return results;
All of the references to em are imported through this package:
import javax.persistence.EntityManager
Shouldn't the two queries above generate the same result? Am I missing a cast to the List interface to allow this to work in the typed query?
You have an AbstractMethodError exception which is thrown when an application tries to call an abstract method.
You have quite a mix of Hibernate and JPA versions.
TypedQuery was introduced in JPA 2.0 and Hibernate implements this specification since 3.5.X
Suggesstion : Use implementation from Hibernate version 3.6.3 (or higher).
you are probably using two differnet version of interface EntityManager and implementation EntityManagerImpl.
I want to insert doctor object to database, how should I put annotations for properties?
I tried to do it with te code shown below.
But i don't know how to do it on list properties specializations and phoneNumbers.
#Table(databaseName = WMDatabase.NAME)
public class Doctor extends BaseModel{
#Column
#PrimaryKey
#Unique(unique = true)
private String doctorId;
#Column
private FullName fullName;
#Column
private String organizationId;
#Column What shuld i put here?????
private List<Specialization> specializations;
#Column What shuld i put here?????
private Contacts contacts;
}
Below are the classes I use for doctor attributes:
public class Contacts extends BaseModel {
private List<PhoneNumber> phoneNumbers;
private String email;
private String fax;
}
public class Specialization extends BaseModel {
#Column
#PrimaryKey
#Unique(unique = true)
private String doctorId;
#Unique(unique = true)
private String specializationName;
public String getSpecializationName() {
return specializationName;
}
public void setSpecializationName(String specializationName) {
this.specializationName = specializationName;
}
DBFlow is a relational database system (not a mongo-type key/value store) and doesn't support lists as columns, according to the doc here.
List : List columns are not supported and not generally proper for a relational database. However, you can get away with a non-generic List column via a TypeConverter. But again, avoid this if you can.
The documentation on relationships may help you refine the model to suit your needs.
The following query throws the exception:
Query query = session.createQuery("from Associate as a order by a.username asc");
associates = query.list();
org.hibernate.ObjectNotFoundException: No row with the given identifier exists: [ca.mypkg.model.Associate#0]
If I create an entry in the database with id of 0 it works just fine. I don't really get it because I'm just trying to load all the entries in the db not just a specific one.
Similar questions I've found have been concerned with trying to load an object with a given ID I'm doing no such thing.
Associate class:
#Table(name = "user")
#XmlRootElement(name = "associate")
public class Associate implements Serializable {
private String username;
private String password;
private String firstName;
private String lastName;
private String userType;
private int id;
private String email;
private String isActive;
private Department dept;
private String lastUpdated;
private String associate_type;
// ...
#Id
#GeneratedValue
public int getId() {
return id;
}
#OneToOne
#JoinColumn(name = "dept")
public Department getDept() {
return dept;
}
From my experience this type of error message usually means it does not find joined entity by mentioned id, and not the entity requested in the query (Associate, in your case).
My guess is that Associate class contains a join entity which has primitive type primary key.