Confusing indentation, why and how it can happen - java

This is actually not a problem for solving but I felt curious that why the following code would gives the confusing indentation warning for possible missing of surrounding block:
if(x!=y)
System.out.println("not equal");
index++;
If I put the System.out.println("not equal"); inside {} the warning would go away but I feel curious in what situation the current looking code would go wrong.

The problem is that, when you read this code, you are missing a visual cue that the System.out.println("not equal"); is only run when the condition (x!=y) is true. The error will go away as well when you indent the code:
if (x != y)
System.out.println("not equal");
Some people may still advise against using single-line consequences and encourage you to use blocks anyway. People might be tempted to just add another line of code underneath the System.out, thinking that it will also just be executed when x != y - without noticing that the braces are missing.

Anything within an if statement is generally indented for clarity. For instance:
if(foo) {
if (bar) {
System.out.println("foo bar");
}
}
As you are writing only a 1 line statement, you don't need the {} but indentation is still recommended. Without it, it is not immediately obvious what will and won't get executed.
For instance, if someone reading your code didn't know that only 1 line get's executed in an if statement with no brackets, they might think the index++; line will only get called if (x!=y)
Also, you are more likely to make mistakes as a developer if you don't use {} for all if statements. If you get into the habit of not using them, and you forget to use them for a multi-line if statement, you will get unexpected results. For instance, if you decided to put something after the System.out.println("not equal"); within the if block, it would be very easy to forget the {}.

Related

unreachable code when trying to stop executing method if condition true [duplicate]

Today, after half an hour of searching for a bug, I discovered that it is possible to put a semicolon after an if statement instead of code, like this:
if(a == b);
// Do stuff
Which basically means that the stuff will be done whether a equals b or not, and the if statement has no point whatsoever. Why doesn't Java give me an error? Is there any situation in which this would be useful?
Why does it happen?
Java Language Specification says that:
The Empty Statement
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally
It essentially means that you want to execute empty statement if a==b
if(a == b);
What should you do:
There are two main solutions to this problem:
You can avoid problems with empty statement by using code formatter
and surrounding stuff inside if with { and }. By doing this
Your empty statement will be much more readable.
if(a == b){
;
}
You can also check tools used for static code analysis such as:
Findbugs
Checkstyle
Pmd
They can instantly highlight problems such as this one.
I would recommend to combine both solutions.
Is there any situation in which this would be useful?
Useful? As in "makes your code cleaner, clearer, faster, more maintainable"? Not at all. This is most likely poor, confusing code.
But it's not necessarily benign. Such a statement can perform actions and/or alter state due to methods which cause side effects, and optionally evaluate those methods due to short-circuiting of operators.
if( a() && b() );
Here, a() or b() may do something, and b() will only execute if a() is true.
As to why, I think the answer is simply that it would be worse to deviate from defined, expected behavior (e.g. statements like while(reader.read());) than the alternative of developers writing bad code.
Writing bad code is always possible. And just to reiterate, this would be bad code in almost any case.
A possible use case:
if (a==b);
else {
// Do something
}
Not good, but possible.
Still, I do think that the Java specification should disallow an empty if.
If you're using Eclipse, you can make it warn you about those statements:
If you use an if statement, the first statement after the if will be executed if the condition is true. If you have a block after the if (with curly braces), it counts for that whole block. If there is no block it counts for only one statement. A single semicolon is an empty statement. You could also write the code from you example like this:
if(a==b) {
;
}
It is an old leftover from the days when there was more syntactic sugar to differentiate expressions from statements.
Basically, the comma was used as the list item separator, so the semicolon was used as the "list of statements" separator. The downside is in the handling of null items in lists, and null statements in blocks.
In a list of items, Java uses the explicit keyword null, but a "null statement" is just an empty line. Allowing the existence of an empty line is a holdover from tradition inherited from C.
Why do it? Especially with an if statement when you know that no statements are being executed: Because some if statements have side effects:
int c;
if ((c = in.read()) != -1);
Yes, it is not the best example, but basically it says read a byte from the stream and do nothing. Might be useful in some corner cases, but even if this example isn't the best, it illustrates the intent. We want to feel the side-effects of the expression without accidentally executing any statements.
I can't think of an occasion where it is useful. It can be useful for loops like
while(do something);
or
for(init; do something; something else);
If you use your code formatting in your IDE regularly these sort of bugs become obvious. Some IDEs highlight this as a probable bug as well.
I'd agree with you there's no useful purpose to this for a human. I suspect it's there because it simplifies the language definition; it means that the thing that comes after an if is e same as the thing that comes after a while, for instance.
Why? It's because its easier for compiler writers. You don't have to make a special case to check for semicolons after if(cond) and has an added usage of allowing
if (cond && maybeFunc())
;// Code here I want to ignore
Even though it's actually a terrible idea to allow this. It's just easier to allow and then to add a case to check this.
Java allows an empty block any place a statement block is allowed. I am sure making this a general rule for all blocks simplifies the compiler.
I agree that this is primarily the cause of bugs that are spectacularly hard to find. I always use braces around blocks, even when there is a single statement, but Java allows you to make a block with braces at any point, so using braces can not save you from this fate. For example, I once wasted 4 hours trying find something like this:
while (condition);
{
statement;
statement;
}
The semicolon at the end of the first line was a typo, accidentally making the statement block for the while loop empty. Because the syntax is valid the program compiled and ran fine, just not the way I wanted it to. It was really hard to find.
I can think of one situation where it is very nice that you are allowed to have empty blocks, and this is something like this:
if (condition1) {
do_action_1();
}
else if (condition2) {
//nothing really to do in this case
}
else if (condition3) {
do_action2();
}
else {
do_action3();
}
In the above example, you want to be able to separate out various conditions. Remember, those conditions might be overlapping, so it is not always possible to rearrange the order. If one of the conditions really does not need anything done, then it is nice that Java allows you to have an empty block. Otherwise, the language would need some form of a "noop" method to use when you really do not want anything done.
I personally would prefer the explicit "noop" statement -- but that is not how Java is defined.
Just a FYI about the usability and what difference it makes or can make if there is a statement like that
Consider a piece of code like the following.
int a = 10;
if ((a = 50) == 50);
System.out.println("Value of a = " + a);
Clearly in this case, the if statement does change the output. So a statement like that can make a difference.
This is a situation where this could be useful or better to say have an impact on program.
if(a==b)
println("a equals b");
You can use an IF statement without {} if there is only a single line to be executed, so by using if(a==b); you are saying if they equal, execute and empty statement... So it will do nothing, and then return to your normal loop, outside of the IF block.
A few definitions from the jls explain this (chapter 14):
Blocks are Statements
As stated here, a Block is a StatementWithoutTrailingSubstatement, which in turn is a StatementNoShortIf, which is a Statement. Thus where ever any of these is required, we can insert a Block.
The if-clause
Though this is as well the case for for and while-loops, I'll use if-statements. These rules are pretty much the same. The syntactical description of if-statements can be found here.
IfThenStatement:
if ( Expression ) Statement
IfThenElseStatement:
if ( Expression ) StatementNoShortIf else Statement
IfThenElseStatementNoShortIf:
if ( Expression ) StatementNoShortIf else StatementNoShortIf
So we can use our block here.
But why does it work with ; ?
; is defined as the EmptyStatement (link), which is as well a StatementNoShortIf. So in conditional pieces of code, like if-statement and loops, we can replace a Block with a EmptyStatement, if a StatementNoShortIf or Statement is required.
Thus if(Expression)EmptyStatement works.
Why doesn't this give an error?
Pretty simple: java gives an error if it finds invalid syntax. But if(Expression)EmptyStatement is perfectly valid syntax. Instead javac gives a warning if launched with the proper parameters. The full list of warnings that can be dis-/enabled lists the warning-name empty for this purpose. So compilation with -Xlint:all or -Xlint:empty will generate a warning about this.
Your IDE should have an option to enable this kind of warning as well.
For eclipse, see #nullptr's answer. In IntelliJ, you can press Ctrl + Shift + A, enter empty body into the search field and enable the warning (marked in the image)
What is this even used for?
To be honest, there's not much use in it from a minimalistic point of view. There's usually a way to get things done without a "do nothing" command. It's rather a question of personal preferences, whether you rather use
if( a() && b() );
or
if( a() ) b();
and same would apply to other cases, in which the EmptyStatement is used. An important point to consider on this topic is readability of code. There are occasions, where code becomes more readable by using the no-op. On the other hand there are cases, where code becomes quite a lot harder to comprehend with using the EmptyStatement - the above example would count to the later IMO.
I can think of a scenario where an empty statement is required (not for if condition but for while loop).
When a program just want an explicit confirmation from the user to proceed. This may be required when the work after the user confirmation depends on some other things and user want to take control of when to proceed.
System.out.println("Enter Y to proceed. Waiting...");
System.out.println("");
while(!(new Scanner(System.in).next().equalsIgnoreCase("Y")));
System.out.println("Proceeding...");
// do the work here
look this:
int a,b,c = 0;
if(a == b){
c =1;
}
System.out.print(c);//1
so, you can write like this:
if (a == b)c=1;
but,if this code is this:
int a,b,c=0;
if (a != b){
}
if (a == b ){
c =1;
}
you can write like this:
if(a != b);
if(a == b )c=1;
so,you will know if(a != b); do noting
The semi-colon in the if indicates the termination of the if condition as in java ; is treated as the end of a statement, so the statement after if gets executed.
Semicolon at the end of,
if(a==b); simply finish the statement in single line which means ignore the result of condition and continue the execution from the next line
This code is useful, on the other hand sometime introduce bug in program, for example,
case 1.
a = 5;
b = 3;
if(a == b);
prinf("a and b are equal");
case 2.
a = 5;
b = 5;
if(a == b);
prinf("a and b are equal");
would print the same output on the screen...
While working on a programming assignment for class where I am working with a N by N grid of doodads and comparing characteristics of a random doodad to those above, below, left, and right, I found a nice use of this to prevent nested statements and potential boundary exceptions. My goal was to minimize code and keep from nesting if-statements.
if (row == 0);
else (method (grid[row][col], grid[row-1][col]));
if (row == N-1);
else (method (grid[row][col], grid[row+1][col]));
if (col == 0);
else (method (grid[row][col], grid[row][col-1]));
if (col == N-1);<br>
else (method (grid[row][col], grid[row][col+1]));
where method(Doodad a, Doodad b) does some operation between a and b.
Alternatively, you could use exception handling to avoid this syntax, but it works and works well for my application.

Is using return at the start of method bad coding practice?

I have found myself using the following practice, but something inside me kind of cringes every time i use it. Basically, it's a precondition test on the parameters to determine if the actual work should be done.
public static void doSomething(List<String> things)
{
if(things == null || things.size() <= 0)
return;
//...snip... do actual work
}
It is good practice to return at the earliest opportunity.
That way the least amount of code gets executed and evaluated.
Code that does not run cannot be in error.
Furthermore it makes the function easier to read, because you do not have to deal with all the cases that do not apply anymore.
Compare the following code
private Date someMethod(Boolean test) {
Date result;
if (null == test) {
result = null
} else {
result = test ? something : other;
}
return result;
}
vs
private Date someMethod(Boolean test) {
if (null == test) {
return null
}
return test ? something : other;
}
The second one is shorter, does not need an else and does not need the temp variable.
Note that in Java the return statement exits the function right away; in other languages (e.g. Pascal) the almost equivalent code result:= something; does not return.
Because of this fact it is customary to return at many points in Java methods.
Calling this bad practice is ignoring the fact that that particular train has long since left the station in Java.
If you are going to exit a function at many points in a function anyway, it's best to exit at the earliest opportunity
It's a matter of style and personal preference. There's nothing wrong with it.
To the best of my understanding - no.
For the sake of easier debugging there should be only one return/exit point in a subroutine, method or function.
With such approach your program may become longer and less readable, but while debugging you can put a break point at the exit and always see the state of what you return. For example you can log the state of all local variables - it may be really helpful for troubleshooting.
It looks like there a two "schools" - one says "return as early as possible", whereas another one says "there should be only one return/exit point in a program".
I am a proponent of the first one, though in practice sometimes follow the second one, just to save time.
Also, do not forget about exceptions. Very often the fact that you have to return from a method early means that you are in an exceptional situation. In your example I think throwing an exception is more appropriate.
PMD seems to think so, and that you should always let your methods run to the end, however, for certain quick sanity checks, I still use premature return statements.
It does impair the readability of the method a little, but in some cases that can be better than adding yet another if statement or other means by which to run the method to the end for all cases.
There's nothing inherently wrong with it, but if it makes you cringe, you could throw an IllegalArgumentException instead. In some cases, that's more accurate. It could, however, result in a bunch of code that look this whenever you call doSomething:
try {
doSomething(myList);
} catch (IllegalArgumentException e) {}
There is no correct answer to this question, it is a matter of taste.
In the specific example above there may be better ways of enforcing a pre-condition, but I view the general pattern of multiple early returns as akin to guards in functional programming.
I personally have no issue with this style - I think it can result in cleaner code. Trying contort everything to have a single exit point can increase verbosity and reduce readability.
It's good practice. So continue with your good work.
There is nothing wrong with it. Personally, I would use else statement to execute the rest of the function, and let it return naturally.
If you want to avoid the "return" in your method : maybe you could use a subClass of Exception of your own and handle it in your method's call ?
For example :
public static void doSomething(List<String> things) throws MyExceptionIfThingsIsEmpty {
if(things == null || things.size() <= 0)
throw new MyExceptionIfThingsIsEmpty(1, "Error, the list is empty !");
//...snip... do actual work
}
Edit :
If you don't want to use the "return" statement, you could do the opposite in the if() :
if(things != null && things.size() > 0)
// do your things
If function is long (say, 20 lines or more), then, it is good to return for few error conditions in the beginning so that reader of code can focus on logic when reading rest of the function. If function is small (say 5 lines or less), then return statements in the beginning can be distracting for reader.
So, decision should be based on primarily on whether the function becomes more readable or less readable.
Java good practices say that, as often as possible, return statements should be unique and written at the end of the method. To control what you return, use a variable. However, for returning from a void method, like the example you use, what I'd do would be perform the check in a middle method used only for such purpose. Anyway, don't take this too serious - keywords like continue should never be used according to Java good practices, but they're there, inside your scope.

Semicolon at end of 'if' statement

Today, after half an hour of searching for a bug, I discovered that it is possible to put a semicolon after an if statement instead of code, like this:
if(a == b);
// Do stuff
Which basically means that the stuff will be done whether a equals b or not, and the if statement has no point whatsoever. Why doesn't Java give me an error? Is there any situation in which this would be useful?
Why does it happen?
Java Language Specification says that:
The Empty Statement
An empty statement does nothing.
EmptyStatement:
;
Execution of an empty statement always completes normally
It essentially means that you want to execute empty statement if a==b
if(a == b);
What should you do:
There are two main solutions to this problem:
You can avoid problems with empty statement by using code formatter
and surrounding stuff inside if with { and }. By doing this
Your empty statement will be much more readable.
if(a == b){
;
}
You can also check tools used for static code analysis such as:
Findbugs
Checkstyle
Pmd
They can instantly highlight problems such as this one.
I would recommend to combine both solutions.
Is there any situation in which this would be useful?
Useful? As in "makes your code cleaner, clearer, faster, more maintainable"? Not at all. This is most likely poor, confusing code.
But it's not necessarily benign. Such a statement can perform actions and/or alter state due to methods which cause side effects, and optionally evaluate those methods due to short-circuiting of operators.
if( a() && b() );
Here, a() or b() may do something, and b() will only execute if a() is true.
As to why, I think the answer is simply that it would be worse to deviate from defined, expected behavior (e.g. statements like while(reader.read());) than the alternative of developers writing bad code.
Writing bad code is always possible. And just to reiterate, this would be bad code in almost any case.
A possible use case:
if (a==b);
else {
// Do something
}
Not good, but possible.
Still, I do think that the Java specification should disallow an empty if.
If you're using Eclipse, you can make it warn you about those statements:
If you use an if statement, the first statement after the if will be executed if the condition is true. If you have a block after the if (with curly braces), it counts for that whole block. If there is no block it counts for only one statement. A single semicolon is an empty statement. You could also write the code from you example like this:
if(a==b) {
;
}
It is an old leftover from the days when there was more syntactic sugar to differentiate expressions from statements.
Basically, the comma was used as the list item separator, so the semicolon was used as the "list of statements" separator. The downside is in the handling of null items in lists, and null statements in blocks.
In a list of items, Java uses the explicit keyword null, but a "null statement" is just an empty line. Allowing the existence of an empty line is a holdover from tradition inherited from C.
Why do it? Especially with an if statement when you know that no statements are being executed: Because some if statements have side effects:
int c;
if ((c = in.read()) != -1);
Yes, it is not the best example, but basically it says read a byte from the stream and do nothing. Might be useful in some corner cases, but even if this example isn't the best, it illustrates the intent. We want to feel the side-effects of the expression without accidentally executing any statements.
I can't think of an occasion where it is useful. It can be useful for loops like
while(do something);
or
for(init; do something; something else);
If you use your code formatting in your IDE regularly these sort of bugs become obvious. Some IDEs highlight this as a probable bug as well.
I'd agree with you there's no useful purpose to this for a human. I suspect it's there because it simplifies the language definition; it means that the thing that comes after an if is e same as the thing that comes after a while, for instance.
Why? It's because its easier for compiler writers. You don't have to make a special case to check for semicolons after if(cond) and has an added usage of allowing
if (cond && maybeFunc())
;// Code here I want to ignore
Even though it's actually a terrible idea to allow this. It's just easier to allow and then to add a case to check this.
Java allows an empty block any place a statement block is allowed. I am sure making this a general rule for all blocks simplifies the compiler.
I agree that this is primarily the cause of bugs that are spectacularly hard to find. I always use braces around blocks, even when there is a single statement, but Java allows you to make a block with braces at any point, so using braces can not save you from this fate. For example, I once wasted 4 hours trying find something like this:
while (condition);
{
statement;
statement;
}
The semicolon at the end of the first line was a typo, accidentally making the statement block for the while loop empty. Because the syntax is valid the program compiled and ran fine, just not the way I wanted it to. It was really hard to find.
I can think of one situation where it is very nice that you are allowed to have empty blocks, and this is something like this:
if (condition1) {
do_action_1();
}
else if (condition2) {
//nothing really to do in this case
}
else if (condition3) {
do_action2();
}
else {
do_action3();
}
In the above example, you want to be able to separate out various conditions. Remember, those conditions might be overlapping, so it is not always possible to rearrange the order. If one of the conditions really does not need anything done, then it is nice that Java allows you to have an empty block. Otherwise, the language would need some form of a "noop" method to use when you really do not want anything done.
I personally would prefer the explicit "noop" statement -- but that is not how Java is defined.
Just a FYI about the usability and what difference it makes or can make if there is a statement like that
Consider a piece of code like the following.
int a = 10;
if ((a = 50) == 50);
System.out.println("Value of a = " + a);
Clearly in this case, the if statement does change the output. So a statement like that can make a difference.
This is a situation where this could be useful or better to say have an impact on program.
if(a==b)
println("a equals b");
You can use an IF statement without {} if there is only a single line to be executed, so by using if(a==b); you are saying if they equal, execute and empty statement... So it will do nothing, and then return to your normal loop, outside of the IF block.
A few definitions from the jls explain this (chapter 14):
Blocks are Statements
As stated here, a Block is a StatementWithoutTrailingSubstatement, which in turn is a StatementNoShortIf, which is a Statement. Thus where ever any of these is required, we can insert a Block.
The if-clause
Though this is as well the case for for and while-loops, I'll use if-statements. These rules are pretty much the same. The syntactical description of if-statements can be found here.
IfThenStatement:
if ( Expression ) Statement
IfThenElseStatement:
if ( Expression ) StatementNoShortIf else Statement
IfThenElseStatementNoShortIf:
if ( Expression ) StatementNoShortIf else StatementNoShortIf
So we can use our block here.
But why does it work with ; ?
; is defined as the EmptyStatement (link), which is as well a StatementNoShortIf. So in conditional pieces of code, like if-statement and loops, we can replace a Block with a EmptyStatement, if a StatementNoShortIf or Statement is required.
Thus if(Expression)EmptyStatement works.
Why doesn't this give an error?
Pretty simple: java gives an error if it finds invalid syntax. But if(Expression)EmptyStatement is perfectly valid syntax. Instead javac gives a warning if launched with the proper parameters. The full list of warnings that can be dis-/enabled lists the warning-name empty for this purpose. So compilation with -Xlint:all or -Xlint:empty will generate a warning about this.
Your IDE should have an option to enable this kind of warning as well.
For eclipse, see #nullptr's answer. In IntelliJ, you can press Ctrl + Shift + A, enter empty body into the search field and enable the warning (marked in the image)
What is this even used for?
To be honest, there's not much use in it from a minimalistic point of view. There's usually a way to get things done without a "do nothing" command. It's rather a question of personal preferences, whether you rather use
if( a() && b() );
or
if( a() ) b();
and same would apply to other cases, in which the EmptyStatement is used. An important point to consider on this topic is readability of code. There are occasions, where code becomes more readable by using the no-op. On the other hand there are cases, where code becomes quite a lot harder to comprehend with using the EmptyStatement - the above example would count to the later IMO.
I can think of a scenario where an empty statement is required (not for if condition but for while loop).
When a program just want an explicit confirmation from the user to proceed. This may be required when the work after the user confirmation depends on some other things and user want to take control of when to proceed.
System.out.println("Enter Y to proceed. Waiting...");
System.out.println("");
while(!(new Scanner(System.in).next().equalsIgnoreCase("Y")));
System.out.println("Proceeding...");
// do the work here
look this:
int a,b,c = 0;
if(a == b){
c =1;
}
System.out.print(c);//1
so, you can write like this:
if (a == b)c=1;
but,if this code is this:
int a,b,c=0;
if (a != b){
}
if (a == b ){
c =1;
}
you can write like this:
if(a != b);
if(a == b )c=1;
so,you will know if(a != b); do noting
The semi-colon in the if indicates the termination of the if condition as in java ; is treated as the end of a statement, so the statement after if gets executed.
Semicolon at the end of,
if(a==b); simply finish the statement in single line which means ignore the result of condition and continue the execution from the next line
This code is useful, on the other hand sometime introduce bug in program, for example,
case 1.
a = 5;
b = 3;
if(a == b);
prinf("a and b are equal");
case 2.
a = 5;
b = 5;
if(a == b);
prinf("a and b are equal");
would print the same output on the screen...
While working on a programming assignment for class where I am working with a N by N grid of doodads and comparing characteristics of a random doodad to those above, below, left, and right, I found a nice use of this to prevent nested statements and potential boundary exceptions. My goal was to minimize code and keep from nesting if-statements.
if (row == 0);
else (method (grid[row][col], grid[row-1][col]));
if (row == N-1);
else (method (grid[row][col], grid[row+1][col]));
if (col == 0);
else (method (grid[row][col], grid[row][col-1]));
if (col == N-1);<br>
else (method (grid[row][col], grid[row][col+1]));
where method(Doodad a, Doodad b) does some operation between a and b.
Alternatively, you could use exception handling to avoid this syntax, but it works and works well for my application.

Is there a way to ignore the 'Unreachable statement' error?

Is it possible to somehow ignore this error? I find it much easier to just put return in front of the code I don't want to run than to comment it (when the comments overlap and behave badly)...
No. It's a compile time error. So you must get rid of it before running your class.
What I usually do is put a fake if statement in front of it. Something like:
if(true)
return;
// unwanted code follows. no errors.
i++;
j++;
With this code, you will not get a Unreachable statement error. And you will get what you want.
33. if (1==1) return;
34. System.out.println("Hello world!");
It works in other languages too. But ByteCode without row 34.
It isn't possible to ignore this error since it is an error according to the Java Language Specification.
You might also want to look at this post: Unreachable code error vs. dead code warning in Java under Eclipse?
If you want disable/enable certain piece of code many times trick from old C may help you:
some_code();
more_code();
// */
/*
some_code();
more_code();
// */
Now you need only to write /* at the beginning
you have to fix that unreachable code.
public void display(){
return; //move the return statement to appropriate place
int i;
}
compiler will not compile your source code.
you have to take care of your source code that every line is reachable to compiler.

Java for-loop, do i need continue statement here?

Consider this code:
if (int a == 0) {
System.out.println("hello");
continue;
}
This if is part of a for loop in java. What is the significane of continue statement here? I know continue is the opposite of break so that it wont break out of the loop rather just skip that iteration for anything below it. But in case it is inside an if statement, do I really need it like this?
No, you don't need to use continue there, you can use an else block instead:
if (a == 0) {
System.out.println("hello");
} else {
// The rest of the loop body goes here.
}
Which is better is a style issue. Sometimes one is better, sometimes the other - it depends on what the typical flow should be and which flow you want to emphasize in the code.
If this is the last statement of the for loop - no, you don't need it. Otherwise you need it to skip everything below the if-clause. If you don't want to skip it, then don't use continue.
Here is an explanation with examples of what continue is doing.
continue means that the statements below the if block won't work. If this is the behavior you need, you should continue. Otherwise it is not needed.

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