Stack Push Method Infinite Loop Java - java

I do not understand why printList() loops infinitely when called. I am attempting to code a stack linked list and print the list without using the built-in stack methods in java. Why is my print method looping infinitely and how do I correct this issue?
public class LinkedListStack{
private String item;
private Node next;
private Node top = null;
public LinkedListStack(){
}
public void push(String item){
top = new Node(item, top);
}
public void printList(){
Node currentNode = top;
for(currentNode = top; currentNode.getItem()!= null; currentNode = currentNode.getNext()){
System.out.println(currentNode.getItem());
}
}
public class Node{
public Node(String newItem, Node nextNode){
item = newItem;
next = nextNode;
}
public Node(String newItem){
item = newItem;
next = null;
}
//to set the value of the next field
public void setNext(Node nextNode){
next = nextNode;
}
//read the value of the next field
public Node getNext(){
return(next);
}
//to set the value of the item field
public String setItem(String newItem){
item = newItem;
return(item);
}
//read the value of the item field
public String getItem(){
return(item);
}
}
public static void main(String args[]){
LinkedListStack newList = new LinkedListStack();
newList.push("hello");
newList.push("goodbye");
newList.printList();
}
}

The problem is that item and next are fields of LinkedListStack and shared between all Node instances. When you create another Node and set the item you change all nodes. To fix it just move the field declarations to the Node inner class.
Beside that, your loop's condition in the printList method is wrong: the next node is null, not its item.
Here is a working example:
public class LinkedListStack {
private Node top = null;
public LinkedListStack() {
}
public void push(final String item) {
top = new Node(item, top);
}
public void printList() {
Node currentNode = top;
for (currentNode = top; currentNode != null; currentNode = currentNode.getNext()) {
System.out.println(currentNode.getItem());
}
}
public class Node {
private String item;
private Node next;
public Node(final String newItem, final Node nextNode) {
item = newItem;
next = nextNode;
}
public Node(final String newItem) {
item = newItem;
next = null;
}
// to set the value of the next field
public void setNext(final Node nextNode) {
next = nextNode;
}
// read the value of the next field
public Node getNext() {
return next;
}
// to set the value of the item field
public String setItem(final String newItem) {
item = newItem;
return item;
}
// read the value of the item field
public String getItem() {
return item;
}
}
public static void main(final String args[]) {
final LinkedListStack newList = new LinkedListStack();
newList.push("hello");
newList.push("goodbye");
newList.printList();
}
}

Related

Add and Print new Nodes

I was working on a program to add nodes to a list, but I seem to be doing something wrong...
My java program has three Classes; Demo, Lista and Node
Class Node:
public class Node {
private int num;
private Node tail;
private Node head;
public Node (int num, Node head, Node tail) {
this.num = num;
this.head = head;
this.tail = tail;
}
}
Class Lista:
public class Lista {
private Node nil;
public Lista () {
nil = null;
}
public void add (int num) {
Node newNode = new Node(num, head, tail);
if (head == null) {
head = newNode;
tail = newNode;
}
}
public void display () {
Node current = head;
while(current != null) {
System.out.print(current.num);
}
}
}
Class Demo:
public class Demo {
public static void main ( String [] args) {
Lista lista = new Lista();
lista.add(3);
lista.add(9);
lista.add(7);
lista.display();
}
}
Demo class is to add the different nodes to the list "lista". Class Node has num, head which is the next one and tail which is the previous one. How can I go about getting Class Lista to be able to use head and tail from Class Node? And if it is possible would this code work when running Demo? What should I change/modify to get this to work?
You may want to modify your code something like this:
EDIT - This is a doubly-linked list implementation.
class Node {
int num;
Node prev;
Node next;
Node(int num) {
this.num = num;
}
Node(int num, Node prev, Node next) {
this.num = num;
this.prev = prev;
this.next = next;
}
void setPrev(Node prev) {
this.prev = prev;
}
void setNext(Node next) {
this.next = next;
}
}
class Lista {
Node root;
Node endNode;
public void add(int num) {
Node n = new Node(num);
if (root == null) {
root = n;
} else {
n.setPrev(endNode);
endNode.setNext(n);
}
endNode = n;
}
public void display() {
Node iterateeNode = root;
while (iterateeNode != null) {
System.out.print(iterateeNode.num + " ");
iterateeNode = iterateeNode.next;
}
}
}
The selected answer is technically not correct. For a (single) Linked List, all your Lista need is a single (head) node. Additionally, the Node class needs a single (next) Node field.
The following is a potential implementation of Node:
public class Node {
private Node next;
private int value;
public Node(int value) {
this.value = value;
}
public boolean hasNext() {
return next != null;
}
public Node next() {
return next;
}
public void add(Node node) {
if (next == null) {
next = node;
} else {
Node temp = next;
while (temp != null) {
temp = temp.next;
}
temp = node;
}
}
#Override
public String toString() {
return String.valueOf(value);
}
}
The add() method will insert the new node in next if it is null. Otherwise, it will traverse the nodes until it finds the tail node (the one where next is null).
The Lista has only the first element in the list (head node).
public class Lista {
private Node head;
public void add(Node node) {
if (head == null) {
head = node;
} else {
Node temp = head;
while (temp.hasNext()) {
temp = temp.next();
}
temp.add(node);
}
}
// Other methods
}
When the add() function in the list is called, it will either add the new node as the head (if the list doesn't have one already) or rely on the already added nodes to figure out where the end of the list is in order to insert the new node.
Lastly, to display the list, just override the toString() method in node and add the "toString" value to a string buffer and send the concatenated string value to the console similar to the the code below.
public void display() {
StringBuilder buff = new StringBuilder("[");
buff.append(head);
if (head != null) {
Node next = head.next();
buff.append(",");
while (next != null) {
buff.append(next);
next = next.next();
buff.append(",");
}
}
buff.append("]");
int idx = buff.lastIndexOf(",");
buff.replace(idx, idx+1, "");
System.out.println(buff.toString());
}
Executing the following displays [3,9,7] as expected.
public class Demo {
public static void main ( String [] args) {
Lista lista = new Lista();
lista.add(new Node(3));
lista.add(new Node(9));
lista.add(new Node(7));
lista.display();
}
}

When I pass the Node variable that is "top" inside the node objects ? does it help it to point the previous data?

I am writing a code to practice some linked list example with basics but came across a problem when in linked list class in voidadd method what does it means when I pass the Node variable that is "top" inside the node objects ? does it help it to point the previous data? i have indicated the part that refers to my question
public class Node
{
private int data;
private Node nextNode;
public Node(int dataP , Node nextNodeP)
{
data = dataP;nextNode = nextNodeP;
}
public int getData()
{
return data;
}
public Node getNextNode()
{
return nextNode;
}
public void setData(int newData) //to replace the value of some notes [12| ] --> [120| ]
{
data = newData;
}
public void setNext(Node newNextNode) // pointing to top ---> [120| ] ---> [last | null]
{
nextNode = newNextNode;
}
}
public class LinkedList {
private Node top;
private int size;
public LinkedList() {
top = null;
size = 0;
}
public int getSize() {
return size;
}
public void addNode(int newData) {
Node temp = new Node(newData, top); //question
top = temp; //points to the same
size++;
}
}
Define a node at its own class.
Here is a simple example :
public class LinkedList {
private Node first,last;
private int size ;
//adds node as last. not null safe
public void addNode(Node node) {
if(first == null) {
node.setParent(null);
first = node;
last = node;
}else {
node.setParent(last);
last = node;
}
size++;
}
public Node getFirst() {return first;}
public Node getLast() { return last; }
public int getSize() {return size;}
public static void main(String[] args) {
LinkedList list = new LinkedList();
list.addNode(new Node(0,null));
list.addNode(new Node(1,null));
list.addNode(new Node(2,null));
list.addNode(new Node(3,null));
Node node = list.getLast();
System.out.println("list has "+ list.size + " nodes:");
while(node != null) {
System.out.println(node);
node = node.getParent();
}
}
}
class Node{
private int data;
private Node parent;
Node(int nodeData, Node parent) {
data = nodeData;
this.parent = parent;
}
public int getData() { return data;}
public void setData(int data) { this.data = data; }
public Node getParent() {return parent; }
public void setParent(Node parent) {this.parent = parent;}
#Override
public String toString() {return "Node "+getData() +" parent:"+ getParent();}
}

How to change the order of a single linkedlist queue in java?

public class Node<E> {
private E element;
public Node<E> next;
int data;
Node(int d)
{
data = d;
next = null;
}
public Node(E element, Node<E> next) {
this.element = element;
this.next = next;
}
public E getElement() {
return element;
}
public Node<E> getNext() {
return next;
}
public void setElement(E element) {
this.element=element;
}
public void setNext(Node<E> n) {
next = n;
}
public void displayNode(){
System.out.print(element+ " ");
}
}
public class SinglyLinkedList<E> {
private Node<E> head;
private Node<E> tail;
private int size;
public SinglyLinkedList() {
head = tail = null;
size = 0;
}
public SinglyLinkedList(Node<E> head, Node<E> tail) {
this.head = head;
this.tail = tail;
}
public Node<E> getHead() {
return head;
}
public Node<E> getTail() {
return tail;
}
public void setHead(Node<E> head) {
this.head = head;
}
public void setTail(Node<E> tail) {
this.tail = tail;
}
public boolean isEmpty() {
if (head == null) {
return true;
}
return false;
}
public E first() {
return head.getElement();
}
public E last() {
return tail.getElement();
}
public void addFirst(E e) {
if (head == null) {
head = tail = new Node(e, null);
} else {
Node<E> newest = new Node(e, head);
head = newest;
}
size++;
}
public void addLast(E e) {
if (tail == null) {
head = tail = new Node(e, null);
} else {
Node<E> newest = new Node(e, null);
tail.setNext(newest);
tail = newest;
}
size++;
}
public E removeFirst() {
E e = head.getElement();
head = head.getNext();
size--;
return e;
}
#Override
public String toString() {
Node<E> tmp = head;
String s = "";
while (tmp != null) {
s += tmp.getElement();
tmp=tmp.getNext();
}
return s;
}
public void displayList() {
Node current = head;
while (current != null) {
current.displayNode();
current = current.next;
}
}
}
public interface Queue<E> {
int size();
boolean isEmpty();
void enqueue( );
E first();
E dequeue();
}
public class LinkedQueue<E> implements Queue<E> {
private SinglyLinkedList<E> list = new SinglyLinkedList<>();
public LinkedQueue() {
}
public int size() {
return list.size();
}
public boolean isEmpty() {
return list.isEmpty();
}
public void enqueue(E element) {
list.addLast(element);
}
public E first() {
return list.first();
}
public E dequeue() {
return list.removeFirst();
}
#Override
public void enqueue() {
throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools |list.addLast(element);
}
public void displayQueue() {
list.displayList();
System.out.println();
}
public class Main {
public static void main(String[] args) {
LinkedQueue list = new LinkedQueue();
list.enqueue(sam);
list.enqueue(adams);
list.enqueue(john);
list.enqueue(isac);
list.enqueue(gad);
System.out.print("\n Linked list before calling swapNodes() ");
list.displayQueue();
}}
How to change the order of these names in the queue?
I have try to put function that swap nodes in the singlylinkedlist class but it didn't work.i m confused in which layer should i make this function in the linkedqueue class or the singlylinkedlist class or in the main class. yes i want just to swap names in the queue as simple as that.
UPDATED ANSWER
I modified your Node and NodeList Classes in a way which is easier to understand. I also kept similar private values and similar methods for those classes.
public class JavaApplication287 {
public static class Node{
private Node node;
private Node nextNode;
int data;
Node(int d){
data = d;
nextNode = null;
}
public Node getNode(){return node;}
public void setNode(Node someNode){node = someNode;}
public Node getNextNode(){return nextNode;}
public void setNextNode(Node someNextNode){nextNode = someNextNode;}
public int getData(){return data;}
public void setData(int d){data = d;}
public void printNode(){System.out.println(data);}
}
public static class NodeLinkedList{
private Node head;
private Node tail;
private int size;
NodeLinkedList(Node nodeHead, Node nodeTail, int s){
this.head = nodeHead;
this.tail = nodeTail;
this.size = s;
}
public Node getHead(){return head;}
public void setHead(Node n){head = n;}
public Node getTail(){return tail;}
public void setTail(Node n){tail = n;}
public int getSize(){return size;}
public void setSize(int n){size = n;}
public void printNodeList(){
System.out.println("Head: " + head.getData());
Node current = head;
while (current.nextNode != null){
System.out.println(current.data);
current = current.getNextNode();
}
System.out.println("Tail: " + tail.getData());
}
}
public static void main(String[] args) {
// create Sample Nodes
Node zero = new Node(0);
Node one = new Node(1);
Node two = new Node(2);
Node three = new Node(3);
Node four = new Node(4);
Node five = new Node(5);
//Link Them
zero.setNextNode(one);
one.setNextNode(two);
two.setNextNode(three);
three.setNextNode(four);
four.setNextNode(five);
//Create the Linked Node List with head = one & tail = five
NodeLinkedList myNodeLinkedList = new NodeLinkedList(zero, five, 6);
//Print Current LinkedNodes
myNodeLinkedList.printNodeList();
//Invert the NodeLinkedList
Node position = myNodeLinkedList.getHead(); //Node we look at
Node prev = null; // Store the prev Node
Node node = null; // Temp Node of the next Node in the Linked List
for (int i=0; i< myNodeLinkedList.getSize(); i++){
node = position.getNextNode(); //Store the Next Node so we do not lose access to it
position.setNextNode(prev); // Update current Node's NextNode value
prev = position; // Set previous Node as the Node we are currently looking at
position = node; // Move our position to the next Node
}
//Invert Head and Tail
Node temp = myNodeLinkedList.getHead();
myNodeLinkedList.setHead(myNodeLinkedList.getTail());
myNodeLinkedList.setTail(temp);
//Print Current LinkedNodes
myNodeLinkedList.printNodeList();
}
}
This is working code and here is the output I get,
run:
Head: 0
0
1
2
3
4
Tail: 5
Head: 5
5
4
3
2
1
Tail: 0
BUILD SUCCESSFUL (total time: 0 seconds)
Hope it helps,

Remove method for Stack in Java

I am struggling to figure this out - I need to implement a method:
public int remove(int n)
where I remove the top most n entries from my stack. Any suggestions on where I can start to tackle this would be greatly appreciated.
Here is the code provided where I need to implement this remove() method.
public class LinkedStack<T> implements StackInterface<T>
{
private Node topNode; // references the first node in the chain
public LinkedStack()
{
topNode = null;
} // end default constructor
public void push(T newEntry)
{
Node newNode = new Node(newEntry, topNode); topNode = newNode;
} // end push
public T peek()
{
T top = null;
if (topNode != null)
top = topNode.getData();
return top;
} // end peek
public T pop()
{
T top = peek();
if (topNode != null)
topNode = topNode.getNextNode();
return top;
} // end pop
public boolean isEmpty() {
return topNode == null;
}
public void clear() {
topNode = null;
}
private class Node
{
private T data; // entry in stack
private Node next; // link to next node
private Node(T dataPortion)
{
this(dataPortion, null);
} // end constructor
private Node(T dataPortion, Node nextNode)
{
data = dataPortion;
next = nextNode;
} // end constructor
private T getData()
{
return data;
} // end getData
private void setData(T newData)
{
data = newData;
} // end setData
private Node getNextNode()
{
return next;
} // end getNextNode
private void setNextNode(Node nextNode)
{
next = nextNode;
} // end setNextNode
} // end Node
} // end LinkedStack
The trivial solution is just to call this.pop() n times. For this, you need to use a loop.
Seems like your homework, so I'm not going to show a code example.

Iterating over a linked list in Java?

I have been diligently watching YouTube videos in an effort to understand linked lists before my fall classes start and I am uncertain how to proceed with iterating over the following linked list. The 'node' class is from a series of videos (same author), but the 'main' method was written by me. Am I approaching the design of a linked list in an illogical fashion (assuming of course one does not wish to use the predefined LinkedList class since the professor will expect each of us to write our own implementation)?:
class Node
{
private String data;
private Node next;
public Node(String data, Node next)
{
this.data = data;
this.next = next;
}
public String getData()
{
return data;
}
public Node getNext()
{
return next;
}
public void setData(String d)
{
data = d;
}
public void setNext(Node n)
{
next = n;
}
public static String getThird(Node list)
{
return list.getNext().getNext().getData();
}
public static void insertSecond(Node list, String s)
{
Node temp = new Node(s, list.getNext());
list.setNext(temp);
}
public static int size(Node list)
{
int count = 0;
while (list != null)
{
count++;
list = list.getNext();
}
return count;
}
}
public class LL2
{
public static void main(String[] args)
{
Node n4 = new Node("Tom", null);
Node n3 = new Node("Caitlin", n4);
Node n2 = new Node("Bob", n3);
Node n1 = new Node("Janet", n2);
}
}
Thanks for the help,
Caitlin
There are some flaws in your linked list as stated by some of the other comments. But you got a good start there that grasps the idea of a linked list and looks functional. To answer your base question of how to loop over this particular implemention of the linked list you do this
Node currentNode = n1; // start at your first node
while(currentNode != null) {
// do logic, for now lets print the value of the node
System.out.println(currentNode.getData());
// proceed to get the next node in the chain and continue on our loop
currentNode = currentNode.getNext();
}
Maybe this will be useful:
static void iterate(Node head) {
Node current = head;
while (current != null) {
System.out.println(current.getData());
current = current.getNext();
}
}
// or through recursion
static void iterateRecursive(Node head) {
if (head != null) {
System.out.println(head.getData());
iterateRecursive(head.getNext());
}
}
class List {
Item head;
class Item {
String value; Item next;
Item ( String s ) { value = s; next = head; head = this; }
}
void print () {
for( Item cursor = head; cursor != null; cursor = cursor.next )
System.out.println ( cursor.value );
}
List () {
Item one = new Item ( "one" );
Item two = new Item ( "three" );
Item three = new Item ( "Two" );
Item four = new Item ( "four" );
}
}
public class HomeWork {
public static void main( String[] none ) { new List().print(); }
}
Good luck!!
You can have your linked list DS class implement 'Iterable' interface and override hasNext(), next() methods or create an inner class to do it for you. Take a look at below implementation:
public class SinglyLinkedList<T>{
private Node<T> head;
public SinglyLinkedList(){
head = null;
}
public void addFirst(T item){
head = new Node<T>(item, head);
}
public void addLast(T item){
if(head == null){
addFirst(item);
}
else{
Node<T> temp = head;
while(temp.next != null){
temp = temp.next;
}
temp.next = new Node<T>(item, null);
}
}
private static class Node<T>{
private T data;
private Node<T> next;
public Node(T data, Node<T> next){
this.data = data;
this.next = next;
}
}
private class LinkedListIterator implements Iterator<T>{
private Node<T> nextNode;
public LinkedListIterator(){
nextNode = head;
}
#Override
public boolean hasNext() {
return (nextNode.next != null);
}
#Override
public T next() {
if(!hasNext()) throw new NoSuchElementException();
T result = nextNode.data;
nextNode = nextNode.next;
return result;
}
}
}

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