Develop Reference

Tomcat localhost:8080 "sent an invalid not opening/tomcat doesn't start

I was having issues installing and running tomcat today and had to do a lot of research to get it running. I'm putting my solution here in case anyone runs into the same problem.
When I opened the url localhost:8080 in my browser, I would get a "refused to connect" error. I checked if the port 8080 was being used by another service, and it was not.
I then noticed that tomcat wasn't starting. I tried opening it through services but that didn't work either. Later services showed tomcat stuck in the "starting" status. I then tried to run tomcat through the command prompt with these commands.
cd: c:/filepathToTomcat/bin
bin>startup`
That gave me this error
jre_home variable undefined and java_home variable undefined
Using the solution to
https://stackoverflow.com/questions/18468681/tomcat-6-java-home
I created a setenv.bat file in the tomcat bin and set the java_home variable.
My setenv.bat file contained
#ECHO OFF
set "JAVA_HOME=C:\Program Files\Java\jdk-19"
set "JRE_HOME="
Tomcat still wouldn't run. A solution on
https://stackoverflow.com/questions/5398654/tomcat-not-starting
suggested using "catalina.bat run" on the command prompt instead of startup.
This showed that tomcat wouldn't start because it couldn't get the java virtual machine to run. I then uninstalled and reinstalled java and tomcat started working for me.
I used Java version 19 and tomcat 10.1.5 on a windows 11.

Tomcat startup batch issue

Can anyone please explain the below problem.
I'm using tomcat 8 and when I'm trying to start startup.bat file, the command prompt is opening and closing immediately just like blinking. However in the past while I'm working with java programs it worked fine but recently I installed Xampp and there in it again tomcat is downloaded "C:\xampp\tomcat". The same problem comes here in this folder as well, when I try to run startup.bat file. But when I use "XAMPP control panel" to start the Tomcat its able to get start and I'm getting "localhost:8080" start page in the browser.
The connector port for both tomcats are 8080 and I tried with changing the port number in tomcat 8 but no use. There should not be 2 tomcat servers in a single system? If not, why? (I've not installed them, both are in C drive)
I want to work with java servlet programs now.So I need use of tomcat. I've set below environment user varibles:
JAVA_HOME to C:\Program Files\Java\jdk1.8.0_65;
path to C:\Program Files\Java\jdk1.8.0_65\bin;C:\apache-maven-3.3.9\bin
Please suggest the solutions.
Thanks in advance.

I think you should check the tomcat log to find some clues, it is in log folder of your tomcat installation folder. Maybe you have missed some startup variable in start.bat for your new installed things.
BTW, if you want to keep seeing what happened in startup, try to run startup.bat in a command line console, but not double click it through your mouse. It will continue on generating log output in that console.

Tomcat: startup.bat is missing

In many materials about tomcat what I've looked I saw that authors uses exeternal batch script for start and stop tomcat.
I didn't see information about wrting this script. I think this script provided by tomcat.
I used exe file for installing my tomcat 7 on my windows 7. In tomcat directory I search startup.bat. This file is missed.
Can you help me?

It should be in the /bin directory. If you're missing this file possibly it means that you have installed Tomcat using Windows Installer. Try to download appropriate .zip archive, I believe that you will find startup script there.

I was puzzled by this - windows people need to script too!
However I think it is because tomcat gets installed as a service with a manager. If you want to start and stop it without using the manager you start and stop the service directly.
You can do this by typing (in an admin command prompt)
net start tomcat7
and
net stop tomcat7

Though it would be everywhere, still if you download the zip from their site, you can follow these instructions - http://www.ntu.edu.sg/home/ehchua/programming/howto/Tomcat_HowTo.html
bin\startup.bat is for windows & .sh is for Unix.

Have you checked bin directory under Tomcat instalation dir? It should containt *.bat for start and stop server etc.

If you want to start Tomcat server by using startup.bat and you are unable to find it(that's because installer does not have it, you can only see it if you download and run .zip this will show startup.bat explicitly https://www.screencast.com/t/RMPCq5eJre3),
So to solve the issue just go to C:\Program Files\Apache Software Foundation\Tomcat 7.0_Tomcat7\bin and double click Tomcat.exe, a command prompt like screen will appear this is the the same as clicking startup.bat script. Hope this helps

"Failed to create java" on running Windows service

I have a java application, which has to run as windows service.
I am able to install the service using the following command.
"%EXECUTABLE%" //IS//%SERVICE_NAME% --StartClass %STARTER% --StopClass %STOPPER% %START_PARAMS% %STOP_PARAMS%
The service is installed successfully but when i try to run it it shows Failed to create java. path also it is not showing in the jkartha log file.
I have JAVA_HOME environment variable pointing to jdk1.5.
and even i copied msvcr71.dll to windows\system32 folder and restarted the PC.
I am running this on windows 2008 server.
I didn't install apache tomcat server. prunsrv.exe and procmgr.exe i just copied.
Please suggest me how i need to overcome this problem.
whether to run application as windows service, prunsrv.exe, prunmgr.exe are enough is it? I am able to successfully install but not able to start why???

You probably need to set your service to run as the user that installed Java, otherwise it won't find its environment variables.
If you must run in the default Local System account, then you can run a batch file that sets up the environment and then launches java.exe.

How to pass a system property to a web application hosted in Tomcat 7 running as a Windows Service?

There are numerous places on the Internet, suggesting that it is easily achieved by any (or all) of the following methods:
through CATALINA_OPTS
through JAVA_OPTS
through TOMCAT_OPTS
by placing the set statements in the setenv.bat file inside the tomcat's bin folder
My problem, is that I have tried all of the above and my web application still does not see my system property!
Here is what I am doing:
Stop tomcat7 service
set CATALINA_OPTS=-Dabc.def=true in the system environment
set JAVA_OPTS=-Dabc.def=true in the system environment
set TOMCAT_OPTS=-Dabc.def=true in the system environment
put all of the above into c:\Program Files\Apache Software Foundation\Tomcat 7.0\bin\setenv.bat (seems totally redundant, but just in case)
Start tomcat7 service
Inspect the environment of the tomcat7 process using the Process Explorer tool - the environment is correct, I do see both CATALINA_OPTS and JAVA_OPTS and TOMCAT_OPTS equal to -Dabc.def=true
run my web app, which is a simple servlet dumping all the system properties to the response stream - abc.def is not amongst them
Please, put me out of my misery and tell me how to do it.

For the Tomcat service, startup settings are stored in the registry under Options key at:
HKEY_LOCAL_MACHINE\SOFTWARE\Apache Software Foundation\Procrun 2.0\Tomcat<X>\Parameters\Java
(substitute appropriate Tomcat version where needed).
Edit:
On 64-bit Windows, the registry key is:
HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\Apache Software Foundation\Procrun 2.0\Tomcat<X>\Parameters\Java
even if Tomcat is running under a 64-bit JVM.

I know this post is almost 9 years old but thought someone might find this useful.
Although #prunge and #mark answers were very accurate and following their logic I was able to add system properties to my tomcat 7 instance running on Windows, there is an easier way.
In the installation directory of Tomcat there is an exe you can run called
%INSTALL_DIRECTORY%\bin\tomcat7w.exe
This opens up a Tomcat properties windows where you can control the service i.e. start and stop tomcat and there is a tab (Java) that allows you to set the Java properties as well
Scroll to the end of that panel under "Java Options" and add your system properties
-Dpropertyname=value
Then navigate back to the General tab and restart tomcat
I have tested this and my grails app now can see my properties. I use the following Groovy code to get the property out
System.properties.getProperty("propertyname")
Adding the system properties in the Windows registry showed up in this window as well so its one and the same thing, just this application seems to me to be slightly more convenient.
Hope this helps someone else