I'm still new to Java and so I'm not understanding where the termination error is coming from. The System.out.println in the main is not being printed out and it says:
< terminated, exit value: 0> C:\Program Files\Java\jre1.8.0_71\bin\javaw.exe (Jan 27, 2016, 1:22:17 PM)
Here is the main of my code.
public class BrainCenter {
public static void main(String[] args) {
System.out.println("Welcome to the Stock Center!");
System.out.println("Realtime Reports within the stock market");
System.out.println("");
Market mk = new Market(6000);
mk.printMarket();
System.out.println("Individual status listed below");
System.out.println("");
Buyers bu = new Buyers();
bu.buildRandomPortfolio(mk);
}
}
The first three lines are not being outputted and I'm not sure why. It appears as the rest of the code loads but then disappear and said to be terminated at the end. I'm using Eclipse IDE.
Any help would be greatly appreciated. Thank you in advance!
Try to use java.exe instead of javaw.exe. The first will wait until the program completes. It will also put all output the program generates directly in console. The last should be used when the program runs with its own GUI or simply in background. It will not wait until the program completes.
See Difference between java.exe and javaw.exe.
you can fix this problem by setting path variable in Environment. In my system I have copied path of bin as "C:\Program Files\Java\jdk1.8.0_25\bin" and saved.
Related
I met some interesting question on which I was not able to find an answer. Does anybody know how to pass hieroglyphs as an argument to the main method from command line?
Below there is some pseudo code which will help to test suggested solution:
public class Test {
public static void main(String args[]) {
if ("香港政府".equals(args[0])) {
System.out.println("Match");
}
}
}
So question is how to call Test.class with an argument so the application prints Match to the console? args[0] can be transformed before passing to the if statement.
Thanks in advance.
After some additional research I was able kinda figured it out. So guys who commented on question were very near to the answer.
Encoding which I tried to find was 936. But it doesn't mean that you will be able to run chcp 936 if you OS locale is other than chinese. Once you will try to run it on other locale than chinese:
chcp 936
You will get following error:
Invalide code page
For making it working you have to change region. FOllowing steps will be needed:
Start - COntrol panel
Select "Region and Language"
Select "Administrative" and click "Change system locale..."
Select "Chinese (Simplified, PRC)" and reboot laptop
After restart when you will run chcp you will see following output Active code page: 936. Now you are ready to execute command line with hieroglyphs.
I'm using Eclipse for Java on my Macbook air, OS 10.9. I keep getting the error Obsolete Methods on the Stack, with a warning about how it may cause problems with the virtual machine when I run very basic programs that have no errors. I ran a program that just had the class and the main method and I got this error. After the error box, the bug referred to the main method, but I know the syntax is correct because I used Eclipse's main method.
import java.util.Scanner;
public class Dowhile {
public static void main(String[] args) {
/*Scanner scanner = new Scanner(System.in);
System.out.println("Enter a number");
int value = scanner.nextInt();
System.out.println(value);*/
/*do{
System.out.println("Enter a number ");
int value = scanner.nextInt();
}
while(value != 5);
System.out.println("Got 5");*/
}
}
Update:
I'm not getting the obsolete methods error now, just Exception in thread "main"... at line 5.
This error message indicates that you are doing hot code replace, and that
the frames on the stack no longer match the class files in the running VM.
Restarting your debug session/target VM should suffice.
Hot code replace (HCR) meaning:
It is a debugging technique whereby the Eclipse Java debugger transmits new class files over the debugging channel to another JVM.
read more.
Bugzilla
Dreamincode
I clicked on Terminate button and it no longer showed that warning message again.
I am using eclipse for long time and this never happened but I have this really simple program . And it doesnt display anything . what can be the reason ?
public class ReportGenerator {
public static void main(String[] args){
System.out.println("STARTING");
}
}
try Window -> Show View -> Console if the console is not visible
If you are doing javac ReportGenerator.java, it is just building a .class file. You need to run java ReportGenerator to see the program working and therefore printing on the terminal in your case.
Too many opened consoles in Eclipse?
Here is the reference: http://help.eclipse.org/juno/index.jsp?topic=%2Forg.eclipse.jdt.doc.user%2Freference%2Fviews%2Fconsole%2Fref-open_action.htm
Click the grey X until all of them are closed.
How to exit the console of a simple Java program after displaying an error message?
currently my code has:
...
...
if (some condition){
//print error
System.exit();
...
...
But this System.exit(); leaves the console open. I have tried exit(0);, System.exit(0); as well.
If you're wanting to close the Command Prompt window that your application is running in, then I don't believe there is a way to do it (At least not nicely).
Why do you want to start your application from the command prompt and then close the pre-existing Command Prompt window? This will surely get rid of the error message that you're outputting (unless it's also being logged - in which case why print it to a window you want to close?).
This is Windows specific, but would creating a shortcut in Windows Explorer to java -jar MyJarFile.jar or java MyCompiledClass do what you want? Instructions for this sort of approach can be found here.
System.exit(1);
should work fine. Note that if you're exiting with an error, you would normally set a non-zero exit code. From the doc:
The argument serves as a status code; by convention, a nonzero status
code indicates abnormal termination.
This means you can script using common conventions, any process spawning your program can react correspondingly etc.
If I understand you correctly, you want to run your program in a command prompt and if the program fails you want it to display the error message, close the program AND the commad prompt window?
If this is the case then the only thing I could think of would to be to run your program in a batch file that checks the exit status of your program. So in your code write your error message, then I suggest sleep for a few seconds so the user can actually see it, then exit with status code 1.e.g.
if(SomeCondition){
System.err.println("ERROR MESSAGE...");
Thread.sleep(3000);//Sleep for 3 seconds...
System.exit(1);
}
Then run your program from a batch file which checks the "ERRORLEVEL" environment variable e.g.
java <INSERT_PROGRAM_NAME>
IF %ERRORLEVEL% == 1 exit
Hope this helps :)
java.lang.System doesn't have an exit method with no parameters, so System.exit(); would be a compile-error. (System.exit(1);, however, would be fine.) The reason that your code isn't working is probably that you're not recompiling it, so you're still running some old version from before you added that line.
Suppose you are trying to install firefox .bat file from java
public static void main(String[] args) throws InterruptedException {
try {
String[] command = { "cmd.exe", "/C", "Start", "C:\\firefox.bat" };
Runtime.getRuntime().exec(command).waitFor();
}
catch (Exception e)
{
System.out.println("Execution error");
}
}
This would trigger the command prompt and the window will be opened until you manually go and close it after the firefox is installed.
The fix is that in your .bat file just after your command just put an "exit" For eg:
Your firefox.bat would contain
#Start /wait "Firefox" "C:\Firefox Setup 41.0.exe" -ms
exit
This will close your command prompt window. Hope this helps...
have a look at the below link
http://www.cs.bris.ac.uk/jot/decisions/exercise11/exit.html
There is a general convention that a program must return an exit code. The exit code should be zero to indicate success, and non-zero to indicate failure. Platforms differ about what different non-zero codes mean, so programmers often just return 1 as a general indication of failure.
System.exit(); terminates the JVM. The int is the status code (0 means "normal" exit). If it's not exiting it's because that part of your code is not reachable and not being executed at all.
Java API - System.exit()
When I write this in the main method:
System.out.println("Hello");
Nothing is outputted on the output console. It just says "Build successful (total time: 0 seconds)". What's the problem?
Here is my full program:
package names;
public class myName {
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
System.out.println("test");
}
}
Here's the window after I debug the program:
Have no file for /System/Library/Java/JavaVirtualMachines/1.6.0.jdk/Contents/Classes/jsfd.jar
Have no file for /System/Library/Java/JavaVirtualMachines/1.6.0.jdk/Contents/Classes/laf.jar
Have no file for /System/Library/Java/JavaVirtualMachines/1.6.0.jdk/Contents/Classes/sunrsasign.jar
BUILD SUCCESSFUL (total time: 1 second)
On netbeans right click and click run file. It would run. Seems like you're building the project, and not executing it.
Don't debug it. Run it.
I'm nearly sure it's due to an IDE issue: the ant/build output is being redirected to a different place (not stdout) and you're seeing that "other place" as a "Console". Please let us know your IDE and as much code as you can.
You have to run it then. In netbeans, to run you can press F6 - http://netbeans.org/kb/docs/java/quickstart.html