I'm using Java code to download a file from the Internet and save it to some directory.
However, the code downloads the HTML source code of the page instead of the file contents.
The code below illustrates the problem:
import java.awt.*;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.net.URL;
import java.nio.channels.Channels;
import java.nio.channels.ReadableByteChannel;
public class JavaFileDownloadTest
{
public static void download(String remoteURL, String targetFilePath)
throws IOException
{
URL downloadableFile = new URL(remoteURL);
ReadableByteChannel readableByteChannel = Channels.newChannel(downloadableFile.openStream());
FileOutputStream fileOutputStream = new FileOutputStream(targetFilePath);
fileOutputStream.getChannel().transferFrom(readableByteChannel, 0, Long.MAX_VALUE);
}
public static void main(String[] arguments) throws IOException
{
String userHome = System.getProperty("user.home");
String fileName = "Test.txt";
String targetFilePath = userHome + File.separator + "Downloads" + File.separator + fileName;
download("http://bullywiiplaza.cuccfree.com/" + fileName, targetFilePath);
Desktop.getDesktop().open(new File(targetFilePath));
}
}
The file located here contains the text
Hello StackOverflow!
However, when downloaded using the above code, I'm getting the HTML source code as file content instead:
<html><body><script type="text/javascript" src="/aes.js" ></script><script>function toNumbers(d){var e=[];d.replace(/(..)/g,function(d){e.push(parseInt(d,16))});return e}function toHex(){for(var d=[],d=1==arguments.length&&arguments[0].constructor==Array?arguments[0]:arguments,e="",f=0;f<d.length;f++)e+=(16>d[f]?"0":"")+d[f].toString(16);return e.toLowerCase()}var a=toNumbers("f655ba9d09a112d4968c63579db590b4"),b=toNumbers("98344c2eee86c3994890592585b49f80"),c=toNumbers("ae71113e4baf38cee1c1aacf0ae66c00");document.cookie="__test="+toHex(slowAES.decrypt(c,2,a,b))+"; expires=Thu, 31-Dec-37 23:55:55 GMT; path=/"; document.cookie="referrer="+escape(document.referrer); location.href="http://bullywiiplaza.cuccfree.com/Test.txt?ckattempt=1";</script><noscript>This site requires Javascript to work, please enable Javascript in your browser or use a browser with Javascript support</noscript></body></html>
Why is this and how do I fix it? I already tried various libraries and methods for downloading files but all of them yielded this same "faulty" result.
I think the target url executes some javascript to provide the file. This script has to be interpreted (and executed) by some javascript engine.
So you need either some resolution to get the real file url (and not just the javascript) or integrate some javascript engine to execute the script code and get the result.
I think this could help you: Executing javascript in java - Opening a URL and getting links
or better:
http://www.java2s.com/Code/Java/JDK-6/ExecuteJavascriptscriptinafile.htm
I switched the website hoster to this one and now the code from above works as expected.
http://bullywiiplaza.cuccfree.com/Test.txt doesn't exist. I think the url should be https://bullywiiplaza.cuccfree.com/Test.txt which exists.
Related
I'm working on a very simple project that's supposed to open an image with the windows video player when run. However, I've encountered a problem. I want to have it be able to access the file "snp.jpg" with a relative file path, so it will work on computers other than my own. But, when I have it set to a absolute file path, it fails and tells me that "the file ... does not exist". Any Ideas?
import java.awt.Desktop;
import java.io.File;
public class openpic {
public static void main (String args[]) throws Exception
{
File f = new File ("C:\Users\charl\Desktop\Computer Science\JavaProjects\src\snp.png");
Desktop d = Desktop.getDesktop();
d.open(f);
System.out.println("imageviewer open;");
}
}
(Ops... fixing the answer, after I read the text above the code)
The relative path will start from the directory you run the program. Also called current working directory.
Also, as you are using Files, try to use the NIO API, with Path. Like:
Path filePath = Paths.get("./snp.png")
With this API, you can check the working directory using:
filePath.toAbsolutePath()
// just print it then, or check with a debugger
Also, be careful about the slashes.
When using Windows and this slash \, you need to make them double: \\.
Other option is to invert it: /.
Microsoft Windows syntax
import java.awt.Desktop;
import java.io.File;
public class openpic {
public static void main (String args[]) throws Exception
{
// Microsoft Windows syntax
File f = new File ("C:\\Users\\charl\\Desktop\\Computer Science\\JavaProjects\\src\\snp.png");
Desktop d = Desktop.getDesktop();
d.open(f);
System.out.println("imageviewer open;");
}
}
I am working on creating a personal utility downloader for things like Malwarebytes, Adware Cleaner, and etc. But I have never worked with anything like this before. I searched around and found some documentation on how to download files from a URL into a directory, but I haven't been able to get it to work yet. The first time it turned the directory into a file that was unsuable and now that I have changed the URL it is failing to download due to the errors listed at the bottom. Could someone point me in the right direction or tell me what I am doing wrong?
package com.kcc;
import java.io.File;
import java.io.IOException;
import java.net.URL;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.StandardCopyOption;
public class Testing2 {
public static String testURL;
public static String saveDir;
public static void main(String[] args) throws IOException {
testURL ="https://download.bleepingcomputer.com/dl/a652734ff3304da2530acb93754c1bf7/5af5a320/windows/security/security-utilities/a/adwcleaner/AdwCleaner.exe";
//"https://download.toolslib.net/download/file/1/1511?s=2LPvu8kniU2T794QD0FXSN21jxnJOqLP";
saveDir = "C:\\Users\\Austin\\Desktop\\kccutil";
download(testURL, saveDir);
}
private static Path download(String sourceURL, String targetDirectory) throws IOException
{
URL url = new URL(sourceURL);
String fileName = sourceURL.substring(sourceURL.lastIndexOf('/') + 1, sourceURL.length());
Path targetPath = new File(targetDirectory + File.separator + fileName).toPath();
Files.copy(url.openStream(), targetPath, StandardCopyOption.REPLACE_EXISTING);
return targetPath;
}
}
I am currently getting these errors
Exception in thread "main" java.nio.file.NoSuchFileException: C:\Users\Austin\Desktop\kccutil\AdwCleaner.exe
at sun.nio.fs.WindowsException.translateToIOException(WindowsException.java:79)
at sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:97)
at sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:102)
at sun.nio.fs.WindowsFileSystemProvider.newByteChannel(WindowsFileSystemProvider.java:230)
at java.nio.file.spi.FileSystemProvider.newOutputStream(FileSystemProvider.java:434)
at java.nio.file.Files.newOutputStream(Files.java:216)
at java.nio.file.Files.copy(Files.java:3016)
at com.kcc.Testing2.download(Testing2.java:25)
at com.kcc.Testing2.main(Testing2.java:17)
EDIT: For the error above, turns out the directory wasn't created. But now I am receiving a new error
Exception in thread "main" java.io.FileNotFoundException: https://download.bleepingcomputer.com/dl/a652734ff3304da2530acb93754c1bf7/5af5a320/windows/security/security-utilities/a/adwcleaner/AdwCleaner.exe
at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1872)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1474)
at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:254)
at java.net.URL.openStream(URL.java:1045)
at com.kcc.Testing2.download(Testing2.java:25)
at com.kcc.Testing2.main(Testing2.java:17)
For the debugging purposes you can try saving files to working directory (i.e. refer to . folder). Using this approach you can access file by it's filename.
For the future I recommend you using Java 7 NIO Api: Paths.get() - for originally building path from parts, path.parent() - to refer to parent directory, path.resolve() - to build child path.
If you want to download a file you should use FTP server and not HTTP in case you have the executable.
But if you already have an HTTP link on web who calls a downloadable .exe (Like in your case), you don't really need a download method. You just need to send an http request to navigator (preferably if it is a web app), something like:
File htmlFile = new File(url);
Desktop.getDesktop().browse(htmlFile.toURI());
Or you can download that file using Apache Common IO's FileUtils:
import org.apache.commons.io.FileUtils;
FileUtils.copyURLToFile(url, file_destination);
Or you can check this response using Java NIO
I'm nearing the end of a program development for my computer science course. However, one of the requirements is to have a user manual within the app. I saved the user manual as a PDF inside Eclipse's workspace.
It is stored under "/Documents/PDF Manual.pdf". I originally used this code:
URL url = getClass().getResource( fileSeparator + "Documents" + fileSeparator + "PDF Manual.pdf");
//fileSeparator = '/' on mac, & '\\' on windows
File userManual = new File (url.toURI());
if (userManual.exists())
{
Desktop.getDesktop().open(userManual);
}
This works fine while running the project from eclipse, however URI returns a non hierarchical exception (as expected) when the program is exported to a jar file. I thought of playing around with url.toString(), using substring and replaceAll() to get rid of unwanted characters (%20 for the space), however this gave weird results and of course the code wouldn't work properly when it wasn't a jar file.
I looked at InputStream, however this is only used to read from a file and I cannot open the file using a desktop app.
Due to the process of submission, the pdf HAS to be saved inside the project folders.
Also, my code has to be platform independent (or at the very least, work on windows and mac) and thus manipulating file names becomes a lot more complicated. Any suggestions?
Edit:
After #SubOptimal 's help, this is the code I am now using:
String inputPdf = "Documents" + fileSeparator + "PDF Manual.pdf";
InputStream manualAsStream = getClass().getClassLoader().getResourceAsStream(inputPdf);
Path tempOutput = Files.createTempFile("TempManual", ".pdf");
tempOutput.toFile().deleteOnExit();
Files.copy(manualAsStream, tempOutput, StandardCopyOption.REPLACE_EXISTING);
File userManual = new File (tempOutput.toFile().getPath());
if (userManual.exists())
{
Desktop.getDesktop().open(userManual);
}
This works on mac. However, on windows manualAsStream is null for some unknown reason.
Full working example. Tested in Windows environment.
file structure
.\REPL.java
.\doc\manual.pdf
.\manifest.mf
REPL.java
package sub.optimal;
import java.io.InputStream;
import java.io.File;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.nio.file.StandardCopyOption;
import java.awt.Desktop;
public class REPL {
public static void main(String[] args) throws Exception {
String inputPdf = "doc/manual.pdf";
Path tempOutput = Files.createTempFile("TempManual", ".pdf");
tempOutput.toFile().deleteOnExit();
System.out.println("tempOutput: " + tempOutput);
try (InputStream is = REPL.class.getClassLoader().getResourceAsStream(inputPdf)) {
Files.copy(is, tempOutput, StandardCopyOption.REPLACE_EXISTING);
}
Desktop.getDesktop().open(tempOutput.toFile());
}
}
manifest.mf
Main-Class: sub.optimal.REPL
compile
javac -d . REPL.java
create JAR
mkdir dist\
jar cvfm dist/REPL.jar MANIFEST.MF sub/optimal/REPL.class doc/manual.pdf
execute JAR
cd dist\
java -jar REPL.jar
Use getResourceAsStream instead of getResource
To write in the temp directory use createTempFile
As the title says, I have a PDF document which is stored locally and using Java I would like to open it on an arbitrary page. My question is much the same as this question, however the proposed solution seems rather hacky so I would prefer a more conventional answer if possible. I understand that the code shown below will not work because #page=5 should be appended to the URL in the browser and not the file path, however I'm really not sure what to try next. Any help would be much appreciated!
import java.io.File;
import java.io.IOException;
import java.net.URL;
public class OpenPdfTest {
public OpenPdfTest(){
try {
File myFile = new File("test.pdf");
URL url = myFile.toURI().toURL();
Process p = Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + url + "#page=5");
} catch (IOException e) {
e.printStackTrace();
}
}
public static void main(String[] args){
new OpenPdfTest();
}
}
What about using http://tika.apache.org/ and read the whole file, convert it and use the part of the pdf File that you want. You can read in any File you want with Apache Tika. With this Lib you can open any kind of files, also pdf-Files and proceed them.
Take my Answer just as a first guess.
I need to programatically change the encoding of a set of *nix scripts to UTF-8 from Java. I won't write anything to them, so I'm trying to find what's the easiest|fastest way to do this. The files are not too many and are not that big. I could:
"Write" an empty string using an OutputStream with UTF-8 set as encoding
Since I'm already using FileUtils (from Apache Commons), I could read|write the contents of these files, passing UTF-8 as encoding
Not a big deal, but has anyone run into this case before? Are there any cons on either approach?
As requested, and since you're using commons io, here is example code (error checking to the wind):
import java.io.File;
import java.io.IOException;
import org.apache.commons.io.FileUtils;
public class Main {
public static void main(String[] args) throws IOException {
String filename = args[0];
File file = new File(filename);
String content = FileUtils.readFileToString(file, "ISO8859_1");
FileUtils.write(file, content, "UTF-8");
}
}