I'm having a problem when parsing a date from a string.
This is my code:
String date = "04/01/2016 03:52:33 PM";
SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss aa");
Date dt = format.parse(date);
But it keeps throwing an exception:
java.text.ParseException: Unparseable date: "04/01/2016 03:52:33 PM" (at offset 20)
Any help would be appreciated.
The am/pm marker from your default Locale (Peru - Spanish) probably doesnt match that of the input String
SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a", Locale.US);
You don't need two aas.
"dd/MM/yyyy hh:mm:ss a"
Related
I am facing problems some while formatting the date:
Date : 11/06/2020 04:14:20
Date Format:dd/MM/yyyy hh:mm:ss a
Exception:
java.text.ParseException: Unparseable date: "11/06/2020 04:14:20"
Following is the code
Blockquote
public String getFormatDate(String inputDate) {
String strDate = "";
try {
DateFormat outputFormat = new SimpleDateFormat("MMMM dd, yyyy hh:mm:ss a");
DateFormat inputFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
Date date1 = inputFormat.parse(inputDate);
strDate = outputFormat.format(date1);
}catch( Exception exe) {
exe.printStackTrace();
logger.error( "[ERROR] getFormatDate:. ", exe );
}
return strDate;
}
Blockquote
Any help would be greatly appeciated.
You can check this code you have to pass the am/pm part too with the date string value as your format is expecting that.
//String date = "11/06/2020 04:14:20";
String date = "11/06/2020 04:14:20 am";
DateFormat df = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
https://ideone.com/3nibwJ
Use proper date-time objects for your dates and times
For the vast majority of purposes you should not keep your date and time in a string and should not convert your date and time from a string in one format to a string in another format. Keep your date and time in a ZonedDateTime or LocalDateTime object.
When you are required to accept string input, parse that input into a date-time object immediately. I am using and recommending java.time, the modern Java date and time API:
DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern("dd/MM/uuuu HH:mm:ss");
String input = "11/06/2020 04:14:20";
LocalDateTime dateTime = LocalDateTime.parse(input, inputFormatter);
System.out.println(dateTime);
Output so far is:
2020-06-11T04:14:20
Since there is no AM or PM in your string, I have assumed that 04:14:20 was the time of day from 00:00:00 through 23:59:59. If you intended otherwise, you need to explain how.
Only when you need to give string output, format your date and time back into a string of appropriate format:
DateTimeFormatter outputFormatter = DateTimeFormatter
.ofPattern("MMMM dd, yyyy hh:mm:ss a", Locale.ENGLISH);
String output = dateTime.format(outputFormatter);
System.out.println(output);
June 11, 2020 04:14:20 AM
Do provide a locale for the formatter so Java knows which language to use for the month name and the AM/PM indicator.
What went wrong in your code?
Your string has no AM nor PM: 11/06/2020 04:14:20. Yet your format pattern string requires an AM/PM marker in the end. This is what format pattern letter a signifies. So your string wasn’t in the format that you required. This was the reason for the exception that you observed.
Link
Oracle tutorial: Date Time explaining how to use java.time.
Thanks All for your help:
I have changed the source date "11/06/2020 04:14:20" to "06/11/2020 04:14:20 PM", and then after perform follwoing steps, its working for me:
Blockquote
DateFormat inputFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss a");
inputFormat.setTimeZone( TimeZone.getTimeZone("UTC") );
Date dDate = inputFormat.parse( srcDate );
String strDeDate = formatDateToString( dDate, "dd/MM/yyyy hh:mm:ss a", "IST" );
public String formatDateToString(Date date, String format,String timeZone) {
if (date == null) return null;
SimpleDateFormat sdf = new SimpleDateFormat(format);
if (timeZone == null || "".equalsIgnoreCase(timeZone.trim())) {
timeZone = Calendar.getInstance().getTimeZone().getID();
}
sdf.setTimeZone(TimeZone.getTimeZone(timeZone));
return sdf.format(date);
}
Blockquote
This question already has answers here:
Java string to date conversion
(17 answers)
Closed 6 years ago.
Unable to parse the given date
String DT = "14 Jun 2016 09:54:02 GMT";
DateFormat simpleDateFormat = new SimpleDateFormat("dd MM yyyy HH:mm:ss z");
Date date = simpleDateFormat.parse(DT);
after this I want to convert to CST Time in this format 13-JUN-16 08.53.43
Exception StackTrace
java.text.ParseException: Unparseable date: "14-Jun-2016 09:54:02 GMT" at java.text.DateFormat.parse(Unknown Source) at package2.TimeZone.parseTime(TimeZone.java:16) at package2.TimeZone.main(TimeZone.java:10)
Date format should be like as below:
String DT = "14 Jun 2016 09:54:02 GMT";
DateFormat simpleDateFormat = new SimpleDateFormat("dd MMM yy HH:mm:ss z");
Date date = (Date) simpleDateFormat.parse(DT);
After converting date format, it should pass like below:
String newstring = new SimpleDateFormat("dd-MMMM-yy HH:mm:ss").format(date).toString().toUpperCase();
System.out.println(newstring);
To parse:
You are using the wrong mask to parse it, it should be as follows(with MMM instead of MM):
DateFormat simpleDateFormat = new SimpleDateFormat("dd MMM yyyy HH:mm:ss z");
Date date = simpleDateFormat.parse(DT);
To format it to the desired format:
DateFormat sdf= new SimpleDateFormat("dd-MMM-yy HH.mm.ss");
sdf.setTimeZone(TimeZone.getTimeZone("US/Central"));
String formattedDate = sdf.format(date).toUpperCase();
Without the uppercase it will show 13-jun-16 08.53.43 instead of 13-JUN-16 08.53.43
2015-11-03T17:33:27
I currently get the above date as a String from a JSON call. The problem is, I have no idea how to parse the T in between the 3 and the 17. When I use SimpleDateFormat, shown below, I keep getting unparseable date. What exactly do I do with the T here?
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy");
messageDate = format.parse(recentMessage.getJSONObject("message_data").getString("sent_at"));
This should work
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date messageDate = format.parse("2015-11-03T17:33:27".replace("T", " "));
Also keep Timezone in mind when parsing the dates.
i have a string "12/3/2014 12:00:00 AM" and i want to cast this string in date which have format like this "yyyy-MM-dd HH:mm:ss"
#DatabaseField(columnName="out_date",dataType=DataType.DATE_STRING,format="yyyy-MM-dd HH:mm:ss")
private Date out_date;
above is the object to get value from date string
SimpleDateFormat formater = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
outlet.setOut_date(formater.parse(json.getString("outletDate")));
after i using like the error occur java.text.ParseException: Unparseable date: ... (at offset 2) how to solve that problem thank in advance
Based on this answer, you need something like this. First convert your string in its present format to a date object, then reformat the date object.
String date = "12/3/2014 12:00:00 AM";
SimpleDateFormat sdf = new SimpleDateFormat("mm/dd/yyyy HH:MM:SS a");
Date testDate = null;
try {
testDate = sdf.parse(date);
}catch(Exception ex){
ex.printStackTrace();
}
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String newFormat = formatter.format(testDate);
System.out.println(".....Date..."+newFormat);
Conversion steps :
Create date object from your date format.
Target date format provide to SimpleDateFormat class constructor.
Parse date using SimpleDateFormat.
The code provided convert yyyy-MM-dd HH:mm:ss to dd/mm/yyyy HH:mm:ss format.
try {
SimpleDateFormat sdf1 = new SimpleDateFormat("dd/mm/yyyy HH:MM:SS a");
Date date = sdf1.parse("12/3/2014 12:00:00 AM");
String format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(date);
System.out.println(format);
}catch(Exception e){
e.printStackTrace();
}
Error : java.text.ParseException: Unparseable date: ... (at offset 2) indicates that you are using wrong date format to parse your sting.
I'm currently working on some simple project in Java and I have date in the following string:
String dateString = "Sun 7/14 03:44 AM 2013";
and want to to convert this string to Date object. I'm using following lines of code to do that. I searched site and found solution how to do this with DateFormatter:
DateFormat format = new SimpleDateFormat("EEE M/dd hh:mm a yyyy");
Date d = format.parse(dateString);
But I'm probably doing something wrong, because I always get exception:
Unparseable date: "Sun 7/14 03:44 AM 2013"
This seems to be problem with pattern I'm using but tried different patterns and nothing work.
Certain fields such as the day of week fields and/or AM/PM marker may not match those from your default Locale. ParseException has the method getErrorOffset to determine exactly where the pattern does not match.
try
DateFormat format =
new SimpleDateFormat("EEE M/dd hh:mm a yyyy", Locale.ENGLISH);
It is important to add Locale as you are parsing language day of week names.
String dateString = "Sun 7/14 03:44 AM 2013";
DateFormat format = new SimpleDateFormat("EEE M/dd hh:mm a yyyy", Locale.US);
Date d = format.parse(dateString);
I tried this out and the following worked,
String stringDate = "Sun 7/14 03:44 AM 2013";
DateFormat format = new SimpleDateFormat("EEE MM/dd hh:mm a yyyy");
System.out.println("Parsed Date = "+format.parse(stringDate));
The output was as follows
Parsed Date = Sun Jul 14 03:44:00 BST 2013
SimpleDateFormat formatter = new SimpleDateFormat("/* type your own format*/");
String formattedDate = formatter.format(todaysDate);
System.out.println("Formatted date is ==>"+formattedDate);
try this code
The modern answer for the sake of completeness. While the other answers were good answers in 2013, Date, DateFormat and SimpleDateFormat are now long outdated, and I recommend you replace them with their modern counterparts:
DateTimeFormatter parser
= DateTimeFormatter.ofPattern("EEE M/dd hh:mm a yyyy", Locale.ENGLISH);
LocalDateTime ldt = LocalDateTime.parse(dateString, parser);
The result is a LocalDateTime of 2013-07-14T03:44 as expected.
The format pattern string is still the same, and the need for an English language locale is the same.