I have following code:
session
.createCriteria(MyObj.class)
.add(Restrictions.
sqlRestriction("1=1 CONNECT BY conn_by = PRIOR id START WITH id = ?",
id, Hibernate.LONG)).list();
This code works however I want to select also level information (used with connect_by in Oracle). How I can select also this value? I do not consider level information as part of the MyObj class.
Thanks in advance.
Hibernate criteria will return only information that is available in MyObj.class ...according to you if your class don't have level info then it will give you error
Related
I configured a JPA store and see users and roles getting added correctly to the db when I call the related picketlink (2.7.1) API's
My questions is this: how does one get a list of all users that have a given role?
I tried doing this using the following RelationshipQuery
RelationshipQuery<Grant> rq = relationshipManager.createRelationshipQuery(Grant.class);
rq.setParameter(Grant.ROLE, role);
List<Grant> grants = rq.getResultList()
But the resulting grant list contains a single assignment grant, that refers to the last user in the database that has that role.
I checked the example queries in the documentation and tests but found nothing that does what I want. I know the project is no longer active but am hoping to find a solution to this.
Found out that role data wasn't imported correctly from the old db. Once I fixed that the above code worked as expected.
I'm trying to update all my 4000 Objects in ProfileEntity but I am getting the following exception:
javax.persistence.QueryTimeoutException: The datastore operation timed out, or the data was temporarily unavailable.
this is my code:
public synchronized static void setX4all()
{
em = EMF.get().createEntityManager();
Query query = em.createQuery("SELECT p FROM ProfileEntity p");
List<ProfileEntity> usersList = query.getResultList();
int a,b,x;
for (ProfileEntity profileEntity : usersList)
{
a = profileEntity.getA();
b = profileEntity.getB();
x = func(a,b);
profileEntity.setX(x);
em.getTransaction().begin();
em.persist(profileEntity);
em.getTransaction().commit();
}
em.close();
}
I'm guessing that I take too long to query all of the records from ProfileEntity.
How should I do it?
I'm using Google App Engine so no UPDATE queries are possible.
Edited 18/10
In this 2 days I tried:
using Backends as Thanos Makris suggested but got to a dead end. You can see my question here.
reading DataNucleus suggestion on Map-Reduce but really got lost.
I'm looking for a different direction. Since I only going to do this update once, Maybe I can update manually every 200 objects or so.
Is it possible to to query for the first 200 objects and after it the second 200 objects and so on?
Given your scenario, I would advice to run a native update query:
Query query = em.createNativeQuery("update ProfileEntity pe set pe.X = 'x'");
query.executeUpdate();
Please note: Here the query string is SQL i.e. update **table_name** set ....
This will work better.
Change the update process to use something like Map-Reduce. This means all is done in datastore. The only problem is that appengine-mapreduce is not fully released yet (though you can easily build the jar yourself and use it in your GAE app - many others have done so).
If you want to set(x) for all object's, better to user update statement (i.e. native SQL) using JPA entity manager instead of fetching all object's and update it one by one.
Maybe you should consider the use of the Task Queue API that enable you to execute tasks up to 10min. If you want to update such a number of entities that Task Queues do not fit you, you could also consider the user of Backends.
Put the transaction outside of the loop:
em.getTransaction().begin();
for (ProfileEntity profileEntity : usersList) {
...
}
em.getTransaction().commit();
Your class behaves not very well - JPA is not suitable for bulk updates this way - you just starting a lot of transaction in rapid sequence and produce a lot of load on the database. Better solution for your use case would be scalar query setting all the objects without loading them into JVM first ( depending on your objects structure and laziness you would load much more data as you think )
See hibernate reference:
http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/batch.html#batch-direct
I have a problem while I'm making a Dynamic Query in Liferay 6. I'm trying to make a query to order JournalArticles based on their view count. The view count is specified in another table (AssetEntry).
I'm stuck with this:
DynamicQuery query = DynamicQueryFactoryUtil.forClass(
JournalArticle.class, "articleParent", PortalClassLoaderUtil.getClassLoader());
//adding criterions
query.add(...);
DynamicQuery dq0 = DynamicQueryFactoryUtil.forClass(AssetEntry.class, "asset",
PortalClassLoaderUtil.getClassLoader())
.setProjection(ProjectionFactoryUtil.property("asset.classPK"))
.add(PropertyFactoryUtil.forName("asset.companyId")
.eqProperty("articleParent.companyId"))
.add(PropertyFactoryUtil.forName("asset.groupId")
.eqProperty("articleParent.groupId"));
query.add(PropertyFactoryUtil.forName("articleParent.resourcePrimKey").in(dq0))
.addOrder(OrderFactoryUtil.desc("asset.viewCount"));
With this I get an error message saying: could not resolve property: asset of: com.liferay.portlet.journal.model.impl.JournalArticleImpl.
If I remove the addOrder-call, this error disappears. How should I add the order statement so the main query is aware of asset.viewCount?
AssetEntryQuery assetEntryQuery = new AssetEntryQuery();
assetEntryQuery.setClassName(JournalArticle.class.getName());
assetEntryQuery.setXXX //adding criterions
assetEntryQuery.setOrderByCol1("viewCount");
List<AssetEntry> assetEntries = AssetEntryServiceUtil.getEntries(assetEntryQuery);
I am afraid that there is no direct way to do this with the DynamicQuery API.
I think you would need to use Service builder Finders i.e. Custom Query with Service builder.
You can't use dynamic query because there is no direct reference from JournalArticle entity to AssetEntry entity.
One possibility is to retrieve ordered ids of articles from the AssetEntry table (basically you dq0), then do another query and do the sorting programatically (you have the ids ordered).
Finally I think that this line
query.add(PropertyFactoryUtil.forName("articleParent.resourcePrimKey").in(dq0))
doesn't do what you think it does. resoucePrimKey is reference to resource table for permissions. You need to use id column.
I'm having trouble getting objects back out of SimpleDB using the simpleJPA persistance API. I have successfully installed all the jars and can persist objects no problem. However I cannot seem to retrieve objects using select queries - but weirdly I can get results using count queries. There are no errors or exceptions, the queries simply don't return any results. When I debug I can view the actual AWS Query that is being generated in the background by simpleJPA, and when I run this query against a domain it returns the expected results no problem.
I've included my Java code below, it should return me a list of all the users in my database.
Query query = em.createQuery("SELECT u FROM User u");
List<User> results = (List<User>)query.getResultList();
As I said I can persist objects and count them, so there isn't anything wrong with my entity manager or factory, its just returning empty lists. If you need any more information just ask,
Thanks in advance!
I never got to the bottom of this problem. In the end I started a new AWS project in Eclipse and re-added the JAR files, solving the issue.
I have 4 tables involved in this query.
Campaign - many to one business
Business - one to many client
Client - one to one contact
Contact
In contact there is the field contact_name which is unique. I need to retrieve all campaigns related to contact(via client and business) which campaign field type equals 2.
What is the best way to do it with hibernate?
In SQL is will look like this:
select *
from campaign,contact, business, client
where campaign.type=2
and client.contact_id = contact.contact_id
and contact.name = 'Josh'
and client.business_id = business.business_id
and campaign.campaign_id = business.business_id
I think that the following should work.
from Compaign where Compaign.type=2 and compaign.business.client.contact.contact_name=:name
You can execute native SQL Queries too using createSQLQuery() method of Session.
You can also use Scalar Property to avoid the overhead of using ResultSetMetadata.
You can find more information on this from here