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Regex to remove line break within double quote in CSV

Hi I have a csv file with an error in it.so i want it to correct with regular expression, some of the fields contain line break, Example as below
"AHLR150","CDS","-1","MDCPBusinessRelationshipID",,,"Investigating","1600 Amphitheatre Pkwy
California",,"Mountain View",,"United States",,"California",,,"94043-1351","9958"
the above two lines should be in one line
"AHLR150","CDS","-1","MDCPBusinessRelationshipID",,,"Investigating","1600 Amphitheatre PkwyCalifornia",,"Mountain View",,"United States",,"California",,,"94043-1351","9958"
I tried to use the below regex but it didnt help me
%s/\\([^\"]\\)\\n/\\1/

Try this:
public static void main(String[] args) {
String input = "\"AHLR150\",\"CDS\",\"-1\",\"MDCPBusinessRelationshipID\","
+ ",,\"Investigating\",\"1600 Amphitheatre Pkwy\n"
+ "California\",,\"Mountain View\",,\"United\n"
+ "States\",,\"California\",,,\"94043-1351\",\"9958\"\n";
Matcher matcher = Pattern.compile("\"([^\"]*[\n\r].*?)\"").matcher(input);
Pattern patternRemoveLineBreak = Pattern.compile("[\n\r]");
String result = input;
while(matcher.find()) {
String quoteWithLineBreak = matcher.group(1);
String quoteNoLineBreaks = patternRemoveLineBreak.matcher(quoteWithLineBreak).replaceAll(" ");
result = result.replaceFirst(quoteWithLineBreak, quoteNoLineBreaks);
}
//Output
System.out.println(result);
}
Output:
"AHLR150","CDS","-1","MDCPBusinessRelationshipID",,,"Investigating","1600 Amphitheatre Pkwy California",,"Mountain View",,"United States",,"California",,,"94043-1351","9958"

Create a RegEx surrounding the text you want to keep by parentheses and that will create a group of matched characters. Then replace the string using the group index to compose as you wish.
String test = "\"AHLR150\",\"CDS\",\"-1\",\"MDCPBusinessRelationshipID\","
+ ",,\"Investigating\",\"1600 Amphitheatre Pkwy\n"
+ "California\",,\"Mountain View\",,\"United\n"
+ "States\",,\"California\",,,\"94043-1351\",\"9958\"\n";
System.out.println(test.replaceAll("(\"[^\"]*)\n([^\"]*\")", "$1$2"));
So when we replace the matching string ("United\nStates") by $1$2 we are removing the line break because it not belongs to any group:
$1 => the first group (\"[^\"]*) that will match "United
$2 => the second group ([^\"]*\")" that will match States"

Based on this you can try with:
/\r?\n|\r/
I checked it here and seems to be fine

how to split a string which contains of ( \n : , .)

so how can split this combination in android ?
Thanks in advance :)`
i'm trying like thatString lines[] = String.split("\\r?\\n", -1);
but how can split all data in one time

You can use Pattern for regex split
String fields = "name[Employee Name], employeeno[Employee No], dob[Date of
Birth], joindate[Date of Joining]";
Pattern pattern = Pattern.compile("\\[.+\\]+?,?\\s*" );
String[] split = pattern.split(fields);
References: How to split this string using Java Regular Expressions

Parsing String and Int in java

Im using java and I have a String that I would like to parse which contains the following
Logging v0.12.4
and would like to split it into a String containing
Logging
and an integer array containing
0.12.4
where
array[i][0] = 0
and
array[i][1] = 12
and so on. I have been stuck on this for a while now.

split your string on space to get Logging and v0.12.4
remove (substring) v from v0.12.4
split 0.12.4 on dot (use split("\\.") since dot is special in regex)
you can also parse each "0" "12" "4" to integer (Integer.parseInt can be helpful).

You can use a regex or just normal String splitting
String myString = "Logging v0.12.4";
String[] parts = myString.split(" v");
// now parts[0] will be "Logging" and
// parts[1] will be "0.12.4";
Then do the same for the version part:
String[] versionParts = parts[1].split("\\.");
// versionParts[0] will be "0"
// versionParts[1] will be "12"
// versionParts[2] will be "4"
You can "convert" these to integers by using Integer.parseInt(...)

Here ya go buddy, because I'm feeling generous today:
String string = "Logging v0.12.4";
Matcher matcher = Pattern.compile("(.+?)\\s+v(.*)").matcher(string);
if (matcher.matches()) {
String name = matcher.group(1);
int[] versions = Arrays.stream(matcher.group(2).split("\\.")).mapToInt(Integer::parseInt).toArray();
}

How to split a string into two parts on specific delimeter

I have a string "Rush to ER/F07^e80c801e-ee37-4af8-9f12-af2d0e58e341".
I want to split it into 2 strings on the delimiter ^. For example string str1=Rush to ER/F07 and String str2 = e80c801e-ee37-4af8-9f12-af2d0e58e341
For getting this i am doing splitting of the string , I followed the tutorial on stackoverflow but it is not working for me , here is a code
String[] str_array = message.split("^");
String stringa = str_array[0];
String stringb = str_array[1];
when I am printing these 2 strings I am getting nothing in stringa and in stringb I am getting all the string as it was before the delimiter.
Please help me

You have to escape special regex sign via \\ try this:
String[] str_array = message.split("\\^");

It is because the .split() method requires a regex pattern. Escape the ^:
String[] str_array = message.split("\\^");
You can get more information on this at http://docs.oracle.com/javase/8/docs/api/java/lang/String.html#split-java.lang.String-.

Giving inputs to java regex

I have a regex like below one :
"\\t'AUR +(username) .*? /ROLE=\"(my_role)\".*$"
username and my_role parts will be given from args. So they always change when the script is starting. So how can i give parameters to that part of regex ?
Thanks for your helps.

Define regex like this:
String fmt = "\\t'AUR +(%s) .*? /ROLE=\"(%s)\".*$";
// assuming userName and myRole are your arguments
String regex = String.format(fmt, userName, myRole);

You should escape special characters in dynamic strings using Pattern.quote. To put the regex parts together you can simply use string concatenation like this:
String quotedUsername = Pattern.quote(username);
String quotedRole = Pattern.quote(my_role);
String regexString = "\\t'AUR +(" + quotedUsername +
") .*? /ROLE=\"(" + quotedRole + ")\".*$";
I think mixing regular expressions with format strings when using String.format can make the regex harder to understand.

Use string format or straight string concat to construct the regex before passing it to compile ...

Try this for an example:
String patternString = "\\t'AUR +(%s) .*? /ROLE=\"(%s)\".*$";
String formatted = String.format(patternString, username,my_role);
System.out.println(formatted);
Pattern pattern = Pattern.compile(patternString);
You can run a working example here: http://ideone.com/93YeNg