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Could someone please help me with storing -1.0539727e+15 within java. I have never come across having to store such a number so have no idea what the best data type would be
I think you are looking for a double.
Try out this:
double d = 2e-6;
double f = -1.0539727e15;
System.out.println(d);
System.out.println(f);
System.out.printf("d: %f\n", d);
System.out.printf("f: %f\n", f);
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My Friend ask me this question and i am posting it here, if you have better approach please share
String getRandomMobileNumber() {
double random = Math.random();
Double randomten = random*1000000000.0;
return "0"+Math.round(randomten);
}
You can use this, see javadoc:
String phoneNumber = "0" + ThreadLocalRandom.current().nextInt(10000000, 99999999);
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Calculate the sum of amountField in MyDTO, Java 8
private Double getSum(List<MyDTO> myDTOList) {
return myDTOList.stream().map(MyDTO::getAmount).reduce(0d, Double::sum);
}
You can use Stream.mapToDouble to convert it into a DoubleStream and then use DoubleStream.sum:
return myDTOList.stream().mapToDouble(MyDTO::getAmount).sum();
To mention, the above shall work for amount being of integer type as well, while the code shared by you and this shall still work fine if the type of amount is already double.
Or as pointed out in comments by you, if your DTO object can be null, you can filter out those values using:
return myDTOList.stream().filter(Objects::nonNull).mapToDouble(MyDTO::getAmount).sum();
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I am using Java and have some problems.
I made two BigInteger variables, p and q.
In my code, I want to add if function, like if(p=1 \ q=1).
I tried many ways but there was error. Do you know how to solve this?
Your question is not completely clear, but you need to use the BigInteger.equals() method, as in this example:
if (BigInteger.equals(p, BigInteger.ONE) || BigInteger.equals(q, BigInteger.ONE)) {
// do something
}
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double ps1 = (double) (((double)1)/(double)100);
int maz = (double) ((ps1) * Double.parseDouble(500000.102)));
Is this right to use double, or shall i use long?
I am doing large calculations. And need to keep the correctness of the .102.
Use double! Because long has no signs after , (they have no fraction)
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I have a function:
ItemValue[i] = substring(toString(obj),0,toString(obj).indexOf(".") + 4);
where obj is a number. The function works for 9,999,999.99999 -> 9999999.999 but values such as 99,999,999.99999 gets converted to 9.999.
Is it a data type issue?
Thanks,
The problem is with the double values you are using. The value 99999999.99999 will be translated to 9.999999999999E7 by toString() so the results you are getting. In order to strip the digits after decimal you can use DecimalFormat class:
DecimalFormat f = new DecimalFormat();
f.setMaximumFractionDigits(3);
f.setMinimumFractionDigits(3);