I have a String containing an ASCII digit character. I'd like to convert it to its ASCII-code as an int, so the charAt-method does not work directly here.
E.g. I have String number = "4";, how do I get its ASCII code (52) into an int?
You need the typecast the character to integer.
String name = "a";
char character = name.charAt(0);
int ascii = (int) character;
Related
I have this:
char c = "\ud804\udef4".charAt(0);
char d = "\ud804\udef4".charAt(1);
How will I print c and d as hex Strings ?
I want d804 for c and def4 for d.
It doesn't matter whether the char is a surrogate pair or not. If you have a char, you can convert it to a hex string by Integer.toHexString(), since chars can be implicitly converted to int.
System.out.println(Integer.toHexString(c));
System.out.println(Integer.toHexString(d));
Getting invalid unicode error with below code
Uniocde want to print: unicode:0x16
PrintWriter pw = new PrintWriter(System.out, true);
char aa = "\u0x16";
pw.println(aa);
What's wrong happening here ?
\u0x16 is not a valid unicode character reference. There should be 4 hexadecimal digits (numbers 0-9 letters a-f) after \u - the "x" is not valid.
If you meant to use the character U+0016, it's written as \u0016:
char aa = '\u0016';
The following is equivalent, but it uses an integer constant rather than a character constant.
char aa = 0x16;
I want to know how to divide a String and seperate it into two variables, one as char and other as integer
Example:
If "C 365" Is my string then char variable will be 'C' and Integer variable will be 365
The char can be extracted with charAt. For the int, just use substring to take the string from the third character (the first is the char and the second is a space), and then parse it:
String str = "C 365";
char ch = str.charAt(0);
int i = Integer.parseInt(str.substring(2));
I have a integer:
int octalValue = 103
I want to convert this to text in Java. How can I do this?
The expected output would be 'C'.
Octal literals need to be prefixed with a 0:
int octalValue = 0103; //89
You can then convert it to the corresponding ASCII code:
char c = (char) octalValue; //C
This did it for me:
int octalValue = 123;
String abc = Integer.toString(octalValue);
char abcChar = (char) Integer.parseInt(abc, 8);
Better solutions might be out there.
private static byte[]theTestText ={0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,(byte) 0x88,(byte) 0x99,(byte) 0xAA,(byte) 0xBB,(byte) 0xCC,(byte) 0xDD,(byte) 0xEE,(byte) 0xFF};
String str= new String(theTestText); // converted the byte array to string
char ch = str.charAt(8); // extracting a specific character from string
I want to obtain the hex value from the character 'ch' as defined in the original byte array i.e. 0x88. Is there any way to get that?
To get the hexa value in a string:
String str= new String(theTestText); // converted the byte array to string
char ch = str.charAt(8); // extracting a specific character from string
String hex = String.format("%04x", (int) ch); // Converting the char to a string with its hexadecimal value