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cant find the element using classname in selenium java

I'am using selenium framework to test my own website. Im trying to click on specific icon which using anchor tag. I have java selenium code to click but couldn't click. Tried many xpath, css selectors, class name and names. but didn't worked. But can run the script and it is opening the chrome and navigating to entered domain but the clicking option is not working
above code I need to click nav-twitter class anchor option . which will create another tab in chrome to show my twitter page. but after running the app .it is only navigating to the page domain and nothing works.
So, This is my code where I have added. until the maximize everything works but not the anchor tag
This kind of error im getting when running the script in chrome. Please anyone let me know where I have been wrong here or is there are any way to make it happen. Thanks in advance.

Whenever you are initiating webdriver make sure to add implicit wait statement, so it can wait for sometime before looking for objects. Add below statement right after chromedriver initialization and your code should work without any issues.
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);

Your locator is slightly off. In your code you are looking for an element with tagName as twitter which doesn't exists. Instead you can use either of the following locator strategies:
Using cssSelector:
WebElement navTwitter = driver.findElement(By.cssSelector("a.nav-twitter[name='twitter']"));
navTwitter.click();
Using xpath:
WebElement navTwitter = driver.findElement(By.xpath("//a[#class='nav-twitter' and name='twitter']"));
navTwitter.click();

You have used wrong selector/locator here. "twitter" is not tag name, Tag name is the value from less than symbol to the first space or greater than symbol. Words like div, p, a, span are the tag names.
So here a is the tag name and name, class, href are attribute which you can use while forming xpath or css locators. So you can create multiple locators here:
By using class name attribute
By.className("nav-twitter");
By creating xpath using name attribute
By.xpath("//a[#name='twitter']");]
By creating xpath using class attribute
By.xpath("//a[#class='nav-twitter']");
By creating css locator using class attribute.
By.cssSelector("a[class*='nav-twitter']");
By using dot symbol in css selector with class name
By.cssSelector("a.nav-twitter");
Similarly you can create css selector with name too. Since there are multiple tags, so you can not use a tag directly and If you want to use By.tagName("a") then it will click on first tag present on the page
Note: We use dot with class name and Hash (#) with Id name while forming css selectors.

How to click a button where the class is the same for another options?

I am trying to click a button from a list but this button has the same class than others in the list because they have the same name (btn ban-red) so how can I click it if in the inspect I have this information:
<a class=“btn ban-red” data-track-event=“navigate” data-track=name=“Jobylon” - Quality Engineer” href=“https://emp.jobylon.com/jobs/16654-f/” target=“_blank”>View job/a>
The inspect is copying this xpath:
/html/body/div[1]/div[4]/div/div/div/div[3]/div/div/div/div[1]/section/div/div[2]/div[1]/div[1]/article[14]/a
But it is not working
I also created my own xpath this way:
wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//a[#data-track-name=‘Jobylon - Quality Engineer’]"))).click();
But is not working either
I am using Selenium with java and I am in a Macbook, thank you for your help.

Absolute xpath not recommended. You can try using relative xpath.
Locate based on element text
driver.findElement(By.xpath("//a[contains(.,'View job')]")).click()
Locate using combination of element attribute if classes are not unique
driver.findElement(By.xpath("//a[#class='btn ban-red'][#data-track-event='navigate']")).click()
OR
driver.findElement(By.xpath("//a[#class="btn ban-red"][#href='https://emp.jobylon.com/jobs/16654-f/']")).click()
Better to use CSS selector as its faster then xpath. So you try like
driver.findElement(By.cssSelector("a[class='btn ban-red'][data-track-event='navigate']")).click()
OR
driver.findElement(By.cssSelector("a[class="btn ban-red"][href='https://emp.jobylon.com/jobs/16654-f/']")).click()
Still facing some issue like element not visible or no such element then try with explicit wait conditions until your element gets visible or clickable.

How do I get an xpath using Firepath plugin

I'm not able to get an xpath using FirePath. I want to locate username field of a login form using xpath in Firepath. But when I try to find the same element,
I'm getting xpath like :
html/body/div[3]/div/div/div/div/div[2]/div/form/div[1]/input
How can I use it in Selenium script ?

You can use it like:-
WebElement ele1 = driver.findElement(By.xpath("html/body/div[3]/div/div/div/div/div[2]/div/form/div[1]/input"));
ele1.sendKeys("username");
Here username in double quotes would be replaced by actual value you want to enter in username field.

This is also xpath which is called absolute xpath If you are looking for relative xpath then uncheck the option as shown in below image
And you can use this xpath like :
driver.findElement(By.xpath("html/body/div[3]/div/div/div/div/div[2]/div/form/div[1]/input")).sendKeys("username");

You can do this via the by.xpath
webdriver.findElement(By.xpath("html/body/div[3]/div/div/div/div/div[2]/div/form/div[1]/input")).click();
You can also search for a relative xpath witch is more robust have a look at this for more information of xpath.
Also have a look at locators in selenium for more information about the diffrent locators

How to find element having dynamic ID / Name changing on every page load using Selenium WebDriver

I found a few answers about this but they did not answer my question an so I am writing a new question.
I have HTML code having below kind of checkbox elements (in browser's inspect element)
<input role="checkbox" type="checkbox" id="jqg_TransactionFormModel501EditCollection2_147354_grid_-1274" class="cbox" name="jqg_TransactionFormModel501EditCollection2_147354_grid_-1274" value="true">
In my test case I want to click on checkbox using its ID using Selenium Webdriver.
here Id= "jqg_TransactionFormModel501EditCollection2_147354grid-1274" is dynamic.
in above id, Bold & Italic marked letters (dynamic) will change with different check boxes in same page as well as page refresh.
Bold marked letters (dynamic) will change on page refresh only (remain same through all the check boxes in same page.)
How shoud I format/write XPATH so that I can click on desired check boxes using below statement.
WebElement checkbox = webDriver.findElement(By.id("idOfTheElement"));
if (!checkbox.isSelected()) {
checkbox.click();
}
Thanks for your help in advance.. !

Here are a few examples of xpaths which you can use to find your checkbox
//input[contains(#id,'jqg_TransactionFormModel')]
OR, if you want more checks, try something like
//*[starts-with(#id,'jqg_TransactionFormModel') and contains(#id,'EditCollection2_')]
Additionally, you can try regex as well using matches
//*[matches(#id,'<regex matching your id>')]

You can use partial ID using cssSelector or xpath
webDriver.findElement(By.cssSelector("[id*='TransactionFormModel']"));
webDriver.findElement(By.xpath("//input[contains(#id, 'TransactionFormModel')]"));
You can replace TransactionFormModel with any other fixed part of the ID.
As a side note, no need to locate the element twice. You can do
WebElement checkbox = webDriver.findElement(By.id("idOfTheElement"));
if (!checkbox.isSelected()) {
checkbox.click();
}

You can write xpath like this :
//input[starts-with(#id,'jqg_TransactionFormModel')]
//input[contains(#id,'jqg_TransactionFormModel')]

I recommend not using ID's or xpath and adding a data attribute to your elements. This way, you can avoid the annoyance of xpath and have a strong selector that you feel confident will always be selectable.
For example, you could call the attribute: data-selector. You can assign a value of "transactionFormModelCheckbox". Then, when creating a new element, you create by css selector with the value referenced above.
No matter what type of formatting, you'll always be able to select that checkbox - as long as the element exists in the DOM. If you need to investigate other attributes, you can use the selector to do things like hasClass() or anything else you need.
Hope that helps !

How to click on a specific link with Selenium?

I have an integration test. It uses Selenium, from Java. I would like to click on a specific link, which has no ID. All I know about it is that it is in a specific cell in a specific table. The table has an ID.
How can I click on that element using DefaultSelenium?
I tried
defaultselenium.click("th.tblHeader:nth-child(14) > a:nth-child(1)");
because Firefox said that it's the XPath of the element, and I also tried
defaultselenium.click("#tableId > thead:nth-child(1) > tr > th.tblHeader:nth-child(14) > a:nth-child(1)");
because I don't use XPath very often and I had no idea what I was doing, but I thought that having a unique ID in the equation may help.
Both of them give me "ERROR: Element ... not found" messages.

That's not XPath, it's CSS. Vanilla Firefox isn't helpful for extracting XPath from a page, but there are plugins available. Alternatively, Chrome will give you the XPath.