Develop Reference

Parse a Date of MMMM YYYY format

I have to parse a date string (e.g. "October 2015") to a Date.
So the question is: how can I parse a date of MMMM yyyy format? Its ok if the new Date object is the first month of the given month.
I tried:
DateTimeFormatter formatter = new DateTimeFormatterBuilder().appendPattern("MMMM yyyy").toFormatter();
TemporalAccessor ta = formatter.parse(node.textValue());
Instant instant = LocalDate.from(ta).atStartOfDay().atZone(ZoneId.systemDefault()).toInstant();
Date d = Date.from(instant);
But it does not work since the day is missing.

What you have there is a YearMonth, not a LocalDate since the day is missing.
The following works:
String string = "October 2015";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMMM yyyy", Locale.ENGLISH);
YearMonth yearMonth = YearMonth.parse(string, formatter);
// Alternatively: YearMonth yearMonth = formatter.parse(string, YearMonth::from);
LocalDate date = yearMonth.atDay(1);
System.out.println(yearMonth); // prints "2015-10"
System.out.println(date); // prints "2015-10-01"
If you then want that as a java.util.Date, you need to specify which time zone you mean, maybe UTC or system default?
// ZoneId zone = ZoneOffset.UTC;
ZoneId zone = ZoneId.systemDefault();
Date javaUtilDate = Date.from(date.atStartOfDay(zone).toInstant());
System.out.println(javaUtilDate); // prints "Thu Oct 01 00:00:00 CEST 2015"
// because i'm in Europe/Stockholm.

How about this
DateFormat format = new SimpleDateFormat("MMMM yyyy", Locale.ENGLISH);
Date date = format.parse("October 2015");
System.out.println(date); // Prints Thu Oct 01 00:00:00 BST 2015

For java 8
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.appendPattern("MMMM yyyy")
.toFormatter(Locale.US);
TemporalAccessor ta = formatter.parse("October 2015");
YearMonth ym = YearMonth.from(ta);
LocalDateTime dt = LocalDateTime.of(ym.getYear(), ym.getMonthValue(),
1, 0, 0, 0);
Instant instant = Instant.from(dt.atZone(ZoneId.systemDefault()));
Date d = Date.from(instant);

You can use SimpleDateFormat's parse method for that
private static final SimpleDateFormat DATE_FORMAT = new SimpleDateFormat("MMMMM yyyy"); //MMMM yyyy example: October 2015
public Date getDateFromString(String input) {
return DATE_FORMAT.parse(input);
}
For more information, see: http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html#parse(java.lang.String,%20java.text.ParsePosition)
Explanation of format:
MMMM indicates you are parsing full name months such as "October"
yyyy indicates you have 4-digit length years. If you wanted to parse for example, October 15, your format would look like this: "MMMM yy"

Why not use a SimpleDateFormatter?
This works fine for me:
SimpleDateFormat formatter = new SimpleDateFormat("MMMM yyyy");
Date d = formatter.parse("Oktober 2015");

ParseException when parse date via SimpleDateFormat

I'm trying to parse date from string to Date
My string date is: Fri Apr 30 01:20:29 +0700 2010
My code is:
SimpleDateFormat format = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
Date date = format.parse(input);
But i'm getting an Unparsable date exception.
What's wrong?

Check your format, you only have one E instead of three :
EEE MMM dd HH:mm:ss Z yyyy
EDIT : also check your JVM's language locale or specify one for your call.
As writen in comments, following code works :
SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss Z yyyy", Locale.US);

SimpleDateFormat parse throws exception

I have the following variable declaring format of SimpleDateFormat:
private static SimpleDateFormat dateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
When I try to parse following string with above format I get Unparsable date exception :
newDate = dateFormat.parse("Mon Mar 24 16:49:31 UTC 2013");
What am I doing wrong? Any idea? It is strange that above line works in emulator, but not on phone.

Unparseable date: when convert date from dd MMM yyyy format to dd/MM/yyyy

I get Unparseable error when I run below code. How can I convert dd MMM yyyy format to dd/MM/yyyy format?
public Calendar myMethod(){
String dateStr = "16 Dec 2014"
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
Date thedate = formatter.parse(dateStr);
Calendar cal = Calendar.getInstance();
cal.setTime(thedate);
return cal;
}

Assuming you fix the blatant syntax errors, then:
String dateStr = "16 Dec 2014" // <== This date is in dd MMM yyyy
formatter = new SimpleDateFormat(dd/MM/yyyy); // <== This SDF is in dd/MM/yyyy
Date thedate = formatter.parse(dateStr); // <== So how can it be expected to parse?
What you do is create a parser for the format you need to parse, and a formatter for the format you want:
String dateStr = "16 Dec 2014";
SimpleDateFormat parser = new SimpleDateFormat("dd MMM yyyy");
Date thedate = parser.parse(dateStr);
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
String dateStrReformatted = formatter.format(thedate);

java.text.ParseException: Unparseable date Exception while converting timestamp value to time in java

I want to convert a Timestamp value which is passed as String to SimpleDateFormat Object into Time Value but it throws a Unparseable date exception.
The Value which i am passing is Thu Jan 1 17:45:00 UTC+0530 1970
Bur i am getting an Exception as mentioned below:
java.text.ParseException: Unparseable date: "Thu Jan 1 17:45:00 UTC+0530 1970"
Please find the below code which i have implemented(Not Working):
static SimpleDateFormat dateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy", Locale.US);
static SimpleDateFormat inputFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy", Locale.US);
static SimpleDateFormat outputFormatTime = new SimpleDateFormat("HH:mm:ss");
public static String convertUtcDateStringToTime(String utcDateValue) throws Exception
{
Date parsedDate = dateFormat.parse(utcDateValue);
String returnDate=outputFormatTime.format(inputFormat.parse(parsedDate.toString()));
return returnDate;
}
If i use the below code it works fine for me(Working) but its a depreciated function of Date which i want to avoid..
#SuppressWarnings("deprecation")
public static String convertUtcDateStringToTime(String utcDateValue) throws Exception
{
Date dateValue=new Date(utcDateValue);
Date parsedDate = dateFormat.parse(dateValue.toString());
String returnDate=outputFormatTime.format(inputFormat.parse(parsedDate.toString()));
return returnDate;
}
Please Guide Me To implement the logic where i have missed. Thanks in advance.

with an addition to the answers if the formatting string is like this
"EEE MMM dd HH:mm:ss z yyyy"
then your input string should be
"Thu Jan 1 17:45:00 +0530 1970"
note that the "UTC" is skipped as implicitly it refers to the RFC 822 time zone

First of all, your 2nd SimpleDateFormat object, is not needed at all. You are doing the extra work, which is not needed. So, remove this variable:
static SimpleDateFormat inputFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy", Locale.US); // Not needed.
Secondly DateFormat#format(Date) methods takes a Date object. You are passing it a String. That wouldn't work. That is why you don't need the above object. There is no need to do a inputFormat.parse(parsedDate.toString()) again.
Now, the format to parse your current string should be:
"EEE MMM dd HH:mm:ss 'UTC'z yyyy"
You need to give the UTC in quotes, before z. Or for more general case:
"EEE MMM dd HH:mm:ss zZ yyyy"
So, your code should be like:
static SimpleDateFormat dateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss zZ yyyy", Locale.US);
static SimpleDateFormat outputFormatTime = new SimpleDateFormat("HH:mm:ss");
public static String convertUtcDateStringToTime(String utcDateValue) throws Exception
{
Date parsedDate = dateFormat.parse(utcDateValue);
String returnDate=outputFormatTime.format(inputFormat);
return returnDate;
}

You input dateformat needs to be
SimpleDateFormat dateFormat = new SimpleDateFormat("EEE MMM dd HH:mm:ss zZ yyyy", Locale.US);
The other formatting is all upto, you based on your requirements.