Develop Reference

Getting NumberFormat while trying to parse a string

I'm trying to parse a string to an integer. The string is a number when I do sys out but when I try to parse it then it adds a double quote at the beginning. I'm not doing anything additional.
Following is a snippet of my code:
System.out.println("Result 2 is: "+results[2]);
String temp = results[2].replace("\"", "");
System.out.println("String Temp is: "+temp);
int height = Integer.parseInt(results[1].replace("\"", ""));
int width = Integer.parseInt(results[2].replace("\"", ""));
In the logs:
String Temp is: 2550
wt.system.err wcadmin - java.lang.NumberFormatException: For input string: "2550
This exception is only for result[2]. Something to do with character set?

Option 1: Parse temp. Change
int width = Integer.parseInt(results[2].replace("\"", ""));
to
int width = Integer.parseInt(temp);
Option 2: Use a regular expression to remove everything not a digit instead of trying to handle corner cases by hand.
int width = Integer.parseInt(results[2].replaceAll("\\D+", ""));

How to convert string with $ sing in it to int

I have a string "$1,076.00" and I want to convert them in to int,
I capture some value $1,076.00 and saved in string called originalAmount,
and tried int edited = Integer.parseInt(originalAmount); and it gave me error java.lang.NumberFormatException: For input string: "$1,076.00"
can anyone help?

You need to remove the undesired part ($ sign) and then parse the string to double carefully since the decimal part is a locale dependent
String pay = "$1,076.00";
NumberFormat format = NumberFormat.getInstance(Locale.FRANCE);
Number number = format.parse(pay.replace("$", ""));
double result = number.doubleValue();
System.out.println(result);

string sourceString = "$1,076.00";
sourceString.substring(1, sourceString.length() - 1)
int foo = Integer.parseInt(sourceString);

Try this:
String amount = "$1,076,.00";
String formatted = amount.replace("$", ""); // remove "$" sign
formatted = formatted.replace(",", ""); // remove "," signs from number
double amountDouble = Double.parseDouble(formatted); // convert to double
int amountInt = (int)amountDouble; // convert double value to int
System.out.println(amountInt); // prints out 1076

String originalAmount="$1076.00";
String amount = originalAmount.replace($,"");
int edited = Integer.parseInt(amount);

Thanks everyone yr answers help me a lot
I have come up with
originalAmount = originalAmount.substring(1);
if (originalAmount.contains("$")) {
originalAmount = originalAmount.replace("$", "");
}
newOriginalAmt = Double.parseDouble(originalAmount);
System.out.println(newOriginalAmt);
pls let me know yr thoughts

How to Select the last part from ArrayAdapter.getItem(which)?

I am selecting an item from arraylist
ArrayAdapter.getItem(which)
I am getting the result as Amazon.com%2C%20Inc.-AMZN
I just want the last part that is AMZN of this string to append in my url.

Normal String operation like lastIndexOf and substring
String str = "Amazon.com%2C%20Inc.-AMZN";
String result = str.substring(str.lastIndexOf("-") + 1);
System.out.println(result);
or if there are no other - in the String use
String endBit = str.split ("-")[1];

Please refer this url
How to get a string between two characters?
String s = "Amazon.com%2C%20Inc.-AMZN";
String result = s.substring(s.indexOf("-") + 1);
System.out.println(result);
Output: AMZN

try this.
if there is no other -
String val = "Amazon.com%2C%20Inc.-AMZN";
String arr[]=val.split("-");
and at index 1 you can get your value.
like arr[1]// this will contain "AMZN"

Decimal Format, says it needs to be a string?

I'm getting the error "cannot convert from String to Double" when I run this code, any ideas?
DecimalFormat df = new DecimalFormat("##.###");
String [] data = null;
data = str.split(" ");
Double bat_avg = Double.parseDouble(data[4])/Double.parseDouble(data[2]);
bat_avg = df.format(bat_avg);
System.out.println(bat_avg);

DecimalFormat#format(double) returns a String so the output needs to be this type rather than a Double:
String output = df.format(bat_avg);

How to convert / cast long to String?

I just created sample BB app, which can allow to choose the date.
DateField curDateFld = new DateField("Choose Date: ",
System.currentTimeMillis(), DateField.DATE | DateField.FIELD_LEFT);
After choosing the date, I need to convert that long value to String, so that I can easily store the date value somewhere in database.
I am new to Java and Blackberry development.
long date = curDateFld.getDate();
How should I convert this long value to String? Also I want to convert back to long from String. I think for that I can use long l = Long.parseLong("myStr");?

See the reference documentation for the String class: String s = String.valueOf(date);
If your Long might be null and you don't want to get a 4-letter "null" string, you might use Objects.toString, like: String s = Objects.toString(date, null);
EDIT:
You reverse it using Long l = Long.valueOf(s); but in this direction you need to catch NumberFormatException

String strLong = Long.toString(longNumber);
Simple and works fine :-)

Long.toString()
The following should work:
long myLong = 1234567890123L;
String myString = Long.toString(myLong);

very simple,
just concatenate the long to a string.
long date = curDateFld.getDate();
String str = ""+date;

1.
long date = curDateFld.getDate();
//convert long to string
String str = String.valueOf(date);
//convert string to long
date = Long.valueOf(str);
2.
//convert long to string just concat long with empty string
String str = ""+date;
//convert string to long
date = Long.valueOf(str);

String logStringVal= date+"";
Can convert the long into string object, cool shortcut for converting into string...but use of String.valueOf(date); is advisable

Just do this:
String strLong = Long.toString(longNumber);

String longString = new String(""+long);
or
String longString = new Long(datelong).toString();