Develop Reference

How to send binary content to a servlet in Action Script

I have an action script function in a file which sends a pdf file as binary content to a servlet as shown below.
private function savePDF(pdfBinary:ByteArray, urlString:String):void{
try{
Alert.show("in savePDF urlString" +urlString);
//result comes back as binary, create a new URL request and pass it back to the server
var header:URLRequestHeader = new URLRequestHeader("Content-type", "application/octet-stream");
var sendRequest:URLRequest = new URLRequest(urlString);
sendRequest.requestHeaders.push(header);
sendRequest.method = URLRequestMethod.POST;
sendRequest.data = pdfBinary;
Alert.show("in savePDF calling sendToURL");
sendToURL(sendRequest);
}catch(error:*){
Alert.show("in savePDF err" +error);
trace(error);
}
}
This code works fine in flashplayers versions like 10,11,13
But fails in flashplayers of higher versions like 14.0.0.126 or above.
I get the following error
SecurityError: Error #3769: Security sandbox violation: Only simple headers can be used with navigateToUrl() or sendToUrl().
Any suggestions on how to resolve this ?

You could try using a URLLoader instead of sendToURL()
Alert.show("in savePDF urlString" +urlString);
var header:URLRequestHeader = new URLRequestHeader("Content-type", "application/octet-stream");
var sendRequest:URLRequest = new URLRequest(urlString);
sendRequest.requestHeaders.push(header);
sendRequest.method = URLRequestMethod.POST;
sendRequest.data = pdfBinary;
Alert.show("in savePDF calling URLLoader");
var loader:URLLoader = new URLLoader();
loader.load(sendRequest);

Retrieving absolute URL from a webpage

I want to extract full link from a HTML file. Full link I mean absolute links. I used Tika for this purpose. Here is my code:
URL url = new URL("http://www.domainname.com/");
InputStream input = url.openStream();
LinkContentHandler linkHandler = new LinkContentHandler();
ContentHandler textHandler = new BodyContentHandler();
ToHTMLContentHandler toHTMLHandler = new ToHTMLContentHandler();
TeeContentHandler teeHandler = new TeeContentHandler(linkHandler,
textHandler, toHTMLHandler);
Metadata metadata = new Metadata();
ParseContext parseContext = new ParseContext();
HtmlParser parser = new HtmlParser();
parser.parse(input, teeHandler, metadata, parseContext);
System.out.println("title:\n" + metadata.get("title"));
for (Link link : linkHandler.getLinks()) {
System.out.println(link.getUri());
}
This give me relative url like /index.html or documents/US/economicreport.html but the absolute url in this case is http://domainname.com/index.html.
How can I get all the link correctly means the full link including domain name? How can I do that in Java?

If you have stored the base website URL in url, the following should work:
URL url = new URL("http://www.domainname.com/");
String givenUrl = ""; //This is the parsed address
if (givenUrl.charAt(0) == '/') {
String absoluteUrl = url + givenURL;
} else {
String absoluteUrl = givenUrl;
}

Slightly better than the previous, but only slightly, is
URL targetDocumentUrl = new URL("http://www.domainname.com/content.html");
String parsedUrl = link.getURI();
String absoluteLink = new URL(targetDocumentUrl, parsedURL);
However, it is still not a good solution as it has problems when the html document has the following tag
base href="/"
and the link being parsed is relative and starts with "../".
Of course you can get around this a number of ways but they involve a bit of work such as implementing a ContentHandler. I have to think for something so basic there must be a simple way to do this with the Tika LinkContentHandler.

how to send url in email without encoding

I am using Amazon Simple Email Service java API to send mail to receivers.
I am sending URL in mail body inside tag.
My use case demands the user to double click on the URL received to prompt some action. (like confirmation mail)
Problem is the url gets encoded while receiving. On double clicking it gives page not found (404) error.
Original URL : http://something.com/confirm/email=abc#hotmail.com&regKey=somekey&confirm=true
When i double click on this URL on mail, the link is opened in address bar as :
http://something.com/confirm/email=abc%40hotmail.com%26regKey=somekey%26confirm=true
I am using AmazonSimpleEmailServiceClient. Code is below :
SendEmailRequest request = new SendEmailRequest().withSource(sourceAddress);
String confirmationURL="http://something.com/confirm/email=abc#hotmail.com&regKey=somekey&confirm=true";
List<String> toAddresses = new ArrayList<String>();
toAddresses.add(toEmail);
Destination dest = new Destination().withToAddresses(toAddresses);
request.setDestination(dest);
Content subjContent = new Content().withData("Confirmation Request");
Message msg = new Message().withSubject(subjContent);
// Include a body in both text and HTML formats
Content textContent = new Content().withData("Dear please go to the following URL:"+
confirmationURL+"\n\n");
Content htmlContent = new Content().withData("<p>Dear please go to the following URL:</p>"+
"<p>"+confirmationURL+"</p>");
Body body = new Body().withHtml(htmlContent).withText(textContent);
msg.setBody(body);
request.setMessage(msg)
UPDATE
Just found, this problem is occurring only when recipient email is in hotmail.com. Why microsoft always have to do something differently ? Somebody help !

Use the class java.net.URLEncoder:
String confirmationURL = URLEncoder.encode( "http://something.com/confirm/email=abc#hotmail.com&regKey=somekey& confirm=true", "UTF-8");

jcifs.smb.SmbException: The network name cannot be found

The following is my piece of code
SmbFile catalExp = new SmbFile("smb://<Shared machine name>/Project share/Home/4. Folders/planning - Design & Exec/sample.txt",
new NtlmPasswordAuthentication(LoadProp.getShrdDomain(),"user","paswd"));
In this i am getting the error
jcifs.smb.SmbException: The network name cannot be found
at jcifs.smb.SmbTransport.send(SmbTransport.java:753)
at jcifs.smb.SmbSession.sessionSetup(SmbSession.java:140)
at jcifs.smb.SmbSession.send(SmbSession.java:103)
at jcifs.smb.SmbTree.treeConnect(SmbTree.java:132)
at jcifs.smb.SmbFile.connect(SmbFile.java:674)
at jcifs.smb.SmbFile.connect0(SmbFile.java:644)
at jcifs.smb.SmbFile.open0(SmbFile.java:700)
at jcifs.smb.SmbFile.createNewFile(SmbFile.java:2027)
Is this anything to do with the user rights to that particular shared folder or am I doing anything wrong
Please advice

I ran into this error message, and it turned out the problem was that my network path was incorrect. You'll want to ensure that the NtlmPasswordAuthentication object is configured correctly, that your network path is correct, and that you've set the jcifs.netbios.wins property correctly, as indicated in the first example on this page.
For example, to load a remote properties file:
final NtlmPasswordAuthentication AUTH = new NtlmPasswordAuthentication("domainname", "username", "password");
Config.setProperty("jcifs.netbios.wins", "10.10.1.1");
Properties props = new Properties();
InputStream in = new SmbFileInputStream(new SmbFile("smb://10.10.1.1:445/rootfolder/path/filename.properties", AUTH));
props.load(in);
(You'll need to add try/catch and input stream closing)
A good way to ensure that all of your parameters are correct is to test logging into and locating the file using a smb/cifs client. For example smbclient on linux/unix:
smbclient -Uusername -p 139 //10.10.1.1/rootfolder
The domain is displayed at the top when you login with smbclient:
Domain=[DOMAINNAME]
..and you can navigate to your file to make sure you've got the path correct.

After running into this issue for almost 1 day i realize that these exception is meaningless
I was just giving wrong path of server side location
Below is the peace of groovy code worked for me
String domain = "domain"
String user = "username"
String pass = "password"
String IP = "xx.yy.zz.aa"
String sharedFolder="//my//path//to//server//";
String path="smb://$IP"+sharedFolder+"test.txt";
NtlmPasswordAuthentication auth = new NtlmPasswordAuthentication(domain, user, pass );
SmbFile smbFile = new SmbFile(path,auth);
SmbFileOutputStream smbfos = new SmbFileOutputStream(smbFile);
smbfos.write("testing....and writing to a file".getBytes());
System.out.println("completed ...nice !");

Well I'm getting this error also but only on one device, my code that works on Android 4.04 is
String strprog = "STRING CREATED| "; //debug log string
try {
strprog += "NTLM| ";
NtlmPasswordAuthentication auth = new NtlmPasswordAuthentication("username:password");
strprog += "SMB| ";
SmbFile file = new SmbFile("smb://<pcname>/foldername/filename.txt",auth);
strprog += "EXIST| ";
String there = String.valueOf(file.exists());
strprog += "View| ";
TextView pp;
pp = (TextView) findViewById(R.id.tv);
pp.setText(there);
} catch (Exception e) {
// TODO Auto-generated catch block
strprog += "ERROR! ";
TextView ll;
ll = (TextView) findViewById(R.id.tv);
ll.setText(strprog + e.getStackTrace().toString() + " " + e.getMessage() + " " + e.getLocalizedMessage() );
}
The only difference I see is where you have your NtlmPasswordAuth compared to mine.
But as I stated for some reason this throws null input param on Andriod 2.0 when I dive deeper then smb://host but I hope this helps you out.

I had this problem, and it turned out that I did not see what the share name was that was mapped to my Windows shared drive... So, using Mac OS, I ran:
smbutil view smb://MYUSERNAME#HOSTNAME
After I was prompted for my password, I then was displayed a list of share names (that weren't evident when I looked at this stuff using Windows). Once I found my share name, it was as simple as using that when connecting with JCIFS:
new SmbFile("smb://HOSTNAME/SHARENAME/path/I/was/trying/to/access", auth);

Getting the sessionKey using Facebook-Java API

I am developing a Facebook application. In this application, I use Java API provided by Google and the application is based on web.
I have the facebook_api_key and facebook_secrete, but how to get the sessionKey?
This code is not web-based:
FacebookJsonRestClient client = new FacebookJsonRestClient(Test.API_KEY, Test.SECRET);
String token = client.auth_createToken();
String url = "http://www.facebook.com/login.php?api_key=";
url += Test.API_KEY;
url += "&v=1.0";
url += "&auth_token=";
url += token;
String strCommand = "C:/Program Files/Internet Explorer/IEXPLORE.EXE ";
strCommand += url;
Runtime.getRuntime().exec(strCommand);
// wait until the login process is completed
// fetch session key
String session = client.auth_getSession(token, true);
......
I want to change it to a web-based one.

Why can't you try this way:
String sessionKey = request.getParameter(FacebookParam.SESSION_KEY.toString());
FacebookXmlRestClient client = new FacebookXmlRestClient(FB_API_KEY, FB_SECRET_KEY, sessionKey);
I also suggest the FaceBook Developer Forum Dicussion and an article describe about generating session keys. I thought it could be helpful to you..