I am using following code to decrypt cipher text encrypted by 128 bit AES.
final IvParameterSpec ivSpec = new IvParameterSpec(ivBytes);
final SecretKeySpec keySpec = new SecretKeySpec(keyBytes, "AES");
final Cipher cipherSpec = Cipher.getInstance("AES/CBC/PKCS5PADDING");
cipherSpec.init(Cipher.DECRYPT_MODE, keySpec, ivSpec);
cipherSpec.doFinal(DatatypeConverter.parseBase64Binary(encrypted));
My encrypted text is simple one line statement and I am using following key and initial verctor
Key = "77696567683763656548616574326F6F"; // 128 bit key, hext string
initVector = "6F68706865726F68563274686F6F3761"; // 16 bytes IV, hex string
Everything worked fine except following scenario.
1)Encrypt the plain text using key as the initial vector and initial vector ad the key. Decryption failed with BadPaddingException
2)Encrypt using key as the key and initial vector as the initial vector. Above code decrypts the cipher text without exception but output is garbage. Not what I encrypted.
3)Decrypts again above correctly encrypted cipher text (in 2 step) and now it is decrypted to the correct plain text.
My question is why the decryption fails to decrypt into correct cipher text in step 2 ?
I believe your key, if 128 bits, need to be a 16 character(utf-8) byte array as opposed to 32 characters. So you'd want to do something like :
Key = ("7769656768376365").getBytes("UTF-8");
Related
I am in a situation where a JSON is encrypted in PHP's openssl_encrypt and needs to be decrypted in JAVA.
$encrypted = "...ENCRYPTED DATA...";
$secretFile = "/path/to/secret/saved/in/text_file";
$secret = base64_decode(file_get_contents($secretFile));
var_dump(strlen($secret)); // prints : int(370)
$iv = substr($encrypted, 0, 16);
$data = substr($encrypted, 16);
$decrypted = openssl_decrypt($data, "aes-256-cbc", $secret, null, $iv);
This $decrypted has correct data which is now decrypted.
Now, the problem is when I try to do same things in Java it doesn't work :(
String path = "/path/to/secret/saved/in/text";
String payload = "...ENCRYPTED DATA...";
StringBuilder output = new StringBuilder();
String iv = payload.substring(0, 16);
byte[] secret = Base64.getDecoder().decode(Files.readAllBytes(Paths.get(path)));
String data = payload.substring(16);
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
SecretKeySpec secretKeySpec = new SecretKeySpec(secret, "AES");
IvParameterSpec ivParameterSpec = new IvParameterSpec(iv.getBytes(), 0, cipher.getBlockSize());
cipher.init(Cipher.DECRYPT_MODE, secretKeySpec, ivParameterSpec); // This line throws exception :
cipher.doFinal(data.getBytes(StandardCharsets.UTF_8));
Here it is:
Exception in thread "main" java.security.InvalidKeyException: Invalid AES key length: 370 bytes
at com.sun.crypto.provider.AESCrypt.init(AESCrypt.java:87)
at com.sun.crypto.provider.CipherBlockChaining.init(CipherBlockChaining.java:91)
at com.sun.crypto.provider.CipherCore.init(CipherCore.java:591)
at com.sun.crypto.provider.AESCipher.engineInit(AESCipher.java:346)
at javax.crypto.Cipher.init(Cipher.java:1394)
at javax.crypto.Cipher.init(Cipher.java:1327)
at com.sample.App.main(App.java:70)
I have already visited similar question like
AES-256 CBC encrypt in php and decrypt in Java or vice-versa
openssl_encrypt 256 CBC raw_data in java
Unable to exchange data encrypted with AES-256 between Java and PHP
and list continues.... but no luck there
btw, this is how encryption is done in PHP
$secretFile = "/path/to/secret/saved/in/text_file";
$secret = base64_decode(file_get_contents($secretFile));
$iv = bin2hex(openssl_random_pseudo_bytes(8));
$enc = openssl_encrypt($plainText, "aes-256-cbc", $secret, false, $iv);
return $iv.$enc;
and yes, I forgot to mention that my JRE is already at UnlimitedJCEPolicy and I can't change PHP code.
I am totally stuck at this point and can't move forward. Please help out.
EDIT#1
byte[] payload = ....;
byte[] iv = ....;
byte[] secret = ....; // Now 370 bits
byte[] data = Base64.getDecoder().decode(payload);
Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding");
SecretKeySpec secretKeySpec = new SecretKeySpec(Arrays.copyOfRange(secret, 0, 32), "AES");
IvParameterSpec ivParameterSpec = new IvParameterSpec(iv, 0, cipher.getBlockSize());
cipher.init(Cipher.DECRYPT_MODE, secretKeySpec, ivParameterSpec);
byte[] output = cipher.doFinal(data);
System.out.println(new String(output).trim());
Above snippet seems to be working with openssl_encrypt
EDIT#2
I am not sure if this is correct, but following is what I have done and encryption-decryption on both side are working fine.
Encrypt in PHP, Decrypt in JAVA use AES/CBC/NoPadding
Encrypt in JAVA, Decrypt in PHP use AES/CBC/PKCS5Padding
I won't provide a complete solution, but there are a few differences you should take care of
Encoding:
String iv = payload.substring(0, 16);
String data = payload.substring(16);
are you sure the IV and data are the same in Java and PHP (The IV is string?)? If the data are encrypted, they should be treated as a byte array, not string. Just REALLY make sure they are THE SAME (print hex/base64 in php and java)
For the IV you at the end call iv.getBytes(), but the locale encoding may/will corrupt your values. The String should be use only when it's really string (text). Don't use string for binaries.
Simply treat data and iv as byte[]
Key generation according to the openssl
AES key must have length of 256 bit for aes-256-cbc used. The thing is - openssl by default doesn't use the provided secret as a key (I believe it can, but I don't know how it is to be specified in PHP).
see OpenSSL EVP_BytesToKey issue in Java
and here is the EVP_BytesToKey implementation: https://olabini.com/blog/tag/evp_bytestokey/
you should generate a 256 bit key usging the EVP_BytesToKey function (it's a key derivation function used by openssl).
Edit:
Maarten (in the comments) is right. The key parameter is the key. Seems the PHP function is accepting parameter of any length which is misleading. According to some articles (e.g. http://thefsb.tumblr.com/post/110749271235/using-opensslendecrypt-in-php-instead-of) the key is trucated or padded to necessary length (so seems 370 bit key is truncated to length of 256 bits).
According to your example, I wrote fully working code for PHP and Java:
AesCipher class: https://gist.github.com/demisang/716250080d77a7f65e66f4e813e5a636
Notes:
-By default algo is AES-128-CBC.
-By default init vector is 16 bytes.
-Encoded result = base64(initVector + aes crypt).
-Encoded/Decoded results present as itself object, it gets more helpful and get possibility to check error, get error message and get init vector value after encode/decode operations.
PHP:
$secretKey = '26kozQaKwRuNJ24t';
$text = 'Some text'
$encrypted = AesCipher::encrypt($secretKey, $text);
$decrypted = AesCipher::decrypt($secretKey, $encrypted);
$encrypted->hasError(); // TRUE if operation failed, FALSE otherwise
$encrypted->getData(); // Encoded/Decoded result
$encrypted->getInitVector(); // Get used (random if encode) init vector
// $decrypted->* has identical methods
JAVA:
String secretKey = "26kozQaKwRuNJ24t";
String text = "Some text";
AesCipher encrypted = AesCipher.encrypt(secretKey, text);
AesCipher decrypted = AesCipher.decrypt(secretKey, encrypted);
encrypted.hasError(); // TRUE if operation failed, FALSE otherwise
encrypted.getData(); // Encoded/Decoded result
encrypted.getInitVector(); // Get used (random if encode) init vector
// decrypted.* has identical methods
Trying to decrypt data as byte array encrypted with AES-128 with String key "keykeykeykeykey1"
code:
byte[] dataBytes = new byte []{(byte)0xf3,(byte)0x8b,(byte)0x0c,(byte)0xb3,(byte)0xa3,(byte)0x26,(byte)0x12,(byte)0x23,(byte)0xe0,(byte)0xe0,(byte)0x9f,(byte)0x1f,(byte)0x28,(byte)0x01,(byte)0x28,(byte)0x35};
SecretKeySpec secretKeySpec = new SecretKeySpec("keykeykeykeykey1".getBytes("UTF-8"), "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.DECRYPT_MODE, secretKeySpec);
byte[] decryptedData = cipher.doFinal(dataBytes); //this line throws exception
gives me BadPaddingException. What I missed?
You don't specify the mode or padding in your Cipher algorithm. You need to establish what values were used when the data was enciphered.
When you change the algo to "AES/ECB/NOPADDING" there is no error, but this might not necessarily be the right mode or padding.
I have "inherited" a Ruby on Rails app, and I must translate this app from Ruby to Java, and the most important thing, I don't have contact with the creator.
My problem is with the IV vector in AES-256 authentication. Ruby app uses AESCrypt gem to encrypt and decrypt user's password. It works fine, and I have already some thousands of users in DB.
The problem is when I try to do the same in Java (I've already updated JCE to allow 256bit key lenght). The Key and the IV are writen as binary strings in ruby source code (see bellow), and when I try to use it in Java I get a exception which say that the IV lenght must be 16 bytes long (I know that it must be 16 bytes long, but the binary string in Ruby has 32 characters).
Ruby code (works fine):
require 'openssl'
require 'digest/md5'
require 'base64'
module AESCrypt
KEY = "AB1CD237690AF13B6721AD237A"
IV = "por874hyufijdue7w63ysxwet4320o90"
TYPE = "AES-256-CBC"
def AESCrypt.key(key)
key = Digest::MD5.hexdigest(key)
key.slice(0..32)
end
# Encrypts a block of data given an encryption key and an
# initialization vector (iv). Keys, iv's, and the data returned
# are all binary strings. Cipher_type should be "AES-256-CBC",
# "AES-256-ECB", or any of the cipher types supported by OpenSSL.
# Pass nil for the iv if the encryption type doesn't use iv's (like
# ECB).
#:return: => String
#:arg: data => String
#:arg: key => String
#:arg: iv => String
#:arg: cipher_type => String
def AESCrypt.encrypt(data)
return nil if data.nil?
return data if data.blank?
aes = OpenSSL::Cipher::Cipher.new(TYPE)
aes.encrypt
aes.key = AESCrypt.key(KEY)
aes.iv = IV if IV != nil
result = aes.update(data) + aes.final
Base64.encode64(result)
end
end
and this is my Java code (it should do the same, seems that works with a 16 chars/bytes IV):
public static void main(String[] args) throws UnsupportedEncodingException {
String KEY = "AB1CD237690AF13B6721AD237A";
String IV = "por874hyufijdue7w63ysxwet4320o90";
SecretKeySpec key = generateKey(KEY);
String message = "password";
final Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
IvParameterSpec ivSpec = new IvParameterSpec(IV.getBytes());
cipher.init(Cipher.ENCRYPT_MODE, key, ivSpec);
byte[] ciphedText = cipher.doFinal(message.getBytes());
String encoded = Base64.encodeBase64String(ciphedText);
System.out.println("ENCRYPTED text= " + encoded);
}
public static SecretKeySpec generateKey(final String password) throws NoSuchAlgorithmException, UnsupportedEncodingException {
final MessageDigest digest = MessageDigest.getInstance("MD5");
byte[] bytes = password.getBytes("UTF-8");
digest.update(bytes, 0, bytes.length);
byte[] key = digest.digest();
SecretKeySpec secretKeySpec = new SecretKeySpec(key, "AES");
return secretKeySpec;
}
And I'm getting this exception (obviously):
java.security.InvalidAlgorithmParameterException: Wrong IV length: must be 16 bytes long
at com.sun.crypto.provider.CipherCore.init(CipherCore.java:516)
at com.sun.crypto.provider.AESCipher.engineInit(AESCipher.java:339)
at javax.crypto.Cipher.implInit(Cipher.java:801)
at javax.crypto.Cipher.chooseProvider(Cipher.java:859)
at javax.crypto.Cipher.init(Cipher.java:1370)
at javax.crypto.Cipher.init(Cipher.java:1301)
at com.javi.test.security.Test.main(Test.java:129)
I guess my problem is the way I convert the IV java string in byte[]. I think that openSSL code in ruby is unpacking (or doing something internally) the 32 bytes of the IV to 16 bytes. I have tried a lot of things, but I'm going crazy.
Anyone had the same problem or figure out where could be my problem?
I have posted the encryption code but I hace the same issue with decryption.
Thanks in advance, I'll be very grateful with every answer. :)
First, your IV is not actually iv, IV should be HEX encoded, but you have ASCII string "por874hyufijdue7w63ysxwet4320o90", may be it is some how encoded?
Second, IV.getBytes() will transofr IV's each character to hex encoding like p = 0x70, o = 0x6F, r = 0x72, etc...
It is not a useful answer, but may be hint.
Actually IV must be the same length as block cipher single block length. You have 32 bytes long IV itself, if you make IV.getBytes() IV length should match the cipher block length
An Exception caught at the line
encryptedData = cipher.doFinal(data);
javax.crypto.IllegalBlockSizeException: Data must not be longer than 501 bytes
at com.sun.crypto.provider.RSACipher.doFinal(RSACipher.java:344)
The key size is given by: keyPairGenerator.initialize(4096);
How to solve this problem without increasing the size of key?
With asymmetric encryption there is no way to encrypt data longer than key minus padding. Since it's 11 bytes for you I can conclude you use PKCS#1 padding. What you can do is try to compress data, but depending on data length and nature it easily can fail. Another option is to combine symmetric block ciphers (which has no limitation for the size of data) and asymmetric encryption:
Generate random AES key
byte[] keyData = new byte[32];
SecureRandom random = new SecureRandom();
random.nextBytes(keyData);
Encrypt data with AES.
// zero filled input vector
byte[] ivData = new byte[32];
IvParameterSpec iv = new IvParameterSpec(ivData);
SecretKeySpec keySpec = new SecretKeySpec(keyData, "AES");
Cipher aes = Cipher.getInstance("AES/CBC/PKCS5Padding");
aes.init(Cipher.ENCRYPT_MODE, keySpec, iv);
byte[] cipherText = aes.doFinal(data);
Encrypt AES key (for AES-256 it's 32 bytes) with RSA private key.
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.WRAP_MODE, rsaKeyPair.getPublic());
byte[] wrappedKey = cipher.doFinal(keyData);
Combine wrappedKey with cipherText. Can be done with just appending one to another, but also some binary format can be used.
I am trying to decrypt an encrypted text.
I have the salt value, iteration count and key length. But i don't have the initialization vector (IV) value, how can i go about and decrypt this. I also have secret key.
For time being I am using some random IV value whose size is 16 bytes.
But still i am not able to decrypt the value properly.
Can anyone please help as i am stuck with this for a long time?
Below are the values which were given to me.
salt= EW0h0yUcDX72WU9UiKiCwDpXsJg=, Iteration=128,Keylenght=16.
MasterKeyName="Passphrase1", MACMethod algo = hmac-sha1, MACKey="jq/NdikC7AZf0Z+HEL5NrCICV8XW+ttzl/8687hVGHceoyJAaFws+111plQH 6Mlg" encrypted kae = "pM7VB/KomPjq2cKaxPr5cKT1tUZN5tGMI+u1XKJTG1la+ThraPpLKlL2plKk6vQE" and valuemac="lbu+9OcLArnj6mS7KYOKDa4zRU0=".
Secret key = "xxxxxxxxxxx".
Below is the code which I am using to decrypt.
SecretKeyFactory factory = SecretKeyFactory.getInstance("PBKDF2WithHmacSHA1");
KeySpec spec = new PBEKeySpec(secretkey.toCharArray(), salt, iterationCount, keyStrength);
SecretKey tmp = factory.generateSecret(spec);
key = new SecretKeySpec(tmp.getEncoded(), "AES");
dcipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
AlgorithmParameters params = dcipher.getParameters();
iv = "0000000000000000".getBytes();
System.out.println("IV " + new sun.misc.BASE64Encoder().encodeBuffer(iv));
dcipher.init(Cipher.DECRYPT_MODE, key, new IvParameterSpec(iv));
byte[] decryptedData = new sun.misc.BASE64Decoder().decodeBuffer(base64EncryptedData);
byte[] utf8 = dcipher.doFinal(decryptedData);
You cannot decrypt the first block of CBC encrypted ciphertext if you don't know the IV.
It is however not unlikely that you can retrieve the IV value:
often the IV value is 16 bytes retrieved after the key bytes) generated from the PBKDF;
the IV is often prepended to the ciphertext, resulting in one block of garbage before the full plaintext during decryption;
not secure but the IV is also left out or set to a constant value, with an all-zero IV being the most common (this is identical in CBC mode to not using any IV.)