Develop Reference

Displaying the contents of a textfile by typing the filename in a java program?

Write a program that reads in a file and displays its contents. Get the input filename from the command line. For example, if your program is in the file Display.class, you would enter on the command line:
java Display t1.txt
to display the content file t1.txt.
How can this be done?

you can use FileReader or BufferedReader to read the contents of file. below code may be helpful to you
import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
public class Display {
public static void main(String[] args) {
if(args.length > 0) {
String fileName = args[0];
try {
File file = new File(fileName);
if(file.exists() && file.isFile() ) {
BufferedReader br = new BufferedReader(new FileReader(file));
String line = null;
System.out.println("FileContents are...");
while((line = br.readLine()) != null) {
System.out.println(line);
}
}else{
System.out.println("File Not Found");
}
} catch (FileNotFoundException e) {
System.out.println("File Not Found");
} catch (IOException e) {
e.printStackTrace();
}
}
}
}

Data missing during importing data from source to sink file in kafka

I have been using kafka to get and process streaming inputs and I have the source and sink properties as:
name=local-file-sink
connector.class=org.apache.kafka.connect.file.FileStreamSinkConnector
tasks.max=10
file=pnrsink5.xml
topics=test
name=local-file-source
connector.class=org.apache.kafka.connect.file.FileStreamSourceConnector
tasks.max=10
file=pnrtes.xml
topic=test
And I run the standalone as:
bin/connect-standalone.sh config/connect-standalone.properties config/connect-file-source.properties config/connect-file-sink.properties
And when I give parsed input using a java program written as:
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
public class parse
{
public static void main(String args[]) throws IOException
{
int count=0,c=1,a=0;
String file="/home/tthteg/speed_pnr/Source/Source_pnr.xml";
String l1="</PNR>";
String line;
try
{
FileReader fileReader=new FileReader(file);
BufferedReader bufferedReader=new BufferedReader(fileReader);
String file="/home/tthteg/speed_pnr/Source/Source_pnr.xml";
String l1="</PNR>";
String line;
try
{
FileReader fileReader=new FileReader(file);
BufferedReader bufferedReader=new BufferedReader(fileReader);
BufferedWriter bufWriter = new BufferedWriter(new FileWriter("/home/tthteg/speed_pnr/kafka/pnrtes.xml"));
try
{
while((line=bufferedReader.readLine())!=null)
{
if(c%2==0)
{
Thread.sleep(5000);
c=1;
}
if(line.contains("<PNR"))
{
c++;
System.out.println(line);
bufWriter.write(line);
while((line=bufferedReader.readLine()).equals(l1)==false)
{
System.out.println(line);
bufWriter.write(line);
}
bufWriter.write("</PNR>");
bufWriter.flush();
System.out.println("</PNR>");
count++;
a=count;
}
}
}catch(Exception e)
{
System.out.println(e);
}
bufferedReader.close();
bufWriter.flush();
System.out.println(a);
}catch (FileNotFoundException e) {
e.printStackTrace();
}
System.out.println(a);
}
}
PROBLEMS:
1.Whenever I run the java file,I have to touch the source file(echo -e >> pnrtes.xml) to get the data imported to the sink file(pnrsink5.xml)
2.I have found some data missing at the beginning(some 4 words) in the sink file.
Thank you in advance

Read and edit the file from Java

I'm trying to introduce a line break at every 100th character of the line from the existing file.But it doesn't write anything to it. below is the code written in java to read the existing file and write to it with a temporary file.
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
public class ReplaceFileContents {
public static void main(String[] args) {
new ReplaceFileContents().replace();
}
public void replace() {
String oldFileName = "Changed1.ldif";
String tmpFileName = "Changed2.ldif";
BufferedReader br = null;
BufferedWriter bw = null;
try {
br = new BufferedReader(new FileReader(oldFileName));
bw = new BufferedWriter(new FileWriter(tmpFileName));
String line;
while ((line = br.readLine()) != null) {
line.replaceAll("(.{100})", "$1\n");
}
} catch (Exception e) {
return;
} finally {
try {
if(br != null)
br.close();
} catch (IOException e) {
//
}
try {
if(bw != null)
bw.close();
} catch (IOException e) {
//
}
}
// Once everything is complete, delete old file..
File oldFile = new File(oldFileName);
oldFile.delete();
// And rename tmp file's name to old file name
File newFile = new File(tmpFileName);
newFile.renameTo(oldFile);
}
}

while ((line = br.readLine()) != null) {
line.replaceAll("(.{100})", "$1\n");
}
First off, line.replaceAll does not replace your line variable with the result. Because Strings are immutable, this method returns the new string, so your line should be line = line.replaceAll(....
Second, you're never writing the new String back into the file. Using replaceAll doesn't change the file itself in any way. Instead, try using your bw object to write the new String to the same line.

From what you've published here, you never try to write line back to bw. Try this:
package hello;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
public class Test {
public static void main(String[] args) {
new Test().replace();
}
public void replace() {
String oldFileName = "d:\\1.txt";
String tmpFileName = "d:\\2.txt";
BufferedReader br = null;
BufferedWriter bw = null;
try {
br = new BufferedReader(new FileReader(oldFileName));
bw = new BufferedWriter(new FileWriter(tmpFileName));
String line;
while ((line = br.readLine()) != null) {
line = line.replaceAll("(.{100})", "$1\n");
bw.write(line);
}
} catch (Exception e) {
return;
} finally {
try {
if(br != null)
br.close();
} catch (IOException e) {
//
}
try {
if(bw != null)
bw.close();
} catch (IOException e) {
//
}
}
// Once everything is complete, delete old file..
File oldFile = new File(oldFileName);
oldFile.delete();
// And rename tmp file's name to old file name
File newFile = new File(tmpFileName);
newFile.renameTo(oldFile);
}
}
You never try to write line back to bw;
String#replaceAll will return the copy of the source not the original String;

Reading text file into String array, then converting to ArrayList

How can I read a file into a array of String[] and then convert it into ArrayList?
I can't use an ArrayList right away because my type of list is not applicable for the arguments (String).
So my prof told me to put it into an array of String, then convert it.
I am stumped and cannot figure it out for the life of me as I am still very new to java.

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
/**
* Created by tsenyurt on 06/04/15.
*/
public class ReadFile
{
public static void main(String[] args) {
List<String> strings = new ArrayList<>();
BufferedReader br = null;
try {
String sCurrentLine;
br = new BufferedReader(new FileReader("/Users/tsenyurt/Development/Projects/java/test/pom.xml"));
while ((sCurrentLine = br.readLine()) != null) {
System.out.println(sCurrentLine);
strings.add(sCurrentLine);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
there is a code that reads a file and create a ArrayList from it
http://www.mkyong.com/java/how-to-read-file-from-java-bufferedreader-example/

Well there are many ways to do that,
you can use this code if you want have a List of each word exist in your file
public static void main(String[] args) {
BufferedReader br = null;
StringBuffer sb = new StringBuffer();
List<String> list = new ArrayList<>();
try {
String sCurrentLine;
br = new BufferedReader(new FileReader(
"Your file path"));
while ((sCurrentLine = br.readLine()) != null) {
sb.append(sCurrentLine);
}
String[] words = sb.toString().split("\\s");
list = Arrays.asList(words);
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
for (String string : list) {
System.out.println(string);
}
}

How to open a text file?

I can't figure out for the life of me what is wrong with this program:
import java.io.*;
public class EncyptionAssignment
{
public static void main (String[] args) throws IOException
{
String line;
BufferedReader in;
in = new BufferedReader(new FileReader("notepad encypt.me.txt"));
line = in.readLine();
while(line != null)
{
System.out.println(line);
line = in.readLine();
}
System.out.println(line);
}
}
The error message says that the file can't be found, but I know that the file already exists. Do I need to save the file in a special folder?

The error is "notepad encypt.me.txt".
Since your file is named "encypt.me.txt", you can't put a "notepad" in front of its name. Moreover, the file named "notepad encypt.me.txt" probably didn't exist or is not the one that you want to open.
Additionally, you have to provide the path ( absolute or relative ) of your file if it's not located in your project folder.
I will take the hypothesis that your are on a Microsoft Windows system.
If your file has as absolute path of "C:\foo\bar\encypt.me.txt", you will have to pass it as "C:\\foo\\bar\\encypt.me.txt" or as "C:"+File.separatorChar+"foo"+File.separatorChar+"bar"+File.separatorChar+encypt.me.txt".
If it's still not working, you should verify that the file :
1) Exist at the path provided.
You can do it by using the following piece of code:
File encyptFile=new File("C:\\foo\\bar\\encypt.me.txt");
System.out.println(encyptFile.exists());
If the path provided is the right one, it should be at true.
2) Can be read by the application
You can do it by using the following piece of code:
File encyptFile=new File("C:\\foo\\bar\\encypt.me.txt");
System.out.println(encyptFile.canRead());
If you have the permission to read the file, it should be at true.
More informations:
Javadoc of File
Informations about Path in computing

import java.io.*;
public class Test {
public static void main(String [] args) {
// The name of the file to open.
String fileName = "temp.txt";
// This will reference one line at a time
String line = null;
try {
// FileReader reads text files in the default encoding.
FileReader fileReader =
new FileReader(fileName);
// Always wrap FileReader in BufferedReader.
BufferedReader bufferedReader =
new BufferedReader(fileReader);
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
// Always close files.
bufferedReader.close();
}
catch(FileNotFoundException ex) {
System.out.println(
"Unable to open file '" +
fileName + "'");
}
catch(IOException ex) {
System.out.println(
"Error reading file '"
+ fileName + "'");
// Or we could just do this:
// ex.printStackTrace();
}
}
}

package com.mkyong.io;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class BufferedReaderExample {
public static void main(String[] args) {
BufferedReader br = null;
try {
String sCurrentLine;
br = new BufferedReader(new FileReader("C:\\testing.txt"));
while ((sCurrentLine = br.readLine()) != null) {
System.out.println(sCurrentLine);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}
Reference: http://www.mkyong.com/java/how-to-read-file-from-java-bufferedreader-example/