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I have a string "eur0.99", it can be "eur123.0" or "som0.10", or "0.99usd", or "123.34any" or something like that. How can I simply insert a space between the price and letters without making a huge nasty messy code?
You can use
System.out.println(input.replaceAll("(?<=[A-Za-z])(?=[0-9])|(?<=[0-9])(?=[A-Za-z])", " "));
Ideone Demo
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I'm writing a simple program where I can change a piece of text. For example printing text "This is a problem with xxx" and I could delete "xxx" and place my own text there. "xxx" representing a default value.
I tried searching but I think I'm using the wrong search terms or I just don't understand the answers.
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By mistake while typing code I pressed something and my cursor "|" replaced with "_".
Try the insert key.
It selects if a sign gets shifted or replaced.
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So the question is basically if to have
getDriver().findElement(by).clear();
or to have
String text = getDriver().findElement(by).getText();
if (!text.equals(""))
getDriver().findElement(by).clear();
and after that a sendKeys.
Note: Most of the times, the field is empty.
This is simple math
getDriver().findElement(by).clear();
Costs as
getDriver().findElement(by).getText();
To the second line you add an if check and maybe getDriver().findElement(by).clear(); anyway.
So just call clear() without a check.
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I want to construct a Regular Expression in Java that allows a number that is greater than 100. Can anyone help with that?
^(?!(?:\d{1,2}|100)$)[0-9]\d+$
Try this.See demo.
https://regex101.com/r/sJ9gM7/549
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In a Text file I need to print only last character Is Possible
Example Input
Steve Jobs
Android
Apple
Core Java
Facebook(Assume Its in file name Sample)
Output
Input
droid
pple
book
Question is not clear. You can get the last charactor by
String str = "awesome";
System.out.println(str.charAt(str.length()-1));
Output
e
You can manipulate this in order to get what you expect.