We have to connect to a asp.net server to download media items.
We've got this code:
URLConnection urlConnection;
try {
String localTempPath = SettingsManager.getInstance().getLocalTempMediaItemFilePath(loadingItem);
URL serverPath = new URL(SettingsManager.getInstance().getServerMediaItemFilePath(loadingItem));
urlConnection = serverPath.openConnection();
String urlParameters = "http://tempuri.org/";
HttpURLConnection connection = (HttpURLConnection) serverPath.openConnection();
connection.setFollowRedirects(true);
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestMethod("GET");
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
for (String cookie:cookies.keySet()) {
connection.setRequestProperty("Cookie", cookie + "=" + cookies.get(cookie));
} //only one Cookie: ASPNET_SessionId=...
connection.connect();
int response = connection.getResponseCode();
File f = new File (localTempPath);
f.createNewFile();
if (f.exists()){
FileOutputStream fileOutput = new FileOutputStream(f);
//Get Response
InputStream is = connection.getInputStream();
int totalsize = connection.getContentLength();
int downloadedSize = 0;
byte[] buffer = new byte [1024];
int bufferLength = 0;
while ((bufferLength = is.read(buffer)) > 0){
fileOutput.write(buffer,0,bufferLength);
downloadedSize += bufferLength;
}
fileOutput.close();
}
return null;
} catch (Exception e) {
e.printStackTrace();
return null;
} finally {
}
We have to send the Session-Cookie to the server but we always get a 404:java.io.FileNotFoundException: http://possuite.emmgt.at/v30/dataservice/MediaItem/6629.mi
Related
I want to upload the image to the server.
I got the bitmap of the image and encoded it to base64.
I convert the base64 of the image to a string using the encodeToString method.
I post the string to PHP using httpurlconnection. Actually, I got the string from PHP which is not the whole string. I don`t get any error. Please give me feedback!
public String httpURLConnectionPost(final String urlString){
String result="";
try {
URL url = new URL(urlString);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setUseCaches(false);
connection.connect();
Bitmap bitmap = BitmapFactory.decodeResource(getResources(), R.drawable.download);
ByteArrayOutputStream baos = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, baos);
byte[] imageBytes = baos.toByteArray();
String encodedImage = Base64.encodeToString(imageBytes, Base64.NO_CLOSE);
String body= "image="+encodedImage;
Log.d("serverPostData","body = " +body);
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(connection.getOutputStream(), "UTF-8"));
writer.write(body);
writer.close();
int responseCode = connection.getResponseCode();
if(responseCode == HttpURLConnection.HTTP_OK){
InputStream inputStream = connection.getInputStream();
StringBuilder stringBuilder = new StringBuilder();
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(inputStream));
while ((line = br.readLine()) != null) {
stringBuilder .append(line);
}
result = stringBuilder .toString();
}
} catch (Exception e) {
e.printStackTrace();
}
return result;
}
The php got the string and decode it.
<?php
include("mysqli_connect.php");
$image= $_POST['image'];
$a = uniqid() ;
$ImagePath = "good/$a.JPEG";
$ServerURL = "https://172.30.10.1/$ImagePath";
$InsertSQL = "INSERT INTO Photoshop(photo) VALUES('$ServerURL')" ;
if(mysqli_query($connect, $InsertSQL)){
file_put_contents($ImagePath,base64_decode($image));
echo $image;
}else{
echo "failed";
}
mysqli_close();
?>
Try this to convert image to base64:
Uri uri = data.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), uri);
String encodedImageData = getEncoded64ImageStringFromBitmap(bitmap);
Now pass the data in API:
JsonObject data1 = new JsonObject();
data1.addProperty("imageData", "data:image/png;base64," + encodedImageData);
Now set ImageBitmap:
image.setImageBitmap(bitmap);
Here is the method:
private String getEncoded64ImageStringFromBitmap(Bitmap bitmap) {
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 70, stream);
byte[] byteFormat = stream.toByteArray();
// get the base 64 string
String imgString = Base64.encodeToString(byteFormat, Base64.NO_WRAP);
return imgString;
}
And for HttpUrlConnection try this...
jsonObject = new JSONObject();
jsonObject.put("imageString", encodedImage);
String data = jsonObject.toString();
String yourURL = "yourphpfileurl";
URL url = new URL(yourURL);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
connection.setRequestMethod("POST");
connection.setFixedLengthStreamingMode(data.getBytes().length);
connection.setRequestProperty("Content-Type", "application/json;charset=UTF-8");
OutputStream out = new BufferedOutputStream(connection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
connection.connect();
InputStream in = new BufferedInputStream(connection.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(
in, "UTF-8"));
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line);
}
in.close();
String result = sb.toString();
connection.disconnect();
Hope this one will work for you...
I solved my probelm that the base64 need to replace empty to "+".
<?php
include("mysqli_connect.php");
$image= $_POST['image'];
$change = str_replace(" ","+",$image);
$a = uniqid() ;
$ImagePath = "good/$a.JPEG";
$ServerURL = "https://172.30.10.1/$ImagePath";
$InsertSQL = "INSERT INTO Photoshop(photo) VALUES('$ServerURL')" ;
if(mysqli_query($connect, $InsertSQL)){
file_put_contents($ImagePath,base64_decode($change ));
echo $image;
}else{
echo "failed";
}
mysqli_close();
?>
I have many images in a folder, and I want to upload this files, in that folder, to a php server, in java using httpurlconnection.
Until now, I made it but just with one photo, like the code I show you down.
public class SendImage {
private final String CrLf = "\r\n";
public static void main(String[] args) {
SendImage image = new SendImage();
image.httpConn();
}
private void httpConn(){
URLConnection lig = null;
OutputStream os = null;
InputStream is = null;
try{
String urlParameters = "subPasta=sandro&nomepc=Sandro-PC&printPasta=Printscreens";;
byte[] postData = urlParameters.getBytes(StandardCharsets.UTF_8);
int postDataLength = postData.length;
URL url = new URL("http://192.168.0.105/dashboard3/uploadImg.php");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setInstanceFollowRedirects(false);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
conn.setRequestProperty("charset", "utf-8");
conn.setRequestProperty("Content-Length", Integer.toString(postDataLength));
conn.setUseCaches(false);
System.out.println("url: "+ url);
lig = url.openConnection();
lig.setDoOutput(true);
FileInputStream imgIs = new FileInputStream(new File("C:\\Users\\Sandro\\workspace\\testeLogin\\screenshot\\2017_3_16_3_59.png"));
byte[] imgData = new byte[imgIs.available()];
imgIs.read(imgData);
String message1 = "";
message1 += "-----------------------------4664151417711" + CrLf;
message1 += "Content-Disposition: form-data; name=\"uploadedfile\"; filename=\"image.png\"" + CrLf;
message1 += "Content-Type: image/jpeg" + CrLf;
message1 += CrLf;
// the image is sent between the messages in the multipart message.
String message2 = "";
message2 += CrLf + "-----------------------------4664151417711--" + CrLf;
lig.setRequestProperty("Content-Type", "multipart/form-data; boundary=---------------------------4664151417711");
// might not need to specify the content-length when sending chunked
// data.
lig.setRequestProperty("Content-Length", String.valueOf((message1
.length() + message2.length() + imgData.length)));
System.out.println("open os");
os = lig.getOutputStream();
System.out.println(message1);
os.write(message1.getBytes());
// SEND THE IMAGE
int index = 0;
int size = 1024;
do {
System.out.println("write:" + index);
if ((index + size) > imgData.length) {
size = imgData.length - index;
}
os.write(imgData, index, size);
index += size;
} while (index < imgData.length);
System.out.println("written:" + index);
System.out.println(message2);
os.write(message2.getBytes());
os.flush();
System.out.println("open is");
is = lig.getInputStream();
char buff = 512;
int len;
byte[] data = new byte[buff];
do {
System.out.println("READ");
len = is.read(data);
if (len > 0) {
System.out.println(new String(data, 0, len));
}
} while (len > 0);
System.out.println("DONE");
}catch(Exception e){
e.printStackTrace();
}finally {
System.out.println("Close connection");
try {
os.close();
} catch (Exception e) {
}
try {
is.close();
} catch (Exception e) {
}
try {
} catch (Exception e) {
}
}
}
}
But I want send all photos in that folder
if you can, show me the code in php too please.
i am working on a system and need to fetch file from the URL using java URLConnection, Now all i need to copy that contents into excel file.
here is my code.
class getsize {
public static void main(String args[]) throws Exception {
HttpURLConnection conn = null;
try {
String plainCreds = "hmhinstall:hmh201208";
// String url = "http://content.link-systems.com/~hbern/content_update/";
byte[] plainCredsBytes = plainCreds.getBytes();
String base64CredsBytes = Base64.encode(plainCredsBytes);
String base64Creds = base64CredsBytes;
System.out.println(base64Creds);
int code = 0;
URL url = new URL("http://content.link-systems.com/~hbern/content_update/ ");
//Reading
URLConnection uc = url.openConnection();
BufferedReader in = new BufferedReader(new InputStreamReader(
uc.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null) {
System.out.println(inputLine); //Printing file data
}
in.close();
//Getting size
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Authorization", "Basic " + base64Creds);
conn.setRequestProperty("Content-Type", "application/json;charset=UTF-8");
conn.setDoOutput(true);
System.out.println(conn.getResponseCode());
System.out.println(conn.getContentType());
conn.getInputStream();
System.out.println("Length : " + conn.getContentLength()); //Getting content length
} catch (Exception exception) {
} finally {
conn.disconnect(); //Disconnect
}
}
}
How can i copy contents of a file in to excel worksheet? So that i can generate records automatically.
thanks in advance
I am downloading few pdf and video file from the server and for that I am using InputStream to collect response but I want to know that which is better for my purpose InputStream or FileInputStream or BufferedInputStream ?
URL u = new URL(fileURL);
HttpURLConnection c = (HttpURLConnection) u.openConnection();
c.setRequestMethod("GET");
c.setDoOutput(true);
c.connect();
FileOutputStream f = new FileOutputStream(new File(RootFile, fileName));
InputStream in = c.getInputStream();
byte[] buffer = new byte[1024];
int len1 = 0;
while ((len1 = in.read(buffer)) > 0) {
f.write(buffer, 0, len1);
}
f.close();
I am using this for downloading videos
void downloadFile(String vidN){
int downloadedSize = 0;
int totalSize = 0;
try {
// here vidN is the name of the file like bird.mp4
// here sitepath is the path of the file
URL url = new URL(sitepath+vidN);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.setDoOutput(true);
//connect
urlConnection.connect();
//set the path where we want to save the file
String RootDir = Environment.getExternalStorageDirectory()
+ File.separator + "VideoNR2";
File RootFile = new File(RootDir);
RootFile.mkdir();
//create a new file, to save the downloaded file
File file = new File(RootDir,""+vidN);
FileOutputStream fileOutput = new FileOutputStream(file);
//Stream used for reading the data from the internet
InputStream inputStream = urlConnection.getInputStream();
//this is the total size of the file which we are downloading
totalSize = urlConnection.getContentLength();
//create a buffer...
byte[] buffer = new byte[1024];
int bufferLength = 0;
while ( (bufferLength = inputStream.read(buffer)) > 0 ) {
fileOutput.write(buffer, 0, bufferLength);
downloadedSize = bufferLength;
}
//close the output stream when complete //
fileOutput.close();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
catch (Exception e) {
}
}
I want to pass a java application sent a string that is a json,it isn't get this json in servlet, how do I do, who can help me?
This is my servlet code:
public void service(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
BufferedInputStream in = new BufferedInputStream(req.getInputStream());
byte[] data = null;
byte[] bts = new byte[1024];
int index;
while ((index = in.read(bts)) >= 0) {
if (data == null) {
data = new byte[index];
System.arraycopy(bts, 0, data, 0, index);
}
else {
byte[] tmp = data;
data = new byte[tmp.length + index];
System.arraycopy(tmp, 0, data, 0, tmp.length);
System.arraycopy(bts, 0, data, tmp.length, index);
}
}
String json = new String(data);
System.out.print(json);
}
and this is my java application:
String _url = "http://localhost:8080/jsf/test";
URL url = null;
HttpURLConnection urlconn = null;
String json = URLEncoder.encode(JSONObject.fromObject(req)
.toString(), "UTF-8");
url = new URL(_url);
urlconn = (HttpURLConnection) url.openConnection();
urlconn.setRequestMethod("POST");
urlconn.setDoOutput(true);
urlconn.setDoInput(true);
OutputStream out = urlconn.getOutputStream();
out.write(json.getBytes("UTF-8"));
out.flush();
out.close();
BufferedReader rd = new BufferedReader(new InputStreamReader(
urlconn.getInputStream(), "UTF-8"));
StringBuffer sb = new StringBuffer();
int ch;
while ((ch = rd.read()) > -1) {
sb.append((char) ch);
}
System.out.println(sb);
rd.close();
You should write json data to outputStream as out.write(json.getBytes()); . See the complete code below:
String _url = "http://localhost:8080/jsf/test";
URL url = new URL(_url);
String json = "[{\"id\":\"DFAB8108D69642EBBD461160B4519B0F\",\"name\":\"name1\"},{\"id\":\"B048B2521A5619DCE0440003BA11CFDA\",\"name\":\"name2\"}]";
HttpURLConnection urlconn = (HttpURLConnection) url.openConnection();
urlconn.setRequestMethod("POST");
urlconn.setDoOutput(true);
OutputStream out = urlconn.getOutputStream();
out.write(json.getBytes());
out.flush();
out.close();
BufferedReader rd = new BufferedReader(new InputStreamReader(
urlconn.getInputStream(), "UTF-8"));
StringBuffer sb = new StringBuffer();
int ch;
while ((ch = rd.read()) > -1) {
sb.append((char) ch);
}
System.out.println(sb.toString());
rd.close();
Try something like this
String _url = "http://localhost:8080/jsf/test";
URL url = new URL(_url);
String json = "[{\"id\":\"DFAB8108D69642EBBD461160B4519B0F\",\"name\":\"name1\"},{\"id\":\"B048B2521A5619DCE0440003BA11CFDA\",\"name\":\"name2\"}]";
HttpURLConnection urlconn = (HttpURLConnection) url.openConnection();
urlconn .setDoOutput(true);
urlconn .setRequestProperty("Content-Type", "application/json");
urlconn .setRequestProperty("Accept", "application/json");
urlconn .setRequestMethod("POST");
urlconn .connect();
OutputStream os = httpcon.getOutputStream();
os.write((json.getBytes("UTF-8"));
os.close();