Java setOnAction subscribe to event that throws exception - java

Let me preface this by saying, I am not a Java programmer and have thus far been unable to understand WHY this is the case.
I'm currently working on a homework assignment that requires me to create a basic GUI using JavaFX. The functionality of this GUI requires that there are buttons that will perform CRUD operations when clicked. Currently I have everything set up properly in my Insert method:
public void Insert() throws SQLException{
//Insert new record here
}
However, whenever I try to subscribe to this method using 'setOnAction', the compiler is telling me there's an unhandled exception on the event:
btnInsert.setOnAction(e ->Insert());
I'm more curious if there's a way to handle this in a relatively succinct way? I've thus far been unable to come up with a solution.

That's because Java requires you to declare all checked exceptions you throw - so whenever you call a method that may throw a checked exception, you must either catch it or declare you may throw it yourself.
See this question for an explanation of checked vs. unchecked exception (The short version - any Exception which inherits either Error or RuntimeException is unchecked, while all other exceptions are checked.)
When you are providing setOnAction with a lambda, you are actually creating an anonymous class implementation of EventHandler<ActionEvent>. Since it does not declare it throws any exceptions, neither does your anonymous class (and in fact - it can't).
So you have two options of solving the problem:
Catch and handle the exception:
btnInsert.setOnAction(e -> {
try {
Insert();
} catch (SQLException ex) {
// Log error, show error message, etc... Whichever is applicable for your application
}
});
Rethrow an un-checked exception:
btnInsert.setOnAction(e -> {
try {
Insert();
} catch (SQLException ex) {
throw new RuntimeException(ex); // Or any other subclass of RuntimeException or Error
}
});
As to choosing between the two options - Oracle's documentation says this:
Here's the bottom line guideline: If a client can reasonably be expected to recover from an exception, make it a checked exception. If a client cannot do anything to recover from the exception, make it an unchecked exception.
Of course, this could all be moved away from the actual EventHandler, so it can be called on a method that is checked-exception-free.

Related

Add auto-clear notification on Cordova FirebaseX plugin [duplicate]

New Java programmers frequently encounter errors phrased like this:
"error: unreported exception <XXX>; must be caught or declared to be thrown"
where XXX is the name of some exception class.
Please explain:
What the compilation error message is saying,
the Java concepts behind this error, and
how to fix it.
First things first. This a compilation error not a exception. You should see it at compile time.
If you see it in a runtime exception message, that's probably because you are running some code with compilation errors in it. Go back and fix the compilation errors. Then find and set the setting in your IDE that prevents it generating ".class" files for source code with compilation errors. (Save yourself future pain.)
The short answer to the question is:
The error message is saying that the statement with this error is throwing (or propagating) a checked exception, and the exception (the XXX) is not being dealt with properly.
The solution is to deal with the exception by either:
catching and handling it with a try ... catch statement, or
declaring that the enclosing method or constructor throws it1.
1 - There are some edge-cases where you can't do that. Read the rest of the answer!
Checked versus unchecked exceptions
In Java, exceptions are represented by classes that descend from the java.lang.Throwable class. Exceptions are divided into two categories:
Checked exceptions are Throwable, and Exception and its subclasses, apart from RuntimeException and its subclasses.
Unchecked exceptions are all other exceptions; i.e. Error and its subclasses, and RuntimeException and its subclasses.
(In the above, "subclasses" includes by direct and indirect subclasses.)
The distinction between checked and unchecked exceptions is that checked exceptions must be "dealt with" within the enclosing method or constructor that they occur, but unchecked exceptions need not be dealt with.
(Q: How do you know if an exception is checked or not? A: Find the javadoc for the exception's class, and look at its parent classes.)
How do you deal with a (checked) exception
From the Java language perspective, there are two ways to deal with an exception that will "satisfy" the compiler:
You can catch the exception in a try ... catch statement. For example:
public void doThings() {
try {
// do some things
if (someFlag) {
throw new IOException("cannot read something");
}
// do more things
} catch (IOException ex) {
// deal with it <<<=== HERE
}
}
In the above, we put the statement that throws the (checked) IOException in the body of the try. Then we wrote a catch clause to catch the exception. (We could catch a superclass of IOException ... but in this case that would be Exception and catching Exception is a bad idea.)
You can declare that the enclosing method or constructor throws the exception
public void doThings() throws IOException {
// do some things
if (someFlag) {
throw new IOException("cannot read something");
}
// do more things
}
In the above we have declared that doThings() throws IOException. That means that any code that calls the doThings() method has to deal with the exception. In short, we are passing the problem of dealing with the exception to the caller.
Which of these things is the correct thing to do?
It depends on the context. However, a general principle is that you should deal with exceptions at a level in the code where you are able to deal with them appropriately. And that in turn depends on what the exception handling code is going to do (at HERE). Can it recover? Can it abandon the current request? Should it halt the application?
Solving the problem
To recap. The compilation error means that:
your code has thrown a checked exception, or called some method or constructor that throws the checked exception, and
it has not dealt with the exception by catching it or by declaring it as required by the Java language.
Your solution process should be:
Understand what the exception means, and why it could be thrown.
Based on 1, decide on the correct way to deal with it.
Based on 2, make the relevant changes to your code.
Example: throwing and catching in the same method
Consider the following example from this Q&A
public class Main {
static void t() throws IllegalAccessException {
try {
throw new IllegalAccessException("demo");
} catch (IllegalAccessException e){
System.out.println(e);
}
}
public static void main(String[] args){
t();
System.out.println("hello");
}
}
If you have been following what we have said so far, you will realise that the t() will give the "unreported exception" compilation error. In this case, the mistake is that t has been declared as throws IllegalAccessException. In fact the exception does not propagate, because it has been caught within the method that threw it.
The fix in this example will be to remove the throws IllegalAccessException.
The mini-lesson here is that throws IllegalAccessException is the method saying that the caller should expect the exception to propagate. It doesn't actually mean that it will propagate. And the flip-side is that if you don't expect the exception to propagate (e.g. because it wasn't thrown, or because it was caught and not rethrown) then the method's signature shouldn't say it is thrown!
Bad practice with exceptions
There are a couple of things that you should avoid doing:
Don't catch Exception (or Throwable) as a short cut for catching a list of exceptions. If you do that, you are liable catch things that you don't expect (like an unchecked NullPointerException) and then attempt to recover when you shouldn't.
Don't declare a method as throws Exception. That forces the called to deal with (potentially) any checked exception ... which is a nightmare.
Don't squash exceptions. For example
try {
...
} catch (NullPointerException ex) {
// It never happens ... ignoring this
}
If you squash exceptions, you are liable to make the runtime errors that triggered them much harder to diagnose. You are destroying the evidence.
Note: just believing that the exception never happens (per the comment) doesn't necessarily make it a fact.
Edge case: static initializers
There some situations where dealing with checked exceptions is a problem. One particular case is checked exceptions in static initializers. For example:
private static final FileInputStream input = new FileInputStream("foo.txt");
The FileInputStream is declared as throws FileNotFoundException ... which is a checked exception. But since the above is a field declaration, the syntax of the Java language, won't let us put the declaration inside a try ... catch. And there is no appropriate (enclosing) method or constructor ... because this code is run when the class is initialized.
One solution is to use a static block; for example:
private static final FileInputStream input;
static {
FileInputStream temp = null;
try {
temp = new FileInputStream("foo.txt");
} catch (FileNotFoundException ex) {
// log the error rather than squashing it
}
input = temp; // Note that we need a single point of assignment to 'input'
}
(There are better ways to handle the above scenario in practical code, but that's not the point of this example.)
Edge case: static blocks
As noted above, you can catch exceptions in static blocks. But what we didn't mention is that you must catch checked exceptions within the block. There is no enclosing context for a static block where checked exceptions could be caught.
Edge case: lambdas
A lambda expression (typically) should not throw an unchecked exception. This is not a restriction on lambdas per se. Rather it is a consequence of the function interface that is used for the argument where you are supplying the argument. Unless the function declares a checked exception, the lambda cannot throw one. For example:
List<Path> paths = ...
try {
paths.forEach(p -> Files.delete(p));
} catch (IOException ex) {
// log it ...
}
Even though we appear to have caught IOException, the compiler will complain that:
there is an uncaught exception in the lambda, AND
the catch is catching an exception that is never thrown!
In fact, the exception needs to be caught in the lambda itself:
List<Path> paths = ...
paths.forEach(p -> {
try {
Files.delete(p);
} catch (IOException ex) {
// log it ...
}
}
);
(The astute reader will notice that the two versions behave differently in the case that a delete throws an exception ...)
More Information
The Oracle Java Tutorial:
The catch or specify requirement
... also covers checked vs unchecked exceptions.
Catching and handling exceptions
Specifying the exceptions thrown by a method

Is it okay to declare a checked exception for an exception thrown by a called method?

Consider this:
public void Do() throws Exception {
if (blah) throw new Exception(...);
Thingy thingy = ...;
Foo(thingy);
}
public void Foo(Thingy thingy) throws EmptyThingyException {
if (thingy == null ||
thingy.isEmpty()) throw new EmptyThingyException();
...
}
public class EmptyThingyException extends Throwable { ... }
In this case, is it okay to not handle EmptyThingyException inside Do and declare Do like so:
public void Do() throws Exception, EmptyThingyException {
or do I have to handle EmptyThingyException inside Do and throw it back again like so:
public void Do() throws Exception, EmptyThingyException {
try {
} catch (EmptyThingyException empty) {
throw empty;
}
...
}
The short answer to the question is:
Yes, it's correct to declare a checked exception thrown by a called method.
How a method achieves its purpose is an implementation detail and it shouldn't matter to the interface how much it does directly or how much it delegates to methods. The language rules about checked exceptions are carefully defined to make sure methods advertise all checked exceptions they may throw or methods they call throw (but are not handled by the method itself). Letting an unhandled exception get 'thrown through' a method is how things are supposed to work.
Indeed the answer is in the name of the construct "non-local exception handling" it was conceived to take effort out of endless error handling all the way up a call chain when the only real action is "that didn't work" at some point near the start.
To align to that method, you should only catch exceptions you're going to do something about.
Clean up code should be achieved with finally so the normal reasons to catch an exception are to log it and/or abandon a task at some point rather than letting the stack unwind further.
In this specific case the best answer would be to throw an IllegalArgumentException:
throw new IllegalArgumentException("thingy==null || thingy.isEmpty()");
That's unchecked and wisely so. Correct code shouldn't encounter illegal arguments and they should expect to be thrown rarely and be indicative of program flaw (either in the class, it's package or consumer code). External and user input should be validated directly and programs shouldn't rely on IllegalArgumentException.
In practice IllegalArgumentException and IllegalStateException should cover 'internal errors' meaning "You can't do this with that" or "You can't do that right now" respectively and should be commented to specify the fault.
The idea that you might sub-class those two because consumer code might respond differently to different illegal actions it might take is bodging pure and simple.
Program correctness includes that a program never makes an illegal call on some other part of the program or enters an invalid or corrupted state and exceptions only occur as a result of environmental failures that mean a program or sub-task in a program cannot be completed as intended.
if you want to do something after exception happen, then use try-catch, or you can just declare it on the method.
Beyond that, if EmptyThingyException is sub class of Exception, then it is no need to declare EmptyThingyException when you have declared Exception.
1- Declare the specific checked exceptions that your method can throw
public void foo() throws Exception { //Incorrect way
}
Always avoid doing this as in above code sample. It simply defeats the whole purpose of having checked exception. Declare the specific checked exceptions that your method can throw. If there are just too many such checked exceptions, you should probably wrap them in your own exception and add information to in exception message. You can also consider code refactoring also if possible.
2- Always catch only those exceptions that you can actually handle
catch (NoSuchMethodException e) {
throw e; //Avoid this as it doesn't help anything
}
Well this is most important concept. Don’t catch any exception just for the sake of catching it. Catch any exception only if you want to handle it or, you want to provide additional contextual information in that exception. If you can’t handle it in catch block, then best advice is just don’t catch it only to re-throw it.
3- Avoid using Throwable class
Throwable is the superclass of Exception and Error, as far as I know you need to use Throwable when you want to deal with both exceptions and errors, but it's definitely not your concern here, most of the java code deal with Exception and it's the way to go whenever you need to deal with checked exceptions http://docs.oracle.com/javase/tutorial/essential/exceptions/index.html.
**
Well if I was you I would do something like :
public void Do() throws BlahIsFoundException{
try {
if (blah) throw new BlahIsFoundException(...);
Thingy thingy = ...;
Foo(thingy);
} catch(EmptyThingyException exception) {
//Handle the exception correctly, at least log it
} finally {
//Do some clean up if needed, for example close a database connection or free some resources.
}
}
public void Foo(Thingy thingy) throws EmptyThingyException {
if (thingy == null ||
thingy.isEmpty()) throw new EmptyThingyException();
...
}
public class EmptyThingyException extends Exception { ... }
public class BlahIsFoundException extends Exception { ... }
Hope that helps, here are some good documents to read :
http://docs.oracle.com/javase/tutorial/essential/exceptions/index.html
http://howtodoinjava.com/best-practices/java-exception-handling-best-practices

How am I supposed to let an Unchecked Exception bubble up and log?

So quoting from this page, which is titled: Exception-Handling Antipatterns Blog and seems to be written (or at least to be approved) by Oracle..
An unchecked exception probably shouldn't be retried, and the correct response is usually to do nothing, and let it bubble up out of your method and through the execution stack. This is why it doesn't need to be declared in a throws clause. Eventually, at a high level of execution, the exception should probably be logged.
I am not sure if I understand this. How can I log an unchecked exception? If I have something like:
public static void main(String args) {
foo();
// How do I know what to log here? The method I am calling
// is not throwing an Exception.
// Do I just blindly catch(Exception ex)?
}
static void foo() {
bar();
}
static void bar() {
baz();
}
static void baz() {
// I will do nothing as Oracle suggests and let this exception bubble up.. I wonder who is going to catch it and how this is going to be logged though!
throw new NullPointerException();
}
Can you help me understand what Oracle is suggesting here? I do not see any direct (or clear) way to catch runtime exceptions (I do not understand why it is not just called unchecked exceptions..) in higher levels and I am not sure how this suggested practice is useful. To me it would make more sense if it were talking about checked exceptions. Something like..
If a checked exception is thrown in a method that is not reasonable to be re-tried, the correct response is to let it bubble up and log..
You can also register a global ExceptionHandler that will handle the Exceptions that were not caught by your code:
Thread.setDefaultUncaughtExceptionHandler
This exception handle could then log whatever occured.
First of all, this is a general advice and it depends on the context. The idea behind it is that when a runtime exception occurs (ex. NullPointerException), the system is usually in an indeterministic state, meaning the rest of the code is not be guaranteed to execute as expected, so it's better to stop everything.
In most cases, your code will run in a separate thread and the exception will only stop the current thread, while the rest of the program keeps running.
This is not the case in your example, because everything is executed in a single thread, so the uncaught exception will effectively stop the whole program. In this scenario you might want to catch the exception and handle it.
public static void main(String args) {
try {
foo();
catch(Throwable t) {
t.printStackTrace(); // log exception
// handle the failure
}
}
You can also catch the exception earlier on, log and rethrow it further.
static void bar() {
try {
baz();
catch (Throwable t) { // catch
t.printStackTrace(); // log
throw t; // rethrow further
}
}
Edit: catch Throwable instead of Exception, will also catch Error
Note: Catching throwable is usually a bad idea, and should only be done with a specific purpose, not in general case. See #RC.'s comment.
As I understand it the documentation is suggesting that you have a generic handler at a high level of your code that logs such 'unexpected' (unrecoverable?) exceptions just as the comments in your main method suggest. So it might look something like this
public static void main(String args) {
try {
foo();
}
catch (ArithmeticException aex) { //if it's arithmetic log differently
log("arith issue! "+aex.getMessage());
}
catch (Exception ex) { //Otherwise do the best we can
log("unknown issue! "+ex.getMessage())
}
}
So there is still no path to recovery but at least before the process ends you get a chance to log the issue. You can also use the methods of Exception (or throwable) to get the stack trace and first causal exceptions in many case - so there is is a lot of extra useful information that might be logged.
There is a very straightforward way to catch unchecked exceptions, since they are all subclasses of RuntimeException or Error:
public static void main(String[] args) {
try {
// your code
} catch (RuntimeException | Error e) {
// handle uncaught exceptions, e.g.
e.printStackTrace();
}
}
How do I know what to log here? The method I am calling is not throwing an Exception.
As Joshua Bloch recommends in the Effective Java
Use the Javadoc #throws tag to document each unchecked exception that
a method can throw, but do not use the throws keyword to include
unchecked exceptions in the method declaration
And if you are using method wrapping in multilayered app i can recommend use exception translation:
Higher layers should catch lower-level exceptions and, in their place, throw exceptions that can be explained in terms of the higher-level abstraction
See Effective Java item 61
So i think for your example actually you should use something like:
try {
bar();
} catch(NullPointerException e) {
throw new HigherLevelException(...);
}
The most important guideline regarding exceptions is that a method that couldn't sucessfully complete its task should throw an exception.
Only if you can guarantee successful completion of your method's task, you should catch an exception inside your method (without re-throwing this or another exception). From my experience that's only true in very specific situations, e.g. if you have an alternative way to try if some first attempt fails, or if you really really understand all possible causes of this specific Exception class that you are about to catch.
Speaking about RuntimeExceptions, there are so many different types of RuntimeException that you can hardly justify an assertion like "When such an exception arises in my code or a method called from inside my code, that won't affect the outcome of my method - I can continue just as if nothing happened." So, you should signal to your caller that you failed to fulfill your task, and the clearest way to do that is to let the exception ripple through, without try/catch block or throws declaration, just relying on Java's default behaviour.
In my opinion, the same reasoning applies to nearly all kinds of exceptions, not only RuntimeExceptions.
The difference with checked exceptions is that you have to declare them in the throws clause of your method. Then you have two choices: list the exception in the throws clause of your method (and all parent methods as well!) or catch the exception, wrap it in a new RuntimeException(ex), and throw that from your method.
With e.g. a typical GUI application, your users will be grateful if a problem in one menu function won't crash the whole application - probably other menu items might still work as expected. So, top-level commands or menu items are typically the places where to catch exceptions, tell the user something like "Oops!", log the exception to some file for later inspection, and allow the user to continue with another action.
In your main/foo/bar/baz application, I don't see a place where continuing after an exception makes sense. So the whole program should be aborted (which happens automatically in your case). If you want some error logging to a file, then establish an uncaught exception handler or wrap the body of main() in a try / catch(Throwable t) block. You'll probably want every exception logged, whatever type it is, so catch them all, and that's why I'm suggesting Throwable.
public static void main(String[] args) {
try {
foo();
}
catch(NullPointerException e){
System.out.println("NullPointerException in main.");
}
}
static void foo() {
bar();
}
static void bar() {
baz();
}
static void baz() {
// I will do nothing as Oracle suggests and let this exception bubble up.. I wonder who is going to catch it and how this is going to be logged though!
throw new NullPointerException();
}
OUTPUT :
NullPointerException in main.
Basically the error is expected at a higher level, so there is no need to catch it on the baz() method level. If I understood correctly.
You can catch them just like any other exception with try-catch block. But the benefit is that you don't have to.
Use cases can vary. To my mind, the most popular is when it doesn't make sense to catch the exception right in that place or the appropriate handling should be implemented several levels (in terms of methods) higher than the method, calling the one throwing the exception (sorry, if that is not clear enough).
For example, the typical web application layout in java is as follows: you have a layer of controllers, a layer of services and a layer of dao. First one is responsible for dispatching requests, the second one is for managing business logic and the last one makes actual calls to db. So here for example it often doesn't make much sense to catch the exception in service layer if something goes wrong on the dao level. Here unchecked exceptions can be used. You log an exception and throw an unchecked exception so it could be handled some levels above for a user to get valuable feedback of work of the application.
If in this case you throw a checked exception you will have to rethrow it every level above just to bubble up it to the place of the actual handling. So here the unchecked exception is better to use in order not to copy and paste all that ugly try-catch block, rethrowing an exception and add the throws clause to the method.

Java custom exception class usage [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Throws or try-catch
I'm writing an API and I wish to write code such that I can raise an exception in a particular scenario. I've created an exception class as follows :-
public class InvalidSeverityException extends Exception {
private static final long serialVersionUID = 1L;
public InvalidSeverityException() {
// TODO Auto-generated constructor stub
}
}
In the codebase im having the following to call the code :-
throw new InvalidSeverityException();
However Eclipse suggests that I either use throws or enclose it within a try ... catch block. I feel that I shouldn't be catching this error and that the developers who use my API should enclose the code within try...catch.
Does that make sense? Am I doing something wrong?
When handling with exceptions in Java you must understand the concept of checked exceptions and unchecked exceptions.
In your case currently you are defining a checked exception, maybe you want an unchecked one.
Here's a brief description about each one of the types:
Checked Exceptions
This exceptions must be part of the method's signature that raises them (or that invokes one method that does) or you must catch them with a try catch block and deal with the problem. Usually checked exceptions are used when there is something that can be done about the error and also when you want the developer to be aware that such error may occur and that has to be handled.
In java java.lang.Exception is a checked exception and all its subclasses will also be checked.
Unchecked Exceptions
This exceptions on the other hand don't need to make part of the method signature, nor you have to wrap methods that throw new in a try catch block. It's just expected that somewhere in the call stack there will be a try catch to handle it, otherwise if it reaches the JVM it will nicely dump you a stacktrace.
In java java.lang.RuntimeException is an unchecked exception and so are all its subclasses.
My opinion
If you are defining an API my suggestion is to use checked exceptions, this is mostly because you explicitly inform the developers using your API that such an exception might occur (so they can handle it anyway they want).
You are correct, you should not catch it. As suggested by eclipse, you should use throws so that the developers will know that your method potentially throws that exception and can then catch it.
.... method() throws YourException{
The method where you have throw new InvalidSeverityException(); should define throws InvalidSeverityException
Example:
void yourMethod() throws InvalidSeverityException
{
........//Some code
throw new InvalidSeverityException();
}
Well then surely you follow the first suggestion by Eclipse and set your method to throw the exception.
public void myMethod() throws InvalidSeverityException {
//throw it somewhere in here so that other
//developer can catch it while calling your method
}

Handle exception or throw exception in Java

Like such Java code snippet:
public void func() throws XXXException { // throw exception to outer body ------ (2)
try {
......
} catch(XXXException ex) {
// handle exception ------ (1)
}
}
In this condition, how you decide to choose (1) or (2)? Is there any principles in Java exception handling?
If the code that calls the method that throws the exception can properly deal with the exception then it should catch it. If it cannot deal with the exception then it should throw it up.
For instance, if "func" is low-level networking code it should probably throws the exception rather than catch it. The code that ultimatly catches it should display an error message to the user (or whatever else makes sense). If instead "func" is part of the GUI layer it probably would catch the exception and display an error message to the user (or whatever else makes sense).
If you can handle it you handle it. For example, if you are loading a properties file and you get a FileNotFoundException perhaps you can use some default properties. In this case you handle the exception.
If you can't handle it but you think someone else might be able to down the road then you should throw the exception. For example, perhaps you are writing a general utility for reading in property files. In this case you might rethrow the exception so that whoever is using your general utility can then go ahead and load defaults.
If you can't handle it and you don't want to introduce the complexity of throwing the exception then you should send the exception to an exception handling service that you can configure at runtime. This way when unit testing the exception handling service can take that exception and rethrow it as a runtime exception which will crash the test immediately. However, in production code the exception handling service might just log the exception and try and restart the program somehow.
You choose (1) if you want to do something about the exception (e.g. log it, extract info from it). It's also common to throw the exception in the catch block after you are done with it (i.e. throw ex;)
You choose (2) if you want the users of your method to handle it (e.g. Java's String.matches method)
In a nut shell, choose to throw exception to outer body, unless you have a specific reason to catch the exception.
There's an excellent article at the O'Reilly java site about this topic. It goes into some detail about when you should catch versus throw, as well as other stuff, like checked versus unchecked exceptions.
Exceptions represent error conditions. When an error condition occurs, some method in the call chain knows how to handle that error in the context of the application i.e. what to do - ignore, retry, abort, etc. If this is that method that knows how to handle this exception, then you handle it here. If not, you throw it so that the method one level up the call chain receives it and acts on it.
Sometimes, you may want to do both (1) and (2). You may handle the exception, do some intermediate processing and then rethrow it.
public void func() throws XXXException {
try {
......
} catch(XXXException ex) {
logger.log(ex);
throw ex;
}
}
Or you may catch one exception and throw another, for example when you want to wrap a third party exception into an application exception.
public void func() throws YYYException {
try {
......
} catch(XXXException ex) {
throw new YYYException(ex);
}
}
In both cases, this is not the method that fully handles the exception and only does some processing along the way as the exception percolates to the top.

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