Spring - ConversionService no #Autowired because of ConfigurationPropertiesBindingPostProcessor - java

i've found a problem when using the Spring ConversionService (first I thought this was related to my test, but this was my error, it happens always). I try to create it via...
#Configuration
#ComponentScan(basePackages={"com.mybasepacke"})
public class MyConfiguration {
#Bean
#SuppressWarnings("rawtypes")
public ConversionServiceFactoryBean conversionService(ApplicationContext context) {
ConversionServiceFactoryBean factory = new ConversionServiceFactoryBean();
Map<String, MyConverter> converters = context.getBeansOfType(MyConverter.class);
factory.setConverters(new HashSet<>(converters.values()));
factory.afterPropertiesSet();
return factory;
}
}
This way, I expect to be able to simply create Converters (MyConverter is just a marker interface that extends Spring's Converter) like this...
#Component
public class ExampleConverter implements MyConverter<Something, SomethingElse> {
#Autowired
private SomeService someService;
... }
Spring should find all the MyConverters, add them all to the ConversionService (Factory) and I'll be able to use them... Theoretically. In reality, this happens:
ConfigurationPropertiesBindingPostProcessor gets initialized.
It optionally depends on a ConversionService.
Spring finds my ConversionServiceFactoryBean definition and starts it.
Unfortunately, ConfigurationPropertiesBindingPostProcessor is created BEFORE the AutowiredAnnotationBeanPostProcessor is registered. So all of its dependencies are NOT autowired. Which leads to all my converters not being autowired.
Has anyone an idea how to prevent this behavior? Or do I have to get rid of ConversionService since it doesn't seem to be able to use Converters with autowired fields?

Don't name your ConversionService conversionService, check the doc that basically explains what you found out yourself.
#Bean
public ConversionService myConversionService() {
// your setup
}
This is going to register a myConversionService (notice the method name) that will not be eagerly loaded by the configuration stuff. If you need some converters to coerce value from configuration (as defined in the doc), consider marking those converters with ConfigurationPropertiesBinding:
#Component
#ConfigurationPropertiesBinding
// This can't autowire things either ...
public class ExampleConverter implements MyConverter<Something, SomethingElse> { ... }

Related

Why do we use a qualifier when we can have a name for the bean?

Why do we use qualifiers with #Bean when we can have different names for different beans of the same type (class)?
#Bean
#Qualifier("fooConfig")
public Baz method1() {
}
Isn't the following code more clean?
#Bean("fooConfig")
public Baz method1() {
}
If I create two beans of the same type with different names (using #Bean annotation), then can we inject them specifically using the #Qualifier annotation(can be added on field/constructor parameter/setter) in another bean?
#Bean("fooConfig")
public Baz method1(){
}
#Bean("barConfig")
public Baz method2(){
}
// constructor parameter of a different bean
final #Qualifier("fooConfig") Baz myConfig
If the above is true, then where do we use #Qualifier (with #Bean or #Component) instead of giving the bean a name as shown below?
#Bean
#Qualifier("fooConfig")
public Baz method1(){
}
#Bean
#Qualifier("barConfig")
public Baz method2(){
}
// constructor parameter of a different bean
final #Qualifier("fooConfig") Baz myConfig
Beans have names. They don't have qualifiers. #Qualifier is annotation, with which you tell Spring the name of Bean to be injected.
No.
Default Qualifier is the only implementation of the interface(example is below, 4th question) or the only method with a particular return type. You don't need to specify the #Qualifier in that case. Spring is smart enough to find itself.
For example:
#Configuration
public class MyConfiguration {
#Bean
public MyCustomComponent myComponent() {
return new MyCustomComponent();
}
}
If you will try to inject myComponent somewhere, Spring is smart enough to find the bean above. Becaude there is only one Bean with return type MyCustomComponent. But if there was a couple of methods, that would return MyCustomComponent, then you would have to tell Spring which one to inject with #Qualifier annotation.
SIDENOTE: #Bean annotation by default Spring uses the method name as a bean name. You can also assign other name like #Bean("otherComponent").
You have one Interface, and a couple of Classes implementing it. You inject bean of your interface. How can Spring know which Class should be used?
This is you interface:
public interface TestRepository{}
This is your implementation 1:
#Repository
public class Test1Repository implements TestRepository{}
Your implementation 2:
#Repository
public class Test2Repository implements TestRepository{}
Now you are injecting it like:
private final TestRepository testRepository;
public TestServiceImpl(TestRepository testRepository) {
this.testRepository= testRepository;
}
QUESTION! How is Spring supposed to know which class to inject? Test1 or Test2? That's why you tell it with #Qualifier which class.
private final TestRepository testRepository;
public TestServiceImpl(#Qualifier("test1Repository") TestRepository testRepository) {
this.testRepository= testRepository;
}
I Prefer different method to not using #Qualifier
Create common Interface
public interface CommonFooBar{
public String commonFoo();
public String commonBar();
}
Extends to each service
public interface FooService extends CommonFooBar {
}
public interface BarService extends CommonFooBar {
}
Then using it to your class
#Autowired
FooService fooService;
or
#Autowired
BarService barService;
so, we can defined the single responsibility to each interface and This kind of segregation is more readable to every junior.
I quite like a different way of working. Surely if you provide a unique name for your bean, then that is all you need?
Given the example below, its easy to see that Spring will name the beans based on the method name used to create the beans. In other words, if you give your beans sensible names, then the code should become self-explanatory. This also works when injecting beans into other classes.
The end result of this is:
Spring will name your beans based on the method used to create them.
If you import a bean, Spring will try to match on the bean name.
If you try to import a bean that does not match the name, Spring will attempt to match the class.
If your injected field name does not match the bean name and there are more than one instance of your bean, Spring will throw an exception on startup as it won't know which one to inject.
Lets not over-complicate Spring.
#Bean
mqConnectionFactory() {
ConnectionFactory connectionFactory = new MQXAConnectionFactory();
return connectionFactory;
}
#Bean
public ConnectionFactory pooledConnectionFactory(ConnectionFactory mqconnectionFactory) {
JmsPoolConnectionFactory connectionFactory = new JmsPoolConnectionFactory();
connectionFactory.setConnectionFactory(mqConnectionFactory);
return connectionFactory;
}
#Bean
public ConnectionFactory cachingConnectionFactory(ConnectionFactory mqConnectionFactory) {
CachingConnectionFactory connectionFactory = new CachingConnectionFactory();
connectionFactory.setTargetConnectionFactory(mqConnectionFactory);
return connectionFactory;
}
#Bean
public JmsTemplate jmsTemplate(ConnectionFactory cachingConnectionFactory) {
JmsTemplate jmsTemplate = new JmsTemplate();
jmsTemplate.setConnectionFactory(cachingConnectionFactory);
return jmsTemplate;
}
#Bean
public DefaultMessageListenerContainer messageListenerContainer(ConnectionFactory pooledConnectionFactory) {
DefaultMessageListenerContainer container = new DefaultMessageListenerContainer();
container.setConnectionFactory(pooledConnectionFactory);
...
return container;
}

Spring bean decoration without ambiguity errors

I have the following scenario: A factory interface with 2 implementations, while the second one used as decorator to the first one.
public final class BaseMailFactory implements MailFactory {
#Autowired
private final ClassA classA;
#Autowired
private final ClassB classB;
public Mail createMail(){
.
.
.
}
}
public final class MetricAwareMailFactory implements MailFactory {
private final MailFactory mailFactory;
public Mail createMail(){
var mail = mailFactory.createMail();
return new MetricsAwareMail(mail);
}
}
#Configuration
public class MailFactoryConfiguration {
#Bean
public MailFactory metricsAwareMailFactory(){
return new MetricAwareMailFactory(???);
}
}
The wrapped object previously instantiated through spring container (context), hence all auto wired fields populated successfully. After creation of the second implementation I am struggle to find an elegant way to initialize the first instance without adding multiple implementations to MailFactory interface which leads to application startup errors due to ambiguity.
I know that I can use qualifies for that but they pollute my code.
I am looking for a way to instantiate a class through spring but without actually register it as a bean, in older spring versions I get to use anonymous beans for such purposes.
I found the #Primary annotation useful here:
#Configuration
public class MailFactoryConfiguration {
#Bean
#Lazy
MailFactory baseMailFactory(){
return new BaseMailFactory();
}
#Bean
#Primary
public MailFactory metricsAwareMailFactory(){
return new MetricAwareMailFactory(baseMailFactory());
}
}
I such way, both beans will be created but the primary one will be selected in case of multiple implementations.

Eliminating Spring.xml from Spring Framework

In Spring Framework is it possible to eliminate the entire Spring.xml and use a configuration class with #Configuration and #Bean annotation for creating bean, and for all other purpose use a spring.xml?
Yes, you can have pure java configuration in Spring. You have to create a class and annotate it with #Configuration. We annotate methods with #Bean and instantiate the Spring bean and return it from that method.
#Configuration
public class SomeClass {
#Bean
public SomeBean someBean() {
return new SomeBean();
}
}
If you want to enable component scanning, then you can give #ComponentScan(basePackages="specify_your_package") under the #Configuration. Also the method name as someBean serves as bean id. Also if you have to inject a dependency, you can use constructor injection and do as following:
#Configuration
public class SomeClass {
#Bean
public SomeDependency someDependency() {
return new SomeDependency();
}
#Bean
public SomeBean someBean() {
return new SomeBean(someDependency());
}
}
Yes,most of (maybe all of)official guides uses absolutely no xml configuration file,just annotations.

Spring Boot read values from application properties

I'm not sure if I understand it correctly, but from what I got, is that I can use #Value annotations to read values from my application.properties.
As I figured out this works only for Beans.
I defined such a bean like this
#Service
public class DBConfigBean {
#Value("${spring.datasource.username}")
private String userName;
#Bean
public String getName() {
return this.userName;
}
}
When the application starts I'm able to retrieve the username, however - how can I access this value at runtime?
Whenever I do
DBConfigBean conf = new DBConfigBean()
conf.getName();
* EDIT *
Due to the comments I'm able to use this config DBConfigBean - but my initial problem still remains, when I want to use it in another class
#Configurable
public SomeOtherClass {
#Autowired
private DBConfigBean dbConfig; // IS NULL
public void DoStuff() {
// read the config value from dbConfig
}
}
How can I read the DBConfig in a some helper class which I can define as a bean
Thanks
As Eirini already mentioned you must inject your beans.
The #Value annotation only works on Spring beans.
There is another way of accessing configuration with #ConfigurationProperties.
There you define a class that holds the configuration.
The main advantage is, that this is typesafe and the configuration is in one place.
Read more about this:
https://docs.spring.io/spring-boot/docs/current/reference/html/boot-features-external-config.html#boot-features-external-config-vs-value
You shouldn't instantiate your service with the new operator. You should inject it, for example
#Autowired
private DBConfigBean dbConfig;
and then dbConfig.getName();
Also you don't need any #Bean decorator in your getName() method
You just need to tell spring where to search for your annotated beans. So in your configuration you could add the following:
#ComponentScan(basePackages = {"a.package.containing.the.service",
"another.package.containing.the.service"})
EDIT
The #Value, #Autowired etc annotations can only work with beans, that spring is aware of.
Declare your SomeOtherClass as a bean and add the package config in your #Configuration class
#Bean
private SomeOtherClass someOtherClass;
and then
#Configuration
#ComponentScan(basePackages = {"a.package.containing.the.service"
"some.other.class.package"})
public class AppConfiguration {
//By the way you can also define beans like:
#Bean
public AwesomeService service() {
return new AwesomeService();
}
}
Wrap your DBConfig with #Component annotation and inject it using #Autowired :
#Autowired
private DBConfig dbConfig;
Just add below annotation to your DBConfigBean class:
#PropertySource(value = {"classpath:application.properties"})

How to use the #Autowired filed when construct in Spring

I have a bean use the "MongoTemplate" in construction,like this:
public class BasicRepository<T> implements DAO<T>{
...
#Autowired
private MongoTemplate mongoTemplate;
public BasicRepository(Class<?> typeParameterClass,DBConvertor<T> convertor){
getLogger().info("create a Object of BasicRepository,type of "+typeParameterClass);
this.typeParameterClass = typeParameterClass;
mongoTemplate.getCollectionName(typeParameterClass);
this.convertor = convertor;
}
...
}
configuration:
public class BeansConfiguration {
#Bean
DBConvertor<Topic> topicConvertor(){
return new DBConvertor<>(Topic.class);
}
#Bean
BasicRepository<Topic> topicDao(){
return new BasicRepository<Topic>(Topic.class,topicConvertor());
}
}
As you see,when construct the BasicRepository,it will throw the exception,because “mongoTemplate” is null during constructing time.How can I do for this.
#Autowired can not guarantee the constructor order. If you want to initialize the mongoTemplate first, you could use the mongoTemplate as a param of your constructor of BasicRepository.Then the Spring will do the dependent order for you.
Seems missing configuration of MongoTemplate. And you also need to check where you calling this repository. Spring beans are initialized after configuration load, if you use beans before spring loaded, it will be null.

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