AssertJ: how to assert BigDecimals using compareTo together with extracting() - java

I am using AssertJ extracting() method with Java8 lambdas and mapping some fields to BigDecimal, then asserting the resulting array. But I need to compare BigDecimal using compareTo() and not with equals() (because of this). How can I do that?
Example:
Actual actual = performTest();
Assertions.assertThat(actual)
.extracting(
Actual::getName, // returns String
Actual::getValue // returns BigDecimal
)
.containsExactly(
"abc", // ok, String equals comparison
new BigDecimal("1.1") // NOT OK, equals comparison, but I need compareTo comparison
);
Edit: I am looking for a fluent way to do this, because of course I can split this into multiple different Asserts and compare it that way, or put everything in one giant Condition.

You can use BigDecimalComparator like :
Actual actual = performTest();
Assertions.assertThat(actual)
.extracting(
Actual::getName, // returns String
Actual::getValue // returns BigDecimal
)
.usingComparatorForType(BigDecimalComparator.BIG_DECIMAL_COMPARATOR, BigDecimal.class)
.containsExactly("abc", new BigDecimal("1.1"));

If #assylias's solution doesn't work, you can always use a custom Condition.
assertThat(new BigDecimal("1.1")).has(new Condition<BigDecimal>() {
#Override
public boolean matches(BigDecimal s) {
return s.compareTo(new BigDecimal("1.1")) == 0;
}
});
Wrap it in a functional interface for a nicer syntax.
Edit: Using the tuple extractor in your example:
assertThat(foo).extracting("name", "value").has(new Condition<Object[]>() {
#Override
public boolean matches(Object[] value) {
return new BigDecimal("1.1").compareTo(value[1]);
}
});
Without tuple extractor:
Assertions.assertThat(actual).has(actualValue("abc", new BigDecimal("1.1")));
// Hide this somewhere and import static :)
public static Condition<Actual> actualValue(String expectedName, BigDecimal expectedValue) {
return new Condition<Actual>() {
#Override
public boolean matches(Actual value) {
return expectedName.equals(value.getName()) && value.getValue().compareTo(expectedValue) == 0;
}
};
}

I would use matches if it's a one time assertion:
assertThat(actual).matches(a -> a.getName().equals("abc") && p.getValue().compareTo(new BigDecimal("1.1")) == 0);
If you plan to reuse the assertion, I would create a condition as suggested by #fabienbk.

Related

Can we combine two methods that differ largely based on type?

I have two similar, but of different types, blocks of code in Java:
private Integer readInteger() {
Integer value = null;
while (value == null) {
if (scanner.hasNextInt()) {
value = scanner.nextInt();
} else {
scanner.next();
}
}
return value;
}
private Double readDouble() {
Double value = null;
while (value == null) {
if (scanner.hasNextDouble()) {
value = scanner.nextDouble();
} else {
scanner.next();
}
}
return value;
}
Is it possible to make just one method which would work for both of them?
I'd say, use a generic method, combined with the functional interfaces introduced in Java 8.
The method read now becomes a higher order function.
private <T> T read(Predicate<Scanner> hasVal, Function<Scanner, T> nextVal) {
T value = null;
while (value == null) {
if (hasVal.test(scanner)) {
value = nextVal.apply(scanner);
} else {
scanner.next();
}
}
return value;
}
Calling code becomes:
read(Scanner::hasNextInt, Scanner::nextInt);
read(Scanner::hasNextDouble, Scanner::nextDouble);
read(Scanner::hasNextFloat, Scanner::nextFloat);
// ...
So the readInteger() method can be adapted as follows:
private Integer readInteger() {
return read(Scanner::hasNextInt, Scanner::nextInt);
}
You could have something with three methods:
One which says if there is a value of the right type
Another which gets the value of the right type.
Another which discards whatever token you have.
For example:
interface Frobnitz<T> {
boolean has();
T get();
void discard();
}
You can pass this into your method:
private <T> T read(Frobnitz<? extends T> frob) {
T value = null;
while (value == null) {
if (frob.has()) {
value = frob.get();
} else {
frob.discard();
}
}
return value;
}
And then just implement Frobnitz for your Double and Integer cases.
To be honest, I'm not sure this gets you very much, especially if you've only got two cases; I'd be inclined just to suck up the small amount of duplication.
A lot of people have answered that you can use generics, but you can also simply remove the readInteger method, and only use the readDouble, as integers can be converted to doubles without data loss.
This is about code duplication.
The general approach is to turn similar code (you have) into equal code that can be extracted to a common parameterized method.
In your case what make the two code snipped differ is the access to methods of Scanner. You have to encapsulate them somehow. I'd suggest to do this with Java8 Functional interfaces like this:
#FunctionalInterface
interface ScannerNext{
boolean hasNext(Scanner scanner);
}
#FunctionalInterface
interface ScannerValue{
Number getNext(Scanner scanner);
}
Then replace the actual invocation of methods in scanner with the functional interface:
private Integer readInteger() {
ScannerNext scannerNext = (sc)->sc.hasNextInt();
ScannerValue scannerValue = (sc)-> sc.nextInt();
Integer value = null;
while (value == null) {
if (scannerNext.hasNext(scanner)) {
value = scannerValue.getNext(scanner);
} else {
scanner.next();
}
}
return value;
}
There is one more problem that the type of the value variable differs. So we replace it with its common supertype:
private Integer readInteger() {
ScannerNext scannerNext = (sc)->sc.hasNextInt();
ScannerValue scannerValue = (sc)-> sc.nextInt();
Number value = null;
while (value == null) {
if (scannerNext.hasNext(scanner)) {
value = scannerValue.getNext(scanner);
} else {
scanner.next();
}
}
return (Integer)value;
}
Now you have to places with a big equal section. You can select one of those sections starting with Number value = null; ending with the } before return ... and invoke your IDEs automated refactoring extract method:
private Number readNumber(ScannerNext scannerNext, ScannerValue scannerValue) {
Number value = null;
while (value == null) {
if (scannerNext.hasNext(scanner)) {
value = scannerValue.getNext(scanner);
} else {
scanner.next();
}
}
return value;
}
private Integer readInteger() {
return (Integer) readNumber( (sc)->sc.hasNextInt(), (sc)-> sc.nextInt());
}
private Double readDouble() {
return (Double) readNumber( (sc)->sc.hasNextDouble(), (sc)-> sc.nextDouble());
}
Comments argue against the use of custom interfaces against predefined interfaces from the JVM.
But my point in this answer was how to turn similar code into equal code so that it can be extracted to a single method rather that giving a concrete solution for this random problem.
Not an ideal solution but it still achieves the necessary removal of duplicate code and has the added benefit of not requiring Java-8.
// This could be done better.
static final Scanner scanner = new Scanner(System.in);
enum Read{
Int {
#Override
boolean hasNext() {
return scanner.hasNextInt();
}
#Override
<T> T next() {
return (T)Integer.valueOf(scanner.nextInt());
}
},
Dbl{
#Override
boolean hasNext() {
return scanner.hasNextDouble();
}
#Override
<T> T next() {
return (T)Double.valueOf(scanner.nextDouble());
}
};
abstract boolean hasNext();
abstract <T> T next();
// All share this method.
public <T> T read() {
T v = null;
while (v == null) {
if ( hasNext() ) {
v = next();
} else {
scanner.next();
}
}
return v;
}
}
public void test(String[] args) {
Integer i = Read.Int.read();
Double d = Read.Dbl.read();
}
There are some minor issues with this such as the casting but it should be a reasonable option.
A totally different approach from my other answer (and the other answers): don't use generics, but instead just write the methods more concisely, so you don't really notice the duplication.
TL;DR: rewrite the methods as
while (!scanner.hasNextX()) scanner.next();
return scanner.nextX();
The overall goal - write it as a single method - is only possible if you accept some amount of additional cruft.
Java method signatures do not take into account the return type, so it's not possible to have a next() method return an Integer in one context, and Double in another (short of returning a common supertype).
As such, you have to have something at the call sites to distinguish these cases:
You might consider passing something like Integer.class or Double.class. This does have the advantage that you can use generics to know that the returned value matches that type. But callers could pass in something else: how would you handle Long.class, or String.class? Either you need to handle everything, or you fail at runtime (not a good option). Even with a tighter bound (e.g. Class<? extends Number>), you still need to handle more than Integer and Double.
(Not to mention that writing Integer.class and Double.class everywhere is really verbose)
You might consider doing something like #Ward's answer (which I do like, BTW: if you're going to do it with generics, do it like that), and pass in functional objects which are able to deal with the type of interest, as well as providing the type information to indicate the return type.
But, again, you've got to pass these functional objects in at each call site, which is really verbose.
In taking either of these approaches, you can add helper methods which pass the appropriate parameters to the "generic" read method. But this feels like a backwards step: instead of reducing the number of methods to 1, it's increased to 3.
Additionally, you now have to distinguish these helper methods somehow at the call sites, in order to be able to call the appropriate one:
You could have overloads with a parameter of value type, rather than class type, e.g.
Double read(Double d)
Integer read(Integer d)
and then call like Double d = read(0.0); Integer i = read(0);. But anybody reading this code is going to be left wondering what that magic number in the code is - is there any significance to the 0?
Or, easier, just call the two overloads something different:
Double readDouble()
Integer readInteger()
This is nice and easy: whilst it's slightly more verbose than read(0.0), it's readable; and it's way more concise that read(Double.class).
So, this has got us back to the method signatures in OP's code. But this hopefully justifies why you still want to keep those two methods. Now to address the contents of the methods:
Because Scanner.nextX() doesn't return null values, the method can be rewritten as:
while (!scanner.hasNextX()) scanner.next();
return scanner.nextX();
So, it's really easy to duplicate this for the two cases:
private Integer readInteger() {
while (!scanner.hasNextInt()) scanner.next();
return scanner.nextInt();
}
private Double readDouble() {
while (!scanner.hasNextDouble()) scanner.next();
return scanner.nextDouble();
}
If you want, you could pull out a method dropUntil(Predicate<Scanner>) method to avoid duplicating the loop, but I'm not convinced it really saves you that much.
A single (near-)duplicated line is way less burdensome in your code than all those generics and functional parameters. It's just plain old code, which happens to be more concise (and, likely, more efficient) than "new" ways to write it.
The other advantage of this approach is that you don't have to use boxed types - you can make the methods return int and double, and not have to pay the boxing tax unless you actually need it.
This may not be of advantage to OP, since the original methods do return the boxed type; I don't know if this is genuinely desired, or merely an artefact of the way the loop was written. However, it is useful in general not to create those objects unless you really need them.
Reflection is an alternative if you don't care about performance.
private <T> T read(String type) throws Exception {
Method readNext = Scanner.class.getMethod("next" + type);
Method hasNext = Scanner.class.getMethod("hasNext" + type);
T value = null;
while (value == null) {
if ((Boolean) hasNext.invoke(scanner)) {
value = (T) readNext.invoke(scanner);
} else {
scanner.next();
}
}
return value;
}
Then you call
Integer i = read("Int");

Suspicious call to Collection.contains method in ArrayList

I am getting a warning that watchStore.contains(s) is a suspicious call to java.util.Collection#contains. How can I fix it? I want to use contains() to find a particular object with the matching serial number.
public Watch findWatchBySerialNumber(long srch) {
long s = srch;
Watch watch = null;
for(int i = 0; i < watchStore.size(); i++) {
watch = watchStore.get(i);
if(watchStore.contains(s)) {
System.out.print("item found");
return watch;
}
}
System.out.print("item not found");
return null; // watch is not found.
}
Presuming that Watch is the class, watchStore is a List<Watch>, and that a field serialNo exists on Watch...
public Optional<Watch> findWatchBySerialNumber(long serial) {
return watchStore.stream()
.filter(w -> w.getSerialNo() == serial)
.findFirst();
}
If you're not using Java 8, the code is close, but a bit more dangerous since you have the chance to return null. If you can use Guava's Optional, that'd be a better choice here.
public Watch findWatchBySerialNumber(long serial) {
for(Watch w : watchStore) {
if(w.getSerialNo() == serial) {
return w;
}
}
return null;
}
Your contains isn't going to work since your list doesn't contain Longs, it contains Watchs. This is also why the compiler sees it as dubious; contains accepts an Object but it will return false if what you're looking for doesn't have a comparable equals for what's in your list.
You have to iterate over the entirety of your collection to find it in this scenario, especially since you're looking for a specific property on those objects as opposed to a specific, easy-to-provide value.
please how can I fix that. I want to use the contain() to find a
particular object with the matching serial number.
In that case override Watch's equals() to use serialNumber field for comparison.
Then add constructor that accepts serialNumber.
public class Watch {
private final long serialNumber;
public Watch(long serialNumber) {
this.serialNumber = serialNumber;
}
#Override
public boolean equals(Object obj) {
return obj == this ||
(obj instanceof Watch && ((Watch)obj).serialNumber == serialNumber);
}
#Override
public int hashCode() {
return (int)serialNumber;
}
}
Replace if(watchStore.contains(s)){ with if(watchStore.contains(watchToFind)){ where Watch watchToFind = new Watch(s);
you can use contains method from org.apache.commons.lang.ArrayUtils package.
Checks if the value is in the given array.
The method returns false if a null array is passed in.
Parameters:
array the array to search through
valueToFind the value to find
Returns:
true if the array contains the object
long [] imageHashes= {12l,13l,14l,15l};
System.out.println(ArrayUtils.contains(imageHashes, 13l));

Evaluating multiple variable together in if condition

I was wondering whether its possible in java to evaluate multiple variables together in if-else condition like in python.
actual code
if(abc!=null && xyz!=null)
{//...}
dummy code
if(abc && xyz !=null)
{// will it be possible}
FIRST DRAFT
You can write smth like this:
boolean notNull(Object item) {
return item != null;
}
then you could use it like:
if (notNull(abc) && notNull(xyz)) {
//...
}
UPDATE 1:
I came up with a new idea, write function using varargs like:
boolean notNull(Object... args) {
for (Object arg : args) {
if (arg == null) {
return false;
}
}
return true;
}
usage: (you can pass to function multiple arguments)
if (notNull(abc, xyz)) {
//...
}
UPDATE 2:
The best approach is to use library apache commons ObjectUtils,
it contains several ready to use methods like:
allNotNull(Object... values),
anyNotNull(Object... values)
or firstNonNull(T... values)
the only way this would work is if abc was a boolean (and it wouldn't do what you're hoping it would do, it would simply test if abc == true). There is no way to compare one thing to multiple things in Java.
It's Impossible in java, you can use Varargs:
public boolean checkAnything(Object args...){
for(Object obj args){
if(...)
}
return ....;
}
See also:
Varargs
String… parameter in Java
Its not possible to that in Java. Instead you can do something like this:-
public boolean checkForNulls(Object... args){
List<Object> test = new ArrayList<Object>(Arrays.asList(args));
return test.contains(null); // Check if even 1 of the objects was null.
}
If any of the items is null, then the method will return true, else it'll return false. You can use it as per your requirements.
IMHO First is the better way and possible way.
Coming to second way ..if they are boolean values
if(abc && xyz )
{//...}

Assign if not null or if not set in Java

I am really tired of doing all the if null checks, resp. I also want to have a more configurable scenario for this. Let me explain this by an example:
I have a getter() which may return null or '0' in both cases the resp. setter() should not be called passing the getter().
So the implementation is
if(getter() != null && !getter().equals('0')) setter(getter());
this however really anoys me, especially if getter() and setter() are really long method calls and I have to introduce helper variables for this.
I am thinking about a method with parameter
ifNotSet(getter(), setter(), new Object[null, '0']);
which does exactly the same thing. Where the parameters to ifNotSet are
getter - the method to check if it does not equal one of the conditions
setter - the method to call in the way setter(getter) if conditions does not apply
conditions - the conditions which must not apply on evaluation of getter() for the method to be executed
At first sight this does not seem to complicated, it however is! Is anyone aware of a solution to this problem or any kind of implementation?
Thanks!
Update
I've been working some more on the problem, after the feedback of you guys, and found out about the following
private boolean ns(Object[] condition, Object getter) {
boolean ret = false;
for (Object object : condition) {
if(getter) equals or == ??
}
return true;
}
Object[] cond = new Object[] { null, "0" };
Object a;
if (ns(cond, a = getter()))setter(a);
Well, this seemed to be at least a solution if you have a lot of allocations to do. However, if you take a look at the ns() method... the question on the incoming conditions is, whether to use == or equals to do the comparison!?
You can use this way
public boolean checkNotNullOrZero(String s)
{
return (s!=null) && !s.equals("0");
}
Basic use:
if(checkNotNullOrZero(getter()))
{
setter(getter());
}
You can't do what that as in Java methods are not first-class citizens. You could use reflection or anon classes but it would be way more work .
If null and zero are always equivalent for getter then could that be changed to return just one of the two?
If null and zero are always equivalent for setter then could that be changed to normalize the two?
Could you create a method isNullOrZero(x) then you can have
if (!isNullOrZero(getter())) {
setter(getter());
}
Ugly way of doing this literally in Java:
public interface Getter {
public Object get();
}
public interface Caller {
public void call();
}
public void callIfNotNull(Getter getter, Caller caller, Object[] nullObjects) {
Object value = getter.get();
for(Object nullObject : nullObjects) {
if(value==nullObject) {
return;
}
}
caller.call();
}
Usage:
callIfNotNull(new Getter() {
#Override
public Object get() {
return getterMethod();
}
}, new Caller() {
#Override
public void call() {
setter();
}
}, new Object[]{null, '0'});
}
You might need to implement sane way to check for null objects and give reasonable names.
Personnaly, I wouldn't go with this approach. I would try to implement Null Object pattern to resolve an issue.

TreeMap returning null for value that should exist for some object keys

I have an issue with a TreeMap that we have defined a custom key object for. The issue is that after putting a few objects into the map, and trying to retrieve with the same key used to put on the map, I get a null. I believe this is caused by the fact that we have 2 data points on the key. One value is always populated and one value is not always populated. So it seems like the issue lies with the use of compareTo and equals. Unfortunately the business requirement for how our keys determine equality needs to be implemented this way.
I think this is best illustrated with code.
public class Key implements Comparable<Key> {
private String sometimesPopulated;
private String alwaysPopulated;
public int compareTo(Key aKey){
if(this.equals(aKey)){
return 0;
}
if(StringUtils.isNotBlank(sometimesPopulated) && StringUtils.isNotBlank(aKey.getSometimesPopulated())){
return sometimesPopulated.compareTo(aKey.getSometimesPopulated());
}
if(StringUtils.isNotBlank(alwaysPopulated) && StringUtils.isNotBlank(aKey.getAlwaysPopulated())){
return alwaysPopulated.compareTo(aKey.getAlwaysPopulated());
}
return 1;
}
public boolean equals(Object aObject){
if (this == aObject) {
return true;
}
final Key aKey = (Key) aObject;
if(StringUtils.isNotBlank(sometimesPopulated) && StringUtils.isNotBlank(aKey.getSometimesPopulated())){
return sometimesPopulated.equals(aKey.getSometimesPopulated());
}
if(StringUtils.isNotBlank(alwaysPopulated) && StringUtils.isNotBlank(aKey.getAlwaysPopulated())){
return alwaysPopulated.equals(aKey.getAlwaysPopulated());
}
return false;
}
So the issue occurs when trying to get a value off the map after putting some items on it.
Map<Key, String> map = new TreeMap<Key, String>();
Key aKey = new Key(null, "Hello");
map.put(aKey, "world");
//Put some more things on the map...
//they may have a value for sometimesPopulated or not
String value = map.get(aKey); // this = null
So why is the value null after just putting it in? I think the algorithm used by the TreeMap is sorting the map in an inconsistent manner because of the way I'm using compareTo and equals. I am open to suggestions on how to improve this code. Thanks
Your comparator violates the transitivity requirement.
Consider three objects:
Object A: sometimesPopulated="X" and alwaysPopulated="3".
Object B: sometimesPopulated="Y" and alwaysPopulated="1".
Object C: sometimesPopulated is blank and alwaysPopulated="2".
Using your comparator, A<B and B<C. Transitivity requires that A<C. However, using your comparator, A>C.
Since the comparator doesn't fulfil its contract, TreeMap is unable to do its job correctly.
I think the problem is that you are returning 1 from your compareTo if either of the sometimesPopulated values is blank or either of the alwaysPopulated values is blank. Remember that compareTo can be thought of returning the value of a subtraction operation and your's is not transitive. (a - b) can == (b - a) even when a != b.
I would return -1 if the aKey sometimesPopulated is not blank and the local sometimesPopulated is blank. If they are the same then I would do the same with alwaysPopulated.
I think your logic should be something like:
public int compareTo(Key aKey){
if(this.equals(aKey)){
return 0;
}
if (StringUtils.isBlank(sometimesPopulated)) {
if (StringUtils.isNotBlank(aKey.getSometimesPopulated())) {
return -1;
}
} else if (StringUtils.isBlank(aKey.getSometimesPopulated())) {
return 1;
} else {
int result = sometimesPopulated.compareTo(aKey.getSometimesPopulated());
if (result != 0) {
return result;
}
}
// same logic with alwaysPopulated
return 0;
}
I believe the problem is that you are treating two keys with both blank fields as greater than each other which could confuse the structure.
class Main {
public static void main(String... args) {
Map<Key, String> map = new TreeMap<Key, String>();
Key aKey = new Key(null, "Hello");
map.put(aKey, "world");
//Put some more things on the map...
//they may have a value for sometimesPopulated or not
String value = map.get(aKey); // this = "world"
System.out.println(value);
}
}
class Key implements Comparable<Key> {
private final String sometimesPopulated;
private final String alwaysPopulated;
Key(String alwaysPopulated, String sometimesPopulated) {
this.alwaysPopulated = defaultIfBlank(alwaysPopulated, "");
this.sometimesPopulated = defaultIfBlank(sometimesPopulated, "");
}
static String defaultIfBlank(String s, String defaultString) {
return s == null || s.trim().isEmpty() ? defaultString : s;
}
#Override
public int compareTo(Key o) {
int cmp = sometimesPopulated.compareTo(o.sometimesPopulated);
if (cmp == 0)
cmp = alwaysPopulated.compareTo(o.alwaysPopulated);
return cmp;
}
}
I think your equals, hashCode and compareTo methods should only use the field that is always populated. It's the only way to ensure the same object will always be found in the map regardless of if its optional field is set or not.
Second option, you could write an utility method that tries to find the value in the map, and if no value is found, tries again with the same key but with (or without) the optional field set.

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