Develop Reference

Timestamp to String to DateTime issues

I tried to see questions about date convert issues between two database using java but didn't solve my problem.
Here is the current date to insert in my database with a DateTime format :
java.sql.Date SQLDateValue = new java.sql.Date(System.currentTimeMillis()) ;
preparedStatement.setDate(index, SQLDateValue);
And here is the Timestamp from an API named Vdoc, convert to String and i tried to convert it to java.sql.Date (DateTime) :
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date DateValue = (java.util.Date) this.getWorkflowInstance().getValue(this.ListeChamps[i][2]);
String StringDateValue = DateValue.toString();
java.sql.Date SQLDateValue = new java.sql.Date (sdf.parse(StringDateValue).getTime());
preparedStatement.setDate(index, SQLDateValue);
The second line return a field value containing a String but i need to use toString().
The following error message is :
Failed to convert the date and / or time from a string.
Both of my date parameters are java.sql.date, i don't understand.
If you have an idea of ​​what happens with this, it would be nice to help me.
Ezerah
Sorry for my bad english

Just construct the java.sql.Date from java.util.Date.
Call java.util.Date::getTime to extract the count of milliseconds from epoch. Pass that count to constructor of java.sql.Date.
In your case below should work.
java.util.Date DateValue = (java.util.Date) this.getWorkflowInstance().getValue(this.ListeChamps[i][2]);
java.sql.Date SQLDateValue = new java.sql.Date (DataValue.getTime());
preparedStatement.setDate(index, SQLDateValue);

try this:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
java.util.Date DateValue = **sdf.parse(**this.getWorkflowInstance().getValue(this.ListeChamps[i][2])**)**;
String StringDateValue = DateValue.toString();
java.sql.Date SQLDateValue = new java.sql.Date (sdf.parse(StringDateValue).getTime());
preparedStatement.setDate(index, SQLDateValue);
You can't cast String to Date, you should parse it

Mapping Date and Time to MySQL

I have created a table in MySQL as :
CREATE TABLE scheduled(sid INT,id INT,tweet VARCHAR(255),sdate DATE,
stime TIME,PRIMARY KEY(sid),FOREIGN KEY(id) REFERENCES usercred(id));
I receive both Date and Time from the HTML input field. Date received from the HTML field looks like :
4/30/2014
How can I map this in Java ? After receiving both Date and Time and after mapping them correctly , I will commit the transaction or will update the table/entry.

could use the parse() method in the SimpleDateFormat object:
SimpleDateFormat sdf = new SimpleDateFormat("M-dd-yyyy");
String dateInString = "4-30-1982"";
Date date = sdf.parse(dateInString);
System.out.println(date);

In JDBC-layer inside PreparedStatement or ResultSet you work with the mapping java.sql.Date (for SQL-DATE) and java.sql.Time (for SQL-TIME). Then you can wrap both types like:
java.sql.Date sqlDate = ...; // from ResultSet
DateFormat df = new SimpleDateFormat("MM/dd/yyyy"); // or M/d/yyyy
String htmlFormat = df.format(sqlDate);
And in reverse:
String htmlFormat = ...;
DateFormat df = new SimpleDateFormat("MM/dd/yyyy"); // or M/d/yyyy
java.util.Date d = df.parse(htmlFormat);
java.sql.Date sqlDate = new java.sql.Date(d.getTime());
// use result in PreparedStatement for INSERT or UPDATE
Attention: Both approaches use the standard timezone of the server where this code is running. In case of doubt you should probably set the timezone UTC. Similar code for the TIME-part.

Changing the date format to mm-dd-yyyy hh:mm

I'm trying to use this code:
private static Date getTimeStamp() {
return new Timestamp(new Date().getTime());
}
What I'm getting is 2013-03-13 12:46:22.011
But what I need is that the timestamp should be in the format of mm-dd-yyyy hh:mm.

java.sql.Timestamp objects (just like java.util.Date and java.sql.Date) do not have a format by themselves, so you cannot "have a Timestamp in the format [whatever]".
A format only is applicable when you convert the object to a string for display. You can use SimpleDateFormat to convert a Timestamp to a string, using the format you want.
Timestamp timestamp = new Timestamp(System.currentTimeMillis());
DateFormat dateFormat = new SimpleDateFormat("MM-dd-yyyy HH:mm");
String text = dateFormat.format(timestamp);
System.out.println(text);

Hope this helps
String date1="2013-03-13 12:46:22.011";
DateFormat userDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:SS");
DateFormat dateFormatNeeded = new SimpleDateFormat("MM/dd/yyyy HH:mm");
Date date = userDateFormat.parse(date1);
String finaldate = dateFormatNeeded.format(date);

You can use SimpleDateFormat http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html to achieve your goal.
For Example:
new SimpleDateFormat("MM-dd-yyyy HH:mm").format(timestamp));

Get time from entire date

I have to get time from entire date
e.g. time=11:00:00 from date 2012-09-01 11:00:00.0
I tried following snippet but getting error Error : Unparseable date: "2012-9-1.13.30. 0. 0"
DateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
Date date = inputFormat.parse(iResultSet1.getString(i));
DateFormat outputFormat = new SimpleDateFormat("hh:mm:ss");
String outputString = outputFormat.format(date);
Edit: Now I am getting only date instead I want only time
if (iResultSet1.getDate(i) != null) {
Date date = iResultSet1.getDate(i);
System.out.println("date-->" + date);
// Format date into output format
DateFormat outputFormat = new SimpleDateFormat(
"HH:mm:ss");
String outputString = outputFormat.format(date);
// System.out.println("date1-->"+date1);

I wil suggest, in this case rather doing parsing and manipulation in java change your SQL to format and return only date as
Example
SELECT TIME_FORMAT(NOW(), '%H:%i:%s');

You are probably retrieving your date from the database (iResultSet1.getString(i)) and the problem is that you're getting wrong format, i.e. 2012-9-1.13.30. 0. 0. Either change the date format in the database or use:
Date date = iResultSet1.getDate(i);
instead of
DateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
Date date = inputFormat.parse(iResultSet1.getString(i));

how to convert datetime to timestamp in java

forum member
I am having one problem with date time in java. Actually I am receiving the startdate in format 2012-02-27T01:10:10 and I want to insert the received date to my database having datetime datatype.
Actually I tried to convert the startdate received to datetime by below code
String sDate = jsonObject.get("StartDate").toString();
String eDate = jsonObject.get("EndDate").toString();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Date startD = sdf.format(sDate);
Date endD = sdf.format(eDate);
but with the above code only date gets added to my database like 2012-02-27 00:00:00
I want to add the time also to my database but when I change the SimpleDateFormat to SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); nothing works.
please suggest me some solution I can apply so my time also gets added to database. I am using Hibernate JPA as my persistence layer.

SimpleDateFormat's format() method doesn't return a Date type.
try this:
Date startDate = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss").parse(sDate);

Try this,
yyyy-MM-dd'T'HH:mm:ss

String sDate = jsonObject.get("StartDate").toString();
String eDate = jsonObject.get("EndDate").toString();
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Date startD = sdf.format(sDate);
Timestamp startTime = new Timestamp(startD.getTime());
Date endD = sdf.format(eDate);
Timestamp endTime = new Timestamp(endD.getTime());

Of course only the date is parsed, since the pattern you provided to the SimpleDateFormat constructor only contains the date part! Add the time part to it and it will parse the time too just fine.

you can try like this....
DateFormat format = new SimpleDateFormat("MMddyyHHmmss");
Date date = format.parse("022310141505");