Develop Reference

find next word of a word from a string

I have written following code to get next word from a string in Java. I feel its very raw and I shouldn't have to write so much code for this but couldn't find any other way. Want to know if there are better ways available to do same:
public static String getNextWord(String str, String word) {
String nextWord = null;
// to remove multi spaces with single space
str = str.trim().replaceAll(" +", " ");
int totalLength = str.length();
int wordStartIndex = str.indexOf(word);
if (wordStartIndex != -1) {
int startPos = wordStartIndex + word.length() + 1;
if (startPos < totalLength) {
int nextSpaceIndex = str.substring(startPos).indexOf(" ");
int endPos = 0;
if (nextSpaceIndex == -1) {
// we've reached end of string, no more space left
endPos = totalLength;
} else {
endPos = startPos + nextSpaceIndex;
}
nextWord = str.substring(startPos, endPos);
}
}
return nextWord;
}
Note: the input word could be anything (multi words, single word, a word not in string etc).
Test:
String text = "I am very happy with life";
System.out.println(StringUtil.getNextWord(text, "I"));
System.out.println(StringUtil.getNextWord(text, "I am"));
System.out.println(StringUtil.getNextWord(text, "life"));
System.out.println(StringUtil.getNextWord(text, "with"));
System.out.println(StringUtil.getNextWord(text, "fdasfasf"));
System.out.println(StringUtil.getNextWord(text, text));
Output:
am
very
null
life
null
null

This sounds like a job for regex. Something like this:
public static String getNextWord(String str, String word){
Pattern p = Pattern.compile(word+"\\W+(\\w+)");
Matcher m = p.matcher(str);
return m.find()? m.group(1):null;
}

Hope this will serve your purpose.
public static String getNextWord(String str, String word) {
String[] words = str.split(" "), data = word.split(" ");
int index = Arrays.asList(words).indexOf((data.length > 1) ? data[data.length - 1] : data[0]);
return (index == -1) ? "Not Found" : ((index + 1) == words.length) ? "End" : words[index + 1];
}
Input (single word) :
String str = "Auto generated method stub";
String word = "method";
Out Put:
next word: stub
Input (multi-words) :
String str = "Auto generated method stub";
String word = "Auto generated";
Out Put:
next word: method
Input (missing word) :
String str = "Auto generated method stub";
String word = "was";
Out Put:
next word: Not Found
Input (end word) :
String str = "Auto generated method stub";
String word = "stub";
Out Put:
next word: End

You can create an array of words by doing this:
String[] words = str.split(" ");
This splits the string into strings when separated by a space. Note you keep needing to trim the str as you want to.
Now, you can somehow search in the array by finding some word and adding 1 to the index to get the next one.
nextword = words[words.indexOf(word) + 1];

I think, this solution works correctly:
public static String getNextWord(String str, String word) {
String[] strArr = str.split(word);
if(strArr.length > 1) {
strArr = strArr[1].trim().split(" ");
return strArr[0];
}
return null;
}

You can try the below code.
public static String getNextWord(String str, String word) {
try {
List<String> text = Arrays.asList(str.split(" "));
List<String> list = Arrays.asList(word.split(" "));
int index_of = text.indexOf(list.get(list.size() - 1));
return (index_of == -1) ? null : text.get(index_of + 1);
} catch(Exception e) {
return null;
}
}

Hope this is what you are looking for:
public static void main(String[] args) {
String text = "I am very happy with life";
System.out.println(getNextWord(text,"am"));
System.out.println(getNextWord(text,"with"));
System.out.println(getNextWord(text,"happy"));
System.out.println(getNextWord(text,"I"));
System.out.println(getNextWord(text,"life"));
}
public static String getNextWord(String text,String finditsNext){
String result = "There is no next string";
try {
int findIndex = text.indexOf(finditsNext);
String tep = text.substring(findIndex);
if(tep.indexOf(" ") >0) {
tep = tep.substring(tep.indexOf(" ") + 1);
if(tep.indexOf(" ") >0)
result = tep.substring(0, tep.indexOf(" "));
else
result = tep;
}
}catch (IndexOutOfBoundsException ex){
}
return result;
}
The output for the above is:
very
life
with
am
There is no next string

Search and get equal characters in a String

I need to search for a certain String in another character-by-character string and if the characters are the same get such a character;
I'm doing it this way
public String searchForSignature(String texto2) throws NoSuchAlgorithmException {
String myString = "", foundString = "";
myString = "aeiousrtmvb257";
for (int i = 0; i < texto2.length() || i <= 1000; i++) {
char c = texto2.charAt(i);
for (int j = 0; j < myString.length(); j++) {
if (c == myString.charAt(j)) {
foundString = foundString + c;
}
}
}
return foundString;
}
I would like to improve the performance and saw that there are forms and using regular expressions, as I am still a little lay I could not succeed in the way I did.
public String searchForSignature2(String texto2) {
Pattern pattern = Pattern.compile("aeiousrtmvb257");
Matcher matcher = pattern.matcher(texto2);
while (matcher.find()) {
System.out.println(matcher.group(1));
}
return matcher.group(1).toString();
}
Does not return anything
//edit
Really, I guess I was not very clear on the question.
Actually I need to get all the characters equal to "aeiousrtmvb257" the ones that are in the String
I did it that way, now it seems OK, I just do not know if the performance is satisfactory.
public String searchForSignature2(String texto2) {
String foundString = "";
Pattern pattern = Pattern.compile("[aeiousrtmvb257]");
Matcher matcher = pattern.matcher(texto2);
while (matcher.find()) {
System.out.println(matcher.group());
foundString+=matcher.group();
}
return foundString;
}
}

As far as I understood your question, by using Patternand Matcher this should do the trick:
Code
private static final String PATTERN_TO_FIND = "[aeiousrtmvb257]";
public static void main(String[] args) {
System.out.println(searchForSignature2("111aeiousrtmvb257111"));
}
public static String searchForSignature2(String texto2) {
Pattern pattern = Pattern.compile(PATTERN_TO_FIND);
Matcher matcher = pattern.matcher(texto2);
StringBuilder result = new StringBuilder();
while (matcher.find()) {
result.append(matcher.group());
}
return result.toString();
}
Output
aeiousrtmvb257

I don't know what was the reason behind texto2.length() || i <= 1000, but based on the logic in your method, I could suggest the below solution:
public static void main(String... args) throws IOException {
System.out.println(searchForSignature("hello"));
}
public static String searchForSignature(String texto2) {
String myString = "aeiousrtmvb257";
StringBuilder builder = new StringBuilder();
for (char s : texto2.toCharArray()) {
if (myString.indexOf(s) != -1) {
builder.append(s);
}
}
return builder.toString();
}
Output: eo

I don't get it, why would you print the string that you found
public static String searchForSignature2(String texto2) {
String maaString = "aeiousrtmvb257";
String toSearch = ".*" + maaString +".*";
boolean b = Pattern.matches(toSearch, texto2);
return b ? maaString : "";
}
public static void main(String[] args)
{
String input = "4erdhrAW BLBAJJINJOI WETSEKMsef saemfosnens3bntu is5o3n029j29i30kwq23eki4"+
"maoifmakakmkakmsmfajiwfuanyi gaeniygaenigaenigeanige anigeanjeagjnageunega"+
"movmmklmklzvxmkxzcvmoifsadoi asfugufngs"+
"wpawfmaopfwamopfwampfwampofwampfawmfwamokfesomk"+
"3rwq3rqrq3rqetgwtgwaeiousrtmvb2576266wdgdgdgdgd";
String myString = searchForSignature2(input);
System.out.println(myString);
}
you need to add .* to tell that your string is surrounded by any char

Java code to segment string into meaningful dictionary words, getting StringIndexOutOfBoundException

//Here is Java code to segment a string into meaningful dictionary words.
Getting StringIndexOutOfBoundException!
import java.util.*;
public class SeparateStringWords {
public static void main(String[] args) {
//segment a word into meaning full word eg. iamstudent => i am student
String str = "iamstudent";
Set < String > dict = new HashSet < String > ();
dict.add("i");
dict.add("am");
dict.add("student");
//dict is our lookup dictionary
String separated = segmentString(str, dict);
System.out.println("separated string is:" + separated);
}
static String segmentString(String str, Set < String > dict) {
if (dict.contains(str)) return str;
int len = str.length();
System.out.println(len);
for (int i = 1; i < len; i++) {
String prefix = str.substring(0, i);
if (dict.contains(prefix)) {
String suffix = prefix.substring(i, len); //StringIndexOutOfBoundException
String subSuffix = segmentString(suffix, dict);
if (subSuffix != null) {
return prefix + " " + subSuffix;
}
}
}
return null;
}
}
//Solved: thanks for help guys :) ..... suffix=str.substring(i,len);

Prefix is a substring that is shorter then len because len is the length of str and prefix is a substring from o to i so you have to use str.substring(i,len);

You probably wanted to get the suffix of the original String, not from the prefix :
String suffix=str.substring(i,len);
It makes no sense to try to get the suffix of the prefix, since the prefix only has i characters, so both i and len would be out of bounds.

How to flip two words in a string, Java

So say I have a string called x that = "Hello world". I want to somehow make it so that it will flip those two words and instead display "world Hello". I am not very good with loops or arrays and obviously am a beginner. Could I accomplish this somehow by splitting my string? If so, how? If not, how could I do this? Help would be appreciated, thanks!

1) split string into String array on space.
String myArray[] = x.split(" ");
2) Create new string with words in reverse order from array.
String newString = myArray[1] + " " + myArray[0];
Bonus points for using a StringBuilder instead of concatenation.

String abc = "Hello world";
String cba = abc.replace( "Hello world", "world Hello" );
abc = "This is a longer string. Hello world. My String";
cba = abc.replace( "Hello world", "world Hello" );
If you want, you can explode your string as well:
String[] pieces = abc.split(" ");
for( int i=0; i<pieces.length-1; ++i )
if( pieces[i]=="Hello" && pieces[i+1]=="world" ) swap(pieces[i], pieces[i+1]);
There are many other ways you can do it too. Be careful for capitalization. You can use .toUpperCase() in your if statements and then make your matching conditionals uppercase, but leave the results with their original capitalization, etc.

Here's the solution:
import java.util.*;
public class ReverseWords {
public String reverseWords(String phrase) {
List<String> wordList = Arrays.asList(phrase.split("[ ]"));
Collections.reverse(wordList);
StringBuilder sbReverseString = new StringBuilder();
for(String word: wordList) {
sbReverseString.append(word + " ");
}
return sbReverseString.substring(0, sbReverseString.length() - 1);
}
}
The above solution was coded by me, for Google Code Jam and is also blogged here: Reverse Words - GCJ 2010

Just use this method, call it and pass the string that you want to split out
static String reverseWords(String str) {
// Specifying the pattern to be searched
Pattern pattern = Pattern.compile("\\s");
// splitting String str with a pattern
// (i.e )splitting the string whenever their
// is whitespace and store in temp array.
String[] temp = pattern.split(str);
String result = "";
// Iterate over the temp array and store
// the string in reverse order.
for (int i = 0; i < temp.length; i++) {
if (i == temp.length - 1) {
result = temp[i] + result;
} else {
result = " " + temp[i] + result;
}
}
return result;
}

Depending on your exact requirements, you may want to split on other forms of whitespace (tabs, multiple spaces, etc.):
static Pattern p = Pattern.compile("(\\S+)(\\s+)(\\S+)");
public String flipWords(String in)
{
Matcher m = p.matcher(in);
if (m.matches()) {
// reverse the groups we found
return m.group(3) + m.group(2) + m.group(1);
} else {
return in;
}
}
If you want to get more complex see the docs for Pattern http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html

Try something as follows:
String input = "how is this";
List<String> words = Arrays.asList(input.split(" "));
Collections.reverse(words);
String result = "";
for(String word : words) {
if(!result.isEmpty()) {
result += " ";
}
result += word;
}
System.out.println(result);
Output:
this is how

Too much?
private static final Pattern WORD = Pattern.compile("^(\\p{L}+)");
private static final Pattern NUMBER = Pattern.compile("^(\\p{N}+)");
private static final Pattern SPACE = Pattern.compile("^(\\p{Z}+)");
public static String reverseWords(final String text) {
final StringBuilder sb = new StringBuilder(text.length());
final Matcher wordMatcher = WORD.matcher(text);
final Matcher numberMatcher = NUMBER.matcher(text);
final Matcher spaceMatcher = SPACE.matcher(text);
int offset = 0;
while (offset < text.length()) {
wordMatcher.region(offset, text.length());
numberMatcher.region(offset, text.length());
spaceMatcher.region(offset, text.length());
if (wordMatcher.find()) {
final String word = wordMatcher.group();
sb.insert(0, reverseCamelCase(word));
offset = wordMatcher.end();
} else if (numberMatcher.find()) {
sb.insert(0, numberMatcher.group());
offset = numberMatcher.end();
} else if (spaceMatcher.find()) {
sb.insert(0, spaceMatcher.group(0));
offset = spaceMatcher.end();
} else {
sb.insert(0, text.charAt(offset++));
}
}
return sb.toString();
}
private static final Pattern CASE_REVERSAL = Pattern
.compile("(\\p{Lu})(\\p{Ll}*)(\\p{Ll})$");
private static String reverseCamelCase(final String word) {
final StringBuilder sb = new StringBuilder(word.length());
final Matcher caseReversalMatcher = CASE_REVERSAL.matcher(word);
int wordEndOffset = word.length();
while (wordEndOffset > 0 && caseReversalMatcher.find()) {
sb.insert(0, caseReversalMatcher.group(3).toUpperCase());
sb.insert(0, caseReversalMatcher.group(2));
sb.insert(0, caseReversalMatcher.group(1).toLowerCase());
wordEndOffset = caseReversalMatcher.start();
caseReversalMatcher.region(0, wordEndOffset);
}
sb.insert(0, word.substring(0, wordEndOffset));
return sb.toString();
}

How to capitalize the first character of each word in a string

Is there a function built into Java that capitalizes the first character of each word in a String, and does not affect the others?
Examples:
jon skeet -> Jon Skeet
miles o'Brien -> Miles O'Brien (B remains capital, this rules out Title Case)
old mcdonald -> Old Mcdonald*
*(Old McDonald would be find too, but I don't expect it to be THAT smart.)
A quick look at the Java String Documentation reveals only toUpperCase() and toLowerCase(), which of course do not provide the desired behavior. Naturally, Google results are dominated by those two functions. It seems like a wheel that must have been invented already, so it couldn't hurt to ask so I can use it in the future.

WordUtils.capitalize(str) (from apache commons-text)
(Note: if you need "fOO BAr" to become "Foo Bar", then use capitalizeFully(..) instead)

If you're only worried about the first letter of the first word being capitalized:
private String capitalize(final String line) {
return Character.toUpperCase(line.charAt(0)) + line.substring(1);
}

The following method converts all the letters into upper/lower case, depending on their position near a space or other special chars.
public static String capitalizeString(String string) {
char[] chars = string.toLowerCase().toCharArray();
boolean found = false;
for (int i = 0; i < chars.length; i++) {
if (!found && Character.isLetter(chars[i])) {
chars[i] = Character.toUpperCase(chars[i]);
found = true;
} else if (Character.isWhitespace(chars[i]) || chars[i]=='.' || chars[i]=='\'') { // You can add other chars here
found = false;
}
}
return String.valueOf(chars);
}

Try this very simple way
example givenString="ram is good boy"
public static String toTitleCase(String givenString) {
String[] arr = givenString.split(" ");
StringBuffer sb = new StringBuffer();
for (int i = 0; i < arr.length; i++) {
sb.append(Character.toUpperCase(arr[i].charAt(0)))
.append(arr[i].substring(1)).append(" ");
}
return sb.toString().trim();
}
Output will be: Ram Is Good Boy

I made a solution in Java 8 that is IMHO more readable.
public String firstLetterCapitalWithSingleSpace(final String words) {
return Stream.of(words.trim().split("\\s"))
.filter(word -> word.length() > 0)
.map(word -> word.substring(0, 1).toUpperCase() + word.substring(1))
.collect(Collectors.joining(" "));
}
The Gist for this solution can be found here: https://gist.github.com/Hylke1982/166a792313c5e2df9d31

String toBeCapped = "i want this sentence capitalized";
String[] tokens = toBeCapped.split("\\s");
toBeCapped = "";
for(int i = 0; i < tokens.length; i++){
char capLetter = Character.toUpperCase(tokens[i].charAt(0));
toBeCapped += " " + capLetter + tokens[i].substring(1);
}
toBeCapped = toBeCapped.trim();

I've written a small Class to capitalize all the words in a String.
Optional multiple delimiters, each one with its behavior (capitalize before, after, or both, to handle cases like O'Brian);
Optional Locale;
Don't breaks with Surrogate Pairs.
LIVE DEMO
Output:
====================================
SIMPLE USAGE
====================================
Source: cApItAlIzE this string after WHITE SPACES
Output: Capitalize This String After White Spaces
====================================
SINGLE CUSTOM-DELIMITER USAGE
====================================
Source: capitalize this string ONLY before'and''after'''APEX
Output: Capitalize this string only beforE'AnD''AfteR'''Apex
====================================
MULTIPLE CUSTOM-DELIMITER USAGE
====================================
Source: capitalize this string AFTER SPACES, BEFORE'APEX, and #AFTER AND BEFORE# NUMBER SIGN (#)
Output: Capitalize This String After Spaces, BeforE'apex, And #After And BeforE# Number Sign (#)
====================================
SIMPLE USAGE WITH CUSTOM LOCALE
====================================
Source: Uniforming the first and last vowels (different kind of 'i's) of the Turkish word D[İ]YARBAK[I]R (DİYARBAKIR)
Output: Uniforming The First And Last Vowels (different Kind Of 'i's) Of The Turkish Word D[i]yarbak[i]r (diyarbakir)
====================================
SIMPLE USAGE WITH A SURROGATE PAIR
====================================
Source: ab 𐐂c de à
Output: Ab 𐐪c De À
Note: first letter will always be capitalized (edit the source if you don't want that).
Please share your comments and help me to found bugs or to improve the code...
Code:
import java.util.ArrayList;
import java.util.Date;
import java.util.List;
import java.util.Locale;
public class WordsCapitalizer {
public static String capitalizeEveryWord(String source) {
return capitalizeEveryWord(source,null,null);
}
public static String capitalizeEveryWord(String source, Locale locale) {
return capitalizeEveryWord(source,null,locale);
}
public static String capitalizeEveryWord(String source, List<Delimiter> delimiters, Locale locale) {
char[] chars;
if (delimiters == null || delimiters.size() == 0)
delimiters = getDefaultDelimiters();
// If Locale specified, i18n toLowerCase is executed, to handle specific behaviors (eg. Turkish dotted and dotless 'i')
if (locale!=null)
chars = source.toLowerCase(locale).toCharArray();
else
chars = source.toLowerCase().toCharArray();
// First charachter ALWAYS capitalized, if it is a Letter.
if (chars.length>0 && Character.isLetter(chars[0]) && !isSurrogate(chars[0])){
chars[0] = Character.toUpperCase(chars[0]);
}
for (int i = 0; i < chars.length; i++) {
if (!isSurrogate(chars[i]) && !Character.isLetter(chars[i])) {
// Current char is not a Letter; gonna check if it is a delimitrer.
for (Delimiter delimiter : delimiters){
if (delimiter.getDelimiter()==chars[i]){
// Delimiter found, applying rules...
if (delimiter.capitalizeBefore() && i>0
&& Character.isLetter(chars[i-1]) && !isSurrogate(chars[i-1]))
{ // previous character is a Letter and I have to capitalize it
chars[i-1] = Character.toUpperCase(chars[i-1]);
}
if (delimiter.capitalizeAfter() && i<chars.length-1
&& Character.isLetter(chars[i+1]) && !isSurrogate(chars[i+1]))
{ // next character is a Letter and I have to capitalize it
chars[i+1] = Character.toUpperCase(chars[i+1]);
}
break;
}
}
}
}
return String.valueOf(chars);
}
private static boolean isSurrogate(char chr){
// Check if the current character is part of an UTF-16 Surrogate Pair.
// Note: not validating the pair, just used to bypass (any found part of) it.
return (Character.isHighSurrogate(chr) || Character.isLowSurrogate(chr));
}
private static List<Delimiter> getDefaultDelimiters(){
// If no delimiter specified, "Capitalize after space" rule is set by default.
List<Delimiter> delimiters = new ArrayList<Delimiter>();
delimiters.add(new Delimiter(Behavior.CAPITALIZE_AFTER_MARKER, ' '));
return delimiters;
}
public static class Delimiter {
private Behavior behavior;
private char delimiter;
public Delimiter(Behavior behavior, char delimiter) {
super();
this.behavior = behavior;
this.delimiter = delimiter;
}
public boolean capitalizeBefore(){
return (behavior.equals(Behavior.CAPITALIZE_BEFORE_MARKER)
|| behavior.equals(Behavior.CAPITALIZE_BEFORE_AND_AFTER_MARKER));
}
public boolean capitalizeAfter(){
return (behavior.equals(Behavior.CAPITALIZE_AFTER_MARKER)
|| behavior.equals(Behavior.CAPITALIZE_BEFORE_AND_AFTER_MARKER));
}
public char getDelimiter() {
return delimiter;
}
}
public static enum Behavior {
CAPITALIZE_AFTER_MARKER(0),
CAPITALIZE_BEFORE_MARKER(1),
CAPITALIZE_BEFORE_AND_AFTER_MARKER(2);
private int value;
private Behavior(int value) {
this.value = value;
}
public int getValue() {
return value;
}
}

Using org.apache.commons.lang.StringUtils makes it very simple.
capitalizeStr = StringUtils.capitalize(str);

From Java 9+
you can use String::replaceAll like this :
public static void upperCaseAllFirstCharacter(String text) {
String regex = "\\b(.)(.*?)\\b";
String result = Pattern.compile(regex).matcher(text).replaceAll(
matche -> matche.group(1).toUpperCase() + matche.group(2)
);
System.out.println(result);
}
Example :
upperCaseAllFirstCharacter("hello this is Just a test");
Outputs
Hello This Is Just A Test

With this simple code:
String example="hello";
example=example.substring(0,1).toUpperCase()+example.substring(1, example.length());
System.out.println(example);
Result: Hello

I'm using the following function. I think it is faster in performance.
public static String capitalize(String text){
String c = (text != null)? text.trim() : "";
String[] words = c.split(" ");
String result = "";
for(String w : words){
result += (w.length() > 1? w.substring(0, 1).toUpperCase(Locale.US) + w.substring(1, w.length()).toLowerCase(Locale.US) : w) + " ";
}
return result.trim();
}

Use the Split method to split your string into words, then use the built in string functions to capitalize each word, then append together.
Pseudo-code (ish)
string = "the sentence you want to apply caps to";
words = string.split(" ")
string = ""
for(String w: words)
//This line is an easy way to capitalize a word
word = word.toUpperCase().replace(word.substring(1), word.substring(1).toLowerCase())
string += word
In the end string looks something like
"The Sentence You Want To Apply Caps To"

This might be useful if you need to capitalize titles. It capitalizes each substring delimited by " ", except for specified strings such as "a" or "the". I haven't ran it yet because it's late, should be fine though. Uses Apache Commons StringUtils.join() at one point. You can substitute it with a simple loop if you wish.
private static String capitalize(String string) {
if (string == null) return null;
String[] wordArray = string.split(" "); // Split string to analyze word by word.
int i = 0;
lowercase:
for (String word : wordArray) {
if (word != wordArray[0]) { // First word always in capital
String [] lowercaseWords = {"a", "an", "as", "and", "although", "at", "because", "but", "by", "for", "in", "nor", "of", "on", "or", "so", "the", "to", "up", "yet"};
for (String word2 : lowercaseWords) {
if (word.equals(word2)) {
wordArray[i] = word;
i++;
continue lowercase;
}
}
}
char[] characterArray = word.toCharArray();
characterArray[0] = Character.toTitleCase(characterArray[0]);
wordArray[i] = new String(characterArray);
i++;
}
return StringUtils.join(wordArray, " "); // Re-join string
}

public static String toTitleCase(String word){
return Character.toUpperCase(word.charAt(0)) + word.substring(1);
}
public static void main(String[] args){
String phrase = "this is to be title cased";
String[] splitPhrase = phrase.split(" ");
String result = "";
for(String word: splitPhrase){
result += toTitleCase(word) + " ";
}
System.out.println(result.trim());
}

1. Java 8 Streams
public static String capitalizeAll(String str) {
if (str == null || str.isEmpty()) {
return str;
}
return Arrays.stream(str.split("\\s+"))
.map(t -> t.substring(0, 1).toUpperCase() + t.substring(1))
.collect(Collectors.joining(" "));
}
Examples:
System.out.println(capitalizeAll("jon skeet")); // Jon Skeet
System.out.println(capitalizeAll("miles o'Brien")); // Miles O'Brien
System.out.println(capitalizeAll("old mcdonald")); // Old Mcdonald
System.out.println(capitalizeAll(null)); // null
For foo bAR to Foo Bar, replace the map() method with the following:
.map(t -> t.substring(0, 1).toUpperCase() + t.substring(1).toLowerCase())
2. String.replaceAll() (Java 9+)
ublic static String capitalizeAll(String str) {
if (str == null || str.isEmpty()) {
return str;
}
return Pattern.compile("\\b(.)(.*?)\\b")
.matcher(str)
.replaceAll(match -> match.group(1).toUpperCase() + match.group(2));
}
Examples:
System.out.println(capitalizeAll("12 ways to learn java")); // 12 Ways To Learn Java
System.out.println(capitalizeAll("i am atta")); // I Am Atta
System.out.println(capitalizeAll(null)); // null
3. Apache Commons Text
System.out.println(WordUtils.capitalize("love is everywhere")); // Love Is Everywhere
System.out.println(WordUtils.capitalize("sky, sky, blue sky!")); // Sky, Sky, Blue Sky!
System.out.println(WordUtils.capitalize(null)); // null
For titlecase:
System.out.println(WordUtils.capitalizeFully("fOO bAR")); // Foo Bar
System.out.println(WordUtils.capitalizeFully("sKy is BLUE!")); // Sky Is Blue!
For details, checkout this tutorial.

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the sentence : ");
try
{
String str = br.readLine();
char[] str1 = new char[str.length()];
for(int i=0; i<str.length(); i++)
{
str1[i] = Character.toLowerCase(str.charAt(i));
}
str1[0] = Character.toUpperCase(str1[0]);
for(int i=0;i<str.length();i++)
{
if(str1[i] == ' ')
{
str1[i+1] = Character.toUpperCase(str1[i+1]);
}
System.out.print(str1[i]);
}
}
catch(Exception e)
{
System.err.println("Error: " + e.getMessage());
}

I decided to add one more solution for capitalizing words in a string:
words are defined here as adjacent letter-or-digit characters;
surrogate pairs are provided as well;
the code has been optimized for performance; and
it is still compact.
Function:
public static String capitalize(String string) {
final int sl = string.length();
final StringBuilder sb = new StringBuilder(sl);
boolean lod = false;
for(int s = 0; s < sl; s++) {
final int cp = string.codePointAt(s);
sb.appendCodePoint(lod ? Character.toLowerCase(cp) : Character.toUpperCase(cp));
lod = Character.isLetterOrDigit(cp);
if(!Character.isBmpCodePoint(cp)) s++;
}
return sb.toString();
}
Example call:
System.out.println(capitalize("An à la carte StRiNg. Surrogate pairs: 𐐪𐐪."));
Result:
An À La Carte String. Surrogate Pairs: 𐐂𐐪.

Use:
String text = "jon skeet, miles o'brien, old mcdonald";
Pattern pattern = Pattern.compile("\\b([a-z])([\\w]*)");
Matcher matcher = pattern.matcher(text);
StringBuffer buffer = new StringBuffer();
while (matcher.find()) {
matcher.appendReplacement(buffer, matcher.group(1).toUpperCase() + matcher.group(2));
}
String capitalized = matcher.appendTail(buffer).toString();
System.out.println(capitalized);

There are many way to convert the first letter of the first word being capitalized. I have an idea. It's very simple:
public String capitalize(String str){
/* The first thing we do is remove whitespace from string */
String c = str.replaceAll("\\s+", " ");
String s = c.trim();
String l = "";
for(int i = 0; i < s.length(); i++){
if(i == 0){ /* Uppercase the first letter in strings */
l += s.toUpperCase().charAt(i);
i++; /* To i = i + 1 because we don't need to add
value i = 0 into string l */
}
l += s.charAt(i);
if(s.charAt(i) == 32){ /* If we meet whitespace (32 in ASCII Code is whitespace) */
l += s.toUpperCase().charAt(i+1); /* Uppercase the letter after whitespace */
i++; /* Yo i = i + 1 because we don't need to add
value whitespace into string l */
}
}
return l;
}

package com.test;
/**
* #author Prasanth Pillai
* #date 01-Feb-2012
* #description : Below is the test class details
*
* inputs a String from a user. Expect the String to contain spaces and alphanumeric characters only.
* capitalizes all first letters of the words in the given String.
* preserves all other characters (including spaces) in the String.
* displays the result to the user.
*
* Approach : I have followed a simple approach. However there are many string utilities available
* for the same purpose. Example : WordUtils.capitalize(str) (from apache commons-lang)
*
*/
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Test {
public static void main(String[] args) throws IOException{
System.out.println("Input String :\n");
InputStreamReader converter = new InputStreamReader(System.in);
BufferedReader in = new BufferedReader(converter);
String inputString = in.readLine();
int length = inputString.length();
StringBuffer newStr = new StringBuffer(0);
int i = 0;
int k = 0;
/* This is a simple approach
* step 1: scan through the input string
* step 2: capitalize the first letter of each word in string
* The integer k, is used as a value to determine whether the
* letter is the first letter in each word in the string.
*/
while( i < length){
if (Character.isLetter(inputString.charAt(i))){
if ( k == 0){
newStr = newStr.append(Character.toUpperCase(inputString.charAt(i)));
k = 2;
}//this else loop is to avoid repeatation of the first letter in output string
else {
newStr = newStr.append(inputString.charAt(i));
}
} // for the letters which are not first letter, simply append to the output string.
else {
newStr = newStr.append(inputString.charAt(i));
k=0;
}
i+=1;
}
System.out.println("new String ->"+newStr);
}
}

Here is a simple function
public static String capEachWord(String source){
String result = "";
String[] splitString = source.split(" ");
for(String target : splitString){
result += Character.toUpperCase(target.charAt(0))
+ target.substring(1) + " ";
}
return result.trim();
}

This is just another way of doing it:
private String capitalize(String line)
{
StringTokenizer token =new StringTokenizer(line);
String CapLine="";
while(token.hasMoreTokens())
{
String tok = token.nextToken().toString();
CapLine += Character.toUpperCase(tok.charAt(0))+ tok.substring(1)+" ";
}
return CapLine.substring(0,CapLine.length()-1);
}

Reusable method for intiCap:
public class YarlagaddaSireeshTest{
public static void main(String[] args) {
String FinalStringIs = "";
String testNames = "sireesh yarlagadda test";
String[] name = testNames.split("\\s");
for(String nameIs :name){
FinalStringIs += getIntiCapString(nameIs) + ",";
}
System.out.println("Final Result "+ FinalStringIs);
}
public static String getIntiCapString(String param) {
if(param != null && param.length()>0){
char[] charArray = param.toCharArray();
charArray[0] = Character.toUpperCase(charArray[0]);
return new String(charArray);
}
else {
return "";
}
}
}

Here is my solution.
I ran across this problem tonight and decided to search it. I found an answer by Neelam Singh that was almost there, so I decided to fix the issue (broke on empty strings) and caused a system crash.
The method you are looking for is named capString(String s) below.
It turns "It's only 5am here" into "It's Only 5am Here".
The code is pretty well commented, so enjoy.
package com.lincolnwdaniel.interactivestory.model;
public class StringS {
/**
* #param s is a string of any length, ideally only one word
* #return a capitalized string.
* only the first letter of the string is made to uppercase
*/
public static String capSingleWord(String s) {
if(s.isEmpty() || s.length()<2) {
return Character.toUpperCase(s.charAt(0))+"";
}
else {
return Character.toUpperCase(s.charAt(0)) + s.substring(1);
}
}
/**
*
* #param s is a string of any length
* #return a title cased string.
* All first letter of each word is made to uppercase
*/
public static String capString(String s) {
// Check if the string is empty, if it is, return it immediately
if(s.isEmpty()){
return s;
}
// Split string on space and create array of words
String[] arr = s.split(" ");
// Create a string buffer to hold the new capitalized string
StringBuffer sb = new StringBuffer();
// Check if the array is empty (would be caused by the passage of s as an empty string [i.g "" or " "],
// If it is, return the original string immediately
if( arr.length < 1 ){
return s;
}
for (int i = 0; i < arr.length; i++) {
sb.append(Character.toUpperCase(arr[i].charAt(0)))
.append(arr[i].substring(1)).append(" ");
}
return sb.toString().trim();
}
}

Here we go for perfect first char capitalization of word
public static void main(String[] args) {
String input ="my name is ranjan";
String[] inputArr = input.split(" ");
for(String word : inputArr) {
System.out.println(word.substring(0, 1).toUpperCase()+word.substring(1,word.length()));
}
}
}
//Output : My Name Is Ranjan

For those of you using Velocity in your MVC, you can use the capitalizeFirstLetter() method from the StringUtils class.

String s="hi dude i want apple";
s = s.replaceAll("\\s+"," ");
String[] split = s.split(" ");
s="";
for (int i = 0; i < split.length; i++) {
split[i]=Character.toUpperCase(split[i].charAt(0))+split[i].substring(1);
s+=split[i]+" ";
System.out.println(split[i]);
}
System.out.println(s);

package corejava.string.intern;
import java.io.DataInputStream;
import java.util.ArrayList;
/*
* wap to accept only 3 sentences and convert first character of each word into upper case
*/
public class Accept3Lines_FirstCharUppercase {
static String line;
static String words[];
static ArrayList<String> list=new ArrayList<String>();
/**
* #param args
*/
public static void main(String[] args) throws java.lang.Exception{
DataInputStream read=new DataInputStream(System.in);
System.out.println("Enter only three sentences");
int i=0;
while((line=read.readLine())!=null){
method(line); //main logic of the code
if((i++)==2){
break;
}
}
display();
System.out.println("\n End of the program");
}
/*
* this will display all the elements in an array
*/
public static void display(){
for(String display:list){
System.out.println(display);
}
}
/*
* this divide the line of string into words
* and first char of the each word is converted to upper case
* and to an array list
*/
public static void method(String lineParam){
words=line.split("\\s");
for(String s:words){
String result=s.substring(0,1).toUpperCase()+s.substring(1);
list.add(result);
}
}
}

If you prefer Guava...
String myString = ...;
String capWords = Joiner.on(' ').join(Iterables.transform(Splitter.on(' ').omitEmptyStrings().split(myString), new Function<String, String>() {
public String apply(String input) {
return Character.toUpperCase(input.charAt(0)) + input.substring(1);
}
}));

String toUpperCaseFirstLetterOnly(String str) {
String[] words = str.split(" ");
StringBuilder ret = new StringBuilder();
for(int i = 0; i < words.length; i++) {
ret.append(Character.toUpperCase(words[i].charAt(0)));
ret.append(words[i].substring(1));
if(i < words.length - 1) {
ret.append(' ');
}
}
return ret.toString();
}