This question already has an answer here:
Rounding BigDecimal to *always* have two decimal places
(1 answer)
Closed 6 years ago.
This:
BigDecimal.valueOf(0.00)
becomes 0.0
I want it to be 0.00
What is the correct format pattern for that?
Use the String constructor: new BigDecimal("0.00"). Using BigDecimal.valueOf(double) completely destroys any formatting you used to input the value.
Try this
value = value.setScale(2, RoundingMode.CEILING)
Related
This question already has answers here:
Java BigDecimal remove decimal and trailing numbers
(6 answers)
Closed 6 years ago.
I have a BigDecimal number, I just want to remove the decimal numbers from it,
for example if I have 200.88 then output should be 200?
I tried Bigdecimal rounding function but they wont do the job
You can specify the rounding mode to ROUND_FLOOR when you use round.
This question already has answers here:
How do I print a double value without scientific notation using Java?
(18 answers)
Closed 6 years ago.
I need to convert string value to double with dot. Here is simple code
double dValue=Double.parseDouble("999999999.99");
System.out.println(dValue);
output is: 9.9999999999E8
When i gave value like 10000 or 100000 it works. Help me to overcome this problem.
You could use BigDecimal and toPlainString() for that.
BigDecimal dValue= new BigDecimal("999999999.99");
System.out.println(dValue.toPlainString());
Output:
999999999.99
You can use String.format
System.out.println(String.format("%.2f", dValue));
This question already has answers here:
How many significant digits do floats and doubles have in java?
(6 answers)
Closed 7 years ago.
I have a problem when it comes to calculating pi with more than 15 decimal places(i used double).
My result looks quite good except my variable is limited to 15 decimal places:
3.140592653839794
Anybody could tell me what i have to do if i want more decimal places?
Thanks and Greeting!
Use java.math.BigDecimal instead of double for arbitrary (finite) precision.
This question already has answers here:
How can I handle precision error with float in Java?
(9 answers)
Closed 8 years ago.
some calculations with doubles return the wrong result.
E.g.
System.out.println(""+(0.05+0.01));
output
0.060000000000000005
What can I do to correct this error?
Doubles are not made for precise calculations (see Round to 2 decimal places) - for precise calculations, use BigDecimal instead.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
How to round a number to n decimal places in Java
I am trying to format a string that is used as currency to two decimal places. For example, if they enter 100, it will format it to 100.00, and if they enter 100.5, it will be formatted to 100.50. What would be the best way to go about this?
You can use DecimalFormat:
new DecimalFormat("###0.00").format(...);
Other constructors of DecimalFormat introduces support to Locale.