How to join entity by id - java

Could you help me solve a small question?
It's about the project with Spring Data, JPA and Hibernate.
I have 2 entities and I need to join one to another. Yes, it sounds simple :)
First is Activity:
public class Activity {
...
#Column(name="STATUS_ID")
private String statusId;
...
}
Second is Vocab Value (Users can administer it as a simple list of values):
public class VocabValue {
...
// Type of vocab (in our case - 'ACT_STAT')
#Column(name="TYPE")
private String type;
// Name - code of Vocab value
#Column(name="NAME")
private String type;
// Value
#Column(name="VAL")
private String value;
...
}
In my case, I want to store in an Activity a name of Vocab Value and join it.
In the target state, my entity should look like:
public class Activity {
...
#Column(name="STATUS_ID")
private String statusId;
#... what?
private String status;
// Getter returns Vocab Value in accordance with the following join spec (pseudo-sql):
// select voc.value from VocabValue voc where voc.name = %statusId% and type = 'ACT_STAT'
public String getStatus() {
}
...
}
How should I configure my Activity entity to provide this?
Ok, Is it possible?
I'll be grateful for your advice!
Thank!
Update 13.01
I've tried this solution:
public class Activity {
...
#Column(name="STATUS_ID")
private String statusId;
#JoinColumn(name = "STATUS_ID", referencedColumnName = "NAME", insertable = false, updatable = false)
#Where(clause = "type = 'ACT_STAT'")
#ManyToOne(optional = true)
#NotFound(action = NotFoundAction.IGNORE)
private VocabValue status;
...
}
Moreover, I had to make VocabValue implementation of Serializable (VocabValue as Detached entity should be implemetation of Serializable interface in accordance with Hibernate spec).
public VocabValue implemets Serializable {...}
It works, but annotation #Where doesn't work: Join performed only with #JoinColumn specification, an additional criteria, defined in #Where clause doesn't apply.
Whether there are workarounds?
UPDATE 13.01 - 2
It was solved with following configuration:
#JoinFormula(value="SELECT v.ROW_ID FROM VOCAB v WHERE v.NAME=STATUS_ID AND v.TYPE='ACT_STAT'")
#ManyToOne
#NotFound(action = NotFoundAction.IGNORE)
private VocabValue status;
Thanks!)

It was solved with following configuration:
#JoinFormula(value="SELECT v.ROW_ID FROM VOCAB v WHERE v.NAME=STATUS_ID AND v.TYPE='ACT_STAT'")
#ManyToOne
#NotFound(action = NotFoundAction.IGNORE)
private VocabValue status;
Thank's )

Related

Hibernate #Where annotation on a ManyToOne relation

I have recently started to refactor my project because I had to add an extra column to some of my table. The extra column is an Enum (Pending, or Active).
Because of that change I would need now to refactor ALL my queries to only retrieves a row if the status is ACTIVE.
After some research I found that we can annotate an Entity with the #Where annotation. it works fine where I use it on a simple column but my table look like this:
#Where(clause = 'state='ACTIVE'")
#Entity
public class Place {
#Column(name="id_place")
private String placeId;
#Column(name="name")
private String palceName;
#OneToMany(mappedBy = "place")
private Set<PlaceTag> placeTag;
...
...
}
#Where(clause = 'state='ACTIVE'")
#Entity
public class Tag {
#Column(name="id_tag")
private String tagId;
#Column(name="name")
private String tagName;
#OneToMany(mappedBy = "tag")
private Set<PlaceTag> placeTag;
...
...
}
#Where(clause = 'poi.state='ACTIVE' AND tag.state='ACTIVE")
#Entity
public class PlaceTag {
#Column(name="id")
private String id;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY)
#JoinColumn(name = "place_id")
private Place place;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY)
#JoinColumn(name = "tag_id")
private Tag tag;
...
...
}
Now my question would be how can make this statement ONLY return the places and tags that are ACTIVE ?
SELECT pt FROM PlaceTag pt;
Is this possible? Or will I have to write the query Explicitly ?
Thank you
As you already discovered, or simply use cases the #Where clause is just fine, but in your case, you want to filter PlaceTag by the place and tag too, so a joined is required in this situation.
So, you can keep the #Where clause for Place and Tag, while for PlaceTags you need to use a JPQL query:
select pt
from PlaceTag pt
join pt.tag t
join pt.place p
where
t.state='ACTIVE' and p.state='ACTIVE'
At least until #WhereJoinTable annotation is made to work for many-to-one associations too.

JPA 2 Hibernate mapping with composite key in primary key using #IdClass with 3 tier structure

This question is very similar to: JPA (Hibernate, EclipseLink) mapping: why doesn't this code work (chain of 2 relationships using JPA 2.0, #EmbeddedId composite PK-FK)?
Actually my only (from meaningful that I spotted) difference is that I use #IdClass and that I most probably won't be able to switch to a different provider than hibernate.
but anyway here is the code (removed parts that where unimportant):
PermissionContextType.java:
#Entity
#IdClass(PermissionContextTypePk.class)
public class PermissionContextType{
#Id
private String id;
#Id
#JoinColumn (name = "PROJECT", referencedColumnName = "ID")
#ManyToOne ()
private Project project;
public static class PermissionContextTypePk implements Serializable{
public String project;
public String id;
// ... eq and hashCode here ...
}
}
PermissionContext.java:
#Entity
#IdClass(PermissionContextPk.class)
public class PermissionContext{
#Id
private String id;
#Id
#JoinColumns ({
#JoinColumn (name = "PROJECT", referencedColumnName = "PROJECT"),
#JoinColumn (name = "PERMISSIONCONTEXTTYPE", referencedColumnName = "ID")
})
#ManyToOne
private PermissionContextType permissionContextType;
public static class PermissionContextPk implements Serializable{
public String id;
public PermissionContextTypePk permissionContextType;
// ... eq and hashCode here ...
}
}
Permission.java:
#Entity
#IdClass(PermissionPk.class)
public class Permission{
#Id
private String id;
#Id
#JoinColumns ({
#JoinColumn (name = "PROJECT", referencedColumnName = "PROJECT"),
#JoinColumn (name = "PERMISSIONCONTEXTTYPE", referencedColumnName = "PERMISSIONCONTEXTTYPE"),
#JoinColumn (name = "PERMISSIONCONTEXT", referencedColumnName = "ID")
})
#ManyToOne
private PermissionContext permissionContext;
public static class PermissionPk implements Serializable{
public String id;
public PermissionContextPk permissionContext;
// ... eq and hashCode here ...
}
}
and what I get is:
org.hibernate.AssertionFailure: Unexpected nested component on the referenced entity when mapping a #MapsId: PermissionContext
Caused by: org.hibernate.AssertionFailure: org.hibernate.AssertionFailure: Unexpected nested component on the referenced entity when mapping a #MapsId: PermissionContext
does anybody know if this is a hibernate bug and I should post it on their issue tracking system (and pray that I would be able to update to given hibernate version) or is there something fundamentally wrong with my way of binding the entities?
I've checked it with the hibernate implementation on EAP 6.1 (4.2.0) as well as on wildfly (don't really know which one.)
Ok, so this is what I found so far :
Thanks fr my friend : https://hibernate.atlassian.net/browse/HHH-5764 which most probably is the reason for this behaviour.
And I found a workaround :
Permission.java:
#Entity
#IdClass(PermissionPk.class)
public class Permission{
#Id
private String id;
// for the next 3 fields there are no public acessors, so the public API of the class was not changed !
#Id
#Column(name = "PROJECT")
private String projectId;
#Id
#Column(name = "PERMISSIONCONTEXTTYPE")
private String permissionContextTypeId;
#Id
#Column(name = "PERMISSIONCONTEXT")
private String permissionContextId;
#JoinColumns ({
#JoinColumn (name = "PROJECT", referencedColumnName = "PROJECT", updatable = false, insertable = false),
#JoinColumn (name = "PERMISSIONCONTEXTTYPE", referencedColumnName = "PERMISSIONCONTEXTTYPE", updatable = false, insertable = false),
#JoinColumn (name = "PERMISSIONCONTEXT", referencedColumnName = "ID", updatable = false, insertable = false)
})
#ManyToOne
private PermissionContext permissionContext;
public static class PermissionPk implements Serializable{
// previously they where private as well, but removed public constructor for the sake of simplicity of the question - so no changes where necesary in public API of the class !
private String id;
private String projectId;
private String permissionContextTypeId;
private String permissionContextId;
public PermissionPk () {}
public PermissionPk (String aId, PermissionContextPk aPermissionContext) {
this.id = aId;
permissionContextId = aPermissionContext.id;
permissionContextTypeId = aPermissionContext.permissionContextType.id;
projectId = aPermissionContext.permissionContextType.project;
}
... eq and hashCode here ...
}
}
The good thing about this workaround is that it does not change the public API of the class in any way
(the only change was that I needed to make fields in Pk's of context and contexttype visible to the PermissionPk - they where private before with only a public constructor [but again simplified for the question]), nor did it change the jpql queries, and at the same time workaround is scalable (to any tier amount - as long as every even pk does not contain another pk), so if the bug will be resolved it will be easy to remove the workaround.
I would still gladly accept any comments on either my workaround or the question in itself.
Today I found another workaround :)
You can omit #IdClass entirely and use hibernate specific ability to create composite keys on the fly as apparently it is not affected by this bug.
The drawback here is that:
it is entirely Hibernate specific not covered by JPA at all.
you cannot do em.find(ClassName.class,new ClassPk(args...)) as there is no ClassPk at all.
But if you could use anything else than hibernate you could just as well use something without this bug - so probably 1 is not a problem really. and there is a possibility that you don't really need the em.find for this entity (or can live with creating it thru session or jpql query).

PersistenceException, Column 'id' specified twice

I have the following files in Play Framework 2.2.3
Controller:
public class Comment extends Controller
{
public Result create(UUID id)
{
models.blog.Blog blog = models.blog.Blog.finder.byId(id);
Result result;
if(blog == null)
{
result = notFound(main.render("404", error404.render()));
}
else
{
Form<models.blog.Comment> commentForm = Form.form(models.blog.Comment.class);
commentForm = commentForm.bindFromRequest();
if(commentForm.hasErrors())
{
result = badRequest(Json.toJson(commentForm));
}
else
{
models.blog.Comment comment = commentForm.get();
comment.setId(UUID.randomUUID());
comment.setTimeCreated(new Date());
comment.setBlogId(blog.getId());
comment.save();
result = ok(Json.toJson(comment));
}
}
return result;
}
}
And two models
#Entity
#Table(name="blog")
public class Blog extends Model
{
private static final SimpleDateFormat MONTH_LITERAL = new SimpleDateFormat("MMMMM"),
DAY_NUMBER = new SimpleDateFormat("d"),
YEAR_NUMBER = new SimpleDateFormat("yyyy");
public static Finder<UUID, Blog> finder = new Finder<UUID, Blog>(UUID.class, Blog.class);
#Id
#Column(name="id",length=36, nullable=false)
public UUID id;
#OneToOne
#JoinColumn(name="author_id")
public User author;
#Column(name="title",length=255)
public String title;
#Column(name="summary",length=255)
public String summary;
#Column(name="url",length=255)
public String url;
#Column(name="content")
public String content;
#Column(name="time_updated")
public Date time_created;
#Column(name="time_created", nullable=false)
public Date time_updated;
#OneToMany(cascade = CascadeType.ALL)
#JoinColumn(name="blog_id")
public List<Comment> comments;
#ManyToMany(cascade = CascadeType.ALL)
#JoinTable(
name="blog_tag_map",
joinColumns={ #JoinColumn(name="blog_id", referencedColumnName="id") },
inverseJoinColumns={ #JoinColumn(name="tag_id", referencedColumnName="id") }
)
public List<Tag> tags;
public List<Comment> getComments()
{
return this.comments;
}
}
#Entity
#Table(name="blog_comment")
public class Comment extends Model
{
private static final SimpleDateFormat MONTH_LITERAL = new SimpleDateFormat("MMMMM"),
DAY_NUMBER = new SimpleDateFormat("d"),
YEAR_NUMBER = new SimpleDateFormat("yyyy");
#Id
#Column(name="id",length=36, nullable=false)
public UUID id;
#Column(name="blog_id", length=36)
public UUID blog_id;
#ManyToOne
public Blog blog;
#Column(name="content", length=500)
public String content;
#Column(name="website", length=255)
public String website;
#Column(name="name", length=255)
public String name;
#Column(name="time_created", updatable=false)
public Date time_created;
}
I have excluded some setters and getters from these models for brevity, so it doesn't clog up this post.
When I attempt to make a POST request to the aforementioned controller, everything goes fine until I get to the "comment.save()" statement in the controller file, then I get the following error.
I'm unsure why this save isn't going through, and why there is a column conflict.
Help much appreciated
The issue lies in the fact that you have defined basically two foreign key columns for Blog in your Comment's entity:
#Column(name = "blog_id", length = 36)
public UUID blog_id;
#ManyToOne
public Blog blog;
The default column name for your 'blog' field is: blog_id
However, you've already named your 'blog_id' column that.
Interestingly, no error/warning is thrown when creating this table...
So when you call comment.save(), the following insert statement is generated:
insert into blog_comment (id, blog_id, content, website, name, time_created, blog_id) values (?,?,?,?,?,?,?)
Notice a reference to 'blog_id' column twice, which is invalid.
And this is because of the above double mapping.
To fix, just give your 'blog' property a different name to use for the foreign key column:
#Column(name = "blog_id", length = 36)
public UUID blog_id;
#ManyToOne
#JoinColumn(name = "blogId")
public Blog blog;
I'm not sure why you're mapping your entities like this (perhaps legacy schema?) but the 'blog_id' fields seem to be redundant (and confusing) as you already have an entity mapping in the form of your 'blog' property.
This question is pretty old, but for any future reference i have found this answer that solved my problem.
After numerous searchers around the web I found this answer here - thanks to jtal!
Just to summaries the problem:
Using Ebean i have made a #ManyToOne entity that is not implemented in the database in anyway,
even more the join field, in your case
blogId
is a valid field that has values of its own.
when trying to join the column on that field, it will always fail because it creates this sql query:
SELECT
*
FROM
blog_comment;
select
t0.id c0,
t0.blog_id c1,
t0.content c2,
t0.website c3,
t0.time_created c4,
t0.blog_id c5 <---- notice this duplicate
from
blog_comment t0
in order to solve this, i tell ebean not to use the second set of properties.
your new ebean element should look something like this:
#ManyToOne
#JoinColumn(name = "blogId", insertable = false, updatable = false)
public Blog blog;
hope this helps! =)

JPA - Using composite PK's and FK's and defining relationships

I got these 2 entities:
#javax.persistence.Entity
public class Book {
#javax.persistence.EmbeddedId
private BookPK id;
private String title;
#javax.persistence.ManyToOne(fetch = javax.persistence.FetchType.LAZY)
#javax.persistence.JoinColumns({
#javax.persistence.JoinColumn(name = "LNGCOD", referencedColumnName = "LNGCOD"),
#javax.persistence.JoinColumn(name = "LIBCOD", referencedColumnName = "LIBCOD") })
private Language language;
}
#javax.persistence.Entity
public class Language {
#javax.persistence.EmbeddedId
private LanguagePK id;
private String name;
}
with composed PK's:
#Embeddable
public class BookPK implements Serializable {
private Integer bookcod;
private Integer libcod;
}
#Embeddable
public class LanguagePK implements Serializable {
private Integer lngcod;
private Integer libcod;
}
If I try to create a new Book and persist it, I get an exception telling me libcod is found twice in the insert statement ("Column 'libcod' specified twice"). But I can't use "insertable = false" when defining the JoinColumn ("Mixing insertable and non insertable columns in a property is not allowed").
Is there any way to define these objects + relationship so the columns are managed automatically by Hibernate ? (I am especially thinking of libcod).
Thank you.
Create a third property "Integer libcod;" on the Book. Have that property manage the db state of libcod. Use insertable=false,updatable=false for both properties in the join to Language. in your "setLanguage" set the private libcod = language.libcod. don't expose a getter/setter for the private libcod.
Are any of the values generated at insert time? This could complicate things further, I suppose.

How to delete Hibernate #Embeddables containing nullable fields?

When deleting an #Embeddable object, I run into some problems.
I have the following domain classes: SwitchVoipTrunkGroup and PrioritizedCodec. The latter contains several fields that are nullable.
class SwitchVoipTrunkGroup {
//...
#CollectionOfElements(fetch = FetchType.LAZY)
#JoinTable(
name = "SWITCH_VOIP_TKG_CODEC",
joinColumns = #JoinColumn(name = "FK_SWITCH_VOIP_TKG_ID")
)
#ForeignKey(name = "FK_CODEC_SWITCH_VOIP_TKG")
private Set<PrioritizedCodec> prioritizedCodecs = new HashSet<PrioritizedCodec>();
//...
}
#Embeddable
public class PrioritizedCodec {
#Column(name = "PRIORITY")
private String priority;
#Column(name = "FAX_MODE")
private String faxMode;
//... some more columns ...
}
When I edit SwitchVoipTrunkGroup's prioritizedCodecs field (e.g. by deleting an entry) and save the entity, I see the following in my Hibernate logging:
13:54:31,919 INFO [STDOUT] Hibernate: delete from T_SWITCH_VOIP_TKG_CODEC where
fk_switch_voip_tkg_id=? and fax_mode=? and priority=?
From this question I understand why Hibernate uses all the fields in the where clause. However, this gives problems: in case some of these fields are empty, the query will look like so:
delete from T_SWITCH_VOIP_TKG_CODEC where fk_switch_voip_tkg_id=1 and fax_mode = ''
and priority =''
This will however not delete any records, as what is really necessary is for Hibernate to check for NULL iso for an empty string. For example:
delete from T_SWITCH_VOIP_TKG_CODEC where fk_switch_voip_tkg_id=1 and fax_mode
IS NULL and priority IS NULL
(cf. here for more info on why checking for an empty string does not suffice)
Any ideas on how to tackle this? Many thx!
I suggest to normalize your database, so both your classes become entities, and then to setup One-to-Many relation between SwitchVoipTrunkGroup and PrioritizedCodec, then you may setup cascading rules so Hibernate automatically updates collection of elements of PrioritizedCodec type, when you persist instance of SwitchVoipTrungGroup.
#Entity
class SwitchVoipTrunkGroup {
//...
#OneToMany(cascade = {CascadeType.MERGE, CascadeType.PERSIST}, orphanRemoval = true)
#JoinColumn(name = "switchVoipTrunkGroup_id")
#ForeignKey(name = "FK_PrioritizedCodec_SwitchVoipTrunkGroup")
private Set<PrioritizedCodec> prioritizedCodecs = new HashSet<PrioritizedCodec>();
//...
}
#Entity
public class PrioritizedCodec {
#Column(name = "PRIORITY")
private String priority;
#Column(name = "FAX_MODE")
private String faxMode;
//... some more columns ...
}
#Serice("someService")
public class SomeService {
#Autowired
private SwitchVoipTrunkGroupDao trunkDao;
public SwitchVoipTrunkGroup doOperation("criteria") {
SwitchVoipTrunkGroup tg = trunkDao.find("criteroa");
tg.getPrioritizedCodecs().[remove(2)]; //remove should be implemened, that is just lame statement
tg.getPrioritizedCodecs().get(5).setFaxMod("ENABLED");
return trunkDao.save(tg); //hibernate will remove missing elements from PrioritizedCodec table, and will update necessary entities.
}
}
Alternatively, you may specify default values for priority and faxMode fields via attributes of #Column annotation and enforce nullable constraints
#Column(columnDefinition = "VARCHAR(20) default 'NONE'", nullable = false)
private String faxMode;

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