Develop Reference

Selenium replace value for the input field with sendKeys() method

I have an unexpected issue with the sendKeys() method:
A long time before it all worked fine, but unexpectedly the (certain(!)) values are replaced when the code tries to set data into the input field:
For example, if I set value USER_NAME into the field, value replaced with /tmp/7d7b7...../upload123...file/USER_NAME. As we can see - some path was added into the USER_NAME value.
I added logs to the method and we can see a moment when the value was replaced:
clearInputFld(inputFld);
Log.info("INSIDE clearAndTypeIntoInputField() ---------> value after clearing: " + inputElement.getAttribute("value"));
Log.info("INSIDE clearAndTypeIntoInputField() ---------> value to set: " + value);
inputElement.sendKeys(value);
Log.info("INSIDE clearAndTypeIntoInputField() ---------> value after set: " + inputElement.getAttribute("value"));
Output:
INSIDE clearAndTypeIntoInputField() ---------> value after clearing:
INSIDE clearAndTypeIntoInputField() ---------> value to set: USER_NAME
INSIDE clearAndTypeIntoInputField() ---------> value after set: /tmp/7d7b7...../upload123...file/USER_NAME
So we can be sure - value sets exactly at the moment when value sets into the field.
Important to know, and conclusions:
Not all users replaced - Only several certain users! So I suppose a part of users is cached. But I do not understand the process with which this happens, why this happens, and where these users might be cached.
I also restarted the docker, so it seems the problem is not in the automatic side.
Is it possible that this issue occurs via the backend or UI part?

It looks like there is a script running on the page that changes the input you type, as this is a password field.
What I suggest is that you use the Robot object to mimic keyboard strokes.
First click on the text field using Selenium, then launch the Robot code (use package Java.awt):
Robot robot = null;
try {
robot = new Robot();
for (char c : textToType.toCharArray()) {
int keyCode = KeyEvent.getExtendedKeyCodeForChar(c);
if (KeyEvent.CHAR_UNDEFINED == keyCode) {
logger.error("Key code not found for character '" + c + "'");
} else {
try {
robot.keyPress(keyCode);
robot.delay(10);
robot.keyRelease(keyCode);
robot.delay(10);
} catch (Exception e) {
if (c == '_') {
robot.keyPress(KeyEvent.VK_SHIFT);
robot.keyPress(KeyEvent.VK_MINUS);
robot.keyRelease(KeyEvent.VK_MINUS);
robot.keyRelease(KeyEvent.VK_SHIFT);
}
if (c == ':') {
robot.keyPress(KeyEvent.VK_SHIFT);
robot.keyPress(KeyEvent.VK_SEMICOLON);
robot.keyRelease(KeyEvent.VK_SEMICOLON);
robot.keyRelease(KeyEvent.VK_SHIFT);
}
}
}
}
robot.keyPress(KeyEvent.VK_ENTER);
} catch (Exception ex) {
logger.error(ex.getMessage());
}

According to Logs, I think there is something come with the value.
Suggest trying :
Get the changed text, do some operation, fill it back
string[] temp;
temp = (inputElement.Text).Split('/');
inputElement.Sendkeys(temp(temp.Length - 1));

blank number field causing fatal exception even if checked

I'm trying to make sure when you forget to enter a number that my app won't crash, I have a text field called
edit that only accepts numbers, I am getting this error when i test what happens if you don't enter anything in the text field, which is a numeric text field and only brings up the number keyboard on your device, so you cant enter text at all just numbers
can anyone tell me what I'm doing wrong?
this is the error message:
FATAL EXCEPTION: main
Process: com..rhgtimecard, PID: 27379
java.lang.NumberFormatException: Invalid int: ""
at com..rhgtimecard.TimeIn$2.onClick(TimeIn.java:478)
And this is the related code block
if (login == 1) {
int getemn = 0;
if (!edit.equals("")) {//**if you didn't enter anything but pressed set anyway this should stop the rest of the code block.
//I tried setting this to if (edit != null) didn't work either, tried setting this to if (!edit.equals()) but it wont
//compile like that at all**
getemn = Integer.parseInt(edit.getText().toString());//**this is line 478 that throws the fatal exception error**
String getemp = edit2.getText().toString();
String allpass = "Passwords";
SharedPreferences loadPass = getSharedPreferences(allpass, MODE_PRIVATE);
String empStrng = String.valueOf(getemn);
String passes = "pass";
if (getemn < 13) {
passes = "pass" + empStrng;
g.setData4(getemn, loadPass.getString(passes, "0123"));
}
String[] pass = g.getData4();
if (i == 0 && getemp.equals(pass[getemn])) {
g.setData3(getemn);
Logscript();
}
if (i == 0 && !(getemp.equals(pass[getemn]))) {
tfone.setText("No matches found");
tftwo.setText("Enter password");
edit2.setText("");
i = 1;
}
}
}
can anyone tell me where I went wrong here or how to actually check if someone entered a number?

Try this:
if(!edit.getText().toString().equals(""))

if (!edit.equals(""))
This is the line probably you should be changing to:
if(!edit.getText().toString().equals(""))
Right now you are checking if the actual object of edit equals the blank number, not the text of the edit box.
If you are setting the integer to 0 by default, you could do something like this:
getemn = Integer.parseInt(edit.getText().toString().equals("") ? "0" : edit.getText.toString() );

Add this property to EditText in XML file
android:inputType="number"
And in Java :
if(!editText.getText().toString()isEmpty()){
//Your content here
}

Trying to get program to repeat

The program checks to see if the email address entered contains a # and a .edu
if it doesn't it needs to go back through the steps, I think I can use a do-while,but I haven't got one to work yet, how would I nest my if-else statements in a do-while? Thanks!
if (UserEmail.contains("#")) {
if (UserEmail.contains(".edu")){
System.out.print("Please create a password: ");
PassWord = kb.nextLine();
System.out.println(UserEmail.replaceAll("#\\S+?\\.edu\\b", ""));
System.out.print("Your password is " + PassWord);
} else {
System.out.print("email is not valid Please, try again.")
} else {
System.out.print("email is not valid Please, try again.");
// at this point it should repeat and ask for the email again
}
}

Define method isValid(String email, String password,... some more params) aand put all your check logic in the method.
Write something like this
while (!isValid(the params)) {
//ask all the credentials
}

to simplify your if-else code consider using
if (UserEmail.contains("#") && UserEmail.contains(".edu")) {
.
.
}
this can be wrappped in a do - while
do {
if (UserEmail.contains("#") && UserEmail.contains(".edu")) {
.
.
break;
}
System.out.print("email is not valid Please, try again.")
}
while (true);

You can simply add something like boolean correctEmail = false before your logic and at the beginning of your if statements, you write while(!correctEmail) {
At the end of your password-creation you set correctEmail to true and you're ready to go.

It is pretty straight forward.
bool trigger = (true/false);
do {
if (...) {
if (...){...}
else if (...) {...}
else {
print out retry statement;
trigger = false;
}
}
}
while (trigger == true);
Don't forget a semicolon at the end.

Get Android Device Name

How to get Android device name? I am using HTC desire. When I connected it via HTC Sync the software is displaying the Name 'HTC Smith' . I would like to fetch this name via code.
How is this possible in Android?

In order to get Android device name you have to add only a single line of code:
android.os.Build.MODEL;
Found here: getting-android-device-name

You can see answers at here Get Android Phone Model Programmatically
public String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return capitalize(model);
} else {
return capitalize(manufacturer) + " " + model;
}
}
private String capitalize(String s) {
if (s == null || s.length() == 0) {
return "";
}
char first = s.charAt(0);
if (Character.isUpperCase(first)) {
return s;
} else {
return Character.toUpperCase(first) + s.substring(1);
}
}

I solved this by getting the Bluetooth name, but not from the BluetoothAdapter (that needs Bluetooth permission).
Here's the code:
Settings.Secure.getString(getContentResolver(), "bluetooth_name");
No extra permissions needed.

On many popular devices the market name of the device is not available. For example, on the Samsung Galaxy S6 the value of Build.MODEL could be "SM-G920F", "SM-G920I", or "SM-G920W8".
I created a small library that gets the market (consumer friendly) name of a device. It gets the correct name for over 10,000 devices and is constantly updated. If you wish to use my library click the link below:
AndroidDeviceNames Library on Github
If you do not want to use the library above, then this is the best solution for getting a consumer friendly device name:
/** Returns the consumer friendly device name */
public static String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return capitalize(model);
}
return capitalize(manufacturer) + " " + model;
}
private static String capitalize(String str) {
if (TextUtils.isEmpty(str)) {
return str;
}
char[] arr = str.toCharArray();
boolean capitalizeNext = true;
String phrase = "";
for (char c : arr) {
if (capitalizeNext && Character.isLetter(c)) {
phrase += Character.toUpperCase(c);
capitalizeNext = false;
continue;
} else if (Character.isWhitespace(c)) {
capitalizeNext = true;
}
phrase += c;
}
return phrase;
}
Example from my Verizon HTC One M8:
// using method from above
System.out.println(getDeviceName());
// Using https://github.com/jaredrummler/AndroidDeviceNames
System.out.println(DeviceName.getDeviceName());
Result:
HTC6525LVW
HTC One (M8)

Try it. You can get Device Name through Bluetooth.
Hope it will help you
public String getPhoneName() {
BluetoothAdapter myDevice = BluetoothAdapter.getDefaultAdapter();
String deviceName = myDevice.getName();
return deviceName;
}

You can use:
From android doc:
MANUFACTURER:
String MANUFACTURER
The manufacturer of the product/hardware.
MODEL:
String MODEL
The end-user-visible name for the end product.
DEVICE:
String DEVICE
The name of the industrial design.
As a example:
String deviceName = android.os.Build.MANUFACTURER + " " + android.os.Build.MODEL;
//to add to textview
TextView textView = (TextView) findViewById(R.id.text_view);
textView.setText(deviceName);
Furthermore, their is lot of attribute in Build class that you can use, like:
os.android.Build.BOARD
os.android.Build.BRAND
os.android.Build.BOOTLOADER
os.android.Build.DISPLAY
os.android.Build.CPU_ABI
os.android.Build.PRODUCT
os.android.Build.HARDWARE
os.android.Build.ID
Also their is other ways you can get device name without using Build class(through the bluetooth).

Following works for me.
String deviceName = Settings.Global.getString(.getContentResolver(), Settings.Global.DEVICE_NAME);
I don't think so its duplicate answer. The above ppl are talking about Setting Secure, for me setting secure is giving null, if i use setting global it works. Thanks anyways.

universal way to get user defined DeviceName working for almost all devices and not requiring any permissions
String userDeviceName = Settings.Global.getString(getContentResolver(), Settings.Global.DEVICE_NAME);
if(userDeviceName == null)
userDeviceName = Settings.Secure.getString(getContentResolver(), "bluetooth_name");

Try this code. You get android device name.
public static String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return model;
}
return manufacturer + " " + model;
}

#hbhakhra's answer will do.
If you're interested in detailed explanation, it is useful to look into Android Compatibility Definition Document. (3.2.2 Build Parameters)
You will find:
DEVICE - A value chosen by the device implementer containing the
development name or code name identifying the configuration of the
hardware features and industrial design of the device. The value of
this field MUST be encodable as 7-bit ASCII and match the regular
expression “^[a-zA-Z0-9_-]+$”.
MODEL - A value chosen by the device implementer containing the name
of the device as known to the end user. This SHOULD be the same name
under which the device is marketed and sold to end users. There are no
requirements on the specific format of this field, except that it MUST
NOT be null or the empty string ("").
MANUFACTURER - The trade name of the Original Equipment Manufacturer
(OEM) of the product. There are no requirements on the specific format
of this field, except that it MUST NOT be null or the empty string
("").

UPDATE
You could retrieve the device from buildprop easitly.
static String GetDeviceName() {
Process p;
String propvalue = "";
try {
p = new ProcessBuilder("/system/bin/getprop", "ro.semc.product.name").redirectErrorStream(true).start();
BufferedReader br = new BufferedReader(new InputStreamReader(p.getInputStream()));
String line;
while ((line = br.readLine()) != null) {
propvalue = line;
}
p.destroy();
} catch (IOException e) {
e.printStackTrace();
}
return propvalue;
}
But keep in mind, this doesn't work on some devices.

Simply use
BluetoothAdapter.getDefaultAdapter().getName()

static String getDeviceName() {
try {
Class systemPropertiesClass = Class.forName("android.os.SystemProperties");
Method getMethod = systemPropertiesClass.getMethod("get", String.class);
Object object = new Object();
Object obj = getMethod.invoke(object, "ro.product.device");
return (obj == null ? "" : (String) obj);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
you can get 'idol3' by this way.

Tried These libraries but nothing worked according to my expectation and was giving absolutely wrong names.
So i created this library myself using the same data.
Here is the link
AndroidPhoneNamesFinder
To use this library just add this for implementation
implementation 'com.github.aishik212:AndroidPhoneNamesFinder:v1.0.2'
Then use the following kotlin code
DeviceNameFinder.getPhoneValues(this, object : DeviceDetailsListener
{
override fun details(doQuery: DeviceDetailsModel?)
{
super.details(doQuery)
Log.d(TAG, "details: "+doQuery?.calculatedName)
}
})
These are the values you will get from DeviceDetailsModel
val brand: String? #This is the brandName of the Device
val commonName: String?, #This is the most common Name of the Device
val codeName: String?, #This is the codeName of the Device
val modelName: String?, #This is the another uncommon Name of the Device
val calculatedName: String?, #This is the special name that this library tries to create from the above data.
Example of Android Emulator -
brand=Google
commonName=Google Android Emulator
codeName=generic_x86_arm
modelName=sdk_gphone_x86
calculatedName=Google Android Emulator

Within the GNU/Linux environment of Android, e.g., via Termux UNIX shell on a non-root device, it's available through the /system/bin/getprop command, whereas the meaning of each value is explained in Build.java within Android (also at googlesource):
% /system/bin/getprop | fgrep ro.product | tail -3
[ro.product.manufacturer]: [Google]
[ro.product.model]: [Pixel 2 XL]
[ro.product.name]: [taimen]
% /system/bin/getprop ro.product.model
Pixel 2 XL
% /system/bin/getprop ro.product.model | tr ' ' _
Pixel_2_XL
For example, it can be set as the pane_title for the status-right within tmux like so:
tmux select-pane -T "$(getprop ro.product.model)"

Gets an Android system property, or lists them all
adb shell getprop >prop_list.txt
Find your device name in prop_list.txt to get the prop name
e.g. my device name is ro.oppo.market.name
Get oppo.market Operator
adb shell getprop ro.oppo.market.name
My case on windows as follows
D:\winusr\adbl
λ *adb shell getprop ro.oppo.market.name*
OPPO R17

Getting device/driver information related to a COM port?

I have a Serial-to-USB device with a similarly named device driver in the Windows device manager. The devices do not always grab the same COM port on system boot, so my program needs to identify it on start up.
I've tried using RXTX to enumerate the COM ports on the system, but this didn't work because CommPortIdentifier.getName() simply returns the COM name (eg. COM1, COM2, etc.) I need to acquire either the driver manufacturer name, or the driver name as it appears in the device manager, and associate it with the COM name.
Can this easily be done in Java? (I'd be interested in any 3rd party Java libraries that support this.) Otherwise, how I could begin to accomplish this via the win32 API?

I achieved what I wanted by using the WinRegistry class provided by David in this SO question to obtain the FriendlyName from registry key associated with my USB device. I then parse out the COM number from the friendly name.
Some things to consider:
USB devices are located at HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Enum\USB\ in the registry (tested on WinXP, Win7.)
I required the device VID + PID to identify the correct device key (eg. VID_xxxx&PID_xxxx.) Since VID and PID are device specific, this key should be reliable across multiple systems.
The VID_xxxx&PID_xxxx key contains another sub-key with device values. I had some trouble enumerating the sub-keys with WinRegistry, so I hard-coded the sub-key name as a quick hack during development. A much safer solution would search sub-keys to find the correct name.
The device keys exist in the registry regardless of whether the device is currently connected. This code makes the assumption that Windows will update FriendlyName if the device is reconnected to a different COM port. I haven't verified this, but things looked good during use-testing.
Example
String keyPath = "SYSTEM\\CurrentControlSet\\Enum\\USB\\Vid_067b&Pid_2303\\";
String device1 = "5&75451e6&0&1";
System.out.println("First COM device: " + getComNumber(keyPath + device1));
Code
import java.util.regex.Pattern;
import java.util.regex.Matcher;
// Given a registry key, attempts to get the 'FriendlyName' value
// Returns null on failure.
//
public static String getFriendlyName(String registryKey) {
if (registryKey == null || registryKey.isEmpty()) {
throw new IllegalArgumentException("'registryKey' null or empty");
}
try {
int hkey = WinRegistry.HKEY_LOCAL_MACHINE;
return WinRegistry.readString(hkey, registryKey, "FriendlyName");
} catch (Exception ex) { // catch-all:
// readString() throws IllegalArg, IllegalAccess, InvocationTarget
System.err.println(ex.getMessage());
return null;
}
}
// Given a registry key, attempts to parse out the integer after
// substring "COM" in the 'FriendlyName' value; returns -1 on failure.
//
public static int getComNumber(String registryKey) {
String friendlyName = getFriendlyName(registryKey);
if (friendlyName != null && friendlyName.indexOf("COM") >= 0) {
String substr = friendlyName.substring(friendlyName.indexOf("COM"));
Matcher matchInt = Pattern.compile("\\d+").matcher(substr);
if (matchInt.find()) {
return Integer.parseInt(matchInt.group());
}
}
return -1;
}

#robjb Your code does not allow for more than one device to be connected. How will the user know the device name? I added to your code thus to return a list of com ports:
ArrayList<String> subKeys = WinRegistry.readStringSubKeys(WinRegistry.HKEY_LOCAL_MACHINE, keyPath);
ArrayList<Integer> comPorts = new ArrayList<Integer>();
for (String subKey : subKeys) {
String friendlyName = getFriendlyName(keyPath + subKey);
if (friendlyName != null && friendlyName.contains("MyDriverName") && friendlyName.contains("COM")) {
int beginIndex = friendlyName.indexOf("COM") + 3 /*length of 'COM'*/;
int endIndex = friendlyName.indexOf(")");
comPorts.add(Integer.parseInt(friendlyName.substring(beginIndex, endIndex)));
}
}
Update: I don't think these are solutions. Why? This information is statically stored in the registry - even when the device is not connected.

Great example, using JNA, here.
The author (Geir Arne Ruud) has released it under Public Domain License.
My example code
public static String getFriendlyName(GoGPSModel model, String name)
{
if(model.getSystem().getOSType() != OSType.Windows32
&& model.getSystem().getOSType() != OSType.Windows64) {
return name;
}
for (DeviceInformation devInfo : infoObjects) {
System.out.println(devInfo.toString());
String friendlyName = devInfo.getFriendlyName();
if(friendlyName != null && !friendlyName.equals("") && friendlyName.contains(name)) {
return devInfo.getManufacturer() + ": " + friendlyName;
}
}
return name;
}