I am looking way to store EnumSet in mysql column with type set:
#Data
#Entity
#Table(name = "ENTITY_TABLE")
public class Entity implements Serializable {
#Id
#GeneratedValue
#Column(nullable = false)
#NotNull
private String id;
#Column(name = "types")
private EnumSet<Type> types;
}
Enum of type is defined as below:
public enum Type {
TYPE1,
TYPE2,
TYPE3,
TYPE4,
TYPE5
}
And table is defined below:
CREATE TABLE `ENTITY_TABLE` (
`id` int(20) NOT NULL AUTO_INCREMENT,
`types` set('TYPE1','TYPE2','TYPE3','TYPE4','TYPE5') DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
And insert in table:
INSERT INTO ENTITY_TABLE (types) VALUE ( 'TYPE1','TYPE2')
SET in mysql docs
Thanks a lot! I had to use a slightly different version what you have here. What worked for me was:
I had an Enum of permissions that needed to be adjustable:
#Convert(converter = SetConverter.class)
#Column(name = "permission")
private EnumSet<Permission> permission;
//in a util and imported
...
#Converter
public static class SetConverter implements AttributeConverter<EnumSet<Permission>, String> {
public String convertToDatabaseColumn(EnumSet<Permission> attribute) {
StringBuilder sb = new StringBuilder();
for (Permission c : attribute) {
sb.append(c + ",");
}
return sb.toString();
}
public EnumSet<Permission> convertToEntityAttribute(String dbData) {
if (dbData == null) {
dbData = "";
}
EnumSet<Permission> perm = EnumSet.of(Permission.DEFAULT); //default was a value I added.
String[] persistencePermissions = StringUtils.trimAllWhitespace(dbData).toUpperCase().split(",");
if (!StringUtils.isEmpty(StringUtils.trimAllWhitespace(dbData))) {
try {
for (String str : persistencePermissions) {
perm.add(Permission.valueOf(str));
}}
catch (IllegalArgumentException IAE) {
throw new Exception("INVALID_REQUEST");
}}
return perm;
}
}
Default JPA-Solution for Set
#Data
#Entity
#Table(name = "ENTITY_TABLE")
public class Entity implements Serializable {
#Id
#GeneratedValue
private String id;
#ElementCollection
#Enumerated(EnumType.STRING)
#Column(name = "types")
private Set<Type> types;
}
Another possibility would be with a AttributeConverter, But I have never tried this with MySQL set.
#Data
#Entity
#Table(name = "ENTITY_TABLE")
public class Entity implements Serializable {
#Id
#GeneratedValue
#Column(nullable = false)
#NotNull
private String id;
#Convert(converter = SetConverter.class)
#Column(name = "types")
private EnumSet<Type> types;
}
#Converter
public class SetConverter implements AttributeConverter<EnumSet<Type>, String> {
#Override
public String convertToDatabaseColumn(EnumSet<Type> attribute) {
// TODO Auto-generated method stub
return null;
}
#Override
public EnumSet<Type> convertToEntityAttribute(String dbData) {
// TODO Auto-generated method stub
return null;
}
}
Related
I have Spring Boot application (v3.0.2, Java 17), and in it, a simple entity ActivityType and corresponding ActivityDto.
//Entity (uses Lombok 1.18.24)...
#Getter
#Setter
#Entity
public class ActivityType {
#Id
#Column(name = "ActivityTypeId", nullable = false)
private Integer id;
#Column(name = "ActivityName", nullable = false, length = 30)
private String activityName;
#Column(name = "ActivityDescription")
private String activityDescription;
}
//DTO...
public record ActivityTypeDto(
Integer id,
String activityName,
String activityDescription) implements Serializable {
}
I'm using IntelliJ Idea (v2022.2.4) and JPA Buddy (v2022.5.4-222) to generate the Mapper Interface (MapStruct v1.5.3.Final). When I build the Mapper implementation, in the generated code, both the toEntity and toDto methods are incorrect.
#Component public class ActivityTypeMapperImpl implements ActivityTypeMapper {
#Override
public ActivityType toEntity(ActivityTypeDto activityTypeDto) {
if ( activityTypeDto == null ) {
return null;
}
ActivityType activityType = new ActivityType();
return activityType;
}
#Override
public ActivityTypeDto toDto(ActivityType activityType) {
if ( activityType == null ) {
return null;
}
// What's this all about?? Why not activityType.id, etc??
Integer id = null;
String activityName = null;
String activityDescription = null;
ActivityTypeDto activityTypeDto = new ActivityTypeDto( id, activityName, activityDescription );
return activityTypeDto;
}
#Override
public ActivityType partialUpdate(ActivityTypeDto activityTypeDto, ActivityType activityType) {
if ( activityTypeDto == null ) {
return activityType;
}
return activityType;
}
I've tried various alternatives, including using a class for the DTO instead of a record, but no success. Looks like I've missed something, but not sure what.
Update:
I can fix this by not using Lombok for the Entity getters/setters, which leads me on to final question, is there a setting on the MapStruct plugin to take Lomboz into account?
please define you entity like this,
#Entity
#Data
#AllArgsConstructor
#NoArgsConstructor
public class ActivityType {
#Id
#Column(name = "ActivityTypeId", nullable = false)
private Integer id;
#Column(name = "ActivityName", nullable = false, length = 30)
private String activityName;
#Column(name = "ActivityDescription")
private String activityDescription;
}
then define ActivityTypeDTO like this,
#Data
public class ActivityTypeDTO {
#JsonProperty("id")
private Integer id;
#JsonProperty("ActivityName")
private String ActivityName;
#JsonProperty("activityDescription")
private String activityDescription;
best practice to use MapStruct is like this,
#Mapper(componentModel = "spring", uses = {})
public interface ActivityMapper extends EntityMapper<ActivityTypeDTO, ActivityType> {
ActivityTypeDTO toDto(ActivityType activityType);
ActivityType toEntity(ActivityTypeDTO activityTypeDTO);
}
and EntityMApper in Mapper should be like this,
public interface EntityMapper<D, E> {
E toEntity(D dto);
D toDto(E entity);
}
Now I am sure you mapper work correctly.
I have a many to one relationship: A *<-->1 B and I want to deserialize A from a JSON having B's primary key (B exists in db with that primary key):
{
"b": 1
}
I have tried the following:
#Entity
#Table(name = "table_a")
#JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "id")
public class A implements Serializable {
#JsonIgnore
#ManyToOne(fetch=FetchType.LAZY)
#JoinColumn(name = "b", unique = true, nullable = false)
private B b;
}
and
#Entity
#Table(name = "table_b")
public class B implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int id;
#OneToMany(mappedBy = "b")
private List<A> a = new ArrayList<>();
}
but object A is created with b = null. How can I deserialize A with b property correctly instantiated from db?
Note: I am using Jackson version 2.6.1.
You have several options and here is similar question :
#JsonCreator factory in B class (More info)
Custom deserializer
Custom ObjectIdResolver for #JsonIdentityInfo like
private class MyObjectIdResolver implements ObjectIdResolver {
private Map<ObjectIdGenerator.IdKey,Object> _items = new HashMap<>();
#Override
public void bindItem(ObjectIdGenerator.IdKey id, Object pojo) {
if (!_items.containsKey(id)) _items.put(id, pojo);
}
#Override
public Object resolveId(ObjectIdGenerator.IdKey id) {
Object object = _items.get(id);
return object == null ? getById(id) : object;
}
protected Object getById(ObjectIdGenerator.IdKey id){
Object object = null;
try {
//can resolve object from db here
//objectRepository.getById((Integer)idKey.key, idKey.scope)
object = id.scope.getConstructor().newInstance();
id.scope.getMethod("setId", int.class).invoke(object, id.key);
} catch (Exception e) {
e.printStackTrace();
}
return object;
}
#Override
public ObjectIdResolver newForDeserialization(Object context) {
return new MyObjectIdResolver();
}
#Override
public boolean canUseFor(ObjectIdResolver resolverType) {
return resolverType.getClass() == getClass();
}
}
And use it like this:
#JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class,
resolver = MyObjectIdResolver.class,
property = "id", scope = B.class)
public class B {
// ...
}
Here is your case related gist demo more broad github project with some serialization thoughts
I am new to hibernate and having a tough time trying to wrap my head around setting up Joined inheritance with composite Primary Key. With my current setup, I get a:
JDBCException: could not insert: LandHolidayPackage
I am essentially looking for two things:
Are the inheritance annotations in place ?
Is the composite PK setup properly ?
DB Design:
Reference
Here are my classes and the annotations involved:
#Entity
#Table(name = "HOLIDAYPACKAGE")
public final class HolidayPackage {
private Integer idPackage;
private String name;
private Set<HolidayPackageVariant> holidayPackageVariants = new HashSet<HolidayPackageVariant>(0);
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "IDHOLIDAYPACKAGE", nullable = false)
public Integer getIdPackage() {
return idPackage;
}
#OneToMany(fetch=FetchType.LAZY, cascade={CascadeType.ALL}, mappedBy = "holidayPackage")
public Set<HolidayPackageVariant> getHolidayPackageVariants() {
return holidayPackageVariants;
}
// ommitted other part of the code
}
#Entity
#Inheritance(strategy=InheritanceType.JOINED)
#Table(name="HOLIDAYPACKAGEVARIANT")
public abstract class HolidayPackageVariant {
private Integer idHolidayPackageVariant;
private HolidayPackage holidayPackage;
private String typeHolidayPackage;
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="IDHOLIDAYPACKAGEVARIANT", nullable=false)
public Integer getIdHolidayPackageVariant() {
return idHolidayPackageVariant;
}
#ManyToOne(fetch=FetchType.LAZY, cascade={CascadeType.ALL})
#JoinColumn(name="IDHOLIDAYPACKAGE", nullable=false)
public HolidayPackage getHolidayPackage() {
return holidayPackage;
}
#Column(name="TYPEHOLIDAYPACKAGE", nullable=true)
public String getTypeHolidayPackage() {
return typeHolidayPackage;
}
// ommitted setters, equals hashCode
}
#Entity
#Table(name="LANDHOLIDAYPACKAGEVARIANT")
public final class LandHolidayPackageVariant extends HolidayPackageVariant{
private static final String LAND = "LAND";
protected LandHolidayPackageVariant() {}
public LandHolidayPackageVariant(HolidayPackage holidayPackage) {
super(holidayPackage, LAND);
}
}
#Entity
#Table(name="FLIGHTHOLIDAYPACKAGEVARIANT")
public final class FlightHolidayPackageVariant extends HolidayPackageVariant{
private static final String FLIGHT = "FLIGHT";
private Destination originCity;
protected FlightHolidayPackageVariant(){}
public FlightHolidayPackageVariant(HolidayPackage holidayPackage,
Destination originCity) {
super(holidayPackage, FLIGHT);
setOriginCity(originCity);
}
#ManyToOne(fetch=FetchType.LAZY, cascade={CascadeType.ALL})
#JoinColumn(name="IDDESTINATION", nullable=false)
public Destination getOriginCity() {
return originCity;
}
// ommited other setters etc functions
}
You annotated the properties in stead of the fields. JPA by default tries to access the fields. If you want JPA to use the fields you have to annotate the class with #AccessType(AccessType.Field).
I am trying to map the following table
CREATE TABLE Person (
p_id varchar(255) not null,
p_name varchar(255 not null,
p_post_code varchar(12) not null,
primary key (p_id, p_name),
);
Usually when i map an Entity to the above table i would do something like this (for single column primary keys):
private int p_id;
private String p_name;
private String p_post_code;
#Id
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="p_id")
public Long getPId() {
return p_id;
}
public void setPId(int p_id) {
this.p_id = p_id;
}
#Column(name="p_name")
public String getPname() {
return p_name;
}
public void setPname(String string) {
this.p_name = string;
}
#Column(name="p_post_code")
public String getPostCode() {
return p_post_code;
}
public void setPostCode(String string) {
this.p_post_code = string;
}
The above works if the primary key is a single column (i.e. p_id) and the value for this column is generated in the database.
How would i modify the above to map it so that both p_id and p_name are the primary key.
Also, how would this work, if the composite key is a foreign key in another table.
I am trying to google for some examples but i cant find a simple example and most seem to be using the XML based configuration.
When using composite keys with JPA you need to use an embedded class as an id.
In your case you would have a person class and a primary key class for person:
#entity
public class Person
{
#EmbeddedId
private PersonPK key;
#Column(name="p_post_code", nullable = false)
private String p_post_code;
//....
}
#Embeddable
public class PersonPK
{
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="p_id");
private Long p_id;
#Column(name="p_name")
private String p_name;
public PersonPK(String name)
{
p_name = name;
}
//....
}
Using a class for the person's name (so the name is also a foreign key):
#entity
public class Person
{
#EmbeddedId
private PersonPK key;
#MapsId(value="p_name_id")
#ManyToOne
#JoinColumn(name = "p_name_id", referencedColumnName = "id")
private Name p_name;
#Column(name="p_post_code", nullable = false)
private String p_post_code;
//....
}
#Embeddable
public class PersonPK
{
#GeneratedValue(strategy=GenerationType.IDENTITY)
#Column(name="p_id");
private Long p_id;
#Column(name="p_name_id")
private Long p_name_id;
public PersonPK(Name name)
{
p_name_id = name.getId();
}
//....
}
#Entity
public class Name
{
#Id
#GeneratedValue(some generation strategy here)
#Column(name="id")
private Long id;
#Column(name="name")
private String name;
//....
}
I have a situation where I am working with EJB3 and a legacy database. I have a situation where there is a many-to-many relationship between two tables A and B, defined through a third (link) table L.
The complication is that the link table has other fields in it other than the PK's of tables A and B. The columns are standard timestamp and user columns to record who generated the link. These two additional columns are preventing me from defining the many-many relationship using a join table annotation, as they are not nillable and so must be populated.
Does anyone know of a way around this limitation? I could define One-to-many relationships from the link table to each of the other tables in the relationship, but this is not very elegant.
Thanks,
Yes, it is but you need to make it elegant. The following super-class can be used to define arbitrary many-to-many relationship as an entity:
#MappedSuperclass
public abstract class ModelBaseRelationship {
#Embeddable
public static class Id implements Serializable {
public Long entityId1;
public Long entityId2;
#Column(name = "ENTITY1_ID")
public Long getEntityId1() {
return entityId1;
}
#Column(name = "ENTITY2_ID")
public Long getEntityId2() {
return entityId2;
}
public Id() {
}
public Id(Long entityId1, Long entityId2) {
this.entityId1 = entityId1;
this.entityId2 = entityId2;
}
#Override
public boolean equals(Object other) {
if (other == null)
return false;
if (this == other)
return true;
if (!(other instanceof Id))
return false;
final Id that = (Id) other;
return new EqualsBuilder().append(this.entityId1, that.getEntityId1()).append(this.entityId1, that.getEntityId2()).isEquals();
}
#Override
public int hashCode() {
return new HashCodeBuilder(11, 111).append(this.entityId1).append(this.entityId2).toHashCode();
}
protected void setEntityId1(Long theEntityId1) {
entityId1 = theEntityId1;
}
protected void setEntityId2(Long theEntityId2) {
entityId2 = theEntityId2;
}
}
protected Id id = new Id();
public ModelBaseRelationship() {
super();
}
public ModelBaseRelationship(ModelBaseEntity entity1, ModelBaseEntity entity2) {
this();
this.id.entityId1 = entity1.getId();
this.id.entityId2 = entity2.getId();
setVersion(0);
}
#EmbeddedId
public Id getId() {
return id;
}
protected void setId(Id theId) {
id = theId;
}
}
The example of entity based on this super class (fragment):
#Entity(name = "myRealEntity")
#Table(name = "REAL_TABLE_NAME", uniqueConstraints = { #UniqueConstraint(columnNames = {
"FIRST_FK_ID", "SECOND_FK_ID" }) })
#AttributeOverrides( {
#AttributeOverride(name = "entityId1", column = #Column(name = "FIRST_FK_ID")),
#AttributeOverride(name = "entityId2", column = #Column(name = "SECOND_FK_ID"))
})
public class ModelBaseRelationshipReferenceImpl extends ModelBaseRelationship {
private Entity1OfManyToManyRelationship entity1;
private Entity2OfManyToManyRelationship entity2;
...
#ManyToOne
#JoinColumn(name = "FIRST_FK_ID", insertable = false, updatable = false)
public Entity1OfManyToManyRelationship getEntity1OfManyToManyRelationship() {
return entity1;
}
#ManyToOne
#JoinColumn(name = "SECOND_FK_ID", insertable = false, updatable = false)
public Entity2OfManyToManyRelationship getEntity2OfManyToManyRelationship () {
return entity2;
}
...
}