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how internal Implementation of TreeMap is done in Java? Does it use any tree (like : binary tree, red-black, B-tree) for arranging elements?
First line of the documentation:
A Red-Black tree based NavigableMap implementation.
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I have a Map<Type, Data>
We need to convert the keySet of the map to a LinkedHashSet of String.
What is the most efficient way to do it using java 8 stream.
map.keySet().stream().map(Object::toString).collect(toCollection(LinkedHashSet::new));
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does java have a function to make a direct conversion between Little and BigEndien?
Several. Byte order can be swapped using ByteBuffer or Integer/Long.reverseBytes
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What advantage is there in keeping the Set unordered?
Is it more efficient in space/time?
In what way is a random order easier to manage than insertion order?
Elements in a HashSet are ordered (dispersed in the Javadoc) by the Object.hashCode(). You can use a LinkedHashSet if you need a Set that preserves insertion order.
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I'm thinking on possibility of making a Huffman code without "node".
It's based on the nodes then my question seems a bit ambiguous.
I know,maybe we have to use string's abilites ...
Is it possible ? and if "YES" how Is it possible in java?
Thanks.
You can use indices instead of nodes but you need somewhere nodes and/or vertices.
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How can I access userObject in DefaultMutableTreeNode
How can I modify the user object or extract the values defined in it?
What about the methods setUserObject and getUserObject?