SQL strings added more than once for: tablename - java

I'm bootstrapping a database using hibernate-maven-plugin, using models that it scans in the maven module it's executed in.
Unfortunately, it stops when hibernate throws this:
org.hibernate.tool.schema.spi.SchemaManagementException: SQL strings added more than once for: reference_data_source.UK-UK_9ec6wdvyj3mjagiptcnrq2txv
at org.hibernate.tool.schema.internal.SchemaCreatorImpl.checkExportIdentifier(SchemaCreatorImpl.java:299)
at org.hibernate.tool.schema.internal.SchemaCreatorImpl.doCreation(SchemaCreatorImpl.java:255)
at org.hibernate.tool.schema.internal.SchemaCreatorImpl.doCreation(SchemaCreatorImpl.java:128)
at org.hibernate.tool.hbm2ddl.SchemaExport.<init>(SchemaExport.java:199)
So, I have two persistence units, and some tables exists in both. Hibernate seems to interpret this like the same table though, so when it tries to store the same index, but for another schema, it fails thinking it is a duplicate. Their code can be found here.
I'm not sure how to approach this, anyway to configure hibernate hbm2ddl to keep track of these different peristence units?
This is the configuration for the hibernate-maven-plugin:
<plugin>
<groupId>de.juplo</groupId>
<artifactId>hibernate-maven-plugin</artifactId>
<version>2.0.0</version>
<configuration>
<detail>true</detail>
<persistenceUnit>mainPersistenceUnit</persistenceUnit>
<driver>com.mysql.jdbc.Driver</driver>
<dialect>org.hibernate.dialect.MySQL5Dialect</dialect>
<force>true</force>
<url><![CDATA[jdbc:mysql://localhost/auto_bootstrap_schema]]></url>
<username>user</username>
<password>pass</password>
</configuration>
<executions>
<execution>
<goals>
<goal>create</goal>
</goals>
</execution>
</executions>
<dependencies>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>${mysql-connector-java.version}</version>
</dependency>
</dependencies>
</plugin>

I had the same problem. The reason in my case was that I had three entities starting with same prefix name and a OneToMany relation to the each more specialized one:
Person
PersonCard
PersonCardLayout
Renaming my model to this solved my problem:
Person
Card
Layout
This seems to be a bug in Hibernate.

i have the same problem, looks like a bug in:
org.hibernate.mapping.UniqueKey#getExportIdentifier
#Override
public String getExportIdentifier() {
return StringHelper.qualify( getTable().getName(), "UK-" + getName() );
}
because the identifier was build only from table name but without schema/catalog of the table.
Therefore, if you have to entities with same table name but different schema and in these entities two properties with same name and "unique = true" you will drop into the bug.

Another solution to this is to make use of #Table.
For example:
#Table(name="PERSON")
This happened to me when I had two classes representing two entities (#Entity) as follows:
#Entity
public class User {...}
#Entity
public class UserRoles {...}
I fixed this error by specifying the table name as follows:
#Entity
#Table(name="USER")
public class User {...}
And:
#Table(name="USER_ROLES")
#Entity
public class UserRoles {...}

Not sure if this is the same as what I ran into, but I had the same error issue with base class marked with #Entity annotation: changing to #MappedSuperclass removed the error.
Good Luck,
Ray

Related

Generating POJOs using OpenAPI generator with Lombok Annotations

I am using OpenAPI generator maven plugin like one below for generating Java client code for models .
<plugin>
<groupId>org.openapitools</groupId>
<artifactId>openapi-generator-maven-plugin</artifactId>
<version>4.3.1</version>
<executions>
<execution>
<goals>
<goal>generate</goal>
</goals>
<configuration>
<inputSpec>${project.basedir}/src/main/resources/api.yaml</inputSpec>
<generatorName>java</generatorName>
<configOptions>
<sourceFolder>src/gen/java/main</sourceFolder>
</configOptions>
</configuration>
</execution>
</executions>
</plugin>
When , I generate the model classes, they get generated with usual POJO field declarations and getters and setters. But what I want to do is, instead of generating getters and setters, I want my classes to get automatically generated with Lombok annotations for Java pojos like #Getter, #Setter, #Data, etc. Is there a way to customize model generator to fit above use case requirement?
I tried to find out if there is a way. I found this discussion, where the very last comment talks about a PR, where the issue of generating models using Lombok annotations has been addressed. But I do not see any clear indication of usage or any documentation of this feature in the OpenAPI generator open source project that it has been implemented yet. So, is there any way of generating models with Lombok annotations instead of regular getters and setters today?
To complete this very old thread: Now it does support Lombok annotations.
Example taken from here
<configOptions>
<additionalModelTypeAnnotations>#lombok.Builder #lombok.NoArgsConstructor #lombok.AllArgsConstructor</additionalModelTypeAnnotations>
</configOptions>
EDIT: This answer is deprecated. See the post by #Laess3r. I'll leave this, since it is applicable for older versions of openapi generator.
openapi-generator does not yet support Lombok annotations. If you want to generate code with Lombok annotations, you need to create a custom template in mustache, as described in https://openapi-generator.tech/docs/templating/.
If you've never worked with mustache, be aware that it's somewhat hard to read, so try to keep the templates as simple as possible and make sure to add unit tests to validate the generated output. The template will look something like this:
/**
* {{#description}}{{description}}{{/description}}
*/
#Data
public class {{classname}} {{#parent}}extends {{{parent}}} {{/parent}} {
{{#vars}}
/**
* {{#description}}{{description}}{{/description}}
*/
#JsonProperty("{{#lambda.lowercase}}{{nameInSnakeCase}}{{/lambda.lowercase}}")
private {{{datatypeWithEnum}}} {{name}};
{{/vars}}
I've been able to get this working out-of-the-box using a space
separated list of annotations on models:
#lombok.experimental.SuperBuilder #lombok.external.Jacksonized
If models have readOnly set to "true" the Builder becomes the only way to make the object and #Jacksonized allows it to be serialized/deserialized. There are some limitations with inheritance (turning off requiring all required parameters in the configOptions).

How to generate Swagger codegen Java models as JPA Entities

I am using Swagger codegen to create Java models to be used in a Spring REST server, and would like to know how to get Swagger to declare each model as a JPA entity.
I generate the code with the swagger-codegen-maven-plugin as follows:
<plugin>
<groupId>io.swagger</groupId>
<artifactId>swagger-codegen-maven-plugin</artifactId>
<version>2.4.0</version>
<executions>
<execution>
<goals>
<goal>generate</goal>
</goals>
<configuration>
<inputSpec>${project.basedir}/src/main/openApi/Rack.json</inputSpec>
<language>spring</language>
<groupId>com.me</groupId>
<artifactId>rest-server</artifactId>
<apiPackage>com.me.rest.api</apiPackage>
<modelPackage>com.me.rest.model</modelPackage>
<invokerPackage>com.me.rest.invoker</invokerPackage>
<configOptions>
<sourceFolder>src/gen/java/main</sourceFolder>
<java8>true</java8>
<dateLibrary>java8</dateLibrary>
</configOptions>
</configuration>
</execution>
</executions>
</plugin>
As I have it now, this is the abbreviated java code that gets generated:
#Validated
#javax.annotation.Generated(value = "io.swagger.codegen.languages.SpringCodegen", date = "...")
public class Rack {
#JsonProperty("id")
private Long id = null;
#JsonProperty("name")
private String name = null;
...
}
How do I get Swagger to add the #Entity and #Id JPA annotations, as follows?
import javax.persistence.Entity;
import javax.persistence.Id;
#Entity
#Validated
#javax.annotation.Generated(value = "io.swagger.codegen.languages.SpringCodegen", date = "...")
public class Rack {
#Id
#JsonProperty("id")
private Long id = null;
#JsonProperty("name")
private String name = null;
...
}
This way, all I would have to do to get Spring to automatically expose these generated classes as REST APIs, would be to add the following to my pom.xml:
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-rest</artifactId>
</dependency>
Then I could create the JPA repositories with Spring-Data, as follows:
public interface RackRepository extends CrudRepository<Rack, Long> {
}
A PR has recently been merged fixing your issue : https://github.com/OpenAPITools/openapi-generator/pull/11775
You need to upgrade your Maven plugin to use the latest version (currently unreleased, only snapshot is available)
<plugin>
<groupId>org.openapitools</groupId>
<artifactId>openapi-generator-maven-plugin</artifactId>
<version>6.0.0-SNAPSHOT</version>
...
</plugin>
The configuration might be slightly different.
Then you need to add x-class-extra-annotation and x-field-extra-annotation in your spec.
For instance for the Pet Clinic:
schemas:
Pet:
type: object
x-class-extra-annotation: "#javax.persistence.Entity"
required:
- id
- name
properties:
id:
type: integer
format: int64
x-field-extra-annotation: "#javax.persistence.Id"
name:
type: string
tag:
type: string
While the right way to solve this surely is an extension of swagger-codegen (probably with the introduction of some kind of include/exclude config), I got away with a fairly simply post-processing of the generated files.
In contrast to the OP I use Gradle instead of Maven and leveraged its extended filtering functionality. For Maven it is probably necessary to run a Groovy-script by way of the Groovy-Maven-Plugin, since Maven only supports placeholder substitution (as does Ant, so using the AntRun-Plugin would also not work).
I used a simple heuristic to only include entities with an id - the logic is as follows:
for all Java-files containing an ID-field
include import statement for javax.persistence.* after the package declaration
add the #Entity-annotation before the class definition
for the ID-field, add the annotations #Id and #GeneratedValue
(based on field names, other annotations - #OneToMany etc. - may be added as well)
Gradle-users may find the following task useful as a start:
task generateJpaAnnotations(type: Copy) {
from "${swaggerSources.<modelName>.code.outputDir}/src/main/java"
into "<output dir>
include '**/*.java'
eachFile {
if (it.file.text.contains("private Long id")) {
filter { line -> line.contains('package') ? "$line\nimport javax.persistence.*;" : line }
filter { line -> line.contains('public class') ? "#Entity\n$line" : line }
filter { line -> line.contains('private Long id') ? "#Id\n#GeneratedValue(strategy=GenerationType.AUTO)\n$line" : line } }
}
}
So I'm actually asking myself the same question.
I found an example but the guy is simply re-defining his POJOs and providing a way to adapt the generated ones to the handwritten ones. Tedious and not evolutive.
Globally this could be hard because I'm not sure there is a way in your swagger to decide which POJO will be JPA enabled and maybe you don't want them all in your DB (?) Also, how to you tag the id in swagger?
If you know of such a way, you can always modify the mustache (pojo.mustache I guess) to give you the annotations you're missing.

Spring #QuerydslPredicate Questions

Libaries Used
Spring Boot 1.3.2.RELEASE
QueryDSL 3.7.2
QueryDSL Maven Plugin 1.1.3
Hibernate 4.3.11.Final
Issue
Currently, I have a Spring Boot application that has some basic CRUD functionality using Spring Data JPA (backed by Hibernate), and auditing using Spring Data Envers. I also have the following endpoint to retrieve a list of entities from:
http://localhost:8080/test-app/list
Now, I wanted to use the new QueryDSL support that Spring offers through the #QuerydslPredicate annotation. This works fine for most fields or sub-entities, but it doesn't appear to work for collections of sub-entities. The documentation, blog posts, etc. don't seem to cover this case - and the only information I could find is that it supports "in" for simple collections (i.e. collections of String, etc.).
So, my entity is set up something like so:
Person.java
#Data
#Entity
#Audited
public class Person {
#Id
private long id;
private String name;
private List<Pet> pets = new ArrayList<>();
}
Pet.java
#Data
#Entity
#Audited
public class Pet {
#Id
private long id;
private int age;
}
I generate my Q classes using the com.mysema.maven:apt-maven-plugin, which generates my QPerson with the following field:
public final ListPath<com.test.Pet, com.test.QPet> pets = this.<com.test.Pet, com.test.QPet>createList("pets", com.test.Pet.class, com.test.QPet.class, PathInits.DIRECT2);
If I try to query on this though, I get an exception:
Query:
http://localhost:8080/test-app/list?pets.age=5
Exception:
10:21:37,523 ERROR [org.springframework.boot.context.web.ErrorPageFilter] (http-/127.0.0.1:8080-1) Forwarding to error page from request [/list] due to exception [null]: java.lang.NullPointerException
at org.springframework.util.ReflectionUtils.getField(ReflectionUtils.java:143) [spring-core-4.2.4.RELEASE.jar:4.2.4.RELEASE]
at org.springframework.data.querydsl.binding.QuerydslPredicateBuilder.reifyPath(QuerydslPredicateBuilder.java:185) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.data.querydsl.binding.QuerydslPredicateBuilder.reifyPath(QuerydslPredicateBuilder.java:188) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.data.querydsl.binding.QuerydslPredicateBuilder.getPath(QuerydslPredicateBuilder.java:167) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.data.querydsl.binding.QuerydslPredicateBuilder.invokeBinding(QuerydslPredicateBuilder.java:136) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.data.querydsl.binding.QuerydslPredicateBuilder.getPredicate(QuerydslPredicateBuilder.java:111) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.data.web.querydsl.QuerydslPredicateArgumentResolver.resolveArgument(QuerydslPredicateArgumentResolver.java:106) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.data.web.querydsl.QuerydslPredicateArgumentResolver.resolveArgument(QuerydslPredicateArgumentResolver.java:48) [spring-data-commons-1.11.2.RELEASE.jar:]
at org.springframework.web.method.support.HandlerMethodArgumentResolverComposite.resolveArgument(HandlerMethodArgumentResolverComposite.java:78) [spring-web-4.2.4.RELEASE.jar:4.2.4.RELEASE]
Now this query look like it's trying to resolve the propertyPath Person.pets.age. It correctly identifies Person.pets as a ListPath, and then tries to identify CompanyAddress.addressLine1 (which seems correct). The problem is, it tries to use the entity path to get the class, which is the ListPath instead of the QPet:
Field field = ReflectionUtils.findField(entityPath.getClass(), path.getSegment());
Object value = ReflectionUtils.getField(field, entityPath);
The following query works as expected:
http://localhost:8080/test-app/list?name=Bob
My expectation was that by using ?pets.age=5, the following predicate would be built:
QPerson.person.pets.any().age.eq(5)
Is this currently possible with Spring's QuerydslPredicate support? Or should I manually build the predicates from the query parameters?
Additional Question
As an additional question, is the following possible with QuerydslPredicate. Say I have a firstName and lastName on pet, and I want to run a query with just name=Bob:
http://localhost:8080/test-app/pet/list?name=Bob
I would want the query predicate to be built like this:
final BooleanBuilder petBuilder = new BooleanBuilder();
petBuilder.and(QPet.firstName.equals("Bob").or(QPet.lastName.equals("Bob")));
Is that possible? From looking at the customize method of the QuerydslBinderCustomizer it doesn't seem like it would be, since you need to bind off a field of the Q class. I'm guessing that what I want to do is not supported.
If these aren't possible, then I'll stick with manually creating the predicate, and passing that on to the repository.
You can use QuerydslBinderCustomizer to achieve your purpose. Heres some sample code that can help you out:
public interface PersonRepository extends JpaRepository<Job, Integer>,
QueryDslPredicateExecutor<Person>, QuerydslBinderCustomizer<QJob> {
#Override
public default void customize(final QuerydslBindings bindings, final QPerson person) {
bindings.bind(person.pets.any().name).first((path, value) -> {
return path.eq(value);
});
}
}
I ran into the same error. However I noticed that using the QuerydslAnnotationProcessor plugin (instead of the JPA annotation processor) allows me to query sub collections of entities as expected. You just have to mark all of your entity classes with the #QueryEntity annotation. (The JPA annotation processor automatically generates query classes for #Entity annotated classes.)
In your pom:
<plugin>
<groupId>com.mysema.maven</groupId>
<artifactId>apt-maven-plugin</artifactId>
<version>1.1.3</version>
<executions>
<execution>
<phase>generate-sources</phase>
<goals>
<goal>process</goal>
</goals>
<configuration>
<outputDirectory>target/generated-sources/annotations</outputDirectory>
<processor>com.querydsl.apt.QuerydslAnnotationProcessor</processor>
</configuration>
</execution>
</executions>
<dependencies>
<dependency>
<groupId>com.querydsl</groupId>
<artifactId>querydsl-apt</artifactId>
<version>4.1.3</version>
</dependency>
</dependencies>
</plugin>
I'm believe I was running into the exception you encountered because I changed from the JPA Annotation Processor to the QuerydslAnnotationProcessor, for some reason I do not recall, and neglected to mark the entity class of the list in question with the #QueryEntity annotation. However I also believe I have another Spring-Data-Rest\JPA backed API that uses the JPA Annotation Processor built in August 2017, and I believe querying sub collections of entities works as expected. I'll be able to confirm that later today, and provide the versions of the relevant dependencies if that is the case. Perhaps this issue has been fixed.

How to lazy load an entity attribute using JPA

I have a JSF application with JPA and EclipseLink. There is an entity with several attributes including a Lob type to store large binary data.
I need to frequently search the entities and display them in a list. Only when the user wants to view that, the Large Binary data is needed.
Can I have a method to lazy load the binary data? Or do I have to take it out as another entity with one to one relationship?
You either use bytecode enhancement along with #Basic(fetch=FetchType.LAZY) on attributes that are to be loaded lazily:
<plugin>
<groupId>org.hibernate.orm.tooling</groupId>
<artifactId>hibernate-enhance-maven-plugin</artifactId>
<version>${hibernate.version}</version>
<executions>
<execution>
<configuration>
<failOnError>true</failOnError>
<enableLazyInitialization>true</enableLazyInitialization>
</configuration>
<goals>
<goal>enhance</goal>
</goals>
</execution>
</executions>
</plugin>
Or you can define multiple subentities to the same database table. Considering you have an attachment table that has a content column which stores BLOBs.
You can map the non-lazy attributes in a common base class:
#MappedSuperclass
public class BaseAttachment {
#Id
#GeneratedValue
private Long id;
private String name;
#Enumerated
#Column(name = "media_type")
private MediaType mediaType;
//Getters and setters omitted for brevity
}
If you only need to fetch the non-lazy attributes, you need an entity which just extends the base class:
#Entity #Table(name = "attachment")
public class AttachmentSummary extends BaseAttachment {}
This will never fetch the content column.
If you need to fetch all columns including the content one, then you can use this entity:
#Entity #Table(name = "attachment")
public class Attachment
extends BaseAttachment {
#Lob
private byte[] content;
//Getters and setters omitted for brevity
}
Can be done easily. Use the following annotation.
#Basic(fetch=FetchType.LAZY)

How to use JPA Criteria API when joining many tables

This is the further question to this:
How to use JPA Criteria API in JOIN
CriteriaBuilder criteriaBuilder = em.getCriteriaBuilder();
CriteriaQuery<Company> criteria = criteriaBuilder.createQuery( Company.class );
Root<Company> companyRoot = criteria.from( Company.class );
Join<Company,Product> products = companyRoot.join("dentist");
Join<Company, City> cityJoin = companyRoot.join("address.city");//Company->Address->City-city
criteria.where(criteriaBuilder.equal(products.get("category"), "dentist"),      criteriaBuilder.equal(cityJoin.get("city"),"Leeds"));
A company has an address, inside the address there is City-pojo and Country-Pojo. How can I use it in JOIN? I tried to reference it with address.city but I got the error message:
The attribute [address.city] from the managed type
[EntityTypeImpl#1692700229:Company [ javaType: class
com.test.domain.Company descriptor:
RelationalDescriptor(com.test.domain.Company -->
[DatabaseTable(COMPANY)]), mappings: 16]] is not present.
If you use canonical Metamodel, you'll avoid this kind of errors.
In your code you have misused the "dentist" keyword, that's probably the cause of your error, because "dentist" is not a field in Company entity.
However, looking at how you defined your class in the other question, the way to define that join using Metamodel is this:
SetJoin<Company,Product> products = companyRoot.join(Company_.products);
As you can see, Metamodel avoids the use of strings, and so avoids a lot of runtime errors. If anyway you don't use Metamodel, try this:
SetJoin<Company,Product> products = companyRoot.join("products");
If you now want to add a predicate, i.e. something after the where, you'll write something like:
Predicate predicate = criteriaBuilder.equal(products.get(Product_.category), "dentist");
criteria.where(predicate);
If you want to add a join for the City entity:
Join<Company, City> city = companyRoot.join(Company_.city);
predicate = criteriaBuilder.and(predicate, criteriaBuilder.equal(city.get(City_.cityName), "Leeds");
criteria.where(predicate);
(supposing that the field cityName is the correct field name for your city).
Agree with #perissf.
I can't comment but the symbol "Company_" is the metadata class file which contains all the attribute name of the model class.
I strongly suggest to use metadata classes, you can autogenerate metadata classes using the maven processor plugin using org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor as processor in your configuration.
This example pom plugin xml should work it out :
<plugin>
<groupId>org.bsc.maven</groupId>
<artifactId>maven-processor-plugin</artifactId>
<executions>
<execution>
<goals>
<goal>process</goal>
</goals>
<phase>generate-sources</phase>
<configuration>
<processors>
<processor>org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor</processor>
</processors>
</configuration>
</execution>
</executions>
<dependencies>
<dependency>
<groupId>org.hibernate.orm</groupId>
<artifactId>hibernate-jpamodelgen</artifactId>
<version>${version.hibernate-jpamodelgen}</version>
</dependency>
</dependencies>
</plugin>

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