Develop Reference

Scanning a file and getting two tokens at a time and saving those in an ArrayList

Hi everyone this is my first question here so I apologize in advance if it is not in the correct format for this forum. I'm a comp sci student and I am really a novice programmer. For an assignment, I need to read in a file of polynomials and then sort them from highest degree to lowest. On each line of the file I have a coefficient and an exponent separated by a space.
This is what my .txt file looks like:
"5.6 3
4 1
8.3 0" which represents the polynomial 5.6x^3 + 4x + 8.3
I have to scan the file from a JFileChooser and then add the tokens to an ArrayList of type Polynomial. My question/problem is how can I run the file contents through a for loop and separate the first token(coefficients) from the second token(exponents) and then add them to the ArrayList? I'm going to need the exponents to be of type int and the coefficients should be double.
This is what I have so far:
ArrayList aList = new ArrayList();
// scanner used to read each line
try {
scan = new Scanner(file);
if (file.isFile()) {
while (scan.hasNext()) {
for (int i = 0; i < something.size(); i++) {
//this is where I'm lost, not sure what I need to do here
}
}
}
....
Thank you guys I appreciate the assistance.
-Linden
EDIT:
Alright I figured it out, it was a lot more complicated than I thought. Here's what I did:
Scanner scan = new Scanner(file);
if (file.isFile()) {
for (int i = 0; i <=2; i ++) {
term(scan);
}
}
static void term(Scanner scan) {
String s = scan.nextLine();
String [] splitter = s.split(" ");
String coefficient = splitter[0];
String exponent = splitter[1];
//populating
try {
arrayList.add(new Polynomial(coefficient, exponent));
} catch (InvalidPolynomialSyntax e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Thanks to the two guys that tried to help me out and the 24 viewers who didn't lol

First, you need to look at the scanner class. What methods does it have that you should use to get the data you need?
I don't want to give you the answer to your homework out of respect but broadly what you need is a way to get each line of that file from the scanner so you can compare the contents of each line to each other.
So look at the scanner class documentation and see what it has that you can use.
Start by simply trying to print out each line. Once you do that you can think about how you want to compare them.

you can read file as one sentence. First get all the text such as 5.6 3 4 1 8.3 0 as string. Then you can just use String [] arrayOfNumbers = yourString.split(" ");
This will split the string according to " " character so you get numbers directly.

Reading integers in a .txt file (Java)

So basically I'm trying to write a program where someone can enter 10 integers, that would then be saved in a .txt file, then opened and averaged together.
I'm doing pretty good so far, I got all the exception handling and saving a file with my inputted integers down, but I'm unsure how to read the file. I'm assuming calculating the average wouldn't be difficult once I have that all done anyways. Here's part of my code with the rest linked below (I really think you'd need to see the full code to better recognize the issue):
public static void closeFile()
{
if (output != null)
output.close();
}
public static void readRecords()
{
try
{
while (input.hasNext())
{
System.out.printf("%s%n", String.valueOf(numbers[i]));
}
}
}
http://pastebin.com/yW6G8N8C

You are not opening the file properly, you need to use a reader for that:
public static void readRecords(){
try (BufferedReader br = new BufferedReader(new FileReader("numbers.txt"))) {
String line;
int[] number = new int[10];
i=-1;
while ((line = br.readLine()) != null) {
i++;
number[i] = Integer.parseInt(line);
System.out.println("number "+i+" = "+number[i]);
}
}
catch(Exception e){
// Handle the trouble
}
}
I am not entirely sure what you want to do with your numbers you get or the exact format of the numbers.txt file but I am assuming you are doing something sensible, like writing one integer per line to your file. Otherwise, adjust the code accordingly to suit your needs.

First of all as mentioned by chalarangelo you are not opening the file correctly. You can use Formatter class to write to file but you can't read from file using that. So you need to use a proper reader like BufferedReader and use its readLine() method.
That aside is it necessary that you store integers together with the string
"Inputted integer: "... If so then its going to be a bit difficult to just get the numbers. I'd advise printing just numbers into the file i.e just do
output.format("%s%n", String.valueOf(numbers[i]));
instead of
output.format("Inputted integer: %s%n", String.valueOf(numbers[i]));
After that use a reader and read the line and convert it into integer and store it in the array as mentioned in chalarengo's answer.

Parse .csv File in java returns outofbounds exception

I have the following issue: I am trying to parse a .csv file in java, and store specifically 3 columns of it in a 2 Dimensional array. The Code for the method looks like this:
public static void parseFile(String filename) throws IOException{
FileReader readFile = new FileReader(filename);
BufferedReader buffer = new BufferedReader(readFile);
String line;
String[][] result = new String[10000][3];
String[] b = new String[6];
for(int i = 0; i<10000; i++){
while((line = buffer.readLine()) != null){
b = line.split(";",6);
System.out.println("ID: "+b[0]+" Title: "+b[3]+ "Description: "+b[4]); // Here is where the outofbounds exception occurs...
result[i][0] = b[0];
result[i][1] = b[3];
result[i][2] = b[4];
}
}
buffer.close();
}
I feel like I have to specify this: the .csv file is HUGE. It has 32 columns, and (almost) 10.000 entries (!).
When Parsing, I keep getting the following:
XXXXX CHUNKS OF SUCCESFULLY EXTRACTED CODE
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException:3
at ParseCSV.parseFile(ParseCSV.java:24)
at ParseCSV.main(ParseCSV.java:41)
However, I realized that SOME of the stuff in the file has a strange format e.g. some of the texts inside it for instance have newlines in them, but there is no newline character involved in any way. However, if I delete those blank lines manually, the output generated (before the error message is prompted) adds the stuff to the array up until the next blank line ...
Does anyone have an idea how to fix this? Any help would be greately appreciated...

Your first problem is that you probably have at least one blank line in your csv file. You need to replace:
b = line.split(";", 6);
with
b = line.split(";");
if(b.length() < 5){
System.err.println("Warning, line has only " + b.length() +
"entries, so skipping it:\n" + line);
continue;
}
If your input can legitimately have new lines or embedded semi-colons within your entries, that is a more complex parsing problem, and you are probably better off using a third-party parsing library, as there are several very good ones.
If your input is not supposed to have new lines in it, the problem probably is \r. Windows uses \r\n to represent a new line, while most other systems just use \n. If multiple people/programs edited your text file, it is entirely possible to end up with stray \r by themselves, which are not easily handled by most parsers.
A way to easily check if that's your problem is before you split your line, do
line = line.replace("\r","").
If this is a process you are repeating many times, you might need to consider using a Scanner (or library) instead to get more efficient text processing. Otherwise, you can make do with this.

When you have new lines in your CSV file, after this line
while((line = buffer.readLine()) != null){
variable line will have not a CSV line but just some text without ;
For example, if you have file
column1;column2;column
3 value
after first iteration variable line will have
column1;column2;column
after second iteration it will have
3 value
when you call "3 value".split(";",6) it will return array with one element. and later when you call b[3] it will throw exception.
CSV format has many small things, to implement which you will spend a lot of time. This is a good article about all possible csv examples
http://en.wikipedia.org/wiki/Comma-separated_values#Basic_rules_and_examples
I would recommend to you some ready CSV parsers like this
https://commons.apache.org/proper/commons-csv/apidocs/org/apache/commons/csv/CSVParser.html

String's split(pattern, limit) method returns an array sized to the number of tokens found up to the the number specified by the limit parameter. Limit is the maximum, not the minimum number of array elements returned.
"1,2,3" split with (",", 6) with return an array of 3 elements: "1", "2" and "3".
"1,2,3,4,5,6,7" will return 6 elements: "1", "2", "3", "4", "5" and ""6,7" The last element is goofy because the split method stopped splitting after 5 and returned the rest of the source string as the sixth element.
An empty line is represented as an empty string (""). Splitting "" will return an array of 1 element, the empty string.
In your case, the string array created here
String[] b = new String[6];
and assigned to b is replaced by the the array returned by
b = line.split(";",6);
and meets it's ultimate fate at the hands of the garbage collector unseen and unloved.
Worse, in the case of the empty lines, it's replaced by a one element array, so
System.out.println("ID: "+b[0]+" Title: "+b[3]+ "Description: "+b[4]);
blows up when trying to access b[3].
Suggested solution is to either
while((line = buffer.readLine()) != null){
if (line.length() != 0)
{
b = line.split(";",6);
System.out.println("ID: "+b[0]+" Title: "+b[3]+ "Description: "+b[4]); // Here is where the outofbounds exception occurs...
...
}
or (better because the previous could trip over a malformed line)
while((line = buffer.readLine()) != null){
b = line.split(";",6);
if (b.length() == 6)
{
System.out.println("ID: "+b[0]+" Title: "+b[3]+ "Description: "+b[4]); // Here is where the outofbounds exception occurs...
...
}
You might also want to think about the for loop around the while. I don't think it's doing you any good.
while((line = buffer.readLine()) != null)
is going to read every line in the file, so
for(int i = 0; i<10000; i++){
while((line = buffer.readLine()) != null){
is going to read every line in the file the first time. Then it going to have 9999 attempts to read the file, find nothing new, and exit the while loop.
You are not protected from reading more than 10000 elements because the while loop because the while loop will read a 10001th element and overrun your array if there are more than 10000 lines in the file. Look into replacing the big array with an arraylist or vector as they will size to fit your file.

Please check b.length>0 before accessing b[].

counting the number of lines in a text file (java)

Below is how i count the number of lines in a text file. Just wondering is there any other methods of doing this?
while(inputFile.hasNext()) {
a++;
inputFile.nextLine();
}
inputFile.close();
I'm trying to input data into an array, i don't want to read the text file twice.
any help/suggestions is appreciated.
thanks

If you are using java 7 or higher version you can directly read all the lines to a List using readAllLines method. That would be easy
readAllLines
List<String> lines = Files.readAllLines(Paths.get(fileName), Charset.defaultCharset());
Then the size of the list will return you number of lines in the file
int noOfLines = lines.size();

If you are using Java 8 you can use streams :
long count = Files.lines(Paths.get(filename)).count();
This will have good performances and is really expressive.
The downside (compared to Thusitha Thilina Dayaratn answer) is that you only have the line count.
If you also want to have the lines in a List, you can do (still using Java 8 streams) :
// First, read the lines
List<String> lines = Files.lines(Paths.get(filename)).collect(Collectors.toList());
// Then get the line count
long count = lines.size();

If you just want to add the data to an array, then I append the new values to an array. If the amount of data you are reading isn't large and you don't need to do it often that should be fine. I use something like this, as given in this answer: Reading a plain text file in Java
BufferedReader fileReader = new BufferedReader(new FileReader("path/to/file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
If you are reading in numbers, the strings can be converted to numbers, say for integers intValue = Integer.parseInt(text)

I do not have enough reputation to comment but #superbob answer is almost perfect, indeed you must ensure to pass Charset.defaultCharset() as 2nd parameter like :
Files.lines(file.toPath(), Charset.defaultCharset()).count()
That's because Files.lines used UTF-8 by default and then using as it is on non default UTF-8 system can produce java.nio.charset.MalformedInputException.

Storing input from text file

My question is quite simple, I want to read in a text file and store the first line from the file into an integer, and every other line of the file into a multi-dimensional array. The way of which I was thinking of doing this would be of creating an if-statement and another integer and when that integer is at 0 store the line into the integer variable. Although this seems stupid and there must be a more simple way.
For example, if the contents of the text file were:
4
1 2 3 4
4 3 2 1
2 4 1 3
3 1 4 2
The first line "4", would be stored in an integer, and every other line would go into the multi-dimensional array.
public void processFile(String fileName){
int temp = 0;
int firstLine;
int[][] array;
try{
BufferedReader input = new BufferedReader(new FileReader(fileName));
String inputLine = null;
while((inputLine = input.readLine()) != null){
if(temp == 0){
firstLine = Integer.parseInt(inputLine);
}else{
// Rest goes into array;
}
temp++;
}
}catch (IOException e){
System.out.print("Error: " + e);
}
}

I'm intentionally not answering this to do it for you. Try something with:
String.split
A line that says something like array[temp-1] = new int[firstLine];
An inner for loop with another Integer.parseInt line
That should be enough to get you the rest of the way

Instead, you could store the first line of the file as an integer, and then enter a for loop where you loop over the rest of the lines of the file, storing them in arrays. This doesn't require an if, because you know that the first case happens first, and the other cases (array) happen after.

I'm going to assume that you know how to use file IO.
I'm not extremely experienced, but this is how I would think about it:
while (inputFile.hasNext())
{
//Read the number
String number = inputFile.nextLine();
if(!number.equals(" ")){
//Do what you need to do with the character here (Ex: Store into an array)
}else{
//Continue on reading the document
}
}
Good Luck.