I am making a game with java as kind of a side project and am still new to the language. I was wondering how I could run a file when i didn't know the complete path, like if I were to send the game to a friend, and he has a different path location than me.
Thank you in advance for any help.
code I am currently using:
File file = new File("/Users/(my name)/Desktop/script1.vbs");
Desktop desktop = Desktop.getDesktop();
if(file.exists()) desktop.open(file);`
You could place the file (script1.vbs) in the project folder, that way the path would always be like this...
File file = new File("script1.vbs")
Place the file, not in the src or bin folder, but in the root folder.
Instead of
File file = new File("/Users/(my name)/Desktop/script1.vbs");
you should better use
File file = new File(System.getProperty("user.home"), "Desktop/script1.vbs");
See also the list of System Properties
Or you can use this, to locate your file in the resources folder:
File file = new File("classpath:com/company/script1.vbs");
"classpath:Route Of Source folders/Name and extension of the file"
Related
I have a text file that I am trying to read from using a BufferedReader however I'm not sure where I should place this text file in my Java Project and also what that directory would be called.
For example:
File file = new File(Directory that needs to be specified);
From what I understood you are not sure where is your root directory, put your file in you project home directory instead of /src . For example if your project is called MyProject, put your file in .../MyProject/myfile.txt and your relative path would look like this: File file = new File("myfile.txt");
If you want your file in separate folder put it for example in /MyProject/resources/ and then your path would look like this:
File file = new File("/resources/myfile.txt");
I have created a .txt file in my Eclipse Java project, and I want to find out the path to it so I can use it for a Scanner. I do not want to find out the path on my local drive, as I will be planning to share the program to someone else, and they will have a different folder structure, rather a path that can be used on anybodies machine.
Here is the code:
this.file = new File("<insert path here>");
you can use :
= new File("Build Path"); (your .java file exist in your build path)
The build path is used for building your application. It contains all of your source files and all Java libraries that are required to compile the application.
In eclipse, the default behavior is for the Java system property user.dir to be set to the project directory. This is what dictates where the "root" of File operations is. So if you created a file test.txt in the root project directory, you should be able to access it with new File("test.txt").
However, as Andrew Thompson mentioned in his comment, the more correct method would be using embedded resources.
Try one of These:
1.
System.getProperty("user.dir");
2.
File currentDirFile = new File(".");
String helper = currentDirFile.getAbsolutePath();
String currentDir = helper.substring(0, helper.length() - currentDirFile.getCanonicalPath().length());//this line may need a try-catch
I have not tested it just found while googling
I am trying to access a text file, output.txt which is inside a project folder. The image below shows the folder structure.
String file=".\\testFiles\\output.txt";
BufferedReader br=new BufferedReader(new FileReader(file));
When I try to access that file using the code above, I get the following exception.
java.io.FileNotFoundException: .\testFiles\output.txt (No such file or directory)
I have tried different file path formats but none have worked. I think the problem is with the file path format.
Thanks in advance.
If I remember correctly you can get a folder/file in the current directory like so:
File folder = new File("testFiles");
Then you can open the file by getting the absolutePath and creating a new file with it, like so:
File file = new File(folder.getAbsoluteFile() + File.separator + "output.txt");
I'm not sure but I think you can also do:
File file = new File("testFiles/output.txt");
I hope this helps :)
P.S. this is all untested so it might not work.
Judging by the fact that you have a webcontent folder i presume this is a web project, possibly packaged as a war? In this case what you will want to do is package the respective files along with the classes and access it with something like this:
Thread.currentThread().getContextClassLoader().getResourceAsStream("output.txt")
The code above will work if you add the testFiles folder as a source folder (this means it will get packaged with the classes and be available at runtime)
The good thing is that this way the path can stay relative, no need to go absolute
I believe that your problem is due to the fact that you rely on a relative path as your path starts with a dot which means that it will by relative to the user directory (value of the system property user.dir) so I believe that your user directory is not what you expect. What you could do to debug is simply this:
System.out.println(new File(file).getAbsolutePath());
Thanks to this approach you will be able to quickly know if the absolute path is correct.
You must declare your file as a new file:
File yourFile = new File("testFiles/output.txt");
I am using a method that requires a string path to a file that is in my src directory structure in eclipse. Is the path to this file simply src\fileName.txt or is there a different way i should be getting this file as it doesnt seem to be working currently
Thanks
Run this and you will never forget how to remember.
File file = new File("sample.txt");
System.out.println(file.getAbsolutePath());
If you are following the maven standard directory structure, class files will be located relative to the classpath like so:
If you want SomeClass.class, you would access it by com.mydomain.packageorappname.deeperpackage.SomeClass. Is that what you are asking?
I'm trying to get the path to a file that it is located out of the java jar and I don't want to use an absolute path. An exampel: lets say that the jar is located in ~/lib/myjar.jar and the file is located in the same folder. What I've trying is something like this, but it fails:
File myfile = new File(this.getClass().getResource("../../../").toURI());
Note: my package is com.contro.gui, that's why I have "../../../", in order to acces to the "root"
I'm not sure how I can access to the file. Any suggestion?? And what about if the file that I want to access is in other folder like ~/res/ ???
If the file is in the same directory as the jar, I think this will work (feels fairly hacky, but...):
URL url = getClass().getProtectionDomain().getCodeSource().getLocation();
File myfile = new File(url.toURI());
File dir = myfile.getParentFile(); // strip off .jar file
(Haven't tested this, but it seems feasible. Will only work with file-based jars of course).
If the file is in some random location, I think you will need to either pass in parameters or check "known" locations like user.home. (Or, you could always put the file in the jar a use getResource().)
No just do
File FileName = new File(".");
String Directory = FileName.getCanonicalPath();
that will get you the parent directory of your class in a file or jar just remember to set the directory if it's in a jar like this "NameOfJar\NameOfFolder\etc"