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spring boot jdbcTemplate.query throws table not found auto converting table name to upper case

i have a jdbcTemplate.query method with query bit complex with multiple left joins, so its difficult for me to implement interface based repository methods.
I am using a MySQL db from AWS RDS.
when the query is executing spring boot jpa automatically converting table name to upper case and it throws error as: table not found.
exception is:
with path [] threw exception [Request processing failed; nested exception is org.springframework.jdbc.BadSqlGrammarException: StatementCallback; bad SQL grammar [SELECT DISTINCT test_desc FROM test_name_table]; nested exception is org.h2.jdbc.JdbcSQLSyntaxErrorException: Table "TEST_NAME_TABLE" not found; SQL statement:
SELECT DISTINCT test_desc FROM test_name_table [42102-200]] with root cause
org.h2.jdbc.JdbcSQLSyntaxErrorException: Table "TEST_NAME_TABLE" not found; SQL statement:
SELECT DISTINCT test_desc FROM test_name_table [42102-200]
here are the solutions i have tried:
from application.properties:
spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl
spring.jpa.database-platform=org.hibernate.dialect.MySQL8Dialect
spring.jpa.hibernate.naming_strategy = org.hibernate.cfg.DefaultNamingStrategy
database url:
spring.datasource.dataSourceProperties.serverName=test-instance.us-east-1.rds.amazonaws.com;DATABASE_TO_UPPER=FALSE;CASE_INSENSITIVE_IDENTIFIERS=TRUE;
as you see above sql query, i have even put the table name inside backtick. but no luck.
I tried to rename the table name in MySQL to TEST_NAME_TABLE, but still no luck.
any recommended fix for this?

its a good practice use #Table(name = "table_name") for a model and #Column(name = "column_name") annotation for every column in your Model.java
and use #Query("some query in SQL") for every query you use in ModelRepository.java
example:
#Entity
#Table
public class Employee implements Serializable {
#Id
#Column(name = "emp_id")
private Long id;
#Column(name = "name")
private String name;
#Column(name = "email")
private String email;
#Column(name = "jobTitle")
private String jobTitle;
#Column(name = "phone")
private String phone;
#Column(name = "imagUrl")
private String imageUrl;
#Column(name = "employeeCode")
private String employeeCode;
}
#Repository
public interface EmployeeRepository extends JpaRepository<Employee, Long> {
#Query("SELECT s FROM Employee s WHERE s.email = ?1")
Optional<Employee> findEmployeeByEmail(String email);
}

Spring jpa Entity field List<String> to postgre array filed not working

I have an Entity like this:
#Entity
#Data
public class Cat {
#Id
private String catId;
private String catName;
private List<String> favFoods;
}
When I start my Spring boot, it shows this error:
Error creating bean with name 'entityManagerFactory' defined in class path resource [org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Could not determine type for: java.util.List
I drop the table Cat in DB before starting the app
My yml setting is:
spring:
datasource:
url: jdbc:postgresql://localhost:5432/localtest
username: catuser
password:
jpa:
show-sql: false
hibernate:
ddl-auto: create
properties:
hibernate:
dialect: org.hibernate.dialect.PostgreSQLDialect
format_sql: true
If I comment out the field of List, everything works fine.
Is there any annotation that I need to add to solve this problem?
Thank you

You can also use the following code snippet
#ElementCollection
#CollectionTable(name = "my_list", joinColumns = #JoinColumn(name =
"id"))
#Column(name = "list")
List<String> favFoods;
See here

You have to tell Hibernate how to map the list by annotating you class with #TypeDef(name = "list-array",typeClass = ListArrayType.class) and annotating the list with #Type(type = "list-array") i.e.:
#Entity
#Data
#TypeDef(
name = "list-array",
typeClass = ListArrayType.class
)
public class Cat {
#Id
private String catId;
private String catName;
#Type(type = "list-array")
private List<String> favFoods;
}

Not able to fetch result using foreign key. No property found error

I am trying to fetch all rows with my foreign key attribute but I am getting error
Doctor class
#Entity
#Table(name = "doctors")
public class Doctor implements Serializable {
#Column(name = "doctor_id")
private #Id #GeneratedValue(strategy = GenerationType.IDENTITY) int doctorid;
private #NotBlank String doctor_name;
private #NotBlank String speciality;
Appointment class
#Entity
#Table(name = "appointments")
public class Appointment implements Serializable {
#Id
#GeneratedValue
private #NotBlank int App_id;
private #NotBlank String date;
private #NotBlank String time;
#ManyToOne(targetEntity = Doctor.class,cascade = {CascadeType.ALL})
#JsonBackReference("doctors")
#JoinColumn(name = "doctor_id")
private Doctor doctor_id;
Controller
#GetMapping("/appointmentsbydoctor")
public ResponseEntity<Object> doctorsappointment(#Valid #RequestParam(name = "doctor_id") int id) {
return new ResponseEntity<>(appointmentService.appointment(id), HttpStatus.OK);
}
Service class
public List<Appointment> appointment(int id){
List<Appointment> a= appointmentRepository.findAllByDoc(id);
return a;
}
Repository
public interface AppointmentRepository extends JpaRepository<Appointment, Integer> {
#Query(name="select * from Appointment a where a.doctor_id.doctorid=:id",nativeQuery = true)
List<Appointment> findAllByDoc(int id);
I am getting this error
org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'appointmentController' defined in file [D:\courses\Inellij\appointment\target\classes\com\doctor\appointment\controller\AppointmentController.class]: Unsatisfied dependency expressed through constructor parameter 0; nested exception is org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'appointmentServiceImpl': Unsatisfied dependency expressed through field 'appointmentRepository'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'appointmentRepository' defined in com.doctor.appointment.repository.AppointmentRepository defined in #EnableJpaRepositories declared on AppointmentApplication: Invocation of init method failed; nested exception is org.springframework.data.repository.query.QueryCreationException: Could not create query for public abstract java.util.List com.doctor.appointment.repository.AppointmentRepository.findAllByDoc(int)! Reason: Failed to create query for method public abstract java.util.List com.doctor.appointment.repository.AppointmentRepository.findAllByDoc(int)! No property doc found for type Appointment!; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.List com.doctor.appointment.repository.AppointmentRepository.findAllByDoc(int)! No property doc found for type Appointment!
at org.springframework.beans.factory.support.ConstructorResolver.createArgumentArray(ConstructorResolver.java:800) ~[spring-beans-5.3.9.jar:5.3.9]
What should I do, I looked for a lot of solution but nothing works. How should I proceed further?

By changing my query value= to name=, I was able to solve the problem. The latter is used to reference a named query

I am getting an error (HttpMessageNotWritableException: Could not write JSON: Invalid property '' of bean class) when using getter method

I am using an interface LoanInterface.java to display values upon request. My problem is I am encountering this error:
Invalid property 'accountNumber' of bean class [com.meteor.coral.portfolio.modules.loanaccount.domain.Loan$HibernateProxy$Vm2InzHB]:
Getter for property 'accountNumber' threw exception; nested exception is java.lang.reflect.InvocationTargetException;
nested exception is com.fasterxml.jackson.databind.JsonMappingException: Invalid property 'accountNumber' of bean class
[com.meteor.coral.portfolio.modules.loanaccount.domain.Loan$HibernateProxy$Vm2InzHB]: Getter for property 'accountNumber' threw exception;
nested exception is java.lang.reflect.InvocationTargetException
(through reference chain: org.springframework.data.domain.PageImpl["content"]
->java.util.Collections$UnmodifiableRandomAccessList[0]->com.sun.proxy.$Proxy394["loanId"]->com.sun.proxy.$Proxy395["accountNumber"])]
This is my LoanInterface.java
#JsonPropertyOrder({
"id",
"accountNumber"
})
public interface LoanInterface {
public Long getId();
public String getAccountNumber();
}
This is the model, Loan.java, where I want to get the fields:
#Entity
#Component
#Data
#EqualsAndHashCode(callSuper = false)
#Table(name = "m_loan", uniqueConstraints = { #UniqueConstraint(columnNames = { "account_no" }, name = "loan_account_no_UNIQUE"),
#UniqueConstraint(columnNames = { "external_id" }, name = "loan_externalid_UNIQUE") })
public class Loan extends AbstractPersistableCustom<Long> {
#Column(name = "account_no", length = 20, unique = true, nullable = false)
private String accountNumber;
}
The id is inside the AbstractPersistableCustom class which is being extended inside Loan.java.
This is BillingProcessInterface.java where I call the LoanInterface.java
#JsonPropertyOrder({
"id",
"loanId"
})
public interface BillingProcessInterface {
public Long getId();
public LoanInterface getLoanId();
}
BillingProcess.java model, where I call the Loan.java
#Entity
#Table(name = "m_billing")
#Data
#EqualsAndHashCode(callSuper = true)
public class BillingProcess extends AbstractPersistableCustom<Long> {
#ManyToOne(optional = false, fetch = FetchType.LAZY)
#JoinColumn(name = "loan_id", nullable = false)
private Loan loanId;
}
The getId from LoanInterface.java works:
But when I try to get other fields from Loan.java like the accountNumber, I am getting the error.
Does anyone have an idea how to resolve this? Have I overused or lacked something regards the usage of annotation?
Thank you.

Looks like you're trying to do projection from lazy loaded field.
#ManyToOne(optional = false, fetch = FetchType.LAZY)
#JoinColumn(name = "loan_id", nullable = false)
private Loan loanId;
Projection happens outside transaction so you have to have loaded fields before you use them. You can achieve it by changing fetch type to EAGER or use '#EntityGraph' annotation in repository to specify which lazy fields should be loaded.

org.hibernate.MappingException - composite id

In my Spring boot - JPA application, I am trying to implement composite key :
#Entity
public class User
{
#Id
private String timeStamp;
#Id
private String firstName;
#Id
private String lastName;
}
This gives me error, saying :
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.MappingException: Composite-id class must implement Serializable: com.mua.testkeys.model.User
Even if I implement Serializable it gives me error.
How can I resolve this ?
Used : Spring + JPA + H2

Composite Key can be created with #IdClass as below.
User.class
#IdClass(UserPK.class)
#Table(name = "user")
#Entity
public class User {
#Id
private String timeStamp;
#Id
private String firstName;
#Id
private String lastName;
//remaining fields
// getters and setters
}
UserPK.class
public class UserPK {
private String timeStamp;
private String firstName;
private String lastName;
// constructors
// getters and setters
//implement euquels() and hashcode()
}
Define a Class for primary key with all keys as fields.
Implement equals() and hashcode() methods.
Annotate User class with #IdClass(UserPK.class)
Declare Id fields with #Id annotation