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Execute two threads which wait one for the other while main thread continues

How can I start two threads where thread1 executes first, thread2 starts when thread1 ends while the main method thread can continue its work without locking on the other two?
I have tried join() however it needs to be called from the thread which has to wait for the other, there's no way to do something like thread2.join(thread1);
If I call for a join inside main() I therefore effectively stop execution of the main thread and not only of thread2.
I therefore tried with ExecutorService but again same problem.
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.TimeUnit;
public class Test
{
public static void main(String args[]) throws InterruptedException
{
System.out.println(Thread.currentThread().getName() + " is Started");
class TestThread extends Thread
{
String name;
public TestThread(String name)
{
this.name = name;
}
#Override
public void run()
{
try
{
System.out.println(this + " is Started");
Thread.sleep(2000);
System.out.println(this + " is Completed");
}
catch (InterruptedException ex) { ex.printStackTrace(); }
}
#Override
public String toString() { return "Thread " + name; }
}
ExecutorService executor = Executors.newCachedThreadPool();
executor.execute(new TestThread("1"));
boolean finished = executor.awaitTermination(1, TimeUnit.HOURS);
if(finished)
{
//I should execute thread 2 only after thread 1 has finished
executor.execute(new TestThread("2"));
}
//I should arrive here while process 1 and 2 go on with their execution
System.out.println("Hello");
}
}
#EDIT: Why I need this:
I need this because Thread1 copies elements from a database table into another database, thread2 has to copy a linking table which references the table copied from thread1.
Consequently thread2 has to start populating its linking table only when thread1 has finished otherwise an integrity error is given by the database.
Now imagine I have several threads with different priorities due to complex linking tables and you have an idea.

The second Thread can be custom like this (takes as argument the previous thread):
public static void main(String[] a) {
Thread first = new Thread(new Runnable() {
#Override
public void run() {
}
});
Thread second = new MyThread(first);
first.start();
second.start();
//continue executing
}
public static class MyThread extends Thread {
private Thread predecessor;
public MyThread(Thread predecessor) {
this.predecessor = predecessor;
}
public void run() {
if (predecessor != null && predecessor.isAlive()) {
try {
predecessor.join();
} catch (InterruptedException e) {}
}
//do your stuff
}
}

You can use a CountDownLatch:
create it in the main thread, pass it on to both threads and call countdown on it in thread one when it exits and await it being counted down at the start of thread 2.

I am pretty sure you got something wrong because this must work and it does work:
new Thread() {
#Override
public void run() {
TestThread t1= new TestThread("1");
TestThread t2= new TestThread("2");
try {
t1.start();
t1.join();
t2.start();
t2.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}.start();
The ouput is:
main is Started
Hello
Thread 1 is Started
Thread 1 is Completed
Thread 2 is Started
Thread 2 is Completed
Another option would be to extend the TestThread for the "Thread 1" to execute the work of "Thread 2" after it has been done with its own work. Something similar to this:
final TestThread t2= new TestThread("2");
TestThread t1= new TestThread("1") {
#Override
public void run() {
super.run(); //finish t1 work
t2.start(); // start t2 work
}
};
t1.start();

Why not just have thread1 be the one to start thread2?
// in main
new Thread(new Runnable() {
#Override public void run() {
// do thread1 work
new Thread(new Runnable() {
#Override public void run() { /* do thread2 work */ }
}).start();
}
}).start();
However, it's not at all clear why you would want to do this as opposed to just having thread1 do 100% of the background work.

You can use SingleThreadExecutor to run one task after another Java doc
So it will put your task one after another and they will execute in sequence without blocking main thread

Try this, This will work as expected. Two threads printing odd and even one after another and main exiting as soon as possible.
public class YoThreD {
static boolean isThread1 = false;
public static synchronized boolean isThread1() {
return isThread1 = !isThread1;
}
public static void main(String args[]) {
Runnable runnableObject = new Runnable() {
#Override
public void run() {
synchronized (this) {
for (int i = 1; i <= 100; i++) {
try {
if (Thread.currentThread().getName().equals("thread1")) {
if (isThread1()){
System.out.println(Thread.currentThread().getName() + " : " + i);
}else{
this.notify();
this.wait();
}
} else {
if (!isThread1()){
System.out.println(Thread.currentThread().getName() + " : " + i);
this.notify();
this.wait();
}
else{
}
}
} catch (Exception e) {
}
}
}
}
};
Thread thread1 = new Thread(runnableObject);
thread1.setName("thread1");
thread1.start();
Thread thread2 = new Thread(runnableObject);
thread2.setName("thread2");
thread2.start();
System.out.println(Thread.currentThread().getName() + "Main thread finished");
}
}

Silly question, but if thread 2 is supposed to execute when thread 1 is done... why not just start it from thread 1?
Or maybe just have thread 1 trigger an event and the main thread can just launch the new one in response to that.
I found this example, should work for you.

You can run two thread one after other by using several ways:
by using join() method. ex:
Thread t1=new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 4; i++) {
System.out.println("A " + i);
}
}
});
Thread t2=new Thread(new Runnable() {
#Override
public void run() {
for (int i = 0; i < 4; i++) {
System.out.println("B " + i);
}
}
});
by using wait() and notify() methods: ex.
`
{
public class NotiffyAllExample {
int flag = 1;
public static void main(String[] args) {
NotiffyAllExample notiffyAllExample = new NotiffyAllExample();
A1 a = new A1(notiffyAllExample);
B1 b = new B1(notiffyAllExample);
C1 c = new C1(notiffyAllExample);
a.start();
b.start();
}
}
class A1 extends Thread {
NotiffyAllExample notiffyAllExample;
public A1(net.citigroup.mexico.pg.test.test.NotiffyAllExample notiffyAllExample) {
this.notiffyAllExample = notiffyAllExample;
}
#Override
public void run() {
try {
synchronized (notiffyAllExample) {
for (int i = 0; i < 4; i++) {
while (notiffyAllExample.flag != 1) {
notiffyAllExample.wait();
}
System.out.print("A ");
}
notiffyAllExample.flag = 2;
notiffyAllExample.notifyAll();
}
} catch (Exception e) {
System.out.println("Exception 1 :" + e.getMessage());
}
}
}
class B1 extends Thread {
NotiffyAllExample notiffyAllExample;
public B1(NotiffyAllExample notiffyAllExample) {
this.notiffyAllExample = notiffyAllExample;
}
#Override
public void run() {
try {
synchronized (notiffyAllExample) {
for (int i = 0; i < 4; i++) {
while (notiffyAllExample.flag != 2) {
notiffyAllExample.wait();
}
System.out.print("B ");
}
notiffyAllExample.flag = 1;
notiffyAllExample.notifyAll();
}
} catch (Exception e) {
System.out.println("Exception 2 :" + e.getMessage());
}
}
}
}
`

countdown multiple threads java

I have 4 threads witch are printing numbers from 15 to 0.I want to control executing of my threads for example I want first to thread D to finish and after him thread C and after him thread B and finally thread A. For now they are doing it all parallel.
How can I change that? any suggestions?
Here is my code:
// Suspending and resuming a thread for Java 2
class NewThread implements Runnable {
String name; // name of thread
Thread t;
boolean suspendFlag;
NewThread(String threadname) {
name = threadname;
t = new Thread(this, name);
System.out.println("New thread: " + t);
suspendFlag = false;
t.start(); // Start the thread
}
// This is the entry point for thread.
public void run() {
try {
for(int i = 15; i > 0; i--) {
System.out.println(name + ": " + i);
Thread.sleep(200);
synchronized(this) {
while(suspendFlag) {
wait();
}
}
}
} catch (InterruptedException e) {
System.out.println(name + " interrupted.");
}
System.out.println(name + " exiting.");
}
void mysuspend() {
suspendFlag = true;
}
synchronized void myresume() {
suspendFlag = false;
notify();
}
}
public class SuspendResume {
public static void main(String args[]) {
NewThread A = new NewThread("A");
NewThread B = new NewThread("B");
NewThread C = new NewThread("C");
NewThread D = new NewThread("D");
// try {
// System.out.println("****************************************************************");
// System.out.println(A.t.getState());
// System.out.println(B.t.getState());
// System.out.println(C.t.getState());
// System.out.println(D.t.getState());
//
// if(D.t.isAlive())
// {
// System.out.println("Bla bla bla");
// }
//
// Thread.sleep(1000);
// A.mysuspend();
// System.out.println("Suspending thread One");
// Thread.sleep(1000);
// A.myresume();
// System.out.println("Resuming thread One");
// B.mysuspend();
// System.out.println("Suspending thread Two");
// Thread.sleep(1000);
// B.myresume();
// System.out.println("Resuming thread Two");
//
//
//
// } catch (InterruptedException e) {
// System.out.println("Main thread Interrupted");
// }
// wait for threads to finish
try {
System.out.println("Waiting for threads to finish.");
A.t.join();
B.t.join();
C.t.join();
D.t.join();
} catch (InterruptedException e) {
System.out.println("Main thread Interrupted");
}
System.out.println("Main thread exiting.");
}
}

I think you should design structure of you service class first. I can suggest following:
public class Service {
private List<Service> dependencies;
// Starts service.
// It should wait until all dependencies started using awaitStart method and then start itself
public void start();
// Blocks current thread until service is started.
// If it is started returns immediately.
public void awaitStart();
// Stops service.
// Awaits until all dependencies are stopped using awaitStop.
public void stop();
// Blocks current thread until service is stopped.
// If it is already stops returns immediately
public void awaitStop();
// Actual code that has service specific code.
// This method may be invoked as last line in 'start' method.
public void run();
}
Next problem is to implement start and awaitStart (stop methods implemented similar). I recommend to use tools from java.util.concurrent for implementing awaitStart method. E.g. CountDownLatch. Each service has it's own latch that indicates that server is started. So code for awaitStart and start is following:
private CountDownLatch started = new CountDownLatch(1);
public void awaitStart() {
started.await();
}
public void start() {
for (Service service : dependencies) {
service.awaitStart();
}
System.out.println("Service " + name + " is started");
started.countDown();
run();
}

Time out method in java

In a java class I have a method that sometimes takes a long time for execution. Maybe it hangs in that method flow. What I want is if the method doesn't complete in specific time, the program should exit from that method and continue with the rest of flow.
Please let me know is there any way to handle this situation.

You must use threads in order to achieve this. Threads are not harmful :) Example below run a piece of code for 10 seconds and then ends it.
public class Test {
public static void main(String args[])
throws InterruptedException {
Thread thread = new Thread(new Runnable() {
#Override
public void run() {
System.out.println("0");
method();
}
});
thread.start();
long endTimeMillis = System.currentTimeMillis() + 10000;
while (thread.isAlive()) {
if (System.currentTimeMillis() > endTimeMillis) {
System.out.println("1");
break;
}
try {
System.out.println("2");
Thread.sleep(500);
}
catch (InterruptedException t) {}
}
}
static void method() {
long endTimeMillis = System.currentTimeMillis() + 10000;
while (true) {
// method logic
System.out.println("3");
if (System.currentTimeMillis() > endTimeMillis) {
// do some clean-up
System.out.println("4");
return;
}
}
}
}

Execute the method in a different thread, you can end a thread at anytime.

Based on the above snipplet, I tried creating a glorified spring bean.
Such executor runs the passed limitedRuntimeTask in limited runtimeInMs.
If the task finishes within its time limits, the caller continues normally in execution.
If the limitedRuntimeTask fails to finish in the defined runtimeInMs,
the caller will receive the thread execution back. If a timeBreachedTask was defined,
it will be executed before returning to caller.
public class LimitedRuntimeExecutorImpl {
public void runTaskInLessThanGivenMs(int runtimeInMs, final Callable limitedRuntimeTask, final Callable timeBreachedTask) {
Thread thread = new Thread(new Runnable() {
#Override
public void run() {
try {
LOGGER.info("Started limitedRuntimeTask");
limitedRuntimeTask.call();
LOGGER.info("Finished limitedRuntimeTask in time");
} catch (Exception e) {
LOGGER.error("LimitedRuntimeTask exception", e);
}
}
});
thread.start();
long endTimeMillis = System.currentTimeMillis() + runtimeInMs;
while (thread.isAlive()) {
if (System.currentTimeMillis() > endTimeMillis) {
LOGGER.warn("LmitedRuntimeTask did not finish in time (" + runtimeInMs + ")ms. It will run in vain.");
if(timeBreachedTask != null ){
try {
LOGGER.info("Executing timeBreachedTask");
timeBreachedTask.call();
LOGGER.info("Finished timeBreachedTask");
} catch (Exception e) {
LOGGER.error("timeBreachedTask exception", e);
}
}
return;
}
try {
Thread.sleep(10);
}
catch (InterruptedException t) {}
}
}
}

I feel the approach in accepted answer is a bit outdated. With Java8, it can be done much simpler.
Say, you have a method
MyResult conjureResult(String param) throws MyException { ... }
then you can do this (keep reading, this is just to show the approach):
private final ExecutorService timeoutExecutorService = Executors.newSingleThreadExecutor();
MyResult conjureResultWithTimeout(String param, int timeoutMs) throws Exception {
Future<MyResult> future = timeoutExecutorService.submit(() -> conjureResult(param));
return future.get(timeoutMs, TimeUnit.MILLISECONDS);
}
of course, throwing Exception is bad, here is the correct extended version with proper error processing, but I suggest you examine it carefully, your may want to do some things differently (logging, returning timeout in extended result etc.):
private final ExecutorService timeoutExecutorService = Executors.newSingleThreadExecutor();
MyResult conjureResultWithTimeout(String param, int timeoutMs) throws MyException {
Future<MyResult> future = timeoutExecutorService.submit(() -> conjureResult(param));
try {
return future.get(timeoutMs, TimeUnit.MILLISECONDS);
} catch (InterruptedException e) {
//something interrupted, probably your service is shutting down
Thread.currentThread().interrupt();
throw new RuntimeException(e);
} catch (ExecutionException e) {
//error happened while executing conjureResult() - handle it
if (e.getCause() instanceof MyException) {
throw (MyException)e.getCause();
} else {
throw new RuntimeException(e);
}
} catch (TimeoutException e) {
//timeout expired, you may want to do something else here
throw new RuntimeException(e);
}
}

In Java: how can I make thread watch over another thread?

Sorry if the question is quite simple. I am a beginner.
I have to create thread that calulates something, while the first thread works the other one have to measure if the first thread calculate the function in specified time. If not, it has to throw exception. Else it returns the answer.

I'd take the java.util.concurrent components - simple example
public void myMethod() {
// select some executor strategy
ExecutorService executor = Executors.newFixedThreadPool(1);
Future f = executor.submit(new Runnable() {
#Override
public void run() {
heresTheMethodToBeExecuted();
}
});
try {
f.get(1000, TimeUnit.MILLISECONDS);
} catch (InterruptedException e) {
// do something clever
} catch (ExecutionException e) {
// do something clever
} catch (TimeoutException e) {
// do something clever
}
}

Have your thread notify a synchronization object when it is done and have your other thread wait x number of milliseconds for it to finish.
public class Main {
private static final Object mThreadLock = new Object();
static class DoTaskThread extends Thread {
public void run() {
try {
int wait = new Random().nextInt(10000);
System.out.println("Waiting " + wait + " ms");
Thread.sleep(wait);
} catch (InterruptedException ex) {
}
synchronized (mThreadLock) {
mThreadLock.notifyAll();
}
}
}
/**
* #param args the command line arguments
*/
public static void main(String[] args) {
synchronized (mThreadLock) {
DoTaskThread thread = new DoTaskThread();
thread.start();
try {
// Only wait 2 seconds for the thread to finish
mThreadLock.wait(2000);
} catch (InterruptedException ex) {
}
if (thread.isAlive()) {
throw new RuntimeException("thread took too long");
} else {
System.out.println("Thread finished in time");
}
}
}
}

join is a lot simpler than using a lock.
join (millis)
Waits at most millis milliseconds
for this thread to die. A timeout of 0
means to wait forever.
Example code:
Thread calcThread = new Thread(new Runnable(){
#Override
public void run() {
//some calculation
}
});
calcThread.start();
//wait at most 2secs for the calcThread to finish.
calcThread.join(2000);
//throw an exception if the calcThread hasn't completed.
if(calcThread.isAlive()){
throw new SomeException("calcThread is still running!");
}

Have a look at http://download.oracle.com/javase/1.5.0/docs/api/java/util/concurrent/ExecutorService.html#awaitTermination(long,%20java.util.concurrent.TimeUnit) which allows you to handle this without dealing with thread synchronization yourself.

Java - How to know when thread is waiting?

Is there any neat solution of knowing when a thread has been put into wait status? I am putting threads to wait and I notify them when i need it. But sometimes I want to know if a thread is currently waiting, and if so, I have to do something else.
I could probably set a flag myself to true/false. But I can't imagine there is a better way to do this?

The method getState() of a thread returns a Thread.State which can be:
NEW, RUNNABLE, BLOCKED, WAITING, TIMED_WAITING or TERMINATED
See Thread.State.

Have you looked at Thread.getState?

Check
public Thread.State getState()
Thread.State.WAITING
Thread.State: Differences between BLOCKED vs WAITING

You can have all info that you want using the ThreadMXBean.
Try this code:
package com.secutix.gui.seatmap;
import java.lang.management.ManagementFactory;
import java.lang.management.ThreadInfo;
import java.lang.management.ThreadMXBean;
public class ThreadStatus {
private static final ThreadMXBean mbean = ManagementFactory.getThreadMXBean();
public static void main(String[] args) {
for (int i = 0; i < 3; i++) {
buildAndLaunchThread(i);
}
Thread t = new Thread(){
#Override
public void run() {
while(true){
printThreadStatus();
try {
sleep(3000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
};
t.setName("detector");
t.start();
}
protected static void printThreadStatus() {
ThreadInfo[] infos = mbean.dumpAllThreads(true, true);
for (ThreadInfo threadInfo : infos) {
System.out.println(threadInfo.getThreadName() + " state = " + threadInfo.getThreadState());
}
}
private static void buildAndLaunchThread(int i) {
Thread t1 = new Thread(){
#Override
public void run() {
while(true){
try {
sleep(3000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
};
t1.setName("t" + i);
t1.start();
}
}