I have created new thread in my android app to read .p12 file like this:
AssetManager am = getAssets();
InputStream inputStream = am.open("C:\\Users\\UkrBikeApp-ff55878cb577.p12");
This file exist in directory. But every time I get
java.io.FileNotFoundException
The simular code works in simple java app without any problems. What is the reason?
First, C:\\Users\\UkrBikeApp-ff55878cb577.p12 is a path to a file on a Windows machine. Android is not Windows.
Second, C:\\Users\\UkrBikeApp-ff55878cb577.p12 is a filesystem path. It is not a path to an asset within your APK, and so AssetManager would not know what to do with it anyway.
If you want to package this file in your app:
Create an assets/ directory in the appropriate module and source set (e.g., app/src/main/assets/)
Put the file in assets/
Use open() on AssetManager with the plain filename
Related
I want to access a file in included in the folder of the app and I want to be able to access it localy. I also don't want to use methods like android.getresources() and just use
File file = new File( filePath );
My file is saved in app/src/main/assets/ball.obj
The problem is when I do File file = new File("app/src/main/assets/ball.obj");, it alwas gives me a FileNotFoundException. I also tried moving the file in other places and absolute pathes, but it still doesn't work. Please help.
My file is saved in app/src/main/assets/ball.obj
That is a relative path to a file on your development machine. Assets are not files on the filesystem of the device. You cannot use File to access an asset.
To get an InputStream on your asset, call getAssets() on your Activity or other Context, then call open() on the AssetManager returned by getAssets().
For your call to open(), you need to pass in the relative path within assets/ to the asset that you wish to read in. So, if you are in a method of your Activity, getAssets().open("ball.obj") will give you an InputStream that you can use to read in the contents of that particular asset.
I have a file with some data that I want only my application to have access to.
I was wondering in which folder I should put the file in my android project in order to have access to it using
File file = new File(context.getFilesDir(), filename);
Thanks
This is just an empty folder in Android device.
To access your files in assets
InputStream is = getAssets().open("subfolder/anyfile.txt");
to access files inside raw use
InputStream XmlFileInputStream = getResources().openRawResource(R.raw.somesrc);
getFilesDir() is just a folder that uses for openFileOutput(String, int) method. More detailed: https://stackoverflow.com/a/21230946/1979882
Use Assets Folder For files that will be bundled with the application and will be stored inside the apk as is. you can add an "asset" folder to your project by right clicking your app in the project explorer then select
New=> Folder=> Assets Folder.
you can open the files stored in the assets folder using the assets manager for example to open an image kept in /assets/img/image1.png:
InputStream is = assetManager.open("img/image1.png");
for HTML files you can load the file by its URL :
webView.loadUrl("file:///android_asset/"+name);
Here you can get a clear functionality of saving,retrieving a file
Here is the Link:http://www.mysamplecode.com/2012/06/android-internal-external-storage.html
I need a FileInputStream from a file but I don't know where to place the file.
I wrote this code:
InputStream is = new FileInputStream("src/test/resources/Key.p12");
But, where should I save file Key.p12?
InputStream is = new FileInputStream("src/test/resources/Key.p12");
There is no src/test/resources/ directory on any Android device.
Yes, but in app/src/test, there doesnt exist a dir called "resources". Only "res". Maybe it works when i create a dir called "resources"...
No, it will not. FileInputStream will only work for things that are files on the device. Anything packaged in your APK will not be files on the device.
Instead, store this file in app/src/main/assets/. Then, use AssetManager and open() to get an InputStream on that asset.
where ever you want to put the file
just copy the destination and paste it in the constructor
How can I retrieve all the files in /res/raw folder as File?
I have found this solution, and "New Folder" value I have replaced with "res/raw" as you can see in the following code:
public File[] getRawFiles() {
File sdCardRoot = Environment.getExternalStorageDirectory();
File yourDir = new File(sdCardRoot, "res/raw");
return yourDir.listFiles();
}
When program is started, I get an exception on line return yourDir.listFiles:
Caused by: java.lang.NullPointerException: Attempt to get length of null array
How can I fix this, and what is correct path to "res/raw/" ?
How can I retrieve all the files in /res/raw folder as File?
You cannot do this. As we discussed yesterday, resources are not files on the filesystem of the device. They are files on your development machine. They are merely entries in an APK file on the device.
Either:
Do whatever you are trying to do some other way that does not involve files, or
Use openInputStream() on a Resources object (you can get one from any Context via getResources()), and use Java I/O to copy the contents of a resource to a local file, such as on internal storage, and using reflection to iterate over the actual resources, or
Switch to using assets/ instead of res/raw/, as AssetManager allows you to list() assets (though you still only get an InputStream on an asset, as like resources, assets are not files on the device)
I am uploading an excel file to the tomcat server. Which is saving inside my eclipse directory D:\workspace_Eclipse\.metadata\.plugins\org.eclipse.wst.server.core\tmp1\wtpwebapps\StatusPortal\Job_doc\abc.xls
When ever i am accessing this file its giving me file not found Exception \Job_doc\abc.xls.
Its could not able to find the path which is i am giving while accessing the file like
\Job_doc\abc.xls
I am giving the path \Job_doc\abc.xls while accessing.
This is because you are using a relative path. Eclipse will use the current working directory to be a temp location for deploying the webapp. So the file is uploaded to the folder relative to this path (This happens when you start the app from eclipse Run On Server. Define your paths as static constants(May be you can use absolute paths for testing). After testing you can use the relative paths on production deployment.
Still, you can do alternate way. Dont use the integrated tomcat server of Eclipse. Use a standalone server, use the descriptor file to link the webapp in workspace to tomcat. After the save, just reload the app in tomcat manager and try.
Try reading your file using ClassLoader as below:
InputStream inputStream =
getClass().getClassLoader().getResourceAsStream("/Job_doc/abc.xls");
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream ));
If you want to get the File object, then try as below:
URI uri = getClass().getClassLoader().getResource("/Job_doc/abc.xls").toURI();
File file = new File(uri);