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Regex: Read value between multiple brackets

I currently working on translating a website (Smarty) with Poedit. To get all the text from the .tpl files i'm using regex to get the data between the {t} and {/t}. so an example:
{t}Password incorrect, please try again{/t}
The regex will read Password incorrect, please try again and place it in a .po file. This is all working fine. It goes wrong when it gets a little more advanced.
Sometimes the text between the {t} tags uses a parameter. this looks like this:
{t 1=$email|escape 2=$mailbox}No $1 given, please check your $2{/t}
This is also working great.
The real problem start when i use brackets inside the parameter like this:
{t 1={site info='name'} 2=$mailbox}visit %1 or go to your %2{/t}
My regex will close when it sees the first closing brackets so the result will be 2=$mailbox}visit %1 or go to your %2.
My regex looks like this:
\{t.*?\}?[}]([^\{]+)\{\/t\}|\{t\}([^\{]+)\{\/t\}
The regex is used inside a java program.
Does anybody has a way to fix this problem?

The easiest solution I see on this is to normalize the .tpl files. Just use a regex which matches all tags something like this one:
{[^}]*[^{]*}
I had the same issue to solve and it worked pretty good with the normalizing.
The normalizing-method would look like this:
final String regex = "\\{[^\\}]*[^\\{]*\\}";
private String normalizeContent(String content) {
return content.replaceAll(regex, "");
}

Java(Apex) RegEx not working?

I am having trouble with a regex in salesforce, apex. As I saw that apex is using the same syntax and logic as apex, I aimed this at java developers also.
I debugged the String and it is correct. street equals 'str 3 B'.
When using http://www.regexr.com/, the regex works('\d \w$').
The code:
Matcher hasString = Pattern.compile('\\d \\w$').matcher(street);
if(hasString.matches())
My problem is, that hasString.matches() resolves to false. Can anyone tell me if I did something somewhere wrong? I tried to use it without the $, with difference casing, etc. and I just can't get it to work.
Thanks in advance!

You need to use find instead of matches for partial input match as matches attempts to match complete input text.
Matcher hasString = Pattern.compile("\\d \\w$").matcher(street);
if(hasString.find()) {
// matched
System.out.println("Start position: " + hasString.start());
}

Need java Regex to remove/replace the XML elements from specific string

I have a problem in getting the correct Regular expression.I have below xml as string
<user_input>
<UserInput Question="test Q?" Answer=<value>0</value><sam#testmail.com>"
</user_input>
Now I need to remove the xml character from Answer attribute only.
So I need the below:-
<user_input>
<UserInput Question="test Q?" Answer=value0value sam#testmail.com"
</user_input>
I have tried the below regex but did not worked out:-
str1.replaceAll("Answer=.*?<([^<]*)>", "$1");
its removing all the text before..
Can anyone help please?

You need to put ? within the first group to make it none greedy, also you dont need Answer=.*?:
str1.replaceAll("<([^<]*?)>", "$1")
DEMO

httpRequest.send("msg="+data+"&TC="+TC); try like this

Although variable width look-behinds are not supported in Java, you can work around it with .{0,1000} that should suffice.
Please check out this approach using 2 regexes, or 1 regex and 1 replace. Choose the one that suits best (I removed the \n line break from the first input string to show the flaw with using simple replace):
String input = "<user_input><UserInput Question=\"test Q?\" Answer=<value>0</value><sam#testmail.com>\"\n</user_input>";
String st = input.replace("><", " ").replaceAll("(?<=Answer=.{0,1000})[<>/]+(?=[^\"]*\")", "");
String st1 = input.replaceAll("(?<=Answer=.{0,1000})><(?=[^\"]*\")", " ").replaceAll("(?<=Answer=.{0,1000})[<>/]+(?=[^\"]*\")", "");
System.out.println(st + "\n" + st1);
Output of a sample program:
<user_input UserInput Question="test Q?" Answer=value0value sam#testmail.com"
</user_input>
<user_input><UserInput Question="test Q?" Answer=value0value sam#testmail.com"
</user_input>

First off, in your sample above, there is a trailing " after the email and > which I do not know if it was placed by error.
However, I will keep it there as according to your expected result, you need it to still be present.
This is my hack.
(Answer=)(<)(value)(>)(.+?([^<]*))(</)(value)(><)(.+?([^>]*))(>) to replace it with
$1$3$5$8 $10
The explanation...
(Answer=)(<)(value)(>) matches from Answer to the start of the value 0
(.+?([^<]*) matches the result from 0 or more right to the beginning < which starts the closing value tag
(</) here, I still select this since it was dropped in the previous expression
(><) I will later replace this with a space
(.+?([^>]*) This matches from the start of the email and excludes the > after the .com
(>) this one selects the last > which I will later drop when replacing.
The trailing " is not selected as I will rather not touch it as requested.

Why doesn't this Java regex compile?

I am trying to extract the pass number from strings of any of the following formats:
PassID_132
PassID_64
Pass_298
Pass_16
For this, I constructed the following regex:
Pass[I]?[D]?_([\d]{2,3})
-and tested it in Eclipse's search dialog. It worked fine.
However, when I use it in code, it doesn't match anything. Here's my code snippet:
String idString = filename.replaceAll("Pass[I]?[D]?_([\\d]{2,3})", "$1");
int result = Integer.parseInt(idString);
I also tried
java.util.regex.Pattern.compile("Pass[I]?[D]?_([\\d]{2,3})")
in the Expressions window while debugging, but that says "", whereas
java.util.regex.Pattern.compile("Pass[I]?[D]?_([0-9]{2,3})")
compiled, but didn't match anything. What could be the problem?

Instead of Pass[I]?[D]?_([\d]{2,3}) try this:
Pass(?:I)?(?:D)?_([\d]{2,3})

There's nothing invalid with your tegex, but it sucks. You don't need character classes around single character terms. Try this:
"Pass(?:ID)?_(\\d{2,3})"

Need a regex expression to get value between two tags

Need regular expression to extract the values between >xxxxx<. Can anybody help me in this.
<ChangeID type="String">C10286</ChangeID>
<ChangeID type="String">C10296</ChangeID>
Is it possible to get the two values in a comma separated format like C10286,C10296 in a single regex expression?
Thanks and Regards
Riyas Hussain A

try this:
(?<=>)[^<]*
test it with grep -Po:
kent$ echo '<ChangeID type="String">C10286</ChangeID>
<ChangeID type="String">C10296</ChangeID>'|grep -Po '(?<=>)[^<]*'
C10286
C10296

My idea would be to lookup for all words and remove the ones we don't need (in case you have more than 1 value inside your tag):
(?!ChangeID\b)(?!type\b)(?!String\b)\b\w+
You can try it out on : http://regexpal.com/