Entity:
#Entity
public class MyAccount {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
private String userId;
private String password;
private String email;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getUserId() {
return userId;
}
public void setUserId(String userId) {
this.userId = userId;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
}
Naming strategy:
public class HibernateNamingStrategy extends PhysicalNamingStrategyStandardImpl implements Serializable {
private static final long serialVersionUID = -4772523898875102775L;
#Override
public Identifier toPhysicalTableName(Identifier name, JdbcEnvironment context) {
return new Identifier(addUnderscores(name.getText()), name.isQuoted());
}
#Override
public Identifier toPhysicalColumnName(Identifier name, JdbcEnvironment context) {
return new Identifier(addUnderscores(name.getText()), name.isQuoted());
}
protected static String addUnderscores(String name) {
final StringBuilder buf = new StringBuilder(name.replace('.', '_'));
for (int i = 1; i < buf.length() - 1; i++) {
if (Character.isLowerCase(buf.charAt(i - 1)) && Character.isUpperCase(buf.charAt(i))
&& Character.isLowerCase(buf.charAt(i + 1))) {
buf.insert(i++, '_');
}
}
return buf.toString().toLowerCase();
}
}
JPA metamodel:
#Generated(value = "org.hibernate.jpamodelgen.JPAMetaModelEntityProcessor")
#StaticMetamodel(MyAccount.class)
public abstract class MyAccount_ {
public static volatile SingularAttribute<MyAccount, String> password;
public static volatile SingularAttribute<MyAccount, Integer> id;
public static volatile SingularAttribute<MyAccount, String> userId;
public static volatile SingularAttribute<MyAccount, String> email;
}
I am going to do something like below:
Join<Employee,MyAccount> project = emp.join("my_account", JoinType.LEFT);
I don't see any table name related attribute auto-generated in the MyAccount_ metamodel. How can I use metamodel table name in the join criteria (I don't want to use hardcoded string)?
PS: I am using Spring MVC and naming strategy which all camel case is separated by underscore.
It is too bad to hear that (from #Neil Stockton), it is not part of the metamodel, I think it really should be included.
Anyway, my code doesn't have annotation because I am using implicit naming strategy.
So by doing this, it is not working, it got NullPointerException:
System.out.println("Table_Name: " + MyAccount.class.getAnnotation(Table.class).name());
So the simplest way, is to reuse my function addUnderscores (change it to public):
System.out.println("Table_Name: " + HibernateNamingStrategy.addUnderscores(MyAccount.class.getSimpleName()));
Although code become longer but I think it is better than hardcoded string instead.
Hope this help others too.
Related
I am very new to Spring Boot. This is what I want to do: The user's email is test#example.com. That user already exists in my database, but I would like to know if their verificationCode is 123.
Entity:
public class Users {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String email;
private String password;
private String verificationCode;
#Column(name = "verified", columnDefinition = "default false")
private boolean verified = false;
#CreationTimestamp
private Date registrationDate;
protected Users() {}
public Users(String email, String password, String verificationCode) {
this.email = email;
this.password = password;
this.verificationCode = verificationCode;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getVerificationCode() {
return verificationCode;
}
public void setVerificationCode(String verificationCode) {
this.verificationCode = verificationCode;
}
public boolean isVerified() {
return verified;
}
public void setVerified(boolean verified) {
this.verified = verified;
}
}
So with userRepository.findByEmail("test#example.com") I am getting the correct user, but how do I check their verification code?
if you're using userRepository.findByEmail("test#example.com"), just take the verification code from entity.
private static final String CODE = "123";
final User user = userRepository.findByEmail("test#example.com");
if (CODE.equals(user.getVerificationCode())) {
// do something
}
Another option to have it within query.
userRepository.findByEmailAndVerificationCode("test#example.com", CODE);
Or you can have something similar as Philipp wrote, but I would not get whole entity just find out if it exist. So solution would be
if (userRepository.existsByCode(CODE)) {
// do something
}
You search for something like that:
public void checkVerificationCode(final String verificationCode) {
final User user = userRepository.findByEmail("test#example.com");
if (!user.getVerificationCode(verificationCode)) {
throw new VerificationCodeException("Incorrect verification code.");
}
}
I have a next question: while working with Hibernate 3.3.0 run into a situation when I have two tables with one-to-many relationships and I need to get the list of parents. In each entity must be filled the several fields from the parent table and a list of all children mapped in the parent. For the easiest understanding, I give an example. I have two tables with one-to-many relationships: parent is "recipients" and child is "requisites". And I have two classes whose objects are the rows of these tables. Class for the table of recipients:
#Entity
#Table(name = "recipients")
#JsonFilter(value = "recipientsFilter")
public class POJORecipient implements POJO {
private static final long serialVersionUID = 4436819032452218525L;
#Id
#Column
private long id;
#Version
#Column
private long version;
#Column(name = "client_id")
private long clientId;
#Column
private String inn;
#Column
private String name;
#Column(name = "rcpt_country_code")
private String rcptCountryCode;
#Column(name = "rcpt_passp_ser")
private String rcptPasspSer;
#Column(name = "rcpt_passp_num")
private String rcptPasspNum;
#OneToMany(mappedBy = "recipient", fetch = FetchType.LAZY)
#JsonManagedReference
private Set<POJORequisite> requisites = new HashSet<>();
public POJORecipient(){}
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public long getVersion() {
return version;
}
public void setVersion(long version) {
this.version = version;
}
public long getClientId() {
return clientId;
}
public void setClientId(long clientId) {
this.clientId = clientId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getInn() {
return inn;
}
public void setInn(String inn) {
this.inn = inn;
}
public String getRcptCountryCode() {
return rcptCountryCode;
}
public void setRcptCountryCode(String rcptCountryCode) {
this.rcptCountryCode = rcptCountryCode;
}
public String getRcptPasspSer() {
return rcptPasspSer;
}
public void setRcptPasspSer(String rcptPasspSer) {
this.rcptPasspSer = rcptPasspSer;
}
public String getRcptPasspNum() {
return rcptPasspNum;
}
public void setRcptPasspNum(String rcptPasspNum) {
this.rcptPasspNum = rcptPasspNum;
}
public Set<POJORequisite> getRequisites() {
return requisites;
}
public void setRequisites(Set<POJORequisite> requisites) {
this.requisites = requisites;
}
}
and for requisites table:
#Entity
#Table(name = "requisites")
public class POJORequisite implements POJO {
private static final long serialVersionUID = -35864567359179960L;
#Id
#Column
private long id;
#Version
#Column
private long version;
#Column
private String bic;
#Column
private String bill;
#Column
private String comments;
#Column
private String note;
#ManyToOne
#JoinColumn(name = "recipient_id")
#JsonBackReference
private POJORecipient recipient;
public POJORequisite(){}
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public long getVersion() {
return version;
}
public void setVersion(long version) {
this.version = version;
}
public String getBic() {
return bic;
}
public void setBic(String bic) {
this.bic = bic;
}
public String getBill() {
return bill;
}
public void setBill(String bill) {
this.bill = bill;
}
public String getComments() {
return comments;
}
public void setComments(String comments) {
this.comments = comments;
}
public String getNote() {
return note;
}
public void setNote(String note) {
this.note = note;
}
public POJORecipient getRecipient() {
return recipient;
}
public void setRecipient(POJORecipient recipient) {
this.recipient = recipient;
}
}
So, I want to select from the recipients only names and all mapped requisites. Consequently, after the selection, I will have a list of POJORecipient objects and in each object filled only the field "name" and set of POJORequisite objects.
As answer of my question I want to discover one of next: how can I do that with help HQL or Criteria API (the second variant is preferable), or understand it is impossible in Hibernate at all, or that this possibility appeared in later versions (also preferably with example). I'm trying to resolve this question for several months now and will be immensely grateful for any help. All clarifications and advices also will be so helpful. Thanks in advance!!!
I would like to know if there is any way to use a parameter from a function I pass to a repository can be used in the #Query.
I would like to sort users by gaming platform so I added the following function to my UserRepository:
#Repository
public interface UserRepository extends CrudRepository<DbUser, Integer> {
#Query("SELECT * from users WHERE platform = *****parameter here***** ")
public List<DbUser> findAllByPlatform(String platform);
}
Does anybody know if this is possible? If so, how? If not, is there a clean workaround? Thanks in advance.
EDIT: My DbUser class:
#Entity
#Table(name = "users")
public class DbUser {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name="user_id")
private int UserId;
#Column(name="user_name")
private String UserName;
#Column(name="email_address")
private String EmailAddress;
#Column(name="password_hash")
private int PasswordHash;
#Column(name="platform")
private String Platform;
#Column(name="platformid")
private String PlatformID;
#Convert(converter = StringListConvertor.class)
private ArrayList<String> Wishlist;
public DbUser(String userName, String emailAddress, int passwordHash, String platform, String platformID, String newWishlistItem){
UserName = userName;
EmailAddress = emailAddress;
PasswordHash = passwordHash;
Platform = platform;
PlatformID = platformID;
Wishlist.add(newWishlistItem);
}
public DbUser() {
}
public int getUserId() {
return UserId;
}
public void setUserId(int userId) {
UserId = userId;
}
public String getUserName() {
return UserName;
}
public void setUserName(String userName) {
UserName = userName;
}
public String getEmailAddress() {
return EmailAddress;
}
public void setEmailAddress(String emailAddress) {
EmailAddress = emailAddress;
}
public int getPasswordHash() {
return PasswordHash;
}
public void setPasswordHash(int passwordHash) {
PasswordHash = passwordHash;
}
public String getPlatform() {
return Platform;
}
public void setPlatform(String platform) {
Platform = platform;
}
public String getPlatformID() {
return PlatformID;
}
public void setPlatformID(String platformID) {
PlatformID = platformID;
}
public ArrayList<String> getWishlist() {
return Wishlist;
}
public void setWishlist(ArrayList<String> wishlist) {
Wishlist = wishlist;
}
}
If you're using Spring data, annotate parameter with #Param and supply variable name to be used in query:
#Query("SELECT * from users WHERE platform = :pltfrm")
public List<DbUser> findAllByPlatform(#Param("pltfrm") String platform);
You can do something like that
#Query("SELECT * from users WHERE platform = %?1")
spring data jpa documentation
I created a table of "User" which is perfectly created by hibernate, no problem on this one. The problem is on my second model (an entity called "Character") which is a model with a #ManyToOne relation, I don't know why but hibernate can't create this second table.
My server is a MySql instance with AWS RDS. The first table is created by hibernate but not the second.
#Entity
public class Character {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Integer id;
#ManyToOne
private User joueur;
private String pseudo;
private Integer points;
public Character() {
super();
}
public Character(User joueur) {
// appel a l'autre constructeur
this(joueur, null, null);
}
public Character(User joueur, String pseudo,Integer points) {
super();
this.joueur = joueur;
this.pseudo = pseudo;
this.points = points;
}
public Integer getId() {
return id;
}
public String getPseudo() {
return pseudo;
}
public void setPseudo(String pseudo) {
this.pseudo = pseudo;
}
public Integer getPoints() {
return points;
}
public void setPoints(Integer points) {
this.points = points;
}
public User getJoueur() {
return joueur;
}
}
#Entity // This tells Hibernate to make a table out of this class
public class User {
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private Integer id;
private String username;
private String password;
#OneToMany(mappedBy = "joueur")
#OrderBy("id ASC")
private List<Character> personnages;
private String league;
private Integer points;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public List<Character> getPersonnages() {
return personnages;
}
public void setPersonnages(List<Character> personnages) {
this.personnages = personnages;
}
public String getLeague() {
return league;
}
public void setLeague(String league) {
this.league = league;
}
public Integer getPoints() {
return points;
}
public void setPoints(Integer points) {
this.points = points;
}
}
#Controller
#RequestMapping(path="/init")
public class MainController {
#Autowired // This means to get the bean called userRepository
// Which is auto-generated by Spring, we will use it to handle the data
private UserRepository userRepository;
#Autowired
private CharacterRepository characterRepository;
#GetMapping(path="/add") // Map ONLY GET Requests
public String addNewUser () {
User joueur = new User();
joueur.setUsername("testUser");
joueur.setPassword("password");
joueur.setLeague("Bronze");
joueur.setPoints(10000);
userRepository.save(joueur);
Character perso = new Character(joueur,"testPerso1",1000);
characterRepository.save(perso);
return "";
}
#GetMapping(path="/all")
public #ResponseBody Iterable<User> getAllUsers() {
// This returns a JSON or XML with the users
return userRepository.findAll();
}
}
I have this error :
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'character add constraint Kdf2yvyvitaqt2u7de3ywfjcv foreign key (joueur_id) refe' at line 1
Ok I found the solution ... JPA annotation fordid the name of the table 'Character", just change the name of the table and it will work perfectly, stupid JPA ...
I'm new to Java and even more newer to Spring (Boot and JPA) but I was curious, I'm trying to debug an issue that says, "No identifier specified for entity".
For illustartion purposes, I've created the following tables from this diagram:
Originally, there was a M:N relationship between the user and vehicle table, so I created an associative entity (UserVehicleAsso) to split the two up. I was following this guide on M:N mapping in Java, http://viralpatel.net/blogs/hibernate-many-to-many-annotation-mapping-tutorial/
For the most part, it was pretty straight forward but my question is, within the associative entity (UserVehicleAsso), do I have to use the #Id annotation for each of the foreign keys? I assume that I didn't need to because those were automatically generated from each of the respective tables.
Let me know your thoughts or comments, thanks.
Also, below is the code that I used to generate these models:
For the User table/class:
#Entity
public class User {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int userId;
private String fName;
private String lName;
#ManyToMany(cascade = {CascadeType.ALL})
#JoinTable(name="userVehicleAsso",
joinColumns={#JoinColumn(name="userID")},
inverseJoinColumns={#JoinColumn(name="vehicleID")})
private Set<Vehicle> vehicles = new HashSet<Vehicle>();
//constructor
protected User() {}
public int getUserId() {
return userId;
}
public void setUserId(int userId) {
this.userId = userId;
}
public String getFName() {
return fName;
}
public void setFName(String fName) {
this.fName = fName;
}
public String getLName() {
return lName;
}
public void setLName(String lName) {
this.lName = lName;
}
public Set<Vehicle> getVehicles() {
return vehicles;
}
public void setVehicles(Set<Vehicle> vehicles) {
this.vehicles = vehicles;
}
#Override
public String toString() {
return getFName() + "," + getLName();
}}
For the Vehicle table/class:
#Entity
public class Vehicle {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private int vehicleId;
private String brand;
private String model;
//foreign key mappings
//mapping with associative
#ManyToMany(mappedBy="vehicles")
private Set<User> users = new HashSet<User>();
//constructors
protected Vehicle() {}
public Vehicle(int id) {
this.vehicleId = id;
}
public Vehicle (String brand, String model) {
this.brand = brand;
this.model = model;
}
/* public Vehicle() {
}*/
public int getVehicleId() {
return vehicleId;
}
public Set<User> getUsers() {
return users;
}
public void setUsers(Set<User> users) {
this.users = users;
}
public void setVehicleId(int vehicleId) {
this.vehicleId = vehicleId;
}
public String getBrand() {
return brand;
}
public void setBrand(String brand) {
this.brand = brand;
}
public String getModel() {
return model;
}
public void setModel(String model) {
this.model = model;
}
#Override
public String toString() {
// + setBodyType() + "," +
return getBrand() + "," + getModel();
}
}
And then finally, my associtive table/class:
#Entity
public class UserVehicleAsso{
private int userID;
private int vehicleID;
public int getUserID() {
return userID;
}
public void setUserID(int userID) {
this.userID = userID;
}
public int getVehicleID() {
return vehicleID;
}
public void setVehicleID(int vehicleID) {
this.vehicleID = vehicleID;
}
}
In my opinion, it's not necessary to have an Entity class for the middle table in your case. The table will be generated automatically if configured correctly. In this table, there would not be column ID, only two columns with userID and vehicleID data.
Now, if your middle table has more than what are needed to establish the M:N relationship, then your middle Entity class is needed, and the ID of it, too. For example, if this class is intended to store the time stamp every time a relationship is established, you have to:
Create this Entity class,
Give it an ID field with proper generation strategy,
Map the time stamp with a field with adequate type, annotation/XML mapping and so on.
This part of JPA/Hibernate have confused me a lot and I used to get into them. If my memory serves me well this is the proper/perfect way how things should work.
You can specify a composite primary key class that is mapped to multiple fields or properties of the entity.
Here are sample codes:
public class ActivityRegPK implements Serializable {
private int activityId;
private int memberId;
public int getActivityId() {
return activityId;
}
public void setActivityId(int activityId) {
this.activityId = activityId;
}
public int getMemberId() {
return memberId;
}
public void setMemberId(int memberId) {
this.memberId = memberId;
}
}
associtive table/class:
#IdClass(ActivityRegPK.class)
#Entity
#Table(name="activity_reg")
#NamedQuery(name="ActivityReg.findAll", query="SELECT a FROM ActivityReg a")
public class ActivityReg implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(name="activity_id")
private int activityId;
#Temporal(TemporalType.TIMESTAMP)
#Column(name="ins_date")
private Date insDate;
#Id
#Column(name="member_id")
private int memberId;
}
Activity.class
#Entity
#NamedQuery(name="Activity.findAll", query="SELECT a FROM Activity a")
public class Activity implements Serializable {
// some attributes
}