I have string as follows
"ValueFilter("val1") AND ColumnFilter("val2") AND ValueFilter("val3")"
I have stored the following regex in a array. Using for loop I tried to match the pattern
"ValueFilter\\((.*?)\\)","ColumnFilter\\((.*?)\\)"
what I will do is I will replace the value in the bracket and copy it to a new string.
When I run this above regex against the string in the first loop i have XFilter so it will match both occurrence. But I want to do this in order.
Here is the i thing i want to achieve
first i want to match ValueFilter first then ColumnFilter then again ValueFilter. How can I achieve this?
Edit : Added Code
String expr = "\"ValueFilter(\"val1\") AND ColumnFilter(\"val2\") AND ValueFilter(\"val3\")\"";
String patterns = {"ValueFilter\\((.*?)\\)", "ColumnFilter\\((.*?)\\)"}
for (String pattern : patterns) {
Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(expr);
while (m.find()) {
//do something
}
}
Expected Output
ValueFilter("val1")
ColumnFilter("val2")
ValueFilter("val3")
You can use this regex [XY]Filter\((.*?)\) with pattern and you have to loop throw the matches using :
String str = "\"XFilter(\"val1\") AND YFilter(\"val2\") AND XFilter(\"val3\")\"";
String regex = "[XY]Filter\\((.*?)\\)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
System.out.println(matcher.group());
}
Note you can i use [XY] which mean to match both X or Y,
Output
XFilter("val1")
YFilter("val2")
XFilter("val3")
regex demo
If you want to get only the value you can get the group 1 like matcher.group(1) instead, the output should be :
"val1"
"val2"
"val3"
Edit
what if I have filtername as "ValueFilter" and "ColumnFilter" instead
of X and Y
In this case you can use (Value|Column) instead of [XY] which mean match ValueFilter or ColumnFilter, the regex should look like :
String str = "\"ValueFilter(\"val1\") AND ColumnFilter(\"val2\") AND ValueFilter(\"val3\")\"";
String regex = "(Value|Column)Filter\\((.*?)\\)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
System.out.println(matcher.group());
}
Output
ValueFilter("val1")
ColumnFilter("val2")
ValueFilter("val3")
Check code demo
Related
I am using below java program to find list of js files as a Substring.
String str = "jsLib//connect.facebook.net/en_US/fbevents.js , jsLib//connect.facebook.net/en_US/fbevents2.js;";
String patternStr = "(\\/.*?\\.js)";
Pattern pattern = Pattern.compile(patternStr);
Matcher matcher = pattern.matcher(html);
if (matcher.find()) {
System.out.println("Count:" + matcher.groupCount());
jsLib = matcher.group(1);
jsLib = jsLib.substring(jsLib.lastIndexOf('/') + 1, jsLib.length());
System.out.println("jsLib:" + jsLib);
}
Regex : I used String patternStr="(\\/.*?\\.js)";
Expected Result : both fbevents.js and fbevents2.js should be matched and part of result
Actual Result : only fbevents.js is matched
You may get all your results using while loop and a regex like [^/]*\.js:
String str = "jsLib//connect.facebook.net/en_US/fbevents.js , jsLib//connect.facebook.net/en_US/fbevents2.js;";
String patternStr = "[^/]*\\.js";
Pattern pattern = Pattern.compile(patternStr);
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
System.out.println("jsLib:" + matcher.group());
}
Output:
jsLib:fbevents.js
jsLib:fbevents2.js
See the Java demo and the regex demo.
The [^/]*\.js pattern matches any 0+ chars other than / (with [^/]*) and then a .js substring.
Given this String: "a001212a a1212a a00333a a00334a abvbv";
I'm trying to pick the third number just by changing the regex. But I can't figure it out. I am only allowed to change the regex. My code below works if i change the argument to matcher.group(2) but not for group(1).
Help?
String nthNumber(String string) {
Pattern pat = Pattern.compile(
"(\\D+0*(\\d+)\\D+){3,}.*"
);
Matcher matcher = pat.matcher(string);
matcher.matches();
return matcher.group(1);
}
You can make the first group a non-capturing group like below. Then, group(1) should work.
String nthNumber(String string) {
Pattern pat = Pattern.compile(
"(?:\\D+0*(\\d+)\\D+){3,}.*"
);
Matcher matcher = pat.matcher(string);
matcher.matches();
return matcher.group(1);
}
I have a string "Something[Anything]".
First I want to check whether string contains Square brackets if yes then I want this string to be separated in "Something" & "[Anything]".
Need some help with regEx for this.
Thanks in Advance.
Try this:
String test = "Something[Anything]";
if (test.matches(".*\\[.*\\].*")) { // checks if in the string presents open and close square brackets
Pattern pat = Pattern.compile("(.*?)(\\[.*?\\])");
Matcher matcher = pat.matcher(test);
matcher.find();
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
}
Outputs:
Something
[Anything]
Or, as suggested by #madatx, without first check:
Pattern pat = Pattern.compile("(.*?)(\\[.*?\\])");
Matcher matcher = pat.matcher(test);
if (matcher.find()) {
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
}
Same output.
You can use regex withour checking the square brackets.
This could work:
String strPattern = "(.+)(\\[.+\\])";
Pattern p = Pattern.compile(strPattern);
Matcher m = p.matcher("<yout string>");
if (m.matches()){
<your code here>
}
How could I get the first and the second text in "" from the string?
I could do it with indexOf but this is really boring ((
For example I have a String for parse like: "aaa":"bbbbb"perhapsSomeOtherText
And I d like to get aaa and bbbbb with the help of Regex pattern - this will help me to use it in switch statement and will greatly simplify my app/
If all that you have is colon delimited string just split it:
String str = ...; // colon delimited
String[] parts = str.split(":");
Note, that split() receives regex and compilies it every time. To improve performance of your code you can use Pattern as following:
private static Pattern pColonSplitter = Pattern.compile(":");
// now somewhere in your code:
String[] parts = pColonSplitter.split(str);
If however you want to use pattern for matching and extraction of string fragments in more complicated cases, do it like following:
Pattert p = Patter.compile("(\\w+):(\\w+):");
Matcher m = p.matcher(str);
if (m.find()) {
String a = m.group(1);
String b = m.group(2);
}
Pay attention on brackets that define captured group.
Something like this?
Pattern pattern = Pattern.compile("\"([^\"]*)\"");
Matcher matcher = pattern.matcher("\"aaa\":\"bbbbb\"perhapsSomeOtherText");
while (matcher.find()) {
System.out.println(matcher.group(1));
}
Output
aaa
bbbbb
String str = "\"aaa\":\"bbbbb\"perhapsSomeOtherText";
Pattern p = Pattern.compile("\"\\w+\""); // word between ""
Matcher m = p.matcher(str);
while(m.find()){
System.out.println(m.group().replace("\"", ""));
}
output:
aaa
bbbbb
there are several ways to do this
Use StringTokenizer or Scanner with UseDelimiter method
I want to break a string like :
String s = "xyz213123kop234430099kpf4532";
into tokens where each token starts with an alphabet and ends with a number. So the above string can be broken down into 3 tokens :
xyz213123
kop234430099
kpf4532
This string s could be very big but the pattern will remain the same, i.e each token will start with 3 alphabets and end with a number.
How do I split them ?
Try this:
\w+?\d+
Java Matcher:
Pattern pattern = Pattern.compile("\\w+?\\d+"); //compiles the pattern we want to use
Matcher matcher = pattern.matcher("xyz213123kop234430099kpf4532"); //we create the matcher on certain string using our pattern
while(matcher.find()) //while the matcher can find the next match
{
System.out.println(matcher.group()); //print it
}
And then you could use Regex.Matches C#:
foreach(Match m in Regex.Matches("xyz213123kop234430099kpf4532", #"\w+?\d+"))
{
Console.WriteLine(m.Value);
}
And for the future this:
RegExr
Do it like this,
String s = "xyz213123kop234430099kpf4532";
Pattern p = Pattern.compile("\\w+?\\d+");
Matcher match = p.matcher(s);
while(match.find()){
System.out.println(match.group());
}
OUTPUT
xyz213123
kop234430099
kpf4532
You can start from such regexp: (\w+?\d+)
http://regexr.com?36utt