Firstly sorry for my english.
I want to ask you how can I make field of names into which I can put/save name from user.
This was my try, but every time I ran it and user write his name the first name in field was replaced by user name. I hope you understand me.
Scanner sc = new Scanner(System.in);
String[] name = {"John","Nico","Sarah","Pablo","Micheal"};
for (int i = 0; i < 1; i++)
{
System.out.println("Write your name: ");
String s = sc.nextLine();
name[i] = s;
}
Arrays.sort(name);
for (String s2 : name)
{
System.out.print(s2 + ", ");
}
}
}
Scanner scanner = new Scanner(System.in);
String[] names = {"John", "Nico", "Sarah", "Pablo", "Micheal", ""};
System.out.print("Write your name: ");
String userName = scanner.nextLine();
names[names.length - 1] = userName;
System.out.println(Arrays
.stream(names)
.sorted()
.collect(Collectors.joining(",")));
This should return what you want.
An Array always has a fixed size. By typing:
String[] names = {"John", "Nico", "Sarah", "Pablo", "Micheal"};
You define the size of the Array to be 5. By adding the extra "" you can "reserve" a place for the user's name.
Using:
names[names.length - 1] = userName;
You replace "" by the user input, instead of replacing the first name, like in your solution.
Hope this helps. Happy coding!
It looks like you are initializing the array name[] with some values and then overwriting the values with the user inputs. If you want to just initialize the array then you can use array initialization syntax.
String[] name = new String[5];
Also in the for loop the condition i < 1 is wrong. It should be i < name.length.
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
//String[] name = { "John", "Nico", "Sarah", "Pablo", "Micheal" };
String[] name = new String[5];
//for (int i = 0; i < 1; i++) {
for (int i = 0; i < name.length; i++) {
System.out.println("Write your name: ");
String s = sc.nextLine();
name[i] = s;
}
Arrays.sort(name);
for (String s2 : name) {
System.out.print(s2 + ", ");
}
}
Related
When I insert the arguments the search always returns "not found" - even though the searched value was input into the array?
import java.util.Scanner;
public class assignment {
public static void main (String[] args)
{
Scanner sc = new Scanner(System.in);
String searchValue = "";
String [] BookID = new String [3];
String [] Booktitle = new String [3];
//input the BookID
System.out.println("Enter the 12 BookID");
for (int a = 0 ; a < BookID.length; a++)
{
System.out.print("BookID :");
BookID[a] = sc.next();
}
//Input the book title
for (int b = 0 ; b < Booktitle.length ; b++)
{
System.out.print("Booktitle :");
Booktitle[b] = sc.next();
}
//The Linear search on BookID
System.out.print("Enter BookID to find :");
for(int c = 0; c < BookID.length; c++)
{
searchValue = sc.next();
if(searchValue.equals(BookID))
System.out.print("BookID is found : ");
else
System.out.print("BookID is not found : ");
}
}
}
I'm expecting the result to return like so: if input BookID 112. The Linear search would return "The BookID is found :" instead of the else statement.
Try printing out the value of the bookId you wanna find to see if there anything with the string that could cause it to not be equals. Also, you could convert the string to an integer with:
Integer.parseInt("BookId");
The equals would have less chance of failing, you could also change de the array for an array of int instead of String.
This code has some basic things right, but it could be a bit better. Some of the changes I made are for keeping Java conventions (so the code is easier to read and understand) and some are functional. I added them as comments.
import java.util.Scanner;
public class Assignment {
public static void main (String[] args)
{
Scanner sc = new Scanner(System.in);
String searchValue = "";
String [] bookIDs = new String [3]; //lowercase for the attribute name (convention)
String [] bookTitles = new String [3]; //plural for the array (convention)
//input the BookID
System.out.println("Enter the Book ID");
for (int i = 0 ; i < bookIDs.length; i++) { //you can re-use the i in all loops
System.out.print("Enter " + i + " Book ID: ");
bookIDs[i] = sc.next();
}
//Input the book title
for (int i = 0 ; i < bookTitles.length ; i++) {
System.out.print("Enter " + i + " Book title: ");
bookTitles[i] = sc.next();
}
//The Linear search on BookID
System.out.print("Enter Book ID to find: ");
searchValue = sc.next(); //NOTE: this is your first mistake. read out of the loop
for(int i = 0; i < bookIDs.length; i++) {
if(searchValue.equals(bookIDs[i])) { //NOTE: this is your second mistake - you wanted the array value, not the array
System.out.println("BookID is found in position "+i);
break; //suggestion - stop the loop when found.
}
else {
System.out.println("BookID is not found in position "+i);
}
}
sc.close(); //NOTE: important to close scanners at the end.
}
}
Good luck with your studies.
I'm searching for word(s) in a string array and if found I want to return their line.
I have tried to divide the searched input in an array and then search it in the paragraph array line by line. Which does not really work.
public static void main(String[] args) {
String paragraph[] = new String[10];
String toBeSearched;
String curSearch;
boolean intIndex = false ;
paragraph[0] = "Hello my name is";
paragraph[1] = "Jack the reaper";
paragraph[2] = "what up";
System.out.printf("enter string:");
Scanner myScanner = new Scanner(System.in);
toBeSearched = myScanner.nextLine();
String[] divide = toBeSearched.split(" ");
for(int j = 0 ;j <=10 ; j++) {
curSearch = divide[j];
for (int k = 0; k <=paragraph[j].length() ; k++) {
intIndex = paragraph[j].contains(curSearch);
if(intIndex == true) {
System.out.printf("Found at line %d \n",j );
}
}
}
Assuming I can search for at most 10 words at a time.
Lets say user enters : "Hello name the up"
I want the answer : At line 1
At line 1
At line 2
At line 3
If I ask for a word in the 2nd or the 3rd index of the paragraph it does not work I dont understand why (getting no error messages)
Here is a working code compare it to yours and figure out the issue:
public static void main(String[] args)
{
String paragraph[] = {"Hello my name is","Jack the reaper", "what up"};
String toBeSearched;
String curSearch;
boolean intIndex = false ;
System.out.printf("enter string:");
Scanner myScanner = new Scanner(System.in);
toBeSearched = myScanner.nextLine();
String[] divide = toBeSearched.split(" ");
for(int i = 0; i < divide.length ; i ++) {
String word = divide[i];
for(int y = 0; y < paragraph.length ; y++) {
if(paragraph[y].contains(word)) {
System.out.println(word+ "found at line: "+ y);
}
}
}
}
I want get first name when input the name with array and looping
Example :
Enter the name :
1. Alvin Indra
2. Sada Rika
Output :
1. Alvin
2. Sada
Code:
public static void main(String[] args) {
int n;
String teman[],namadepan[];
Scanner sc = new Scanner(System.in);
Scanner x = new Scanner(System.in);
System.out.print("Put how many friends : ");
n = sc.nextInt();
teman = new String[n];
namadepan = new String[n];
for(int i=0;i<n;i++){
System.out.print("Friend Of-"+(i+1)+" : ");
teman[i] = x.nextLine();
}
System.out.print("\n");
System.out.println("First Name : ");
for(int i=0;i<n;i++){
if(teman[i] == ' '){ // this is where I need help
System.out.println((i+1)+". "+teman[i].substring(0,i));
}
}
}
Here you go
String name = "John Smith";
System.out.println(name.split(" ")[0]);
Using this will replace that second for loop, you don't need to cycle through each letter to look for a space you can just use the split method on the string and specifiy the character in which to split the string up and then call the first element.
Updated complete implementation
import java.util.Scanner;
public class testest {
public static void main(String[] args){
int n;
String teman[],namadepan[];
Scanner sc = new Scanner(System.in);
Scanner x = new Scanner(System.in);
System.out.print("Put how many friends : ");
n = sc.nextInt();
teman = new String[n];
namadepan = new String[n];
for(int i=0;i<n;i++){
System.out.print("Friend Of-"+(i+1)+" : ");
teman[i] = x.nextLine();
}
System.out.print("\n");
for(int i=0;i<n;i++){
System.out.println("First Name : ");
System.out.println(teman[i].split(" ")[0]);
System.out.print("\n");
}
}
}
You are probably looking for using contains and indexOf methods of String class in java, to use them as :
if (teman[i].contains(" ")) {
System.out.println((i + 1) + ". " + teman[i].substring(0, teman[i].indexOf(" ")));
}
My goal is to ask the user to enter a bunch of strings in a loop, and when they enter "stop", the loop breaks and prints all those strings with a comma at the end of each word. For example, if the user enters "first", "second", "third", and "fourth", then the program would print the following:
first, second, third, fourth
public static void main(String[] args)
{
Scanner kb = new Scanner(System.in);
int i;
String s;
String[] listOfStrings = new String[1000];
String last = "";
System.out.println("Please enter some Strings: ");
for (i = 1; i>0; i++) {
listOfStrings[i] = kb.next();
last = listOfStrings[i] + ",";
if (listOfStrings[i].equalsIgnoreCase("stop")) {
break;
}
}
System.out.print(last);
There is a problem because it always just winds up printing the last word and nothing else. Any help would be greatly appreciated.
I would use an ArrayList:
Scanner sc = new Scanner(System.in);
List<String> list = new ArrayList<String>();
while (sc.hasNext()) {
String s = sc.next();
if (s.equalsIgnoreCase("stop")) {
break;
} else {
list.add(s);
}
}
for (int i = 0; i < list.size(); i++) {
System.out.println(list.get(i) + ",");
}
If you want everything in one line, you can do this:
Scanner sc = new Scanner(System.in);
String line = "";
while (sc.hasNext()) {
String s = sc.next();
if (s.equalsIgnoreCase("stop")) {
break;
} else {
line += s + ", ";
}
}
System.out.println(line.substring(0, line.length()-2));
How can i put a value into each slot of the array. Meaning i have:
String name[] = new name[50];
for (int i=0; int<=name; int++;){
name[1] = "name 1";
name[2] = 'name 2";
}
This is what i have so far but i know that it is not right. I could make 50 different array and give name i could do name[1] = new name["kevin"]; and so on and keeping that for all 50 people.But that so many lines of code.
so how do i give all 50 a name. and i need to do in one loop or something like that.
or can i do this:
people[] people = new people[50];
If you want to assign a name to all of them according to the pattern name index you do it like this
for (int i = 0; i < name.length; i++) {
name[i] = "name " + (i + 1);
}
and by the way, initialize your array like this
String name[] = new String[50];
open Scanner for input, Take name as input and then loop over 50 times
// open Scanner for input
Scanner keyboard = new Scanner(System.in);
String name[] = new String[50];
for (int i=0; i< name.length; i++){
//take input
System.out.println("Input");
String input = keyboard.nextLine();
name[i] = input;
}